......Vm\.., “: 4 2. x 3 . .33? y. . 145 x a f. o... It . ruuxpfihgr (“in 5.31:. 3...“ «55‘: h. : » . 2 We may.” . a a r .l V ‘ . n .Mydsugfi Wan-3.. .r... ..... £5“?me 3%?4 ‘6. II 1“ Jinx??? (I... .dfiigal. Vuthouvhiflfl l t“! gut-min. .. . On. .fimmm a; .1»; it‘ll-$1 .l . . .me:: :Vi: . I 2": - .. gm?» 4% .239.» .. . G- «If: 5%.... Hmm 3.145. . Nifiu‘lgwh vi! . n .f‘ 2 . 9.. . 5.3%. dear: ‘ LI: «‘9. 1. I inn-Iv- 293v .JHPC‘ H. . . .né 3:}. . u... E. ‘v... .3 $9.33.... W.» . , . 3. “fluvig g . .ui‘]! ‘I. ( .t. .5th .. i1» ; fin “rm. . J1. . w. ‘0, 554% . I I . 4:1. lllllllllllllllllllllllllIllIllllllllllllllllllllll 3 1293 01688043 This is to certify that the thesis entitled Enhancing Student Learning With PowerPoint Presentations presented by Ernest P. Luttig has been accepted towards fulfillment of the requirements for M-S- degree in interdisciplinary Physical Science %<>|~.\ Number of Students 0 o N ' ' ' After PPP v ‘° oo o Before PPP '— (D '— Raw Score Figure 5 Titration Quiz Results For additional information regarding the effectiveness of the presentations I asked students to respond to 3 statements (Appendix P). They also could provide free response input for future use of the slide-shows. The following graphs show how students (n=69) responded to these statements about PowerPoint Presentations. The statements along with student responses are included in each diagram. The first graph (Figure 6) shows that 81.1 % of students surveyed would like to see one or two PowerPoint presentations per week, 13.1 % would like to see more 26 I Would Like PowerPoint Presentations To Be Used In Class Number of Students Never ._ More than hwme weekly Twnce a week Omna ~F7 week 2 Figure 6 RESPONSE TO SURVEY QUESTION 5 than two a week, and only 5.8% would not like to see any. Certainly because of different learning styles there will be some students who do not like something about the presentations. However, for a large majority of students, the PowerPoint presentations are meaningful. In fact, upon further analysis, one of the students who did not want any presentations said it was because they go too fast. This problem is easily remedied by allowing the student access to the programs to use at his/her own pace. Figure 7 shows responses (n=66) to a statement about using the PowerPoint presentations in other classes. This correlates well with the previous conclusion showing that 78.8% of students surveyed either strongly or somewhat agree 27 I Wish More Teachers Used PowerPoint Presentations In Class 96 of Respondents 't Care 20 o: I) is» a Disagree Somewhat Agree Figure 7 RESPONSE TO SURVEY QUESTION 9 that they would like to see more teachers use PowerPoint presentations in class. This indicates that students generally like the idea of the presentations being used in other contexts. Responses to the seventh survey question statement reflect the students' (n=69) perceptions when asked to describe their ability to learn when using PowerPoint presentations in chemistry class (Figure 8). 45.6 % of the students felt they learned more When The Teacher Uses The Computer To Teach Us In Class I... #UI UIO N (.0) U1 U1 96 of Respondents U'I -I—I U1 Learn Learn Learn More About Less the Same Figure 8 RESPONSE TO SURVEY QUESTION 7 when learning material from a PowerPoint presentation, 50.0 % thought they learned the same and only 4.4 % felt they learned less. With almost half of the students feeling they learn more with these presentations there is an indication that the time to develop and use is worthwhile. Furthermore, with alternate teaching strategies employed to give students a different perspective the 4.4% should still be able to learn the concepts. Along with responding to these questions students were asked to indicate things they liked, disliked or wished would change about the PowerPoint presentations. Some of the positive comments indicate some of the desirable traits I mentioned previously about the program. For example, one 29 student wrote, “I liked the way we could go back whenever we needed to". Another wrote, “you can go through the material at a pace that you like". Still another respondent stated, “It made me pay attention to what was going on in class. I paid attention because it was interesting" Several others expressed thoughts similar to these. In terms of negative statements, one student replied, “I still can't see the atoms reacting. I am,a visual learner. I want to see images of atoms". This is one area I am working on and as the years progress and technology in computers increases I plan to include many more images. Many of the other negative comments related to the speed of the presentations. Many students felt they did not have time to adequately write down and think about the concepts being presented. This is another area I am modifying to meet student needs. Making the programs accessible to more students outside of class will also help with this problem. One possible solution is to eventually have these presentations available on the waverly homepage accessible through the internet. 30 SUMMARY AND CONCLUSIONS In conclusion, I am confident that the use of this new technology, PowerPoint presentations, will improve both the teaching style that I have developed and the learning of my students. The PowerPoint presentations generate interest among students. The survey and general statements about the presentations indicate that students both enjoy and learn effectively from the slide shows. It is also evident that it is important to use other teaching methods in conjunction with the presentations. By diversifying the instructional technique, student interest is piqued and motivation is kept high. The presentations are also dynamic. As the students are given feedback about certain presentations, it is easy for the instructor to modify and add onto presentations to make them more effective or interesting to students. The pace of the slide shows are easily adjusted and the use of other modes of teaching such as demonstrations or discussion can be interjected to maximize the learning of students. The use of the PowerPoint presentations is effective both in presenting new material and as a review tool. This is especially important for students who are absent on days when new material is introduced. For this reason I am trying to gain access to a second computer on which the presentations could be reviewed at lunch, when I make myself available for help. The students will be able to use the 31 programs outside of Class and efficiently obtain the missed information. The only difficulty will be gaining access to computers for this use. The web is a possible solution to be used in the future enabling students to access the presentations from home. Other interesting aspects of PowerPoint are its potential for uses in other classes as well as the use by students to present information themselves. The computer is a fixture in today's workplace and student exposure to its uses will benefit them in the future. Whether the instructors are motivating students to create their own presentations or modeling the effective use of technology, the students will gain insight into the advantages of computers as a tool. In conclusion, the computer, and PowerPoint presentations in particular, have significant possibilities towards improving instruction and the ability of students to learn and prepare for their future. With continuing or increasing support for computer use in schools, programs such as PowerPoint will play a very important role in effective education. I hope that other schools will follow the lead of districts such as the one in which I teach and support the use of programs like PowerPoint to enhance student learning. 32 APPENDICES 33 APPENDIX A CONVERSION FACTORS Conversion Factors Number of Atoms<—> Moles<->Mass Moles can be converted to mass ‘ and vice- verSa ‘ ll Nkmx mdmwmmuickmun ‘ - LfimSQQ x mdameeLdemmt_ 1 mol 34 Moles can be converted to number Of particles and vice- versa A M0108 6.022 x m atoms x Number . Example: How many grams of Copper are needed to make some ° Start with the given number of moles and multiply by the correct conversion factor. (Hint: use the diagram on the previous slide) 35 Solution: : " 20.00 moi Cu x 63.55 g Cu = 12709 1 mol Cu Example: How many moles of Gold are required to make a computer circuit board that needs { 45.0 g Of gold to complete? 5 Start with the given number of grams and find a conversion factor that will change to moles. (Hint: use the diagram that relates moles to mass) 36 Solution: 45.0 g Au x 1 mol Au 2 0.228 mol 196.97 g Find the mass of a single atom of silicon which is used in making computer chips, caulking, detergents and more. Start with the amount given (in this case 1 atom Si) and find an appropriate conversion factor(s) to change to the desired units (mass of one atom Si). 37 ] Solution: Why mu'st you assume 3’ that One atom Of silicon has an 7 ' infinite number Of significant digits? 1.00 atom Si x W What “'1"me wanttocanoei? 1.00 atom Si x W You want to cancel atom 35 here There is ”0 di’eCt equality between these . two but I do know that there are 6.022 x _. i , ‘1 10 23 atoms in one mole of Si. Therefore; 38 I x 1 mol Si 6.022x 10 23Wi Now we have accomplished cancelling the atoms Si but we still do not have the units we want (grams of Si), so we try to find another equality to make a conversion factor relating mOI Si and grams Si. That relationship is 1 mol Si 2 m 28.09 g. Therefore; 1.00 Mx 1moLSi/ 6.022x10 23W X 2am: 1W 39 APPENDIX B Molar Mass Of a Compound TO determine the molar mass Of a _ _3 substance you must add the 3 r: individual molar masses of all of E E the elements in the formula. 3 Example: What is the molar mass of barium nitrate? I Write and interpret the formula. The formula for barium nitrate is Ba(NO 3)2 . The subscript 2 means there are 2 NO 3' ions each containing 1 N and 3 O atoms. Therefore; every mole of the compound contains 1 mol Of Ba, 2 mol of N and 6 mol 41 Example: What is the molar 7 mass of Ba(NO3)2? I Check the periodic table for the molar mass of each element. (Round to the nearest 1/ 100 3-) ‘1 Ba molar mass = 137.33 g/mol _... N molar mass = 14.01 g/mol 0 molar mass = 16.00 g/mol Ba(NO3)2 iI Next determine the total weights of the g: j, number of moles each atom in the formula .31 mol Ba x 137.33 g = 137.33 g 1 mol Ba 1%)}.2 mol N x 14.01 g = 28.02 g 1 mol N 36 mol 0 x 16.00 g = 96.00 g E: 1 mol 0 42 Ba(NO3)2 I Add the masses calculated to get the total molar mass of the compound. 1 mol Ba = 137.33 g 2 mol N = 28.02 g g; 6 mol 0 = 96.00 g Molar mass of Ba(NO3)2 261.35 g/mol Example: What is the molar mass of Iron III oxide? (ferric oxide) Write and interpret the formula ’ ads-J..." . ‘ " 1' 32. L . ' L.';‘L~:..\L~ .3.) . L: v‘. 1 The formula for iron III oxide is Fe 203. Therefore; every mole of the compound 1‘ contains 2 mol Of Fe, and 3 mol of 0. it”: I I 23; 43 What is the molar mass of Iron III oxide? (Fe203)? l Check the periodic table for the molar mass Of each element. (Round to the nearest 1/ 100 g.) Fe molar mass = 55.85 g/mol 0 molar mass = 16.00 g/mol Fe203 I Next determine the total weights of the number Of moles each atom in the formula 2 mol Fe x 55.85 g = 111.70g lmol Fe 3mole 16.00g =48.00g lmol O Fe203 i I Add the masses calculated to get the total molar mass of the compound. 2 mol Ba = 111.70g _ 3 mol 0 = 48_g.00 '_ Molar mass of Fe 203 159.70 g/mol Percent Composition problems (more uses Of molar mass to describe compounds) . IThe percent of each element is simply the molar mass of the element divided by the molar mass of the whole compound and multiplied by 100. i luv..."— ~-d ,4 e... Hllll l 45 Example: Find the percent " composition Of magnesium hydroxide. I Find the conect formula - v - l u. w»: . . - - 1.. ~.--, 5, -w - l .- - A ..._-~- . . <. . - :n- 3 ,‘- : 3v .. ‘I' ‘ ' '5‘ “ 3‘ I. '. ‘ . .‘ . ' 1. I . ” N 7. I.“ ,‘u . . T" .' x '-’ v‘. in ~.’ -I. .‘Jr ‘ ‘- .1 ,w. .. . .'..- Jr“ A. r .. r .1 g - . : . i ': ‘-‘ "2- a .3 1 ‘ .. -‘ A.‘ :1 ,. A .j -.- J ‘tv- .«-_ I 11‘ I- '. ‘ .- ’ . ' x“ ‘ . E‘is'hmx‘ ~. Y"‘§M€¥f§“"7% , . ._,. ..i. ."..:-'.... ‘-.r ‘. ...r. . »; ... .- ._ . -. 1“. ,:«n .13.;7. ... composition of magnesium hydroxide. . Find the correct formula I Mg(OH)2 fi—_ _—9_ L wan-i ...J‘D Mg(OH)2 I Find the molar mass of Mg(OH) 2. Mg(OH)2 ’ lmolng 24.3.Lg. = 24.31 g 1 mol Mg 2 mol 0 x 16.00 g = 32.00 g 1 mol 0 2moleflLg = 2.02g 1 mol H Molar Mass of Mg(OH) 2 =58.33 g/mol 47 Percent Mg = MasmflMQlMg. Percent O = Percent H = l LI 1: m; Use the molar masses of Mg, 0 and H to set up calculations of percentage composition for each element in the compound x 100 Molar mass of Mg(OH) 2 Mass of2MolO x100 Molar mass of Mg(OH) 2 Mass of 2 Mol H Molar mass of Mg(OH) 2 x100 Solution for Percent Composition of Mg(OH)2 I Percent Mg = 24.3] g x 100 = 41.68% 58.33 g l Percent O = 32.00 g x 100 = 54.86% 58.33 g I Percent H = 292g x 100 = 3.46 % 58.33 g What do you notice about the percentages? . . . . . . ,V V , . .7 . . ' , . ‘1 ,\._ ,__,, ,, v, ,2- .. ~.~ «.A .A,» ,w ., ~ -. «- ”Harlan-4 ..-..-_:—-, “Uranus. . _,.,fl I When you add them up; 41.68% + 54.86 % + 3.46 % = '3‘ 100 % This will be true any time you find the percent 5:3 composition of all of the elements in a :3: r: compound. . lllLl ‘l i l s t L - in aformual from percent composition data. I Find the formula for the ingredient of a rechargeable battery that has the following percentage composition: 21.9 % O, 1.4 % H, and 76.7 % Cd (You may first notice something about the ' sum of these percentages.) 49 Since these are percentages the first thing we can do to solve the problem is assume we have a certain amount of grams of the substance I Should we assume any particular amount? 5! I What amount should we choose? I Why is this a good assumption? ! HM H! “‘1 4. 7 . H m .. .- v.2. ' We should assume we have 100 grams. Even though it makes no difference what amount we pick, 100 is easy to work with when dealing with percentages. _‘ r._-, . . .. , 1‘ v v- A 1 1.13“ ,_ _.’|,.,. .2. . E I Therefore we have 21.9 g o 1.4 g H 5.» ---~ “-5 u . i- ”W". . , as.-.— ...- I- z“f 76.7 g Cd Ill Next we need to change these to moles I Therefore we have 5}. 21.9g0 x lmol = 1.37 mol 16.00 g o 1.4gH x lmol = 1.39 mol .2. ‘ 1.01 g H 76.7 ng x lmol = .682 mol 112.41 g Cd “r".vv .. . " —,-v. Next we need to find the simplest ' ; whole number Ratio of moles of each element ITo do this divide each number of ' moles by the smallest number of moles present. 5:...” .__ 3.....3 9...... ..,,,,.‘..~LLI Liliaqpuw . “huh v . ' TTH 1 1 3 5 L 3 a 51 Solution The smallest number in our data is 0.682 mol, ’ ‘ therefore; O 1.37mol = 2.01 . . 0.682 mol ‘ H 1.39 mol = 2.02 2.. 2 0.682 mol O 0.682 mol =1.00 0.682 mol Now you can see the simplest whole number ratio of elements and use these to write the formula O:H:Cd 2:2:1 OszCdl After rearranging and dropping the one the correct formula becomes: ’7‘ Cd(OH)2 52 APPENDIX C 2 1111 pm 111115 1111 Ilse 2 C.P. Chemistry Luttig l H On the following slides pictures and names of common items used in the lab are provided. The next slide describes uses of each item. I Can you guess the use of each item before checking the next slide? 2:1. ly, beaker tongs are k up hot beakers. Beaker Tongs rprismg used to pic Not su L” m 0 Used to find the mass of objects to the nearest 1/ 100th of a gram. Always use a weighing boat. "7’77l7l7fl’l7lli 77771777 .7. .7 77.7.7"; 777,77 ’3 W l, 1 1 \ 24 1 a 55 APPENDIX D .1 Gimmmh y How can you tell if it is an ionic compound just by looking at the formula? I 1. Metal bonded to a nonmetal I 2. Contains a polyatomic ion I 3. Electronegativity difference exceeds 2.1 Once you know that It Is an Ionic substance you use the followlng rule to name the compound: I a. Name the cation (If multivalent use roman numerals or -ic or -ous to identify which charge the ion has) I b. Name the anion. _ v\.-‘-»—‘ ,ff-w—m— 2. -flmw, .errvw— (“Fairy ..w . 1 , . ..— 2 _- Fm...“ I Example: Name the following: 7' ’7 7 7 I Na2SO4 I Is this an ionic substance? I -Yes, it contains a cation bonded to a polyatoimc ion. I What is the cation? Is the cation multivalent? I -It is the sodium ion. No, It is not multivalent. I What is the anion? I -It is the polyatomic ion, sulfate 5%.; , .2 .~ What is the name of this compound? —S odium sulfate $.01. I Example: Name the following; I Fe203 I Is this an ionic substance? I -Yes, it contains a metal bonded to a nonmetal I Is the cation multivalent? What is the cation? I -Yes, it is the Iron [11 ion (ferric) I What is the anion? I -It is the oxide ion. What is the name of this compound? Iron III APPENDIX E More Practice Writing Cherrucal Equations Write the balanced chemical equation for the reaction shown below. Can you guess what is reacting here? The reaction shows Cesium ‘ metal reacting with Water. I How do you start? I Write the word equation for the reaction. ICes1um + water Cesium hydroxide + Hydrogen APPENDIX F V ................................. Rules for determining significant digits 9 Nonzero digits are always significant Examples: 235 m has three 23.65 km has four 12 456 mL has five V ................................. Rules for determining significant digits 9 All zeros between nonzero digits are significant Examples: 205 km has three 23.05 m has four 12 006 g has five ...... ' ‘ 61 V ................................. Rules for determining significant digits 9 Zeros to the right of a non-zero digit and left of a written decimal point are significant Examples: 34 800. mL has five 2300. cm has four 100 000. m has six V Rules for determining significant digits 6 Zeros to the right of a non-zero digit and right of a written decimal point are significant Examples: 4.00 kg has three 23.60 mL has four 12 000.0 km has six 2.90 x losii has three 62 V Rules for determining significant digits 0 Zeros to the left of the decimal point in numbers less than one are not significant Examples: 0.985mL has three 0.65 kg has two 0.6 g has one ................................... ‘ V Rules for determining significant digits 0 Zeros to the right of a decimal print, but to the left of the first non-zero digit are not significant Examples: 0.067 km has two 0.005 has one 0.0050has two ...- ................................ ‘ o How many significant digits are in each of the following? 0.00980 m 3 100. m 3 10 000 m 1 2.0 x 104 m Practice Exceptions to the rules 0 Exact conversion factors are understood to have an unlimited number of significant digits and do not count when used. in ‘ problems. 9 Counting numbers are understood to have an unlimited number of significant digits. (i.e. there are exactly 30 days in September but it ap to only have one significant dlglt) . V ................................ Calculating with significant digits vRule One for addition and subtraction o The answer must be rounded so thatit contains the same number of digits to the right of the decimal point as there are in the measurement with the smallest number of digits to the 11' ght of the decimal point. (i.e. the answer may only be as precise as the least precise number) 0 Examples ' 2.89 m + 0.0432 m =2.9332 m =2.93 m 0 60 054 mL + 101000 mL :16] 054 mL =161 000 mL .................................... ‘ 65 ' ................................ Calculating with significant digits vRule Two for multiplication and division 0 The product or quotient should be rounded off to the same number of significant digits as in the measurement with the fewest significant digits. A 9 Examples ' ‘ 2 o 2.89 m x 0.043 m =0.12427m2 =0.12 m2 g. 60 054m2x 101 m2 ‘ =6 065 454m2 :6 070 000m2 ' .. o 2.900 x104cm x 1.8 x105cm =5.22 x 109cm2 7 =5.2 x 109cm2 ' ................................. Final Considerations on significant digits 9 The coefficient in a number written in scientific notation always reflects all significant digits. 2.90 x 10 4cm has three A r w . '1‘} 7M??? Final Considerations on significant digits 0 Rules for rounding 6 If the digit immediately to the right of the last significant digit you want to retain is Greater than 5, increase the last digit by 1. Less than 5, do not change the last digit 5, followed by nonzero digit(s), increase the last digit by 1. 5, not followed by a nonzero digit and preceded by odd digit(s), increase the last digit by 1. 5, not followed by nonzero digit(s), and the preceding significant digit is even, do not change the last digit, 47% is ”A 67 9 Round the following to 4 significant dig 0.0098050 m 0.009805 m 10 235 m 10240 In 0.0543529 m 0.05435 m 2.07655 x 104 m 2.077 x 104 m Practice .................................. ‘ APPENDIX G Naming Binary Molecular Compounds (Covalent Bonds) ii How do you know if it is a binary i molecular substance (covalent bond) by looking at the formula? i f;T I Nonmetal bonded to nonmetal :5 l Hydrogen bonded to metal or nonmetal. . IElectronegativity difference less than ,_ ‘ 2.1 :49; I It contains only two kinds of :3 elements.(binary) 69 Rules for naming Binary Molecular compounds . are contained in the formula. ‘ 9 I *Use Latin prefixes to describe how many of each atom are contained in the formula along with the name of each element. 7; I Make sure the second element in the name 5 ends in in -ide. . *Some exceptions will be illustrated in the examples . k? : - g. LThe Latin prefixes used in naming molecular substances are: I mono- one I di- two I tri- three I tetra- four j j I penta- five I hexa- six ; I hepta- seven .4; E I octa- eight 33 E I nona- nine 2 I. I deca- ten ' 70 Example: Name the following esus celnques onamoecue. p I Yes, it is a nonmetal bonded to a nonmetal. ‘- I What are the names of the elements? : I Phosphorous and oxygen. 7'"? I How many of each in the formula? I Two phosphorous (di-) and five oxygen (penta—) T r 53; I What is the name of this molecule? Diphosphorous pentoxidel Notice that the second element oxygen has been changed to oxide to satisfy the need to end in ide-. 71 N02 I Is the substance in question a molecule? ; I Yes, it is a nonmetal bonded to a nonmetal. I What are the names of the elements? I Nitrogen and oxygen. I How many of each in the formula? I One nitrogen (mono-) and two oxygen (di-) I What is the name of this molecule? Nitrogen dioxide » I This is an exception that was mentioned earlier. When there is only one of the first element in the formula you drop the mono- in the prefix. Notice again that the second element oxygen has been changed to oxide to satisfy the need to end in ide—. 72 Example: Name the following N20 I Is the substance in question a molecule? I Yes, it is a nonmetal bonded to a nonmetal. I What are the names of the elements? I Nitrogen and oxygen. I How many of each in the formula? » I Two nitrogen (di-) and one oxygen (mono- I What is the name of this molecule? w tun . . — v s cw W fl. J , ‘I' Dinitrogen Monoxide I I While this seems similar to the previous example, the mono- prefix must be included in the second element named. l mm; I Example: Name the following: SiO2 I E I Is the substance in question a molecule? I Yes, it is a metalloid bonded to a nonmetal b ti the electonegativity difference is 1.7 indicati g it is a covalent bond. i I What are the names of the elements? 7. I Silicon and oxygen. i E I How many of each in the formula? :5 a: I One silicon (mono—) and two oxygen (di') g E ,. I What is the name of this molecule? 1 Silicon Dioxide 74 Example: Name the following: CCl4 I I Is the substance in question a molecule? ‘ I Yes, it is a nonmetal bonded to a nonmetal. I What are the names of the elements? I Carbon and Chlorine. I How many of each in the formula? 7:, I One carbon (mono-) and four chlorine '9 '_ (tetra-) E I What is the name of this molecule? Carbon Tetrachloride Once again the mono- is dropped because it appears in the first element named and the root of chlorine is changed to end in ide-. 75 if?" . s .V. . ... “WM ,. :- ,4 - . “2' , ..r: _,r_;_.. . :r .-. “an...“ “...“... .. .1 , ., .4“ ”mfg-hr.”,w,.;,»gfi,.,.:,_v.v‘,i Example: Other usesof the Efinmfixes in V i: naming certain compounds. Name the " following: CuSO4-5l120 I: This is clearly not a molecular substance, yet it does i contain a molecule (H20). , I In this special case ( a water of crystallization) you namc the ionic substance (copper II sulfate) and then use Latir prefixes to describe the number of water molecules 3-.. associated with each formula unit. “f if What is the name of this compound? SE: Copper 11 Sulfate Pentahydrate 76 APPENDIX B Charles Law The relationship between volume and temperature for a fixed amount of gas at constant pressure How are volume and. temperature'related" Think about the followmg example How are volume and temperature Of a gas related? i Think about the following example. Clearly the balloon shows that, claim .1 ' temperature must be directly relat' ' The graph shows a direct relationship between , volume and temperature ’ Volume we. how-Mun [hr - Fixed MM afflu- at Con-tans Prensa" W —900 4.00 0 130 300 W “fa-m (“Cl kept constant, this ratio will be true I : j; anywhere on the curve (i. e. at any volume or temperature) I Therefore, the ratio of V/T will be the same for this gas throughout I Therefore, it = 12 T1 TI2 , information; :: VI =: 24.0 ms v2 = 7?? T, = 105 K T2: 450 K I Step 2: Find a formula that will fit the variables from step 1. I Step 4: Substitute the unknowns into the equation: and E calculate. 5 : V2 : 450KX m3 =103m3 105 K 81 - Step 1: Write down all of the known and unknoWn information. ‘ ‘ = 37.4 cm3 V2 = 67.8 cm3 T1 =- 25.0 0C Tz- — 99? ': Remember to change Celsius to Kelvin before using equations. Again use the Séstep pro em so » . ngtechnrqu to iseo the answer. 7 : I Step 1: Write down all of the known and: nkn . information. Vl = 37.4 cm3 = 67.8 cm3 T1=- 25.00C + 273 = 248 K T2 = ??? Remember to change Celsius to Kelvin before using equations. - :- I Step 2: Find a formula that will fit the variables from step 1 ' Xi— 2 X2 T1 T2 he units in dieianswer are . and these are‘appropnate for . temperature. If the temperature needed to be expressed in , CelSius, what Would you do? 0C: K 273: 450K 273:177°C : ’ What answer would you get if you did not change to Kelvin : before using the formula? . 5 this answer possible? : 0 check to see if our answer makes sense qualitatively, the volume 1ncreases so the temperature should also increase and our result shows that it does. 1n1t1ally present if a gas origin fly at 30 0 0C occupies 24 000 cm3 at 89.0 0C ?, IAnswer: 20 100 C1113 APPENDIX I Heats Changes and Calculations N Kinetic and Potential Energy Changes in Action Calculating the heat required to turn ice into steam 9 Study the following cooling / heating curve to determine the energy changes involved. 0 Use the formulas with each accompanying change to calculate the energy change. Calculating the heat required to turn ice into steam How many Joules of energy would be required to turn 25.0 grams of ice at -40.0°C to steam at 140.0°C? 9 First determine if any phase changes occur and points where the temperature changes by studying the diagram End Here The water must go through two phase changes and three different temperature changes S-Temp Change ange ' 3-Temperature Change 2-Phase change l—Temperature change How many Joules of energy would be required to turn 25.0 grams of ice at -40.0°C to steam at 140.00C? 0 Next you calculate each of the five steps by using the formula to accompany each change. PhaeeChangetAH=moles x molar heat) T (AH=cht \ W emperaturechangeflH=cht PhaseChtmgetAH=moles x molar heat) -‘l‘emperaturechange(AH=mcdt Calculations Step One Raise the temperature of the ice from -40.(P C to 0 ° C. This is a kinetic energy change because the temperature changes but the phase stays the same. 1. A H = m C A t A H 25.0 g x 4.13 J/g°C x(0.0° C-(-4o.oC)) Calculations Step Two Melt the ice at 0°C. This is a potential energy change because the phase changes but the temperature stays the same. 1.AH=mol'molar heat The molar heat to be used is the molar heat of fusion since the phase change is from solid to liquid. The mass of ice (H20) must be converted into moles. Alt-25.0 g x 111111. 18.02 g 89 APPENDIX J N SOLUT|0NS 4m | a‘\\\\\ Mo I ar‘\\\\ Homer measures qualitatively when mixing solutions. I It doesn’t always work so well, therefore, we will measure solutions quantitatively using Molarity. Molarity is a quantitative way to measure concentration Molarity = moles solute liters of solution In the following examples, several different problem types will be illustrated to demonstrate the uses of Molarity Example 1: Determining the molarity of a solution from mass and volume data. IFind the molaritg of a Mg(NO3)2 solution in which 25.0 g of Mg(NO3)2 are dissolved in enough water to make 1350 mL of solution I List data solution volume = 1350 mL solute mass = 25.0 g solute molar mass = 148.32 g/mol 91 Tofind the solution concentration use M=uml L I Molarity is moles of solute per Liter solution. Place the solute amount over the solution amount, even though they are not in the correct units M = 25.09% 1350 mL solution I Multiplg Dg a conversion factor that will cancel the mL and covert to L M = Zimmuflsla. X 113—1le warmthatwilloancdthmof“ ‘ Mg(NO-fitogivethcmuntin moles. M 4.2mm xmsLmL XLflQJiMflQflz 1350 mL solution 1 1148.32 g Mg(NO3)z The final answer will be: 0.125 I"! (Reflecting 3 significant digits) Example 2: Finding- mass needed to, 1 make a solution of a specified molarity. I Find the amount of AgNO3 needed to make 375 mL of a 0.750 M solution. I List data solution volume = 375 mL solution concentration = 0.750 M solute molar mass = 169.88 g/mol solute mass = ??? Again we use the formula M um! L . . - Solving this time for moles; We can then change moles into grants. ' not 3 ML mol: 0.750M'375mL' 1 L = 0.281 mol 1000mL 0.281 mol x mm: 47.7 g 1 mol Example 3: Determining the volume of a solution from Molarity and mass data. IDetermine the volume of 0.250 M NaHCO3 needed to react with 5.00 g of H2504 and produce Na2804, C02 and H20. IList Volume =? Molaritg : 0.250 M mass of reactant = 5.00 g balanced equation: 2N3HCO3+ H2504 _—>N32504+2C02+2H20. I 5.00 9 H2304 x 1mol§§$05xz mol NQHCOg 98.09 g 1 mol H2504 X _L_L___ XLQQQDJL = 0.250 mol Ncho3 1L 444mL Ncho3 1. of a. b. c. d. 2. APPENDIX K Quiz 1 Titration name The titration procedure for determining the concentration an unknown acid does not include removing air bubbles from.burets adding indicator to a buret constant swirling of an Erlenmeyer flask recording the exact volume of a titration standard In the titration of 30 mL of XOR solution, 25 mL of 0.30 M HCl were needed to reach the equivalence point. What is the molarity of the K03 solution? 3. Calculate how many milliliters of 0.50 M Ba(OH)2 must be added to titrate 35 mL of 0.25 M 11280‘ 95 APPENDIX L Titration Quiz 2 name 1. What do you do if you are titrating an acid and you add too much base causing the color of the indicator to turn dark pink? 2. If 20 mL of 0.020 M aqueous H1103 are required to titrate 25 mL of an aqueous solution of NaOH, what is the molarity of the NaOH solution? 3. If 25 mL of 0.25 M aqueous 82804 solution are required to titrate 30 mL of an aqueous solution of NaOH, what is the molarity of the NaOH solution? 'l H iii. i l. .1 ll zip-..., APPENDIX M Qp‘% and :G ‘53! 56' Titrations and neutralization I . J UH l“ How can you identifg an acid? Contains a hgdrogen in the form of a donatable proton. Example: HCl HNO3 H2804 (contains 2 How can gou identifg a base? It contains an Oldr is a proton acceptor. NaOH Ba(OH)2(contains 2) AIOH)3(contaIns 3) “4133‘”; .. 31:“; ans» wrkgkxvx“... gm". evil. I-_ rin«-k.». Q‘s-.ii~.t~'i£1xk;}6.i“v“ An Acid- Base tltration is performed as follows. ' ace e am in one 01 the burets Place the base in the other buret. A‘J 1L;- Add a random amount of acid or base to an Erlenmeyer flask along with an appropriate indicator. Perform titration ‘ I 20.0 mL of 0.100M are titrated with 19.5 mL of an NaOH solution. What is the molarity of the NaOH solution? -Write the balanced equation HCl + NaOH —->NaCl + HZO -List Vol. Acid = 20.0 mL Concentration Acid = 0.100M Vol. Base = 19.5 mL Concentration Base = ‘7 ‘7 ‘7 '7 1. Start with the known concentration and volume to determine moles of known. Substitute to find concentration of unknown. ‘0’ l Molarity = mol therefore; ‘ . Liter f": 'y mol = Molarity x Liter “0 mol=0.100Mx20.0mLx 1 L = 1000 mL 0.00200 mol HCl ' . 2. Use stoichiometry to determine moles of 7, unknown. 1 mol HCl 0.00200 mol NaOH L 3. Calculate the molarity of the unknown. Molarity = [L01 = 0 Liter I 1.00200 mol NaOH x 1000 mL = ' . 19.5 mL NaOH 1 L 0.103M NaOH '71 l Check to make sure your answer makes SCIISC. .‘ l The concentration of NaOH should be a ‘ little higher since it required a larger amount of acid to neutralize it Furthermore, the mole ratio is 1:1. I 35.5 mL of 0.345 M H 2SO4 are used to titrate 42.7 mL of KOH solution. What is the molarity of the KOH solution? -Write the balanced equation HZSO4+2 KOH -->KQSO4 +2 H20 -List Vol. Acid = 35.5 mL Concentration Acid 2 0.345M Vol. Base = 42.7 mL Concentration Base = ?? ? N LU A O-I E *< X LL) ' 1. Start with the known concentration and volume to determine moles of known. I I Molarity = mol therefore; Liter ' mol = Molarity x Liter mol = 0.345 x 35.5 mLx 1L - 1000 mL 0.0122 mol H2304 2. Use stoichiometry to determine moles of unknown. .0122 mol H2504): W: 1 mol H2804 0.0244 mol KOH 3. Calculate the molarity of the unknown. Molarity = m_ol_ = Liter £244 I_n_ol KOH x1000 111.14: 42.7 mL KOH l L 101 0.571M KOH I Check to make sure your answer makes sense. I The concentration of KOH should be a little higher since it requires twice as much base as acid according to the balanced equation. Even though a little more base is needed it does not outweigh the need for twice as much base from the stoichiometry. ' How many of1.000 M H2804 would be needed to neutralize 35.4 mL of 0.526 M LiOH? -Write the balanced equation HZSO4+2 LiOH -->Li2804 +2 H20 -List Vol. Acid = ??? mL Concentration Acid = 1.000 M Vol. Base = 35.4 mL Concentration Base = 0.526 M EXAMPLE 3 102 1. Start with the known concentration and volume to determine moles of known. I Molarity = mol therefore; Liter mo] : Molarity X Liter mol = 0.526 x 35.4 mL X __1_L_= ‘ ' 1000 mL 0.0186 mol LiOH L7 2. Use stoichiometry to determine moles of 3 unknown. 1 .0186 mol LiOH x Maser 2 mol LiOH 0.00930m01 H2504 Calculate the volume of the unknown. EMoIarity = m_ol ; Liter: Am!— ” Liter Molarity .00930mol 5250 1 =0.00930Lx1000mL = 1.000 M i550. 1L " 103 ':.S6IlS6 11111 if: . | 9.2430mLHSO I I Chec to m e sure your answer m es ..1111111,-.H..--w,-.--,,-.ru. ....,V.. 104 APPENDIX N Quiz 1 Significant Digits name Record the correct number of significant digits for each of the following 1. 0.000 760 m 2. 100. cm 3. 10 00.0 m 4. 35.10 km 5. 101 cm 6. 100.00 m Perform the following with significant digits 7. 12 000 cm x 100. cm 8. 30.0 g + 12.70 g 9. 12.50 cm - 3.7 cm 10. 1.000 g x 35 g 11. 25 g + 10.00 mL 12. 54 + 75.00 + 13.698 105 APPENDIX 0 Quiz 2 Significant Digits name Record the correct number of significant digits for each of the following 1. 10.050 m 2. 100 cm 3. 100.050 m 4. 3500 km 5. 101 000 cm 6. 1.00 m Perform the following with significant digits 7. 12 cm.x 100 cm 8. 0.050 g + 12.7 g 9. 120 cm.- 3.7 cm 10. 1.0 g x 35 000 g 11. 25 g + lmL 12. 54 + 700 + 13.6 106 APPENDIX P PowerPoint Presentation Survey Please circle the response that most correctly describes how you feel. (1-3 refer to the review presentations in the SSSC) 1. I used the PowerPoint Presentations in the SSSC to review for the exam once twice three times never 2. If I used the exam review presentations they helped me to learn or review the material that was presented? always most of the time seldom. never 3. If I used the review presentations, I think they were worth taking the time to use. agree not sure disagree (4-9 refer to presentations shown during class) 4. I would you like to see more PowerPoint Presentations in the future to help me learn science concepts? I agree with this statement strongly somewhat don't care disagree 5. Ideally I would like PowerPoint presentations to be used in class once a week twice a week more than twice a week never 6. I think the computer should be used to present other material in class once a week twice a week more than twice a week never 7. When the teacher uses the computer to teach us in class I learn more learn about the same learn less 8. The PowerPoint presentations helped me to concentrate more on material being taught. I agree with this statement strongly somewhat don't care disagree 9. I wish more of my teachers used PowerPoint presentations in class. I agree with this statement strongly somewhat don't care disagree Please describe at least one thing you liked about the PowerPoint presentations. Which presentation was most helpful? Why? Please describe at least one thing you did not like about PowerPoint presentations. 107 BIBLIOGRAPHY 108 BIBLIOGRAPHY Beerexplosionsimpson. [Online Video] Available http://www.geocities.com/Hollywood/6174/cloudy.html, Feb. 2, 1998 Titration Movie. [Online Video] Available http://suzy.unl.edu/bruno/java/Titrate.html, Feb. 11, 1998 U.S. Department of Education, Office of Educational Technology. [Online] Available http://inet.ed.gov/Technology/pillar4.html, June 13, 1998 Technology's Impact on Learning, Department of Education. [Online] Available http://www.nsba.org/sbot/toolkit/tiol.html, June 11, 1998 Rodrigues, Susan. Review of Computer Based Technologies on Students' Learning School Science. [Online] Available http://www.sofweb.vic.edu.au/lt/research/sumLsci.htm, June 9, 1998 Cradler, John. Summary of Current Research and Evaluation Findings on Technology in Education. [Online] Available http://www.fwl.org/techpolicy/refind.html, June 15, 1998 Strommen, Erik and Lincoln, Bruce. Constructivism, Technology and the Future of Classroom.Learning. [Online] Available http://www.ilt.columbia.edu/k12Ilivetext- nf/docs/construct.html, June 13, 1998 Johnson, Doug. Evaluating the Impact of Technology: The Less Simple Answer. [Online] Available http://ww.fromnowon.org/jan96/reply.html, June 13, 1998 Bennett, Frederick. Summary. [Online] Available http://www.concentric.net/~Fabenl/ Bielfeldt, Talbot. Systematic Planning for Technology, OSSC Bulletin; v40, NOV. 2, 1997 Report to the President on the Use of Technology To Strengthen K-12 Education in the United States, [Online] Available http://ericir.syr.edu/plweb- cgi/fastweb?searchform+ericdb, ED410950, June 15, 1998 Branch, Robert Maribe, Ed; Fitzgerald, nary Ann, Ed., Educational Media and Technology Yearbook, 1998. VOlume 23 MCkenzie, Jamie. Education, Technology , Planning. [Online] Available http://www.pacificrim.net/~mckenzie, June 12, 1998 109 PowerPoint Help Page, [Online] Available http://garfield.ir.ucf.edu/manual/lan/ppoint.html, August 2, 1997 Schenone-Stevens, M. Carla, Powerful Presentations with PowerPoint, [Online] Available http://ericir.syr.edu/plweb-cgi/fastweb?searchform+ericdb, ED404699, June 15, 1998 Reiber, Lloyd P. The Effects of Visual Grouping on Learning from Computer Animated Presentations. Abstract [Online] Available http://ericir.syr.edu/p1web- cgi/fastweb?searchform+ericdb,ED335006, June 12, 1998 Gibbs, W.J. An Analysis of a Computer Assisted Learning System: Student Perception and Reactions. Abstract [Online] Available http://ericir.syr.edu/plweb- cgi/fastweb?searchform+ericdb,ED335006, June 12, 1998. Constructivist Model for Learning, [Online] Available htp://www.ncrel.org.sdrs/areas/issues/content/cntrareas/scien ce/scSmodel.htm, June 12, 1998 Slavin, Robert. Educational Psychology, Pub. Allyn and Bacon, 1991 Lang, szell, Michigan Essential Goals and Objectives for Science Education, . Michigan Dept. of Education , 7/94 110