LIBRARY Michigan State University This is to certify that the dissertation entitled Energy Decay Estimates For the Von Karman Plate Equations In Nonlinear Elasticity l presented by Peter Vafeades has been accepted towards fulfillment of the requirements for Ph-D-— degree in Mechanics (Kg/41% Major 7:711: Date Ma 11 1987 M5u..,.,.1m.....;_n' .- .n ‘J' ' - 042771 Mg m ill/Mllllllllll L 29 00963 9851 lVl53l_l RETURNING MATERIALS: Place in book drop to nggAmgs remove this checkout from lJ-IIESIIIL. your record. FINES will be charged if book is returned after the date stamped below. ENERGY DECAY ESTIMATES FOR THE VON KARMAN PLATE EQUATIONS IN NONLINEAR ELASTICITY By Peter Vafeades A DISSERTATION Submitted to Michigan State University in partial fulfilllment of the requirements for the degree of DOCTOR OF PHILOSOPHY Department of Metallurgy, Mechanics and Materials Science 1987 ABSTRACT ENERGY DECAY ESTIMATES FOR THE VON KARMAN PLATE EQUATIONS IN NONLINEAR ELASTICITY By Peter Vafeades This dissertation is concerned with the analysis of Saint-Venant edge effects for nonlinear elastic plates. The model used is based on the von Karman plate equations: a coupled system of two nonlinear elliptic partial diflerential equations with the biharmonic operator as the principal part. Energy methods are used to establish a nonlinear integro—diflerential ine~ quality for a quadratic functional. Arguments based on comparison theorems are then used to establish exponential decay of end effects. The results constitute a version of Saint-Venant’s principle for nonlinear elastic plates. iii Emu Kain) Amer) ACKNOWLEDGMENTS -. I would like to express my sincere and deeply felt appreciation towards my advisor Professor Cornelius O. Horgan for his guidance, assistance, persistence and patience without which this research would not have been possible. I should also like to mention that Professor Horgan inspired me to study mechanics and in particular questions related to Saint-Venant’s prin- ciple, for which I am ever so grateful. I would also like to thank the members of my committee, Drs. Nicholas Altiero, Thomas Pence and David Yen. iv Table of Contents List of Tables ........................................................................................................ vii List of Figures ................................................................... . .................................. viii CHAPTER 1: INTRODUCTION .................................................................... 1 CHAPTER 2: STATEMENT OF THE BOUNDARY VALUE PROBLEM ............................................................................................................ 4 CHAPTER 3: THE LINEARIZED PROBLEM: THE BIHAR- MONIC PROBLEM ............................................................................................ 10 CHAPTER 4: ENERGY DECAY ESTIMATES 16 Section 4.1: Derivation of an Integro—Difl'erential Inequality for the energy for the von Ka’rman equations. .......................................................... 16 Section 4.2: A Comparison Theorem for Integro-difl'erential Ines qualities. ............................................................................................................... 20 Section 4.3: An Improved estimate for the Biharmonic Problem. .................................................................................................................................. 22 Section 4.4: A First Result for the von Karman equations. ..................... 23 Section 4.5: An Improvement on the Result (4.42) for E(0)>0.209. .................................................................................................................................. 26 Section 4.6: An Improvement on Result (4.42) for E(0)0 (uniformly in 17) as E-+ 00,) where the subscript on it indicates partial differentiation and 91, 92, 93, 9,, 12,, I12 né-H,C:—h ///////// —-——____. clamped 7/////// -—--- n=H ,C =-h /////r//// ‘--—-__. clamped ,/<:¢//////7////////// -‘—-—- I. FIGURE 2.1 SEMI-INFINITE ISOTROI’IC ELASTIC PLATE are prescribed functions. Let <73 be the Airy stress function associated with the stresses necessary to cancel out any deformation of the plate (d is the Airy stress function for the so-called bending stresses, see STOKER [17] and KNIGHTLY [18]); then it satisfies the same inhomogeneous boundary conditions as 6 along the clamped sides and homogeneous boundary conditions elsewhere. Thus ‘ 'Re-H) = ale—H) = 91(5). ire—H) = ale-H) = 92(5), ‘ 345,11) = 345,”) = 93(5), area) = Merl) = yrs), o0 (uniformly in 17) as 6—»00. (2.11) The boundary conditions on w are: lie—H) = wn(€.-H) = 0. w(€,H) = w,,(E,H) = 0, 0<€0 (uniformly in y) as :1: -+oo. The functions 31. 5'2 satisfy 31(i1)=31’(i1) =32(:1:1) = 0. (225) By a classical solution to the boundary value problem posed above we mean a pair of functions (u, u) that are four times continuously differentiable in the interior of R and twice continuously diflerentiable on its boundary, that are solu- tions to the system (2.20) and satisfy the boundary conditions (2.22) and (2.24) for prescribed functions III, 112, 5'1, 5'2, assumed to be sufliciently smooth. CHAPTER 3 THE LINEARIZED PROBLEM: THE BIHARMONIC PROBLEM In 1966, J. K. KNOWLES [3] formulated and proved a version of Saint- Venant’s principle appropriate to the plane strain and generalized plane stress solutions of the equations of the linear theory of isotropic elastic equilibrium in bounded simply-connected plane domains of general shape. In [3] an explicit esti— mate (lower bound) is obtained for the rate of exponential decay of the energy with distance from a portion of the domain boundary carrying a self-equilibrated load. This result for biharmonic functions was established in [3] using difl'erential inequality arguments. The special case of the biharmonic equation in a semi- infinite strip subject to self-equilibrated loads on the near end only constitutes a linearized version of the problem described in Chapter 2 here. In the present chapter we provide a brief description of the methods and results of [3] for the semi-infinite strip (see also KNOWLES [19]). Subsequent improvements on these results obtained by other authors will also be summarized.‘] Our treatment in Chapter 4 of the nonlinear problem described in Chapter 2 will be seen to make use of energy decay estimates of the type used in [3]. Thus we consider a semi-infinite strip R of width 2 in the (2,31) plane whose T A comprehensive review of work on Saint-Venant’s principle wu given in 1983 by HORGAN and KNOWLES [4). 10 11 t SEMI-INFINI'I‘I‘. STRIP R FIGUR t 3.! long sides are traction free and whose end :r=0 carries a self-equilibrated load (see Fig. 3.1). The stress field is assumed to vanish at infinity. \Ne are concerned with solutions (23 of the biharmonic equation A243 =0 on R, (3.1) ( 45 is the Airy stress function), subject to the boundary conditions: ¢(0.y)=k(y). ¢.(O.y)=l(y), -10 (uniformly in y) as z-+oo, where k and l are prescribed functions such that k(:l:l) = H (i1) = ((4:1) = o. (3.3) We introduce the notation: Rz={(z,y)inR I122}, L,={(z,y)inR Ix=z}, (3.4) so that z is a running variable along the z-axis. Clearly, R0512. Following [3], [19] we define the function e(¢5) by e(¢) = ¢§+2¢fy+¢fy (3.5) so that the energy stored in R, is given byi E(z) = {emu/1. (3.6) Thus, the total energy is: E(O) = [mad/1. (3.7) By repeatedly applying Green’s theorem and using the boundary conditions (3.2) it is shown in [3] that E(z) = _f(¢z¢zz —¢¢nz +2¢y ¢zyldy- (3'8) L: 1 It is shown in [19] that E(z) is finite. 13 We recall from [3] the following difierentiation formula for functions f continuous on the closure of R, .31. f 71.1 = 41.3. (3.9) 21?, L, . Thus we may write E(z) -_- §;J(¢,¢n—¢¢m +2¢,¢,,)dA (3.10) which implies that fE(s)ds = —f(¢,¢,,—¢¢m+2¢,¢,,)dA. (3.11a) 3. It is convenient for subsequent purposes in Chapter 4 to introduce the Volterra integral operator FU E jU(s)ds, (3.11b) 0 on continuous scalar valued functions. Thus the left-hand side of (3.11a) can be on written as fE(s)ds -FE. Applying Green’s theorem and the boundary condi- 0 V tions (3.2) we can now write [E(s)ds = fE(s)ds -FE = f(¢3+¢3—¢¢,,)dy, 0_ 0. ' (4.27) and 11(0) 2 E (0). (4.28) in order to conclude from (4.25) that E(z) S H(z), z _>_ 0. (4.29) In what follows we show that several such choices of H (2) lead to exponentially decaying estimates for E (z). 22 4.3 AN INIPROVED ESTIIVIATE FOR THE BIHARMONIC PROBLEM First we consider the application of Theorem 1 to the integro-difierential ine- quality (3.15) obtained for the biharmonic problem discussed in Chapter 3. We recall that (3.15) reads: f(z,E’ ,FE) = E' (z) + 4k2(7E(s)ds — FE) = E' (z) + 4k27E(s)ds S 0. (4.30) Since E does not appear explicitly on the left-hand sides ’of (4.30), we have used the notation f (z,E’ ,FE) instead of f (z,E' ,E,FE). It may again be readily verified that f satisfies the hypotheses (4.20), (4.21) of Theorem 1. Furthermore, the hypothesis (4.22) is satisfied by virtue of (4.30) if the constant k is chosen as in (3.17). Now the function H (2) defined by 11(2) = E(0)e"2"‘ (4.31) is such that f (z,H’ ,FH) = H' (z) + 41sz119)“ = 0. (4.32) Furthermore, E(O) = H(0) and so Theorem 1 yields the result 5(2) S E(0)e'2"‘, .220, (4-33) where k is given by (3.17). This provides a sharper estimate than (3.18) or (3.20). 23 4.4 A FIRST RESULT FOR THE VON KARMAN EQUATIONS Returning to the nonlinear problem, we seek a comparison function Hl(z) satisfying (4.27), (4.28), where f is given by (4.26). Our first choice is to consider a function similar to (4.31), which was employed for the biharmonic problem. Thus we consider Hl(z) = E(0)e”“ (4.34) where K is a positive constant, as yet undetermined. Clearly, H1(0) = E(O) (4.35) and so (4.28) is satisfied. We now seek the largest value of R. such that (4.27) holds. We have H1' (2:) = —1cE(0)e-“ = —IcHl(z), (4.36) and i; H1(s)ds —- FH, = jH,(s)ds = 59%;: = gig-51, (4.37) and so recalling the definition of f in (4.26) we obtain “ 1 _ 2 3/2 4k2 f(Z:H11H1,FHI)—-’°H1(Z)—4kflH1 (Z)+TH1(Z) 2 = H,(z)[—1c — 4k2uH11/2(z) + %}. (4.38) Since 0 S [ill/2(2) g [ill/2(0) for all z in (0,00), and fill/2(0) = E1/2(0) by virtue of (4.34) it follows that f (2,111' ,H1,FH1) is non-negative for all z in (0,00) if n>0 is such that 2 —x — 4k2uE1/2(O) + % 2 0. (4.39) The largest value of 1c is obtained by taking the equality sign in (4.39) and so we find 24 1c = 2k(V M2+l—M) (4.40) where M = ka173'(0_) (4°41) and k, p are given by (4.15) and (4.18) respectively. Thus (4.27), (4.28) are satisfied and so from (4.29) and (4.34) we obtain the exponential decay estimate E(z) S E(0)e"", 220. (4.42) A decay estimate similar in form to (4.40), (4.41), (4.42) was obtained by HOR- GAN [28] in his investigation of plane entry flows for the Navier-Stokes equations. We observe that the decay rate It given by (4.40) is a monotonically decreas- ing function of M for 0 cams 3 on SE SEE .59. . 2 s m s s m 1.. m m __ cos id nmd 1nd 14.0 ind 10.0 1nd 1nd imd I: 42/,1 26 4.5 AN IMPROVEMENT ON THE RESULT (4.42) FOR E(O) > 0.209 In Section 4.4 we have established the decay estimate (4.40)-(4.42). On using the result (4.42) in our basic integro-difierential inequality (4.19), we obtain the weaker integro—diflerential inequality —3x1 00 E’ (z) —4k2pE3/2(0)e 2 +41:2 [15(3) 3 -3x1 = E’ (z) — 4k2uE3/2(0)e 2 + 4k2(_[E(9)ds — FE) g 0. (4.43) o Denoting the middle term of (4.43) by §(z,E' ,FE) it may be readily verified that 6 satisfies the hypotheses (4.20), (4.21) and (4.22) of Theorem 1. Thus, it remains for us to determine a comparison function H 2(2) such that 9(21H2'1FH2) Z 0 and H2(0) Z E(0). (4-44) in order to conclude that E(z) _<_ H2(z), z_>_0. (4.45) Consider the function :12 112(2) = 0,33/2(0)pe 2 — or?” (4.46) where C, and D are constants to be determined. We have -3x2 112' (z) = —§2-’EC,E3/2(0)peT + acne-2'“, (4.47) and 27 {H2 2(s )ds —FH2= IH2(s)ds -3xz __ atEtmuvue 2 .oe-uv _ _. (4.48) 3_s 2* 2 Thus, 1—3“ 31: C +8k20 To ensure that g(z,H2’ ,FHQZO, the constant 01 is chosen to satisfy 01(— - —)_ > 4k2 (4.50) where 1:, k are given by (4.40), (4.15) respectively. The smallest constant 01 is obtained by taking the equality sign in (4.50), and so we get 24k2n 161112—9102, provided that l6k2—9K2 > 0. On using (4.40), (4.41) we see that this condition is , = (4.51) satisfied if 4 E0 >— , 4.52 (o ) 45112 ( ) that is, if E(O) > 0.209. (4.53) It remains to satisfy the second inequality in (4.44). Thus we set 0,E3/2(0)u — D = E(0), (4.54) thereby satisfying the second of (4.44) with equality, and so D = o,E3/2(0)p — E(0). (4.55) By virtue of (4.51) and (4.55), the result (4.45) reads: 28 —31cz E(z) g E(0)e’2‘” + 0,)1E(3/2)(0)[e 2 44'“), z_>_0, (4.56) provided that E(O) > 0.209, where 24k2n = 4.57 ’ 16k2—9n2’ . ( ) n = 21W M2+1—M), (4-58) M = kin/E(0), (4.59) where k=1.11 and u=0.619. Note that the estimate is made up of two terms: the first is the estimate for the linear problem, i.e. the biharmonic problem, while the second is an exponen- tially decreasing correction which depends on the magnitude of E(0). In the sequel, we shall refer to (4.56) as result II. The result is not valid for E(0)<0.209 but for such E(O) the estimated decay rate 1: as given by (4.40) is quite close to the estimated decay rate 2k for the biharmonic problem. In fact for E(0)=0.209 we get It: 0.734(2k). Moreover, It is even closer to 2k for smaller energies (see Figure 4.1). The result II provides a sharper estimate than I for values of z greater than 2, where 2 depends on the total energy E(O) as indicated in Table 4.1 (see also Fig. 4.2). Table 4.1: Values of E 153(0) 2 0.25 0.54 0.50 0.63 1.00 0.77 1.50 0.89 2.00 0.98 2.50 1.06 3.00 1.14 3.50 1.21 4.00 1.27 4.50 1.33 5.00 1.39 6.00 1.49 7.00 1.59 8.00 1.68 9.00 1.76 10.0 1.84 30 __ oz< _ mbammm no 285528 3 o: 3qu5 SEE .58. N 825% (2)3 A083N3 31 4.6 AN IMPROVEMENT ON RESULT (4.42) FOR E(O) < 0.529 The approach we used in- the previous section was to simplify our basic integro—diflerential inequality 00 f(z,E’ ,E,FE) = E' (z) - 4k2pE3/2(z) + 41:2 j E(s)ds g 0, (4.60) z by using the estimate (4.42) for the nonlinear term E3/2(z). Here we consider a difl'erent method which also involves simplification of (4.60). Recall from the end of Section 4.2 that the estimate 150) 3 He) (4.61) holds for comparison functions H (2) such that f(z.H' ,H,FH) 2 o, o _<_. < oo, (4.62) and 11(0) 2 E(0). f (4.63) We seek a comparison function H3(z)>0 which satisfies H3’ (2) — 4k2pH3/2(2) = —2kH3(z), z 2 0, (4.64) so that f(z,H3' ,H3.FH3) reduces to f(z,H3’ ,H3,FH3) = —2kH3(z) + 411-2 j H3(s)ds oo = —2kH3(z) + 4k2({H3(s)ds — FH3) a f(z,H3,FH3). (4.65) The first order ordinary differential equation (4.64) has the solution 173(2) = (0.21:5 + 2kp)-2, (4.66) where 02>0 is a constant yet to be determined. It remains to establish that the choice H(z) = H3(z) satisfies (4.62) and (4.63). TO show that (4.62) is satisfied, it suffices, by virtue Of (4.65), to show that f (2,113,171,) 2 0, 0 g z <00. (4.67) A direct verification of (4.67) is diflicult due to the complexity in integration Of the function H3(z) defined in (4.66). We will establish (4.67) by using a contradic- tion argument. Thus, suppose that f(z,H3,FH3) < 0, 0 g z <00. (4,68) Consider the function H .,(z) defined by mm = [(02+2kp)e"‘]"2. (4.69) It may by readily verified that f (z,H,,FH,) = 0, z 2 0, (4.70) and that H3(0+) < H,(0+). (4.71) We now employ a stricter version of Theorem 1 (WALTER [27] p. 122) wherein (4.22) is strict and (4.24) is replaced by V(0+)< W (0+). Now the operator f defined in (4.65) satisfies the hypotheses (4.20), (4.21) of Theorem 1. Further- more, in view of (4.68), (4.70) and (4.71) the remaining hypotheses of the stricter version of Theorem 1 are satisfied for the choices V = H 3, W = H 4. Thus, we con- clude that 173(2) < 114(2), 2 Z 0, (4.72) which is a contradiction by virtue Of the definitions Of H3, H4 in (4.66), (4.69) respectively. Thus, (4.68) cannot hold and we deduce that (4.67) holds. It remains for us to choose the constant 02 > 0 such that (4.63) is satisfied with H 5 H3. The largest such constant is Obtained by taking the equality sign in (4.63) and so 0, = E(0)-1/'-’ — 21:71. . (4.73) TO ensure that 02 is positive, we require that 33 q C E(O) < i, as 0.529. (4.74) 4km Thus for sufiiciently small total energies E(O) satisfying (4.74), we conclude from (4.61), (4.66), and (4.73) the decay estimate 13(2) s 1 1 . ‘ (4.75) l E(O) c u(e )l where k, p are given by (4.15) and (4.18) respectively. In what follows we refer to (4.75) as result III. The result 111 is an improvement over the estimate I of Section 4.4 for z 220 (see Fig. 4.3). The value of 20 depends on the total energy E(O) as indicated in Table 4.2 below. Table 4.2: Values of 20 E(O) z, 0.10 2.41 0.20 3.13 0.30 3.99 0.40 5.28 0.50 8.58 34 5 oz< _ mbammm no zone/€28 ms 0.... ofioion SEE .58 N 825% (2)3 ASHBNB 35 4.7 AN ESTIMATE WITH Z-DEPENDENT DECAY RATE We now describe an argument which is more elaborate than the preceding and which leads to a decay estimate with a z-dependent decay rate. We seek comparison functions H (z) of the form 175(2) -.- E(0)c-41):,J'(%]—, (4.76) where x(z)20 is a function to be determined. The function x(z) must be such that 175(2) satisfies (4.27), (4.28). The particular form of the right-hand side Of (4.76) has been chosen so that H5(2) may be readily integrated. This integration is necessary in the evaluation of f (2,1-15' ,H5,FH5). Furthermore, the results Obtained already suggest that we seek a decay estimate with decay rate 1: (given by (4.40)) for small values Of z and decay rate 2k (k is the decay rate for the biharmonic problem) for large values Of 2. Thus, the function x(z) appearing in (4.76) will be required to satisfy X(0) = 0. X’ (0) = K. (4.77) x(z)-+<>0. x’ (z)-+2k as z-wO. (4.78) and X' ' (2) Z 0. z _>_ 0. (4.79) Observe that the first Of (4.77) ensures that H5(0) = E(O) and so (4.28) holds. By direct calculation from (4.76) we Obtain j (2,11; ,H5,FH5) = -2) E 0 :42 [X"(2) — X'2(z) " 4kg” E(:)e 2 X' 3”(3) + 4’52]. (4'80) We now seek to find a x(z) satisfying conditions (4.77)2-(4.79) and which renders the right-hand side Of (4.80) nonnegative. 36 Consider the choice XIV) = It + (ilk—”)2 (4.81) Z+C3 ’ where C3>0 is a constant tO be determined. It is readily verified that (4.77)2, (4.78); and (4.79) are satisfied by x’ (z) for arbitrary Values Of 03. Upon integra- tion and use of (4.77)l we obtain x(2) = £x’(s)ds = 2k[z — 03(1 — A)ln( 2 +303”, (4.82) where x=fiu<1 um) 21: Clearly x satisfies (4.78), for arbitrary values of 03. It remains to satisfy (4.27), that is fZO, in order to conclude that E(z) S H5(z), z 2 0. (4.84) Thus by virtue Of (4.80), we choose the constant 03 in (4.81) such that .2 (/—- ——)-""l’ gun—mflpy-“JQPWR 2X”Wd+4H2fi, 220 (4%) K . The largest such value Of 03, depending on the value of E(0), is determined numerically and the results are shown in Table 4.3. Thus we have established the estimate I x-IZ + C .E 0 .6 (0. He 2+C3, z_. M8) where Z + 03 K _y 4"."I = Z — 03(1— A)ln( C3 ), A = E—k- < I. (4.81) This result will be called result IV. The result IV is sharper than estimate I for sufliciently large z(see Fig. 4.4). The values of 2 beyond which (4.86) provides the sharper estimate, 2 2 .7. are shown in Table 4.3. 37 Table 4.3: Values of C3 and E E(O) C3 3' 0.05 1 .00 0.85 0.10 1.13 0.90 0.15 1.25 0.94 0.20 1.35 0.97 0.25 1.45 1 .00 0.30 1 .55 1.03 0.35 1 .64 1 .06 0.40 1.73 1 .08 0.45 1.82 1.11 0.50 1.91 1.13 1.00 2.75 1.33 1 .50 3.59 1.50 2.00 4.43 1.65 2.50 5.26 1.78 3.00 6.10 1.90 3.50 6.95 2.02 4.00 7.81 2.13 5.00 9.54 2.33 6.00 11.27 2.51 7.00 13.03 2.69 8.00 14.81 2.85 10.00 18.38 3.15 38 >_ oz< _ mbammm no 285.4028 4.4 0.... .osuflovm SEE .59 N 82585 (2)3 ASHENE CHAPTER 5 DISCUSSION OF RESULTS 5.1 A SUNIMARY OF THE RESULTS OF CHAPTER 4 FOR THE VON KARMAN EQUATIONS In Chapter 4 we have established four upper bound results on the energy E(z) associated with the the von Karman system for our problem. Of these, result I Of Section 4.4 and result IV of Section 4.7 hold for all total energies E(0), whereas result 11 of Section 4.5 holds for sufficiently large total energies (E(O) > 0.209) and result 111 of Section 4.6 holds for sufliciently small total energies (E(O) < 0.529). We now present a summary of these results: Result 1: For any total energy E(O): E(z) S E(0)e"", z 2 0, (5.1) where x = 210/1142 + l-M), (5-2) M = kuVE(0), (5.3) and k = 1.11, p = 0.619. (5.4) Result 11: For sufliciently large energies, E(0) > 0.209: -3xz E(z) g E(0).-2" + o,pE3/2(o)(. 2 — e'2h ), z _>_ 0, (5.5) where 24131: a —— > o, 5.6 1 161:2 - 91:2 ( ) 39 40 and 1:, k are still given by (5.2)-(5.4). Result III: For sufiiciently small total energies, E(O) < 0.529: 15(2) s 1 1 . z 2 0. bl _ 2k 88-1 2 [We #(6 )l where k, p are given by (5.4). Result N: For any total energy E(O): 1 >142 "l" C < '2’“ —_——3 > E(z)_E(0)e 2+03 , z_0, where 0 Z, = Z — 03(1 — X)In(z_+—3), 03 X = .5... 1’ 2]: < (5.7) (5.8) (5.0) (5.10) where 1:, k are given by (5.2)-(5.4) and 03 is a constant that depends on E(O) (see Table 4.3). 41 5.2 A CONIPARISON OF ALL RESULTS In Chapter 4 after establishing result I of Section 4.4 we proceeded to estab- lish a series of improvements on this first result. Once presented, all new results were compared to result I. We now compare all results to one another and con- struct the best upper bound for E (z) for difierent total energies E(0). Due to the fact that results H and III are not valid for all energies we break up the discussion into three parts: A. For E(O) < 0.209 where results I, III and IV are valid. B. For 0.209 < E(O) < 0.529 where all results are valid. C. For E(O) > 0.529 where the results I, II, and IV are valid. A. E(O) < 0.209: As can be seen from Figures 5.1-5.4 the best upper bound for E(z) is provided by the function: E(0)e"“, for 0 S 2 < F )5“: + 03 (5'11) , forF 2 where 2 depends on the total energy E(O) (see Table 4.1). Note that results III and N do not enter into the composition of U2(z), and that for this range of energies result I is the sharpest available for small 2, whereas II is the sharpest for larger z. C. E(O) > 0.529: As can be seen from Figures 5.9-5.12 the best upper bound for E(z) is provided by the function U2(z) defined in (5.12). Qualitatively, for this range of E(O) we have exactly what held for the range of energies in B with the only exception being that the estimate III is not valid here. Another way to compare the bounds Obtained is to determine the distance 295 from the left end of the plate 2 = 0, at which 95% of the total energy E(O) has dissipated (see Table 5.1) and the distance 299 from the end, at which 99% of the total energy E(0) has dissipated (see Table 5.2). These distances are called "characteristic decay lengths". Note that a characteristic decay length of 2.00 corresponds to one width of the plate. 43 Table 5.1: :95 values E(0) I 11 III Iv 0.05 1.58 - 1.62 1.53 0.10 1.68 - 1.78 1.61 0.15 1.76 - 1.92 1.67 0.20 1.83 - 2.08 1. 73 0.25 1.90 1.70 2.25 1.78 0.30 1.95 1.74 2.45 1.82 0.40 2.06 1.82 2.99 1.91 0.50 2.16 1.88 4.35 1.98 1.00 2.57 2.16 - 2.30 2.00 3.20 2.60 - 2.79 3.00 3.71 2.96 - 3.20 4.00 4.15 3.28 - 3.55 5.00 4.55 3.57 - 3.87 6.00 4.92 3.84 - 4.16 7.00 5.26 4.09 - 4.44 10.00 6.16 4.76 - 5.17 44 Table 5.2: 29,, values E(0) I II 111 0.05 2.42 - 2.38 2.32 0.10 2.58 - 2.55 2.40 0.15 2.70 - 2.71 2.48 0.20 2.81 - 2.88 2. 55 0.25 2.91 2.52 3.06 2.61 0.30 3.00 2.57 3.27 2.67 0.40 3.17 2.67 3.83 2.77 0.50 3.32 2.76 4.35 2.87 1.00 3.95 3.17 - 3.28 5.00 6.99 5. 20 - 5.33 10.00 9.47 6. 96 - 7.04 45 2 mm<8 8.01808 SEE .58. to 0.... N 82528 00.0 18 1N0.0 1.0.0 1.0.0 (2)3 1083MB 46 94 028 8.01600 55% .58. N0 .0: N 82520 (2)3 1083N3 47 2 828 2.0.1800 SEE 359. man .0: N 8259a { F) N 00.0 100.0 T 0 e- O 0.30 (2)3 1983N3 48 2 Him/48 08.1800 655 .58 4.1.. .0: N 8259a 00.0 300.0 T0...0 Inpd 0N0 (2)3 1983N3 49 ---1- Am mm<8 8.0.1.800 sommzm .52 mm .0: N mozflrm—o .000 58.0 T..0_..0 10.30 TONd 0N0 (2)3 1083N3 50 Am mm<8 ondnflovm GEE .59 gm, .9... N mozflrma “00.0 T000 10F.0 13.0 T0N.0 100:0 0n .0 (2)3 AOBBNE 51 Am mmév ofoiem Gauzm .52 B .o: N woz<._.m_0 (2)3 mama 8 H28 omduavm >05sz .59 m.m .9... N 82590 (2)3 ,ASBBNE 53 8 mm<8 3......“on >9..sz .59 oh .0: N wozflrma (2)3 warms 54 8 mm<8 QNLSM >96sz .52 Ed .9... N moz<._.m.0 (z)a mama 55 _ . . r . _ L _ L 6 9.28 adieu 655 .59 :6 .9... N moz<._.w_0 . 0 ¢ 0 N w I 'l' I ” 1 N (z)a mama 1 n T r... 56 8 H.980 QELSM 552m. .59 a; .0: N moz<._.m_0. (2)3 mama 57 5.3 REMARKS ON THE CONSTANTS k, u AND THE TOTAL ENERGY E(0) As already discussed in Chapter 3, we have used. the largest available value of k for which (3.15) holds, it = 1.11, which underestimates the exact decay rate, R = 2.10. If one could establish (3.15) with a value of k larger than 1.11, the results of Chapter 4 would still hold and would become sharper. One would only need to re-evaluate the values of 2, E, 20 and the constant 03. The constant p in (4.17) is probably greatly overestimated because of the repeated use of some weak inequalities in its derivation (see Appendix A). Any improvement in the value of u would result in an immediate improvement of all results in Chapter 4. All results presented in Chapter 4 involve the total energy E(0) which depends on the geometry and the boundary data at the z = 0 end. In [3] Knowles established an upper bound for the total energy E(0) of the biharmonic problem in terms of the applied traction for a certain class of finite domains with the help of variational arguments (see also [4]). The results of Chapter 3 remain valid when E(0) is replaced by an upper bound. It is reasonable to anticipate that by using variational arguments an upper bound for the total energy E(0) of our problem can be established in terms _of the traction applied at the end and the displace- ment there. We shall not pursue this issue here. 58 5.4 QUESTIONS FOR FURTHER INVESTIGATION We can now raise a number of interesting questions for further investigation. Firstly, in the context of the semi-infinite strip, one could ask how our decay esti- mates depend on the particular boundary conditions used. Secondly, one could introduce a distributed lateral load on the plate and investigate its efl‘ect. Thirdly, interesting bifurcation and associated stability questions arise when non self-equilibrated compressive loads are introduced. Such stability questions have already been investigated by many authors for specific sets of boundary condi- tions. It would be very interesting to attempt to extend these already existing results by admitting wider classes of boundary conditions through the application of a Saint-Venant principle type of argument. Finally, our problem as well as any of the above mentioned open questions can be posed for a "long" thin plate of finite size. APPENDIX A VERIFICATION OF (4.17) To verify (4.17) we follow an approach used by HORGAN [28]. In this development we make use of the following Wirtinger-type inequalities for sufiiciently smooth functions w(y) defined on the interval (-1,1) of length 2: (i)If w(y) is Cl(-1,1) and w(—l) = w(1) = 0, then1 I ”2 1 f wfdy 2 ?[ wzdy. (A.1) -1 -1 (ii) If w(y) is C’(-1,1) and w(—l) = w’ (-1) = w(l) = w'(l) = 0, then 413 11w; dy > -2-— wzdy, . (A.2) l and Iron“; dy > —_{w2dy, (A.3) \ where #0 is the smallest positive root of the transcendental equation cospcoshu = l and so #0 = 4.73 which is slightly larger than 31r/2. For convenience, we use the latter value in (A.3) and thus we obtain 1 4 ‘ I I wédy > 32: Iwzdy. (AA) -1 -1 For a more detailed discussion of the inequalities (A.l) - (A.3), see [28] and the ‘ The multiplicative constant is written in a manner displaying the interval length explicitly. 59 60 references cited therein. We also make use of the following one-dimensional Sobolev inequality: 1 1 1 .1. .4... s. 511.2... "19””) (A5) for sufficiently smooth functions w(y) such that w(-‘—l) = w(l) = 0. Inequalities of the form (A.5) in two and three dimensions have been widely used in investiga- tions of uniqueness and stability for the Navier-Stokes equations. A direct proof of (A.5) is given by HORGAN [28], where it is shown that (A.5) holds with o=4. A modification of the argument given in [28] may be. used to show that (A.5) holds with a=l. This value of a is taken in (A25). below. Finally here, we state the following simple algebraic inequality (0 + (2)3/2 2 Vain/F for a, b > o, (A.6) which we also use in the sequel. We now employ some of the above inequalities to establish a series of inter- mediate results: A. We first establish an upper bound for _[m‘(z,y)dA (A1) 3. where m(z,y) is a function that vanishes along the semi-infinite clamped sides of the plate and that tends uniformly to zero as :r—voo. In view of (2.22) and (2.24) v u can be sub- the functions u, v as well as their first partial derivatives 11,, av, ,, , stituted for In. On applying the Sobolev inequality (A.5) we get co IM‘(=.y)dA S %I[Im2(s.yldylllm.2(s.y)dylds- (A3) R, x L, L, Green’s theorem, the regularity conditions and the Cauchy-Schwarz inequality allow us to write, for such .922, 61 Im2(.,,,)dy = —2Im(s.y)m.(s.y)dA I mm )"iImfm .<_ 2(I m2...) (I my... ‘2.’ (A.9)' On combining (A.8) and (A.9) we get ImwA _<_ dim2M)1/2(Im.’M)1/2(Im.’dA)- (A.10) R, R, R, R. B. Suppose now that the function m in (A.10) is chosen to be u (or equivalently v). Then we have ‘dA < 2M ”2 2dA ”2 24A A11 I" _dI" ) (In. ) (In, )- (- ) We now apply inequality (A.3) with w = u , in an obvious way in (A.11) to get W 2 Iu‘dA <3°227(Iw .dA) (— “In 34A)” (— ,;IuILdA) 9 2 0’2 / 2 < —— E, . A.l2 - 9.5 [ (2)1 ( ) Note that (A.12) is also valid when we write v in place of u. C. Now suppose that the function In in (A.10) is chosen to be uy (or equivalently v”). Wehave Iu‘dA <0(Iu2M)1/2(Iu2dA)1/2(Iu2dA) (A13) R v — R v R 3v R w ' ' We now apply inequality (A.2) with w=u to the first integral on the right-hand side of (A.13) to get Iu‘dA <—(Iu, 334.4) ”(In 3,4,4)” _<_21/2 E2(z). (A.14) Again, we note that (A.14) Is also valid when we write v in place of u. D. Now, suppose that the function In in (A.10) is chosen to be u, (or equivalently v, ). We have Iu:dA g e(fufdA )1/2(Iu,§dA)‘/2(Iu,§dA). (A.15) 62 Now apply inequality (A.l) with w=u, to the first integral on the right-hand side of (A.15) to get 2 3/2 1/2 qu‘dA g—I—(jugu) (Inga) R, R: R! 0 2 S mE. (Z). , , .- (A.16) Again, we note that (A.16) is also valid when we write v in place of u. E. In view of inequality (A2) we have .,.“!sz S LIuJ‘LdA 8. "2 8. Ed?) fl ’ which is also valid when we write v in place of u. S (A.17) F. In view of inequality (A.1) we have lufdA S ifuédA a, #2 a, 2Eu(z) < -— "2 i which is also valid when we write v in place of u. (A.18) We now proceed to obtain upper bounds for the five integrals I 1 — 15 defined in (4.16) and thereby establish (4.17). The Cauchy-Schwarz inequality, (A.14), (A.18) for v, and (A.6) yield: I 1 = I u,2v3dA R. S (IuyidA )1/2(1.!”22M )1/2 01/221/4 32 _ WE / (Z) (A.19) The Cauchy-Schwarz inequality, (A.16), (A.12) for v and (A.6) yield: .. 63 I2 = 2111,11” vdA 3. s 2(IufidA)1/2(.I.u,‘dA)1/4(_[v‘dA)1/4 R, R, R, g 2(%%317/:-)E3/2(z). (A20) Similarly, the Cauchy-Schwarz inequality, (A.12), (A.14) for v and (A.6) yield: 13: qu’vndA 3. 1/2 1/4 1/4 s