.‘ .,1,.. hn—unt 1 3 8: . 1 r. v...)(.r . (11.: : mu.» “SIR 3;“ 33 { LIBRARY University This is to certify that the thesis entitled EQUILIBRIUM MICROSTRUCTURE FOR LIQUID CRYSTALLINE POLYMERS presented by Hemant Kamalakar Kini has been accepted towards fulfillment of the requirements for the MS. degree in Chemical Engineering & Materials Science Michigan State I @«kgi Vim Major Professor’ 8 Signature Q» A MRJ \11’3 O 3 W / Date MSU is an Affirmative Action/Equal Opportunity Institution —t-—‘—-—--~—o_-—-—--oo—.—o-.—.-.- PLACE IN RETURN Box to remove this checkout from your record. TO AVOID FINES return on or before date due. MAY BE RECALLED with earlier due date if requested. DATE DUE DATE DUE DATE DUE 6/01 cJClRC/DatoDuopes-ms EQUILIBRIUM MICROSTRUCTURE FOR LIQUID CRYSTALLINE POLYMERS By Hemant Kamalakar Kini A THESIS Submitted to Michigan State University in partial fulfillment of the requirements for the degree of MASTER OF SCIENCE Department of Chemical Engineering and Materials Science 2003 ABSTRACT EQUILIBRIUM MICROSTRUCTURE FOR LIQUID CRYSTALLINE POLYMERS By Hemant Kamalakar Kini The relaxation of the microstructure of liquid crystalline polymers subject to Brownian motion and a Maier-Saupe (MS-) excluded volume potential is predicted by the following dynamic equation for the second order moment of the orientation distribution: d 1 d1:_ =-(< 22>"3’D+U('I< 2222 >) A recently developed algebraic closure for < ppp p > , the fourth order moment of the orientation distribution function, provides a closure for the abOve equation. The new theory predicts the existence of multiple equilibrium states for a MS-coefficient U between 4.656 and 5.000. At steady state, an isotropic orientation dyadic satisfies the moment equation for all values of U. The theory shows that the isotropic equilibrium microstructure is stable for U < 4.656 and unstable for U > 5.000. For 4.656 < U < 5.000, three steady states are predicted: a conditionally stable isotropic state, an unstable anisotropic state, and a conditionally stable anisotropic state. The equilibrium semi-positive quadratic form associated with the orientation dyadic has a prolate shape (i.e., two equal eigenvalues smaller than the maximum eigenvalue). The temporal relaxation of a non-equilibrium state to an equilibrium state occurs for time scales comparable to l / DR, where DR is a phenomenological rotary diffusion coefficient. To my parents iii ACKNOWLEDGEMENTS My utmost gratitude to my advisor Dr Charles A. Petty for all his help, guidance and inspiration during the course of this research. It is due to his unrelenting support and prodding that I was able to complete the research and write up this thesis in the given time frame. My sincere thanks to Dr André Bénard and other members of the research group for their valuable suggestions towards my research. I am obliged to my family and friends for their love and emotional support. I would also like to thank the National Science Foundation (N SF/CTS- 9986878) and the Department of Chemical Engineering and Materials Science for their financial support to this research. iv TABLE OF CONTENTS LIST OF TABLES LIST OF FIGURES LIST OF NOTATION CHAPTER 1. BACKGROUND 1.1 Introduction 1.2 Characterization of the Microstructure 1.3 Dynamic Equation for the Orientation Dyadic 1.4 Closure Model for the Orientation Tetradic 1 .5 Objectives 1 .6 Methodology 1.7 Scope 1.8 Figures CHAPTER 2. RESULTS 2.1. Steady States and. Equilibrium States 2.2. Relaxation to Equilibrium 2.3. Figures CHAPTER 3. CONCLUSIONS 3.1 Tables and Figures CHAPTER 4. RECOMMENDATIONS APPENDIX A. INVARIANTS OF THE ORIENTATION DYADIC APPENDIX B. SCALAR ORDER PARAMETER FOR THE PROLATE STATES APPENDIX C. TETRADIC CLOSURE AT THE NEMATIC STATE APPENDIX D: NUMERICAL DATA with C2 = 1/3 APPENDD( E: NUMERICAL DATA with C2 = 0.31 APPENDIX F: NUMERICAL DATA with C2 = 0.29 APPENDIX G: COMPUTER CODE LIST OF REFERENCES Page vi viii ix 10 10 15 15 18 19 25 27 29 40 41 45 47 51 53 54 57 60 63 95 LIST OF TABLES Table 3.1 Comparison of the Uip, Upi, api , values for the isotropic-prolate transition predicted by the FSQ-closure (C2=l/3) with the BL], and the de-coupling approximation Table 3.2 The Uip, Upi, api , values for the isotropic-prolate transition predicted by the FSQ-closure with different C2’s. Table A-1. Invariants of the structure tensor Table D] The eigenvalues of g , the structure parameter and the invariants of 2 for U less than Upi and with C2=1/3 Table D2 The eigenvalues of a__ , the structure parameter 0t and the invariants of 2 for U greater than Uip and with C2=1/3 Table D.3 The eigenvalues of g , the structure parameter and the invariants of 1:) for Up, S Us Uip and with C2=1/3. Table E] The eigenvalues of g , the structure parameter and the invariants of g for U less than Upi and with C2=O.31 Table E2 The eigenvalues of g , the structure parameter or and the invariants of 2 for U greater than Uip and with C2=O.31 Table E3 The eigenvalues of a , the structure parameter and the invariants Of 2 for Upi S U S Uip and With C2=O.31 vi Page 42 43 49 54 55 56 57 58 59 Table F.l The eigenvalues of g , the structure parameter and the invariants of 1:) for U less than Up; and with C2=0.29 60 Table F .2 The eigenvalues of g , the structure parameter'a and the invariants of 1:) for U greater than Uip and with C2=0.29 61 Table R3 The eigenvalues of g , the structure parameter and the invariants of 2 for Uip S Us Upi and with C2=0.29 62 vii LIST OF FIGURES Figure 1.1. Progression of order for liquid crystal phases formed by rod like molecules Figure 1.2a,b,c Isotropic phase, Nematic phase, Smectic phase Figure 1.3 Representation of an axisymmetric polymer molecule Figure 1.4 Orientation vector distribution over the unit sphere Figure 1.5 Equilibrium Phase Diagram indicating the prolate-isotropic transition and the isotropic-prolate transition. Figure 2.1 The isotropic—prolate transition predicted by the FSQ-closure with C2=1/ 3 Figure 2.2 The isotropic-prolate transition predicted by the F SQ-closure for C2=1/3 with the region between Uip (5.0) and Up, (4.626) enlarged. Figure 2.3 The isotropic-prolate transition predicted by the F SQ-closure with C2=0.3 1 Figure 2.4 The isotropic-prolate transition predicted by the F SQ-closure for C2=0.31with the region between Uip (4.9) and Upi (4.629) enlarged. Figure 2.5 The isotropic-prolate transition predicted by the FSQ-closure with C2=0.29 Figure 2.6 The isotropic-prolate transition predicted by the FSQ-closure for C2=0.29 with the region between Uip (4.83) and Upi (4.606) enlarged. viii Page 20 21 22 23 24 30 31 32 w 3 34 35 Figure 2.7 or versus 1 (dimensionless time) for the relaxation of LCP microstructure from an initial nematic state with C2=1/3. Figure 2.8 or versus 1: (dimensionless time) for the relaxation of LCP microstructure from an initial nematic state with C2= 1/3 Figure 2.9 or versus 1 ( dimensionless time) for the relaxation of LCP microstructure from different initial states with C2= 1/3 and U= 4.7. Figure 2.10 or versus 1: ( dimensionless time) for the relaxation of LCP microstructure from different initial states with C2= 1/3 and U=6. Figure 3.1 Comparison of the isotropic-prolate transition predicted by the F SQ-closure (C2=l/3 and 0.29) with the MU and the de-coupling approximation. Figure A.1 Invariant diagram of the structure tensor g. The area and the boundaries of the hypothetical triangle represent the set of realizable orientation states ix 36 37 38 39 44 50 Symbol 2 = < 22 > an, 822, 333 < 2222 > at, 32, a3 2 b1, b2, b3 llb lllb ID < 2222 > Q DR LIST OF NOTATION Orientation dyadic Diagonal components of the orientation dayadic Orientation tetradic Eigenvalues of g Anisotropic orientation dyadic Eigenvalues of 2 Second invariant of 1:) Third invariant of 2 Probability distribution function Unit normal vector Orientation tetradic Scalar order parameter Nematic strength Critical U beyond which the isotropic states are unstable U corresponding to prolate-isotropic transition or corresponding to isotopic-prolate transition Boltzman constant Absolute temperature Rotary diffusion coefficient Dimensionless time Symbol C1 Coefficient of linear terms in FSQ-closure C2 Coefficient of quadratic terms in FSQ-closure xi CHAPTER 1 BACKGROUND 1.1 Introduction Liquid crystals are ubiquitous in the world of digital electronics in particular and in our life in general. Nematic liquid crystals can be found in display devices like laptops, calculators, watches to name a few. Cholesterics or chiral nematics (a special case of the nematic state) are used as temperature indicators in medical diagnoses or in paints to produce angle dependent iridescent colors. Smectic liquid crystals due to their layered structure, have potential application as lubricants. Liquid crystals by their structure and properties can be considered as intermediate between classical solids and classical liquids. Liquid crystals are complex fluids, which can flow like liquids but their mechanical properties are anisotropic like those of crystals. Most of the historic work on liquid crystals was with low molecular weight materials. Liquid crystalline polymers (LCPs) are not only liquid crystalline but also viscoelastic. A polymeric mesophase (positional and/or orientational long-range order in one or two dimensions) was first discovered by Bawden and Pirie (see page 503, Larson), when they observed that, a solution of tobacco mosaic virus formed two phases above a critical concentration, one of which was birefringent. A synthetic polymer solution, poly(y-benzyl-L-glutamate) exhibiting liquid crystalline phase, was reported in 1950 by Elliot and Ambrose (see page 1, Weiss,1990). Generally in solids the molecules possess both positional and orientational order. This means that the centers of mass of the molecules lie at specific locations and the molecular axes point in certain directions. Spherically symmetric molecules can have positional order but no orientational order. Such positional and orientational order is absent in classical liquids. In solids, thermal motion may lead to small changes in the positions and orientations of the molecules, but their positions are in general fixed at specific lattice points and the motion is with respect to the perfect geometrical lattice. In liquids, the molecules diffuse freely and randomly in all directions. In LCPs, the molecules diffuse through the sample while still retaining some positional and orientational order. Liquid crystals exhibit long-range orientational order. A liquid crystalline phase (mesomorphic phase) can either be the result of temperature change (therrnotropic), or the addition of a solvent (lyotropic). Figure 1.1 at the end of this chapter, shows the sequential progression of order for various liquid crystal phases exhibited by rod-like particles. A very common example of a lyotropic liquid crystalline polymer is l,4-phenyleneterephthalamide, sold commercially as Kevlar. This progression wherein the liquid crystal phase is intermediate between an isotropic liquid and crystalline solid can be described by three types of order: orientational order, positional order and bond orientational order (see page 3, Collings and Patel, 1997). The nematic phase is characterized by the long axes of the molecules, tending to align along a certain direction as they move about in the sample. This is the only long range order present in the nematic phase and hence its properties are those of an anisotropic fluid. Figure 1.2b is a schematic representation of the molecular order in a nematic phase. The molecules are represented by oblate ellipses. The ellipses can be seen to be exhibiting some average orientation; however there is no long range order in the relative positions of the ellipses. These phases are optically anisotropic and fluid-like, without any long range positional order. The nematic liquid crystals are used in display devices, wherein their direction of preferred orientation can be switched by the application of an electric field. And with the optical properties such as birefringence strongly dependent of the orientation, the nematics can be used as optical switches. A smectic phase exhibits both positional and orientational order. Smectic phases have layered structure, and the positional order may be along the layer or between the layers. There can be three types of positional order: short range positional (SRO) order wherein the order is evident only over a finite distance as in a simple fluid; long range positional order (LRO) which is seen in a three dimensional crystal; quasi-long range order wherein the order is between that of SRO and LRO. Depending on the average orientation angle made by the molecules with the layers there can be different smectic phases. An isotropic state does not posses long range orientational order, the structure can be considered to be reminiscent of the proverbial ‘bag of nails’. The liquid crystalline phases can be identified by various techniques like miscibility and optical observation of textures, the most comprehensive understanding of the molecular order can be attained by the X-ray diffraction studies on oriented samples. As in LCPs, the behavior of rigid rod like particles dispersed in a viscous fluid is of great importance in the processing of composite materials. Due to their low cost, fast cycle times and good mechanical properties, the use of composites has increased tremendously over the years. Many composite materials are formed, by combining a reinforcing fiber with a polymeric or metallic matrix. These materials are processed in different ways depending on the type of reinforcement used and the fiber orientation in the final composite, which influences the final composite mechanical properties. As the composite is being formed, flow induces the fibers to be oriented, this orientation template is retained in the finished product. This fiber orientation template in the composite material controls its mechanical properties. The direction in which most of the fibers are oriented is stronger and stiffer than the direction with the least orientation (see Advani and Tucker 1987; Parks et a1. 1999; Tucker, 1988). There are both theoretical and experimental models for correlating the mechanical properties with the direction of fiber orientation. Hence there is an ample incentive for understanding the complex link between the composite manufacturing process, the final fiber orientations and the composite properties. This knowledge would allow one to design and control the process to obtain the most desirable mechanical properties in the composite material. Predicting full-scale processing flows, where the flow is inhomogeneous, necessitates tracking of all the particles, which is a tedious task. In polymeric liquids, any molecule experiences an average effect of its surroundings and the problem reduces to calculating the mean properties from the behavior of individual molecules. Though these assumptions simplify the problem, they are made while retaining enough information to extract accurate predictions of the rheology and molecular orientation (see F olgar and Tucker, 1984; Advani and Tucker 1987). The change in concentration of rigid rod like polymers causes dramatic changes in the rheological properties of LCPs and other polymeric solutions. Onsager and Flory (see page 229, Doi, 1981) identified critical concentration for solutions of such molecules, above which they form liquid crystals with a nematic structure. This theoretical prediction can be validated by viscosity measurements and polarized light microscopy of the microstructure of polyisocyanates as done by Aharoni (1979,1980). Both these studies have shown the existence of a critical concentration of the polymer above which there is a transition from isotropic state to an anisotropic state, as the polymer concentration is increased. The phenomenological theory of Erickson, Leslie and Parodi (see page 229, Doi, 1981), was successful in describing many dynamical phenomena in nematic, thermotropic liquid crystals. But this theory does not predict the nonlinear viscoelasticity, which is quite conspicuous in such systems. Doi (1981), proposed a model based on molecular approach, which predicted a nonlinear viscoelasticity for LCPs. Also the predicted dependence of the viscosity on molecular weight and concentration agreed fairly well with experiments. Using the fluids microstructure numerous fluid mechanical theories have been formulated. Jeffery (1922), studied the fluid motion in the vicinity of a suspended ellipsoid to explain the increase in viscosity due to its presence, in an otherwise Newtonian fluid. For a suspension of non-interacting dumbbell shaped particles, Prager (see page 33, Hand, 1961) deduced a constitutive equation for stress and equations determining the preferred direction adopted by the particles. The orientation state of the fibers can be represented in numerous ways. The probability distribution function for the fibers is one way (see Advani and Tucker, 1990,1994; Cintra and Tucker, 1995). It is suitable for problems involving nontrivial flow fields with planar orientation. A more compact way of representing the fiber orientation is by using various parameters. The formulation of these parameters depends on assumptions about the direction of the principal axes of orientation and some symmetry in the probability distribution function. An ideal description of fiber orientation would be general like the distribution function and compact like orientation parameters. These requirements are satisfied by a set of tensors that have been called tensorial order parameters or orientation-moment tensors. The underlying theory for this research utilizes this form of representation for the orientation state, as suggested by Hand (1962) and the Doi (seee Doi and Edwards, 1986) theory for liquid crystalline polymers. The tensorial form of description while providing an efficient way to compute flow-induced fiber orientation, requires an accurate closure approximation for the higher-order moments of the orientation distribution function. Over the years several closure approximations have been proposed, some of which are discussed later. 1.2 Characterization of the Microstructure 1.2.1 Orientation Characterization and Distribution The polymer molecule is considered to be a rigid rod uniform in length and diameter. The two ends of this polymer are identical. The orientation of this molecule can be represented by an unit vector p , directed along its molecular axis or by angles 0 and (I) made by the molecular axis. Fig 1.3 shows these forms of representation. The two forms of representation are related by, pl=sin0 cos¢ p2=c080 p3=sin03in¢ . (1.1) pl , p2 , p3 are the components of the unit vector 2 along the co-ordinate axes X,Y and Z respectively. As the ‘head’ and ‘tail’ of the molecule are indistinguishable from each other, the representation of the polymer direction is unchanged by changing p to —p or 0 and (I) as below 9 —> n-e ¢ —> n+¢ . (1.2) A probability distribution function u; (0,4)) describes the orientation state of a particle in space, it is the fraction of orientation states per unit area on a sphere of unit radius. The probability P, of finding a particle between 01 and 01 + A0; and (I). and ¢1+ Ad) is given by P(0$039+A9,¢$¢_<_¢+A¢)=w(0,¢)sin0AOA¢. (1.3) This fimction is normalized by integrating the function over the entire sphere i.e., the probability of finding a particle at some orientation over the sphere is unity, fiw(0,¢,t)sin0d0d¢=l . (1.4) From the definition of p we can write that ME) = w(-g) ’ (1-5) W(9a¢) =‘ll(7t-9a¢+7r) - (1-6) 1.2.2 Continuity Equation Considering an arbitrary area over the unit sphere, as shown in Figure 1.4. This area is bounded by the contour line C. Relative to a material frame of reference, the flux of the orientation states across the boundary C is p w. Writing a balance of orientation states across the surface A, —l(gw)-gds = illw(e.<1>.t)dA c th (1.7) Using Stokes theorem ( see Deen, 1998), the lefi-hand-side of Eq. (1.7) can be written as, -(p_\y)dA . (1.8) The equation for the evolution of w for the spatially homogeneous LCP mixture can be written as, a . —=-—-——- . 1.9 E (2 v) ( ) The term (2 \V) represents the rotary flux, where B is the angular velocity of the LCP 5 component and .6—p— is the surface gradient operator. The rotary flux can now be written as the contributions from convective and diffusive fluxes, 9v 5 133v+(9v-93w) . (1.10) f) 3 is the angular velocity caused by fiber/fluid interactions . Now Eq. (1.9) can be written in terms of the convective and diffusive fluxes 6w_ 6 . 6 . . 333— (3p (gal!) (3p (2 BOW). (1.11) 1.2.3 Rotary Diffusive Flux The rotary diffirsive flux has a contribution due to Brownian motion and a contribution due to an excluded volume potential : . . 5W 5 AUMS _ =—D _+ ____ (g 23w {62 val—)(kBT) , where DR is the rotary diffusion coefficient and has the units of l/time. (1.12) 1.2.3.1 Maier-Saupe potential Orientation distribution can be calculated from a nematic potential which signifies the influence of one molecule or a rod’s orientation on that of its neighbor. Every polymer molecule has a region around it wherein the stearic effect precludes other molecules from that region. This is called the excluded volume. Onsager initially pr0posed a theory to calculate such a potential. This theory is applicable at low concentrations at which pairwise excluded volume interactions are the dominant ones. The Doi theory utilizes the Maier-Saupe potential AUMS, which is more suitable for thermotropic nematics. 3 1 3 l AUMS= —§UkBT(pp—§I).(pp-§l). (1.13) U is a dimensionless measure of the polymer number density n and is directly proportional to the excluded volume between rigid rods. When the concentration of the polymer is increased, the interaction forces become stronger, this increases the alignment of polymer molecules. Hence there can be a transition from a random to an ordered phase even in the absence of flow. 1.3 Dynamic Equation for the Orientation Dyadic 1.3.1 The Smoluchowski Equation The Smoluchowski equation with p 3: 0 (no external flow field), can be written as QE=DRE.[6_‘V+ Pug—"fin , (1.14) at 5p 5p Wag kg The Smoluchowski equation gives the evolution of the orientation distribution function. Multiplying Eq. (1.14) by p p and integrating the equation over the entire unit sphere gives d d1? 9 1 = -(< 22> ‘§l)+U(< 22> ° < 22> - < 22*2222 >> (1.15) where ‘C E 6 DRt is the dimensionless time. 1.4 Closure models for orientation tetradic 1.4.1 Background As evident from the earlier discussion the distribution function \u(9, <1), t;U) provides a description of the fiber orientation state. A compact representation of the orientation for numerical simulations is in the form of orientation tensors. The dyadic product of the vector p with itself and the integration of this product, with the 10 distribution function over all possible directions, yields one set of orientation tensor. As the distribution function is even, the odd order integrals are zero. The integrals of importance are the even-ordered ones (see Irnhoff, 2000)., The second order tensor or dyad can be written as = jjppw(0,¢,t)sin0d0d¢ . (1.16) Similarly the fourth order tensor or tetrad is =fipp pw(0,¢,t)sin0d0d¢ . (1.17) The fourth order tensor must reduce to the second order tensor by contracting any two orientation vectors: =

== 1) s31) SIS] SIJS === rs SJ rs _] s 1 JS 8 (1.18) Clearly, the orientation tetrad also has six fold symmetry inasmuch as >== =< > J k 1 PP PiPPP le Ijk < pipjpkpl = =< pj p1 pi pk >=< p3- pk pi p1 > (1.19) An infinite number of even order tensors can be written. The higher the number of orientation tensor, the better is the description of the orientation state. But the calculation of higher order tensors is very cumbersome. Hence the second and fourth order tensors which provide an adequate representation of the orientation state are commonly used. 11 When the equation for < pp > is written, it has the higher order moment < pppp >, which needs to be determined. Whenever an equation for any finite moment of p is written, it will always contain a higher order moment of B. So to solve for < pp > , we need to close the higher order moment < pppp >. Some of the commonly used closures and the closure used in this research (i.e., the FSQ- closure) are now discussed. 1.4.2 The linear closure model of Hand This linear closure proposed by Hand (1962) is given by l 1 z=[(——+—:)l + —+—-] (1.20) This closure satisfies all the projection and symmetry properties of the exact orientation dyadic. The predictions made by this model are found to be accurate near the isotropic state. 1.4.3 The uncoupling approximation The uncoupling approximation which was first used by Doi (1981), is z=(z<22>). (1.21) This is one of the simplest closures and has been widely used to describe LCPs. Here the fourth order moment is expressed as the product of the first order dyads. For simple shear flows, this approximation fails to show the director tumbling and wagging transitions predicted by the unapproximated Doi theory (see Feng et al. ,(1998)). 12 1.4.4 The quadratic closure of Hinch and Leal (HL1 closure) This closure was proposed by Hinch and Leal (1975,1976). Hinch and Leal developed a closure for the orientation tetrad by interpolating between two regimes: near equilibrium (weak flows ) flows and strong-flows. z+%(6''‘2 -:+§~z£ +21z 2 2 -g£<22>=£-21<22>-<22>=<22>+§£°<22>=D (1.22) The accuracy of the closure varies considerably when applied to the excluded volume term < pp >:< pppp > and the flow term §2, where g is the strain rate dyadic. The quadratic closure is found to be more accurate than the HL1 closure for the nematic term, while the HL1 closure is found to be more accurate than the quadratic closure for the flow term. 1.4.5 The fully symmetric quadratic ( FSQ-) closure This closure was proposed by Petty et a1. (1999). This closure has a linear and a quadratic part, and is defined as follows = C11+ C22 (123) < ppp> < >—[(——+-1-< p>< >)I+—3—< >+fi< >

] E--— 1 BB 35 7 p ‘31—) = 35 BB 7 BB —-9 (1.24) 13 2 2=[(3§——tr( ))l+ 39 2 6 (gs—)——7- +7 o] (1.25) The linear part of the closure i.e., < pppp >l is identical to the Hand closure. The closure retains the six fold symmetry and projection properties of the exact orientation tetradic. The tetradics < pppp >l and < pppp >2 , individually satisfy the six fold symmetry and projection properties. The projection property for Eq. (1.23) is recovered by requiring C1+C2=1. (1.26) At the nematic state C2= 1/3 ( see Appendix D). Eq. (1.23) can be written as, < >< >-2[(——+— >< >)I+—§—< >+i< > < >] 2322 BB 3 35 7 W 22 = 35 BE 7 ER BB 2 2 3K? pp>—7tr( ))l+ 39 2 6 (E)—7 +7 ] The FSQ-closure satisfies the six fold symmetry and contraction properties discussed in Section 1.4.1. 14 1.5 Objectives Equation (1.15) determines the evolution of the orientation dyadic. Solving the differential equation requires the evaluation of the term < [32 >:< pppp >. This term, can be evaluated by the various closure models discussed earlier and the FSQ-closure (see Section 1.4.5). In this research the following characteristics of Eq. (1.15) are examined: 1) the critical vales of U for the transitions between the liquid crystalline phases ; 2) the equilibrium microstructure and phase transitions for lyotropic LCPs using the FSQ- closure ; and 3) the predictions made by the uncoupling approximation and the HL1 closure. [.6 Methodology The second order orientation moment satisfies Eq. (1.15) .The F SQ-closure, which satisfies the above conditions, is used to calculate the fourth order orientation moment . The goal of the simulations is to predict the critical concentrations for the transitions between the different prolate and isotropic states, and to get the equilibrium phase diagram. Figure 1.5 shows a typical equilibrium phase diagram with the different prolate and isotropic states. The arrows “a” and “b” indicate the transition between the conditionally stable prolate states to the conditionally stable isotropic and stable prolate states respectively. The other arrows, as marked, show the prolate-isotropic and isotropic- prolate transition. The equilibrium orientation states depend on the value of U. Below the Up), the microstructure relaxes to a stable isotropic state. Beyond Uip, the isotropic states are unstable, while the prolate states are all stable. Between Up; and Up, the isotropic and 15 prolate states are conditionally stable. The faint curve represents the transition between conditionally stable isotropic and prolate states (i.e, finite perturbation of a microstructure on the faint line will change the microstructure to either the conditionally stable prolate state or the isotropic state). As U is increased beyond Up the microstructure gets increasingly oriented in one direction (i.e, it tends towards the nematic state). However, Brownian motion of the solvent molecules prevents the dispersed phase from becoming nematic for U < 00. 1.6.1 Prolate-Isotropic transition Up) Eq. (1.15) is solved using a fourth order Runge-Kutta algorithm (see Matlab code in Appendix H) subject to the following conditions for 0 < 1: S 800 : < > =8 e . BB 0 —3—3 The temporal step size Ar= 0.01 . The simulations are started with U=1. The nematic state (initial state) corresponds to point A on the invariant diagram ( see Figure A], Appendix A). At the end of the simulation a33(t) is plotted as a firnction of the dimensionless time, 1:. This gives the visual conformation that the orientation state is fully relaxed to a steady state. At the isotropic state the orientation dyadic has the form, The calculation is repeated for larger values of U. At a particular value of U=U;p , the nematic state relaxes to an anisotropic state ( see Figure 1.5). At values of U less than Up) the nematic state relaxes to a stable isotropic state. This is the region of stable l6 isotropic states. For U 2 Up, the nematic state relaxes to a stable prolate state. The prolate state has the form = 3119.191 +a22929.2 +a33§3§-3' where a“ 2 a22 < a”. 1.6.2 Isotropic-prolate transition,Uip For U > Uip, the isotopic state is unstable. To locate this point for a particular value of U beyond Uip, the simulation is started with an initial state very close to the isotropic state, with a step size of 0.001 for a few hundred time steps. If the microstructure tends to relax back to the isotropic state, then the calculation is repeated with a slightly higher value of U. This is continued until U=Uip , beyond which the microstructure tends to relax to the prolate state from an initial state close to the isotropic state as well as from the nematic state. 1.6.3 Region of multiple steady states Up; < U < Uip To identify the region of multiple steady states, the simulations are run similar to the ones developed to identify Uip. An initial state close to the isotropic state is selected. As illustrated in Figure 1.5, if the initial state is at Point “a” for a value of U between Uip and Upi , then it relaxes to the isotropic state. If it is at Point “b”, then it relaxes to the prolate state. The simulations are repeated till the points “a” and “b” merge to yield the conditionally stable prolate and conditionally stable isptropic states between Up) and Up . 17 l. 7 Scope C2 is the coefficient of the quadratic terms in the F SQ-closure (see Eq. (1.23) ). This research examines the influence of C2 on the predictions made by the F SQ-closure. C2 is equal to 1/3 at the nematic state. Two other values of C2 = 0.29 and 0.31 are used for this purpose. The relaxation of the microstructure from an initial state is studied by varying U between 0 and 15. U= 0 corresponds to relaxation due to Brownian motion. As the value of U increases the contribution of the excluded volume increases. The relaxation times for different values of U are compared. 18 1.8 Figures 19 Isotropic I Increasing order Nematic Molecular Orientational order I l Smectic-A Positional order normal to layers Hexatic-B Various tilted Bond Orientational order smectic phases C stal-B ry Positional order within layers Crystal-E Asymmetric Axial site symmetry V Figure 1.1. Progression of order for liquid crystal phases formed by rod like molecules. 20 \I‘ Figure 1.2a Isotropic phase Figure 1.2c Smectic phase Showing order between layers 21 (mi N fit“ Figure 1.2b Nematic phase I'D \ >Y ‘----—-----4 -—--—-—------ 2:131 E1 +P2 92 +P3 93 p =(sin0cos 4)) e, + (0030) 92 + (sinOsin 4)) 93 Figure 1.3 Representation of an axisymmetric polymer molecule 22 Unit sphere rotary flux of orientation states in a material frame of reference . d ~l(gv)-nds = —llv(9,¢,t)dA c dt A \ J \ Vi ‘1 Y loss of orientation states from area A per accumulation of orientation states in A unit time due to fiber/fluid and in area A fiber/fiber interactions Figure 1.4 Orientation vector distribution over the unit sphere 23 al.—>1 for U —)oo f 1 \ .......... stable prolate states OI. A ”pi ........................... IP- transition ' PI- _ _ transition unstable isotropic states Ila. v I 0 5 1 U Pi ip Figure 1.5 Equilibrium phase diagram indicating the prolate-isotropic transition and the isotropic-prolate transition. For definition of a see Appendix B. 24 CHAPTER 2 RESULTS 2.1 Steady States and Equilibrium States The evolution equation for the second order moment ( see Eq. (1.15) ) is D 1 Dr =_(-§£)+U('_KBBBE> The following properties of the orientation dyadic < pp > must be preserved : 1) The trace of the orientation dyadic predicted must also be 1 for all 1 >0. 2) The orientation dyadic is symmetric. For this to be true at all times, the orientation tetradic < pppp > must also have the symmetry properties (see Eq.(1 . 19)). The F SQ-closure, which satisfies the above conditions, is used to calculate the fourth order moment . This differential equation is solved as explained in the earlier chapter. The relaxation of the microstructure is predicted with C2= 0.29, 0.31 and 1/3. 2.1.1 Determining the point of prolate-isotropic transition,Uip with C2 = 1/3 The differential equation, Eq. ( 1.15) is solved with C2 = 1/3 and other conditions described in Section 1.6. The initial run of simulation is started with U = 1. At this value of U = 1, the microstructure relaxes to an isotropic state. The simulations are repeated with a higher value of U and other conditions remaining unchanged, if the microstructure relaxes to an isotropic state. At Up) = 4.656, the microstructure relaxes to a stable prolate state. At this point, a=0.2257 and 25 0 .2581 0 0 = 0 0.2581 0 0 0 0.4838 Up; corresponds to the point of prolate-isotropic transition. 1 2.1.2 Determining the point of isotropic-prolate transition,Uip with C2 = 1/3 Eq. (1.15) is solved with C2 = 1/3 and other conditions described in Section 1.6. To locate this point Uip = 4.6 , the simulation is started with an initial state or = 0.05. This corresponds to the orientation dyadic, 0.3167 0 O : 0 0.3167 0 0 0 0.3666 The components of < p p > are calculated from or as follows, < > =or+l/2 BE 3'3 3/2 _ 1_M I.I'2.2=——2— If the microstructure tends (i.e., or becomes less than 0.05) to relax back to the isotropic state then the calculation is repeated with a slightly higher value of U. This is continued until U= Uip , beyond which the microstructure tends (i.e., or becomes greater than 0.05) to relax to the prolate state form an initial state or=0.05. This is the point of stable- unstable isotropic transition, Uip. 26 2.1.3 Determining the region of multiple steady states Up) < U < Uip with C2 = 1/3 The purpose of the calculations is to determine an or (conditionally stable prolate state) for the value of U lying between Up) and Uip. This is demonstrated by calculating or for a particular value U = 4.7. The calculations are done as follows : Step 1. With U = 4.7 and or=0.1 as the initial condition, the microstructure tends to relax to the isotropic state. Step 2. With U = 4.7 and a=0.2 as the initial condition, the microstructure tends to relax to the prolate state. Step 3. With U = 4.7 , 0t is varied between 0.1 and 0.2 as limits. At 0L=0.129, the microstructure does not show a tendency to relax to the isotropic state or to the stable prolate state. or=0.129 is taken to be the conditionally stable prolate state corresponding to U=4.7. Therefore, this method is repeated for discrete values of U between U... and Up), to determine the conditionally stable prolate region, as indicated by the dashed lines on Figure 2.1. 2.2 Relaxation to Equilibrium As evident from Figure 2.7, the time needed for the microstructure to relax from an initial nematic state to an equilibrium isotropic state (U < 4.656 with C2=1/3) is considerably longer for values of U which are closer to Up) = 4.656 than for values of U which are considerably less than Upi=4.656. This can be attributed to the microstructure trying to reach an equillibrium between the competing Brownian forces (tending to make the microstructure isotropic) and the excluded volume potential (tending to align the microstructure). At U=0 there is no excluded volume potential. The relaxation of the 27 microstructure is entirely due to the Brownian motion. Beyond Uip, when the excluded volume potential dominates the Brownian forces the relaxation time is relatively short for the values of U close to Uip. For U lying between Uip and Up) there are multiple steady states. Figure 2.9 shows the multiple steady states for U=4.7, which lies between Upi= 4.6556 and Uip =5.0. 0t=0. 129 corresponds to the conditionally stable prolate state. So any microstructure with or higher or lower than a=0.129 will relax to the stable prolate state (0t=0.2869) and isotropic state ((1:0) respectively. Figure 2.10 shows the relaxation pathways for different initial states (OF 1, 015,005) with U=6.0 and C2=1/3. or: 0.15 and 0.05 are initial states, which are close to the isotropic state. Since U=6 is greater than Uip =5 , small perturbation from the isotropic states will take them to a stable prolate state. This state can also be reached by relaxing from an initial nematic state with the same value of U. 28 2.3 Figures 29 1.0 - 0.8 - 0.6 - 0.4 4 0.2 - 0.0 3 Figure 2.1 The isotropic-prolate transition predicted by the FSQ-closure with C2=1/3. see Appendix E for the numerical values for the graph. 30 0.6 - 0.4 0'2 - unstable states 0.0 ' .1 ' ' 4.6 4.8 5 5.2 5.4 Figure 2.2 The isotropic-prolate transition predicted by the FSQ-closure for C2=1/3 with the region between Uip (5.0) and Up) (4.626) enlarged 31 0.8 - 0.6 - § a3, =o.2240 0.4 - ------ 1' """""" UIp =4.9 0.2 - / 0 I I l I 1 3 5 7 9 11 13 15 Figure 2.3 The isotropic-prolate transition predicted by the F SQ-closure with C2=0.3 1. See Appendix F for the numerical values for the graph. 32 0 .2 - I unstable states 0 l ‘ l 1 I 4.5 4.7 4.9 5.1 5.3 ' 5.5 U Figure 2.4 The isotropic-prolate transition predicted by the F SQ-closure for C2=0.3] with the region between Up (4.9) and Up) (4.629) enlarged 33 0.8 ' 0.6 ‘ (133:0.2413 0.4 ‘ 0.2 1. 0,, =4.83 0 I I I I I I 3 5 7 9 11 13 15 Figure 2.5 The isotropic-prolate transition predicted by the FSQ-closure with C2=0.29. See Appendix G for the numerical values for the graph. 34 0.4 P 0 2 L unstable states .- 0 l t l l l l 4.50 4.70 4.90 5.10 5.30 5.50 Figure 2.6 The isotropic-prolate transition predicted by the F SQ-closure for C2=0.29 with the region between Uip (4.83) and Upi (4.606) enlarged. 35 1.00 1 0.90 - 0.80 - 0.70 0.60 J U: 6.0 0.50 0 .40 . U: 5.0 0-30 ‘ U= 4.65 0.20 « 0.10 - 511:0 U=4-0 U=4.5 0.00 - 0 10 20 30 40 50 60 70 80 90 100 110 U: 4.58 Figure 2.7 or versus 1 (dimensionless time) for the relaxation of LCP microstructure from an initial nematic state with C2=1/3. 36 1.00 0.90 0.80 0.70 q l. 0.60 - ,3 U: 6.0 0.50 . (X 0 40 . . __ u: 5.0 0.30 - U= 4.65 0.20 - flu: 4.58 0.10 3 04.5 ”=0 U=4.o 0.00 "' l I 0 10 20 30 T Figure 2.8 a versus 1 (dimensionless time) for the relaxation of LCP microstructure from an initial nematic state with C2= 1/3. 37 1.00 r 0.90 ‘ 0.80 ‘ 0.70 r 0.60 0.60 «l (X. 0.40 ‘ 0.30 ‘ a=0.2869 0.20 r 0.10 0.001fi I I I I I I I I I I I I 010 20 30 40 50 60 70 80 90100110120130140 a: 0.129 13 Figure 2.9 or versus 1: ( dimensionless time) for the relaxation of LCP microstructure from different initial states with C2= 1/3 and U= 4.7. 38 1.00 0.90 0.80 - 0.70 4 0.60 r 0.50 r 0.40 ‘ 0.30 r 0.20 r 0.10 - 0.00 r r u . Figure 2.10 or versus 1: ( dimensionless time) for the relaxation of LCP microstructure from different initial states with C2= 1/3 and U=6. 39 CHAPTER 3 CONCLUSIONS Eq. (1.15) is solved using the F SQ-closure to evaluate the orientation tetradic, for different values of C2 and U. By analyzing the results obtained, the following conclusion are made : 1.The Uip =5.0 (see Kini et al. 2003) predicted by the FSQ-closure with C2=1/3 is the same as that predicted by Chaubal et al.(1995) with the HL1 closure . 2. The values of Up, up), Up) predicted are dependent on the value of C2 chosen. The region of transition (i.e., region between Up and Upi) reduces as the value of C2 decreases. 3. The magnitude of U relative to Uip influences the relaxation times of the microstructure from an initial nematic state to an equilibrium state (see Chapter 2, Section 2.2). 4. The F SQ-closure exhibits the isotropic-prolate transition, qualitatively similar to those shown by the de-coupling approximation and the HL1 closure. A comparison of the Uip, up), Up; for the de-coupling approximation, HL1 and FSQ-closures are listed in the Table 3.1. From Figure 3.1 it is evident that with C2=1/3, the predictions made by FSQ-closure are closer to those made by the HL1 closure, and those with C2=0.29 are closer to the predictions made by the de—coupling approximation closure. 40 3.] Tables and Figures 41 Table 3.1 Comparison of the Uip, Up), api, values for the isotropic-prolate transition predicted by the F SQ-closure (C2=1/3) with the HL1, and the de-coupling approximation. Closure Up Up) api Reference de-coupling 3.00 2.667 0.2500 Bhave et approximation al. 1993 FSQ 5.00 4.656 0.2258 This research (C2= 1/ 3) HL1 5.00 4.898 0.125 . Chaubal et al. 1995 42 Table 3.2 The U;,,, Upi, up), values for the isotropic-prolate transition predicted by the FSQ-closure with different C2’s. C2 Uip Upi up; 0.2900 4.83 4.606 0.2413 0.3100 4.90 4.629 0.2249 1/3 5.00 4.656 0.2258 43 0.8 - 0.6 - , - OI. /:/ + FSQ(C2=1/3) 0.4 - / ”3'" HL1 De-coupling +FS C2=0.29 0.2 3 Q( ) 0 I I I I I I I I 0 2 4 6 8 10 12 14 16 Figure 3.1 Comparison of the isotropic-prolate transition predicted by the F SQ- closure(C2=1/3 and 0.29) with the HL1 and the de-coupling approximation. 44 CHAPTER 4 RECOMIVIENDATIONS Experiments The F SQ closure predicts an equilibrium phase diagram, which is qualitatively similar to those made by other closures like the HL1 and the de-coupling approximation. From Figure 3.1 it can be inferred that, the predictions made by the FSQ-closure are influenced by the particular value of C2 chosen. These conclusions are based on the results of the theoretical results. Comparing these results with experimental data on the relaxation phenomena of lyotropic LCPs, will not only help in judging the predictions made by the FSQ-closure, but will also provides a basis for the selection of a C2. The experimental data will also help in evaluating some of the underlying assumptions of the theory that DR, the rotary diffusion coefficient and C2 are constant. Aharoni and Walsh (1979) observed the isotropic to anisotropic transition for liquid crystalline solutions of two, Poly (isocyanates). Beyond a critical concentration they observed that the solution separated into an isotropic and an anisotropic phase (liquid crystalline phase). The optical microscopy with cross-polarized light of the anisotropic phase showed that the isocyanate polymer was being aligned in a particular direction. Though these experiments were done with lyotropic LCPs that undergo phase separation, similar experimental studies with LCPs that do not phase separate should be able to determine the critical concentrations for phase transitions and provide experimental evidence for fixing a particular value for C2. The nematic strength U, is dependent on the number density of the molecules or the concentration of the molecules. So devising experiments to observe and characterize 45 the microstructure with different values of U, should yield an equilibrium phase diagram, which could then be compared with those deduced from theoretical models. Measuring the relaxation time for the limit of U=0, would provide an estimate of DR the rotary diffusion co-efficient. The numerical results indicate that starting from an initial nematic state beyond Uip, the equilibrium states all lie on the prolate line (see. Appendix .B). Characterizing the experimentally observed microstructure should help in understanding this theoretical observation. Variation of C2 For this research the values of C2 used were 1/3, 0.31 and 0.29. Further simulations could be carried out with values of C2 greater than 1/3. 46 APPENDIX A : INVARIANTS OF THE ORIENTATION DYADIC The orientation dyadic g=

has three non-negative eigenvalues a1, a2, and a3 . Also associated with the tensor are the three invariants. Ia , IIa and 1113 . 13,: 0(2): al +a2 +a3 =1 (A.l) Ha: tr(gog)= (61.)2 + ((12)2 +013)2 ‘ (A2) 111,: my; .3): (22,)3 + (4,)3 + (a3)3 . (A3) The structure tensor b is defined as, 1:): g — 1/3 (A.4) Because g=gT and 1:? it follows that =_b=2T . Similarly, the invariants of 2 can be written as Ib= tr(g)=bl +b2 +b3 =0 (A5) [1,: egg): (6,)2 +(b3)2 +(b,)2 (A.6) IIIb= tr(2.2.2)= (b,)3 + (b2)3 + (b3)3 . (A.7) where b1, b2, b3 are the three eigenvalues of I; . 47 The eigenvalues of a__ and 2 are related by bi = a - 1/3 . (A-8) Therefore the nontrivial invariants of bin terms of the eigenvalues of a are given by 11.: (al —1/3)2 +(a2 -1/3)2 +(a3 —1/3)2 (A9) 111,: (al —1/3)3 +(a2 —1/3)3 +(a3 -1/3)3 . (A.10) Figure A] Identifies the set of realizable orientation states (i.e., O S ai $1) . Table A-1 defines the boundary of the invariant diagram (see Petty, et al. 1999; Nguyen, 20013 48 Table A-1. Invariants of the structure tensor Orientation State Invariants of g Eigenvalues of < pp > Ilb 111;, l 2 3 Notes A. Nematic 2/3 2/9 0 0 1 B. Planar Anisotropic IIb=2/9 + 2 III), 0 a l-a 0< a<1/2 C. Smectic 1/6 -1/36 0 1/2 1/2 D. Oblate 11.,=6(- rub/6)”3 1-2a a a 1/3< a<1/2 E. Isotropic 0 0 1/3 1/3 1/3 F. Prolate IIb=6( IIIb/6)2’3 a a l-2a o< a<1/3 49 IIb I 1115 Figure A] Invariant diagram of the structure tensor 2. A. Nematic State B. Planar Anisotropic States C. Planar Isotropic State D. Planar Axisymmetric E. Isotropic States F. Axial Axisymmetric 50 APPENDIX B : SCALAR ORDER PARAMETER FOR THE PROLATE STATES The orientation order parameter on is a scalar measure of the orientation of the microstructure. or varies between the values 0 (isotropic) and 1 (nematic) and is defined by: 3 or: (--b:b) . (8.1) 2:: From Eq.(A.4), it follows that 3( I)( 1) or: — a—=—: a-; 2 = 3 = 3 =\/2[a:a—2+ll I] 2 = = 3 9 = = 3 1 )3... 3. 3 1 a=\/§(alz+a22+a32)—§ . (B.2) At the prolate states the three eigenvalues of a are related as, al =a2 =(1-a3)/2 . Therefore Eq. (B.2) can be written in terms of a3 as follows 51 _ 2 1-..,2 2_1 a—J2[2[ 2 )+a, 3] . (3.3) 0t=—a3 —— . (B.4) a=1 represents all the molecules perfectly aligned in one direction, while 0t=0 corresponds to an isotropic state. 52 APPENDIX C: TETRADIC CLOSURE AT THE NEMATIC STATE C2 is the coefficient corresponding to the quadratic term in the FSQ-closure. The following calculations show that at the nematic state C2= 1/3. At the nematic state =(I-C2)l + C2 <fl>2 . (Cl) 1 1 < > s——S II +—S I < > C2 2222 1 35 [2:1 7 I: 22 1 < > 2 2 < pppp >2: E < pp >:< pp > S[ll]+ S[< pp >< pp >]—-7-S[I(< pp > - < pp >)] (C.3) S[é,§]=AijBk,+AikBj, +A3IBjk +Aleij+A B +A33Bil ji ik (C4) The FSQ-closure at the nematic state reduces to, 1 1 < pipjpkp1 >=—§(1-3C2)(Iijlkl +likljl +Iillkj)+ 7(1_3C2)(Iij§j§3 +Ii3§j§3 +Ii393-e-j ”1.19393 +I3le39k +1333 9391)+3C2§393§393 (C.5) Clearly C2 = 1/3 yields the orientation state tetradic g3 g3 93 e3 , which is representative of the nematic state 53 APPENDIX D: NUMERICAL DATA with C2=1/3 The fourth order tetradic is computed with C2=l/3 for the F SQ-closure and the differential equation Eq.(1.15) is solved for different values of U. Table D.1 The eigenvalues of g , the structure parameter and the invariants of 2 for U less than Up; and with C2=1/3 U a1 a2 a3 0: "0 "1:, 3.00 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.00 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.20 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.40 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 For U < Up) , the microstructure relaxes to an isotropic state. The orientation dyadic is a diagonal matrix. Hence an=a,, a22= a2 and a33= a3 ,Where a,, a2 and a; are the eigenvalues of a_ . llb, Illb are the second and third invariants of the anisotropic orientation tensor 0. The isotropic state corresponds to point B on the invariant diagram (see Appendix A, Figure A-l). 54 Table D2 The eigenvalues of 2:1 , the structure parameter or and the invariants of 1:) for U greater than Up; and with C2=1/3 U a1 a2 a3 a "IL_ 1111, 4.659 0.2550 0.2550 0.4900 0.2350 0.0368 0.0029 4.660 0.2542 0.2542 0.4916 0.2374 0.0376 0.0030 4.700 0.2377 0.2377 0.5246 0.2869 0.0549 0.0052 4.730 0.2304 0.2304 0.5392 0.3088 0.0636 0.0065 5.000 0.1944 0.1944 0.6111 0.4167 0.1158 0.0161 5.500 0.1604 0.1604 0.6792 0.5188 0.1794 0.0310 6.000 0.1389 0.1389 0.7222 0.5833 0.2268 0.0441 6.500 0.1232 0.1232 0.7535 0.6303 0.2649 0.0556 7.000 0.1111 0.1111 0.7778 0.6667 0.2963 0.0659 8.000 0.0932 0.0932 0.8136 0.7204 0.3460 0.0831 9.000 0.0805 0.0805 0.8390 0.7585 0.3835 0.0970 10.000 0.0709 0.0709 0.8581 0.7872 0.4131 0.1084 11.500 0.0603 0.0603 0.8794 0.8191 0.4473 0.1221 13.500 0.0450 0.0450 0.9100 0.8650 0.4988 0.1438 15.000 0.0447 0.0447 0.9105 0.8658 0.4997 0.1442 For U > Uip, the microstructure relaxes to a prolate state. The orientation dyadic is a diagonal matrix. The prolate states correspond to the line F on the invariant diagram (see Appendix A, Figure A-l). At the prolate state a H = a 32 < a 33 . 55 Table D.3 The eigenvalues of g , the structure parameter and the invariants of 2 for Up; S US Uip and With C2=1/3. U a1 a2 a3 a 11!— "lb 4.70 0.2903 0.2903 0.4193 0.1290 0.01 1 1 0.0005 4.75 0.3013 0.3013 0.3973 0.0960 0.0061 0.0002 4.80 0.3133 0.3133 0.3733 0.0600 0.0024 0.0000 4.85 0.3183 0.3183 0.3633 0.0450 0.0014 0.0000 4.90 0.3217 0.3217 0.3567 0.0350 0.0008 0.0000 5.00 0.3333 0.3333 0.3334 0.0001 0.0000 0.0000 ' The values of O. tabulated correspond to the unstable states on Figure 2.2. These are the unstable states or the conditionally stable prolate states. 56 APPENDIX E: NUMERICAL DATA with C2= 0.31 The fourth order tetradic is computed with C2=0.3] for the FSQ-closure and Eq.(l.15) is solved for different values of U. Table E.1 The eigenvalues of g , the structure parameter and the invariants of 1:) for U less than Upi and with C2=0.31 U a1 a} a3 a. “1,—— “lb 4.000 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.500 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.626 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.627 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 For U < Up. , the microstructure relaxes to an isotropic state. The orientation dyadic is a diagonal matrix. Hence an=a,, an: a; and a33= a3 .Where a,, a2 and a; are the a . llb, ”ID are the second and third invariants of the anisotropic eigenvalues of orientation tensor 2. The isotropic state corresponds to point B on the invariant diagram (see Appendix A, Figure A-l). 57 Table 13.2 The eigenvalues of g , the structure parameter and the invariants of 2 for U greater than Up; and with C2=0.3] U a1 a; a3 a "9._ "lb 4.630 0.2561 0.2561 0.4877 0.2316 0.0358 0.0028 4.631 0.2539 0.2539 0.4922 0.2383 0.0379 0.0030 4.633 0.2512 0.2512 0.4975 0.2463 0.0404 0.0033 4.635 0.2493 0.2493 0.5014 0.2521 0.0424 0.0036 4.650 0.2405 0.2405 0.5190 0.2785 0.0517 0.0048 4.660 0.2365 0.2365 0.5270 0.2905 0.0563 0.0054 4.800 0.2070 0.2070 0.5861 0.3792 0.0958 0.0121 5.200 0.1678 0.1678 0.6644 0.4966 0.1644 0.0272 5.500 0.1495 0.1495 0.7010 0.5515 0.2028 0.0373 6.000 0.1275 0.1275 0.7449 0.6174 0.2541 0.0523 7.000 0.0990 0.0990 0.8020 0.7030 0.3295 0.0772 8.000 0.0806 0.0806 0.8388 0.7582 0.3832 0.0969 9.000 0.0675 0.0675 0.8650 0.7975 0.4240 0.1 127 10.000 0.0576 0.0576 0.8848 0.8272 0.4562 0.1258 15.000 0.0305 0.0305 0.9389 0.9084 0.9389 0.9084 For U > Uip , the microstructure relaxes to a prolate state. The orientation dyadic is a diagonal matrix. The prolate states correspond to the line F on the invariant diagram (see Appendix A, Figure A-l). At the prolate state a I = a 2 < a 3 . 58 Table 13.3 The eigenvalues of g , the structure parameter and the invariants of 1:) for Upi S U S Uip and with C2=0.31. 4.90 U a1 a; a3 a "b "lb 4.63 0.2667 0.2667 0.4667 0.2000 0.0267 0.0018 4.66 0.2767 0.2767 0.4467 0.1700 0.0193 0.0011 4.70 0.2917 0.2917 0.4167 0.1250 0.0104 0.0004 4.76 0.3077 0.3077 0.3847 0.0770 0.0040 0.0001 4.80 0.3167 0.3167 0.3667 0.0500 0.0017 0.0000 0.3333 0.3333 0.3334 0.0001 0.0000 0.0000 The values of on tabulated correspond to the unstable states on Figure 2.4. These are the unstable states or the conditionally stable prolate states. 59 APPENDIX F: NUMERICAL DATA with C2 = 0.29 The fourth order tetradic is computed with C2=0.29 for the FSQ-closure Eq.(l.15) is solved for different values of U. Table RI The eigenvalues of g , the structure parameter and the invariants of 1:) for U less than Up. and with C2=0.29 U a1 3L a3 a "2_ "1:, 2.500 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 3.500 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.200 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.600 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 4.605 0.3333 0.3333 0.3334 0.0000 0.0000 0.0000 For U < Up, , the microstructure relaxes to an isotropic state. The orientation dyadic is a diagonal matrix. Hence an=al, 322: a; and a33= a3 _Where a1, a; and a3 are the eigenvalues of i . Uh, Uh, are the second and third invariants of the anisotropic orientation tensor b. The isotropic state corresponds to point B on the invariant diagram (see Appendix A, Figure A-l). 60 Table F2 The eigenvalues of g , the structure parameter and the invariants of 2 for U greater than Up, and with C2=0.29 U a 1 a; a3 a "L... "13, 4.607 0.2495 0.2495 0.5010 0.2515 0.0422 0.0035 4.608 0.2477 0.2477 0.5046 0.2569 0.0440 0.0038 4.610 0.2452 0.2452 0.5096 0.2644 0.0466 0.0041 4.620 0.2379 0.2379 0.5242 0.2863 0.0546 0.0052 4.650 0.2259 0.2259 0.5483 0.3225 . 0.0693 0.0075 4.660 0.2229 0.2229 0.5542 0.3313 0.0732 0.0081 4.670 0.2202 0.2202 0.5595 0.3393 0.0767 0.0087 4.690 0.2155 0.2155 0.5691 0.3537 0.0834 0.0098 4.800 0.1964 0.1964 0.6072 0.4108 0.1125 0.0154 5.500 0.1389 0.1389 0.7222 0.5833 0.2268 0.0441 7.000 0.0872 0.0872 0.8256 0.7384 0.3635 0.0895 8.000 0.0683 0.0683 0.8634 0.7951 0.4215 0.1117 10.000 0.0447 0.0447 0.9107 0.8661 0.5000 0.1444 11.500 0.0333 0.0333 0.9334 0.9001 0.5401 0.1621 13.500 0.0200 0.0200 0.9600 0.9400 0.5891 0.1846 15.000 0.0168 0.0168 0.9664 0.9496 0.6012 0.1903 For U > Uip , the microstructure relaxes to a prolate state. The orientation dyadic is a diagonal matrix. The prolate states correspond to the line F on the invariant diagram (see Appendix A, Figure A-l). At the prolate state a l = a 2 < a 3 . 61 Table F3 The eigenvalues of g , the structure parameter and the invariants of 2 for Upi 5 Us Up and with C2=0.29 U a1 a; 33 a "9— "lb 4.620 0.2700 0.2700 0.4600 0.1900 0.0241 0.0015 4.660 0.2850 0.2850 0.4300 0.1450 0.0140 0.0007 4.680 0.2900 0.2900 0.4200 0.1300 0.0113 0.0005 4.760 0.3133 0.3133 0.3733 0.0600 0.0024 0.0000 4.830 0.3333 0.3333 0.3334 0.0004 0.0000 0.0000 The values of a tabulated correspond to the unstable states on Figure 2.4. These are the unstable states or the conditionally stable prolate states 62 APPENDIX G: COMPUTER CODE (see. Nguyen, 2001) The following is a Matlab code that solves the Eq. (1.15) by using a fourth-order Runge Kutta algorithm. The fourth order tetradic is computed using the FSQ-closure. List of notations for computer code Symbol Definition Corresponding notation used in the computer code 2 = < pp > Orientation dyadic a < pppp > Orientation tetradic ppppO 2 Anisotropic orientation dyadic b llb Second invariant of l__) IIb Illb Third invariant of 1:) IIIb U Nematic strength U T Dimensionless time time 1 Identity matrix ID C1 Coefficient of linear terms in C] F SQ-closure C2 Coefficient of quadratic terms in C2 FSQ-closure dt step size dt stop number of time steps stop 63 F low chart for computer code Initially specify dt , stop , U, a , Cl, n=1 le Calculate a,pppp0 l Solve Eq. (1.15) using fourth-order R—K algorithm Calculate a, b n=n+1 if n < stop V if n = stop 64 dt=0.01 ; stop=90000; %for liquid crystaline polymers; lam=l .0; U=4.626 C1=2/3; C2=l-Cl; % %Initial input: perfect random; a=[ 0 O O O O O 0 O l ] ; %Unit tensor; ID=[ l O 0 O l O O O 1 ]; s=0; w=0; %Defined parameter; alpha=[-1/351/7O 0 000 O 0 0 1-2/7 000 O O 0 O O 000 O 0 O 00 001 -2/7]; %Symmetric and Antisymmetn'c portion of Velocity Gradient tensor; for n=1 :stop %First loop of the R-K method %Determine SH 1]; for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SII(i,j,k,l)=ID(i,j)*ID(k,1)+ID(i,k)*ID(j,l)+ID(i,l)*ID(k,j); end end 65 end end %Determine S[I a]; for i=1 :3 for j=l :3 for k=1 :3 for l=l :3 SIa(i,j,k,l)=ID(i,j)*a(k,l)+ID(i,k)*a(j,1)+ID(i,l)*a(k,j); SIa(i,j,k,l)=a(i,j)*ID(k,l)+a(i,k)*IDG,1)+a(i,l)*H)(kJ)+SIa(iJ,k,l); end end end end %Determine S[a a]; for i=1 :3 for j=l :3 for k=1 :3 for 1:1 :3 SaafiJ,Kl)=a(i.i)*a(k,1)+a(i,k)*a(i,1)+a(i,l)*a(k.i); end end end end %Determine S[I(a*a)]; for i=1 :3 for j=1 :3 aa(i.j)=0; bb(i,j)=0; for k=1 :3 aa(i.i) = aa(i.i)+a(i,k)*a(k,j); bb(i,j) = bb(i,i)+(a(i,k)-ID(i,k)/3)*(a(k,j)-ID(k,j)/3); end end end for i=1 :3 for j=l :3 for k=1 :3 for l=1 :3 SIaa(i,j,k,l)=ID(i,i)*aa(k,l)+ID(i,k)*aa(j,1)+ID(i,l)*aa(k,j); SIaa(i,j,k,l)=aa(i,j)*ID(k,l)+aa(i,k)*ID(j,l)+aa(i,l)*ID(k,j)+SIaa(i,i,k,l); end 66 end end end %Determine S[(a*a)a]; for i=1 :3 for j=l :3 aa(i,j)=0; for k= 1 :3 aa(i.i)=aa(i.i)+a(i,k)*a(k.i); end end end for i=1 :3 for j=1 :3 for k=1 :3 for 1=1 :3 Saaa(i,j,k,l)=aa(i,j)*a(k,l)+aa(i,k)*a0,l)+aa(i,l)*a(k,j); Saaa(i,j,k,l)=a(i,i)*aa(k,l)+a(i,k)*aa(j,l)+a(i,l)*aa(k,j)+Saaa(i,j,k,1); end end end end %Determine SIaaa; for i=1 :3 for j=l :3 aaa(i.i)=0; bbb(i,j)=0; for k=1 :3 aaa(i.i)=aaa(iJ)+aa(i,k)*a(k.i); bbb(i,i)=bbb(i,j)+bb(i,k)*(a(k,j)-ID(k,j)/3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 SIaaa(i,j,k,l)=ID(i,j)*aaa(k,l)+H)(i,k)*aaa(j,l)+ID(i,l)*aaa(k,j); SIaaa(i,j,k,l) = aaa(i,j)*ID(k,l)+aaa(i,k)*ID(j,1)+aaa(i,l)*ID(k,j)+SIaaa(i,j,k,l); end end 67 end end %Determine S[(a*a)(a*a)]; for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 Saaaa(i,j,k,l)=aa(i,j)*aa(k,l)+aa(i,k)*aa(j,l)+aa(i,l)*aa(k,j); end end end end %Determine S[I(a*a*a*a)]; for i =1 :3 for j=l :3 aaaa(i,j)=0; for k=1 :3 aaaa(i.i)=aaaa(i.i)+aaa(i.k)*a(k.i); end end end for i=1 :3 for j=1 :3 for k=1 :3 for 1:] :3 SIaaaa(i,j,k,1)=ID(i,j)*aaaa(k,l)+ID(i,k)*aaaa(i,l)+ID(i,l)*aaaa(k,j); SIaaaa(i,j,k,l)=aaaa(i,i)*ID(k,l)+aaaa(i,k)*ID(i,l)+aaaa(i,l)*ID(k,j)+SIaaaa(i,j,k,l); end end end end %Determine aza (11a) and alpha(2,1); IIa=aa( l , l )+aa(2,2)+aa(3,3); IIb=bb(] ,1 )+bb(2,2)+bb(3,3); alpha(2,1)=2*IIa/3 5; %Determine alpha(3,1); ALP1=aaa(1,1)+aaa(2,2)+aaa(3,3); alpha(3,1)=1/35+(4/35)*(ALP1/Ila); 68 111a=aaa(1,1)+aaa(2,2)+aaa(3,3); IIIb=bbb(l,l)+bbb(2,2)+bbb(3,3); %Determine alpha(3,4); alpha(3 ,4)=- l / (7 * Ila); %Determine alpha(3,5); alpha(3,5)=l/IIa; %Determine alpha(3,6); alpha(3,6)=-4/(7*Ha); %Determine alpha(4,l); ALP2=aaaa( l , l )+aaaa(2,2)+aaaa(3,3); alpha(4,1)=2/35*ALP2+(l/35)*IIa*IIa; %Determine alpha(4,4); alpha(4,4)=(- l/7)* IIa; %MSU contribution; %Determine pppp1,pppp2 for i=1 :3 for j=1 :3 for k=1 :3 for 1:1 :3 pppp5(i.j,k,l)=a(i.i)*a(k,l); ppppl(i,j,k,l)=alpha(l,l)*SII(i,i,k,l)+alpha(1,2)*SIa(i,j,k,l); %pppp2(i,i,k,l)=alpha(2,1)*SH(i,j,k,l)+alpha(2,2)*SIa(i,j,k,l)+alpha(2,3)*Saa(i,j,k,l)+alp ha(2,4)*SIaa(i,j,k,l); pppp2(i,j,k,l)=alpha(2,1)*SII(i,j,k,l)+alpha(2,3)*Saa(i,j,k,l)+alpha(2,4)*SIaa(i,j,k,l); %Casel :Michigan State University model; pppp0(i.i.k,l)=C1*pppp1(iJ,k,l)+C2*pppp2(i.i,k,l); end end end end %Determine :S for i=l:3 forj=l:3 69 M(i.i)=0; for k=1 :3 for l=l :3 M(i.i)=M(i.j)+pppp0(i.j,k,l)*s(l,k); end end end end %Determine : for i=1 :3 for j=l :3 N(i.i)=0; for k=1 :3 for l=l :3 N(i,j)=N(i,j)+ppppo(i.i,k,l)*a(l,k); end end end end %Determine S.a+a.S, W.a+a.W(T); for i=1 :3 for j=l :3 saas(i,j)=0; waaw(i,j)=0; for k=1 :3 saas(i,j)=saas(i,j)+s(i,k)*a(k,j)+a(i,k)*s(k,j); waaw(i,j)=waaw(i,j)+w(i,k)*a(k,j)+a(i,k)*w(i,k); end end end %Right handside of the equation for i=1 :3 for j=1 :3 dkl(i,j)=(ID(i,j)/3-a(i,j))+lam*Pe*(saas(i,i)-2*M(i,j))-Pe*waaw(i,j)+U*(aa(i,j)- N(iJ)); end end %an loop of 4th order R_K for i=1 :3 for j=l :3 a1(i,j)=a(i,j)+dkl(i,j)*dt*0.5; 70 end end %Determine S[I a]; for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIal(i,j,k,l)=ID(i,j)*a1(k,l)+ID(i,k)*al(j,l)+ID(i,l)*al(k,j); SIal(i,j,k,l)=al(i,j)*ID(k,l)+al(i,k)*ID(i,l)+al(i,l)*ID(k,j)+SIal(i,j,k,l); end end end end %Determine S[a a]; for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 Saal(i,j,k,l)=al(iJ)*al(k,l)+al(i,k)*al(j,l)+a1(i,l)*al(k,j); end end end end %Determine S[I(a*a)]; for i=1 :3 for j=1 :3 aa1(i,j)=0; bbl(i,j)=0; for k=1 :3 aal(i,j) = aa1(i,j)+a1(i,k)*al(k,j); bbl(i,j) = bb1(i,j)+(al(i,k)-ID(i,l<)/3)*(al(kJ)-ID(k,j)/3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for 1=1 :3 SIaal(i,j,k,l)=ID(i,j)*aal(k,l)+ID(i,k)*aa1(j,l)+ID(i,l)*aal(k,j); SIaal(i,j,k,l)=aal(i,j)*ID(k,l)+aal(i,k)*ID(j,l)+aa1(i,l)*ID(k,j)+SIaal(iJ,k,l); end end 71 end end %Determine S[(a*a)a]; for i=1 :3 for j=1 :3 aal(iJ)=0; for k=1 :3 aa1(i,j)=aal(i,j)+al (i,k)*al(k,j); end end end for i=1 :3 for j=l :3 for k=1 :3 for l=l :3 Saaal(i,j,k,l)=aa1(i,i)*al(k,l)+aa1(i,k)*al(i,l)+aal(i,l)*al(k,j); Saaal(i,j,k,l)=al(i,j)*aal(k,l)+a1(i,k)*aal(i,l)+al(i,l)*aa1(kJ)+Saaal(i,j,k,l); end end end end %Determine SIaaa; for i=1 :3 for j=1 :3 aaal (i,j)=0; bbbl(i,j)=0; for k=1 :3 aaal(i,j)=aaal(iJ)+aa1(i,k)*al(k,i); bbb1(i,j)=bbbl(iJ)+bb1(i,k)*(a1(kJ)-ID(k,j)/3); end end end for i=1 :3 for j=l :3 for k=1 :3 for 1=1 :3 SIaaal(i,i,k,l)=ID(i,i)*aaal(k,l)+ID(i,k)*aaa1(j,l)+ID(i,l)*aaa1(k,i); SIaaal(i,j,k,l) = aaal(i,j)*ID(k,l)+aaal (i,k)*ID(j,l)+aaal(i,l)*ID(k,j)+SIaaal(i,j,k,1); end end 72 end end %Determine S[(a*a)(a*a)]; for i=1 :3 for j=l :3 for k=1 :3 for l=1 :3 Saaaal(i,j,k,l)=aal(i,i)*aa1(k,l)+aal (i,k)*aa1(j,l)+aal(i,l)*aa1(k,j); end end end end %Determine S[I(a*a*a*a)]; for i =1 :3 for j=1 :3 aaaal(i,j)=0; for k=1 :3 aaaal(i,j)=aaaa1(i,j)+aaal (i,k)*al (1g); end end end for i=1 :3 for j=l :3 for k=1 :3 for l=1 :3 SIaaaal(i,j,k,l)=ID(i,j)*aaaal(k,l)+ID(i,k)*aaaal(j,l)+ID(i,l)*aaaal(k,j); SIaaaal(i,j,k,l)=aaaa1 (i,j)*ID(k,l)+aaaa1(i,k)*ID(j,l)+aaaa1(i,l)*ID(k,j)+SIaaaal(i,j,k,l); end end end end %Determine aza (11a) and alpha(2,l); IIa1=aal(1,1)+aal(2,2)+aal(3,3); Ilbl=bbl( 1,1)+bb1(2,2)+bb1(3,3); alpha1(2,1)=2*(IIal)/35; %Determine alpha(3,1); ALPl l=aaal(l,1)+aaal(2,2)+aaal(3,3); alphal(3,l)=1/35+(4/3S)*(ALP1l/IIal); IIIal=aaal(l ,1)+aaal(2,2)+aaal(3,3); IIIbl=bbb1(1,1)+bbb1(2,2)+bbbl(3,3); 73 %Determine alpha(3,4); alphal(3,4)=l/(7*IIal); %Determine alpha(3,5); alpha1(3,5)=l/IIal; %Determine alpha(3,6); a1phal(3,6)=-4/(7*Ilal); %Determine alpha(4,l); ALP21=aaaal(l, l )+aaaal(2,2)+aaaa1(3,3); alphal(4,1)=2/35*ALP21+(1/35)*Ila1*IIal; %Determine alpha(4,4); alpha 1 (4,4)=(- 1/7)*IIa1 ; %MSU contribution; %Detennine pppp1,ppp92,pppp3,pppp4; for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 pppp51(i.i,k,l)=a1(i.i)*al(k.l); ppppl 1(i,j,k,l)=alpha(1,l)* SII(i,j,k,l)+alpha(1,2)*SIa1(i,j,k,l); %pppp2(i,i ,k,l)=alpha(2, 1 )*SII(i,j ,k,l)+alpha(2,2)* SIa(i,j ,k,1)+alpha(2,3)* Saa(i,j ,k,l)+alp ha(2,4)*SIaa(i,j,k,l); pppp2 1 (i,j,k,l)=alphal (2, 1)* SII(i,j ,k,l)+alpha(2,3)* Saa l (ij ,k,l)+alpha(2,4)* SIaa1(i,j,k,l) %Casel :Michigan State University model; pppp01(i.i.k.l)=C1*pppp1 l(iJ,k.l)+C2*pppp21(iJ,k,1); end end end end %Determine :S for i=1 :3 for j=1 :3 M1(iJ)=0; for k=1 :3 for l=1 :3 M1(i.i)=M1(iJ)+pppp01(iJ,k,l)*s(l,k) end 74 end end end %Determine : for i=1 :3 for j=1 :3 Nl(i,j)=0; for k=1 :3 for l=1 :3 Nl(i.i)=N1(i.i)+pppp01(i.i,k,l)*al(Lk); end end end end %Determine S.a+a.S, W.a+a.W(T); for i=1 :3 for j=1 :3 saasl(i,j)=0; waawl(i,j)=0; for k=1 :3 saasl(i,j)=saasl(i,j)+s(i,k)*a1(k,j)+al(i,k)*s(k,j); waawl(i,j)=waawl(i,j)+w(i,k)*al(k,j)+al(i,k)*w(j,k); end end end %Right handside of the equation for i=1 :3 for j=1 :3 dk2(i,j)=(ID(i,j)/3-al(i,j))+lam*Pe*(saas1(i,j)-2*Ml (i,j))- Pe*waaw1(i,j)+U*(aal(i,j)-N 1(i,j)); end end %3rd loop of 4th order R-K for i=1 :3 for j=1 :3 a2(i,i)=a(i,i)+dk2(i,j)*dt*0.5; end end %Determine S[I a]; 75 for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 SIaZGJ,k,l)=ID(i.j)*aZ(k,1)+ID(i,k)*€120,1)+ID(i,l)*aZ(k.i); SIa2(i,j,k,l)=a2(i,j)*ID(k,l)+a2(i,k)*ID(j,l)+a2(i,l)*ID(k,j)+SIa2(i,j,k,l); end end end end %Determine S[a a]; for i=1 :3 for j=l:3 for k=1 :3 for l=l :3 Saa2(i,j,k,l)=a2(i,j)*a2(k,l)+a2(i,k)*a2(j,1)+a2(i,l)*a2(k,j); end end end end %Determine S[I(a*a)]; for i=1 :3 for j=1 :3 , aa2(i,i)=0; bb2(i,j)=0; for k=1 :3 3320.0 = 332(iJ)+aZ(i,k)*aZ(kJ); bb2(i,j) = bb2(i,j)+(a2(i,k)-ID(i,k)/3)*(a2(k,j)-ID(k,j)/3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for 1=1 :3 SIaa2(i,j,k,l)=ID(i,j)*aa2(k,l)+ID(i,k)*aa2(j,1)+ID(i,l)*aa2(k,j); SIaa2(i,j,k,l)=aa2(i,j)*ID(k,l)+aa2(i,k)*ID(j,l)+aa2(i,l)*ID(k,j)+SIaa2(i,j,k,l); end end end end %Determine S[(a*a)a]; 76 for i=1 :3 for j=1 :3 aa2(iJ)=0; for k=1 :3 aa2(iJ)=aaZ(iJ)+a2(i,k)*a2(kJ); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 Saaa2(i,j,k,l)=aa2(i,j)*a2(k,l)+aa2(i,k)*a2(j,l)+aaZ(i,l)*a2(k,j); Saaa2(i,j,k,l)=a2(i,j)*aa2(k,l)+a2(i,k)*aa2(j,l)+a2(i,l)*aa2(k,j)+Saaa2(i,j,k,l); end end end end %Determine SIaaa; for i=1 :3 for j=1 :3 aaa2(i.i)=0; bbb2(i,j)=0; for k=1 :3 aaaZGJ)=aaaZ(iJ)+aa2(i,k)*a2(kJ); bbb2(i,j)=bbb2(i,j)+bb2(i,k)*(a2(k,j)-ID(k,j)/3); end end end . for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIaaa2(i,j,k,l)=ID(i,j)*aaa2(k,l)+ID(i,k)*aaa2(j,1)+ID(i,l)*aaa2(k,j); SIaaa2(i,j,k,l) = aaa2(i,j)*ID(k,l)+aaa2(i,k)*ID(j,l)+aaa2(i,l)*ID(k,j)+SIaaa2(i,i,k,l); end end end end %Determine S[(a*a)(a*a)]; 77 for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 Saaaa2(i,j,k,l)=aa2(i,j)*aa2(k,l)+aa2(i,k)*aa2(j,l)+aa2(i,l)*aa2(k,j); end ‘ end end end %Determine S[I(a* a*a*a)]; for i =1 :3 for j=1 :3 aaaa2(i,j)=0; for k=1 :3 aaaa2(i,j)=aaaa2(i,j)+aaa2(i,k)*a2(k,j); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIaaaa2(i,j,k,l)=ID(i,j)*aaaa2(k,l)+ID(i,k)*aaaa2(j,l)+ID(i,l)*aaaa2(k,j); SIaaaa2(i,j,k,l)=aaaa2(i,j)*ID(k,l)+aaaa2(i,k)*ID(i,l)+aaaa2(i,l)*ID(k,i)+SIaaaa2(i,j,k,l); end end end end %Determine aza (Ha) and alpha(2,l); 11a2=aa2(1,1)+aa2(2,2)+aa2(3,3); Ilb2=bb2(l ,1)+bb2(2,2)+bb2(3,3); alpha2(2,l)=2*(IIa2)/35; %Determine alpha(3,1); ALP 12=aaa2( l , 1)+aaa2(2,2)+aaa2(3,3); alpha2(3,1)=l/35+(4/35)*(ALP12/IIa2); IIIa2=aaa2(] ,1)+aaa2(2,2)+aaa2(3 ,3); IIIb2=bbb2( 1 , l )+bbb2(2,2)+bbb2(3 ,3); %Determine alpha(3,4); alpha2(3,4)=1/(7*IIa2); 78 %Determine alpha(3,5); alpha2(3,5)=l/Ila2; %Determine alpha(3,6); alpha2(3,6)=-4/(7*Ila2); %Determine alpha(4, 1 ); ALP22=aaaa2(1,1)+aaaa2(2,2)+aaaa2(3,3); alpha2(4, 1 )=2/35 *ALP22+(1/35)*IIa2*IIa2; %Determine alpha(4,4); alpha2(4,4)=(-1/7)*Ila2; %MSU contribution; %Determine ppppl for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 pppp52(iJ,k,l)=a2(i.i)*a2(k,l); pppp12(i,j,k,l)=alpha(l,1)*SII(i,j,k,l)+alpha(1,2)*SIa2(i,j,k,l); %pppp2(i,i,k,l)=alpha(2,l)*SII(i,i,k,l)+alpha(2,2)*SIa(i,j,k,l)+alpha(2,3)*Saa(i,j,k,l)+alp ha(2,4)*SIaa(i,j,k,l); _ pppp22(i,j,k,l)=alpha2(2, 1)*SII(iJ,k,l)+alpha(2,3)* Saa2(i,j,k,l)+alpha(2,4)* SIaa2(i,j ,k,l); pppp32(iJ,k,l)=alpha2(3,1)*SII(i,i,k,l)+alpha2(3,4)*SIaa2(i,j,k,l)+alpha2(3,5)*Saaa2(i,j,k ,l)+alpha2(3,6)*SIaaa2(i,j,k,l); pppp42(i,j ,k,l)=alpha2(4, l )*SII(i,j ,k,l)+alph32(4,4)*SIaa2(i,j ,k,l)+a1pha(4,7)* Saaaa2(i,j ,k ,l)+alpha(4,8)*SIaaaaZ(i,i,k,l); %Casel :Michigan State University model; pppp02(i.i,k,l)=Cl*ppppl2(i.i,k,1)+C2*pppp22(iJ.191); end end end end %Determine zS for i=1 :3 for j=1 :3 M2(iJ)=0; 79 for k=1 :3 for l=l :3 M2(i.i)=M2(i,j)+pppp02(iJ,k,l)*S(l,k); end end end end %Determine : for i=1 :3 for j=1 :3 N2(i.i)=0; for k=1 :3 for l=l :3 N2(iJ)=N2(iJ)+pPPP02(iJ,k,1)*a2(1,k); end end end end %Determine S.a+a.S, W.a+a.W(T); for i=1 :3 for j=1 :3 saa52(i,i)=0; waaw2(i,j)=0; for k=1 :3 saasZ(i,j)=saasZ(i,j)+s(i,k)*a2(k,j)+a2(i,k)*s(k,j); waaw2(i,j)=waaw2(i,j)+w(i,k)*a2(k,j)+a2(i,k)*w(i,k); end end end %Right handside of the equation for i=1 :3 for j=1 :3 dk3(i,i)=(ID(i,j)/3-a2(i,j))+lam*Pe*(saas2(i,j)-2*M2(i,j))- Pe*waaw2(i,j)+U*(aa2(i,j)-N2(i,j)); end end %3nd loop of 4th order R-K for i=1 :3 for j=1 :3 a3(i.il=a(i.i)+dk3(i.j)*dt; 8O end end %Determine S[I a]; for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIa3(i,j,k,l)=ID(i,j)*a3(k,l)+ID(i,k)*a3(j,1)+H)(i,l)*a3(k,j); SIa3(i,j,k,l)=a3(i,i)*ID(k,l)+a3(i,k)*[DO,1)+a3(i,l)*ID(k,j)+SIa3(i,j,k,1); end end end end %Determine S[a a]; for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 Saa3(i,j,k,l)=a3(i,j)*a3(k,l)+a3(i,k)*a3(j,l)+a3(i,l)*a3(k,j); end end end end %Determine S[I(a*a)]; for i=1 :3 for j=1 :3 aa3(i.i)=0; bb3(i,j)=0; for k=1 :3 21330.0 = aa3(i.j)+a3(i,k)*a3(kJ); bb3(i,j) = bb3(ij)+(a3(i,k)-ID(i,k)/3)*(a3(k,j)-ID(k,j)/3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for 1=l :3 SIaa3(i,j,k,l)=ID(i,j)*aa3(k,l)+H)(i,k)*aa3(j,l)+ID(i,l)*aa3(k,j); SIaa3(i,j,k,l)=aa3(i,j)*ID(k,l)+aa3(i,k)*ID(i,l)+aa3(i,1)*ID(k,j)+SIaa3(iJ,k,l); end end 81 end end %Determine S[(a*a)a]; for i=1 :3 for j=1 :3 aa3(i,j)=0; for k=1 :3 aa3(i.j)=aa3(i.i)+a3(i,k)*a3(k.i); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 Saaa3(i,j,k,l)=a33(i,j)*a3(k,l)+aa3(i,k)*a3(j,1)+aa3(i,l)*a3(k,j); Saaa3(i,j,k,l)=a3(i,j)*aa3(k,l)+a3(i,k)*aa3(j,l)+a3(i,l)*aa3(k,j)+Saaa3(i,j,k,l); end end end end %Determine SIaaa; for i=1 :3 for j=1 :3 aaa3(i,j)=0; bbb3(i,j)=0; for k=1 :3 aaa3(i,j)=aaa3(i,i)+aa3(i,l<)*a3(k,j); bbb3(i,j)=bbb3(i,j)+bb3(i,k)*(a3(k,i)-ID(k,j)/3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 SIaaa3(i,j,k,l)=ID(i,j)*aaa3(k,l)+ID(i,k)*aaa3(j,1)+1D(i,l)*aaa3(k,j); SIaaa3(i,j,k,l) = aaa3(i,j)*ID(k,l)+aaa3(i,k)*ID(j,l)+aaa3(i,l)*ID(k,j)+SIaaa3(i,j,k,l); end end 82 end end %Determine S[(a*a)(a*a)]; for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 , Saaaa3(i,j,k,l)=aa3(i,j)*aa3(k,l)+aa3(i,k)*aa3(j,l)+aa3(i,l)*aa3(k,j); end end end end %Determine S[I(a*a*a*a)]; for i =1 :3 for j=1 :3 aaaa3(iJ)=0; for k=1 :3 aaaa3(i,j)=aaaa3(i,j)+aaa3(i,k)*a3 (k,j); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIaaaa3(i,j,k,l)=ID(i,j)*aaaa3(k,l)+ID(i,k)*aaaa3(i,l)+HD(i,l)*aaaa3(kJ); SIaaaa3(i,j,k,l)=aaaa3(iJ)*ID(k,l)+aaaa3(i,k)*1D(j,l)+aaaa3(i,l)*ID(k,j)+SIaaaa3(i,j,k,l); end end end end %Determine aza (113) and alpha(2,l); IIa3=aa3(l,1)+aa3(2,2)+aa3(3,3); IIb3=bb3( 1 , 1 )+bb3(2,2)+bb3(3,3); alpha3(2,l)=2*(IIa3)/35; %Determine alpha(3,1); ALP13=aaa3(1,1)+aaa3(2,2)+aaa3(3,3); alpha3(3, 1)=1/35+(4/35)*(ALP1 3/IIa3); IIIa3=aaa3(l,1)+aaa3(2,2)+aaa3(3,3); IIIb3=bbb3( 1 , 1 )+bbb3 (2,2)+bbb3 (3,3); 83 %Determine alpha(3,4); alpha3(3,4)=l/(7*Ila3); %Determine alpha(3,5); alpha3(3,5)=l/IIa3; %Determine alpha(3,6); alpha3(3,6)=-4/(7*Ila3); %Determine alpha(4,l); ALP23=aaaa3(l,1)+aaaa3(2,2)+aaaa3(3,3); alpha3(4,1)=2/35*ALP23+(1/35)*IIa3*IIa3; %Determine alpha(4,4); alpha3(4,4)=(-1/7)*IIa3; %MSU contribution; %Determine ppppl,pppp2 for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 pppp53(i.i,k,l)=a3(i.i)*a3(k.l); ppppl 3(i,j,k,l)=alpha(l , l )"' SII(i,i,k,l)+alpha( 1 ,2)* SIa3(i,j ,k,l); %pppp2(i,j,k,l)=alpha(2, l )*SII(i,j ,k,l)+alpha(2,2)*SIa(iJ,k,l)+alpha(2,3)*Saa(i,j,k,l)+alp ha(2,4)*SIaa(i,j,k,l); pppp23(i,j,k,l)=alpha3 (2, 1)*SII(i,j,k,l)+alpha(2,3)* Saa3(i,j,k,l)+alpha(2,4)*SIaa3(i,j,k,l); %Casel :Michigan State University model; pppp03(i.i,k.l)=C1*ppppl3(i.i,k,l)+C2*pppp23(i.i.k,l); end end end end %Determine :S for i=1 :3 for j=1 :3 M3(i,j)=0; for k=1 :3 for l=l :3 M3(i.i)=M3(i.i)+pppp03(i.i,k,l)*s(l,k); 84 end end end end %Determine : for i=1 :3 for j=1 :3 N3(iJ)=0; for k=1 :3 for l=1 :3 N3(iJ)=N3(iJ)+PPPP03(iJ,k,l)*a3(l,k); end end end end %Determine S.a+a.S, W.a+a.W(T); for i=1 :3 for j=1 :3 saas3(i,j)=0; waaw3(i,j)=0; for k=1 :3 saas3(i,j)=saas3(ij)+s(i,k)*a3(k,j)+a3(i,k)*s(k,j); waaw3(i,j)=waaw3(i,j)+w(i,k)*a3(k,j)+a3(i,k)*w(j,k); end end end %Right handside of the equation for i=1 :3 for j=1 :3 dk4(i,j)=(ID(i,j)/3-a3(i,j))+lam*Pe*(saas3(i,j)-2*M3(i,j))- Pe*waaw3(i,j)+U*(aa3(i,j)-N3(i,j)); end end %4nd loop of 4th order R-K for i=l:3 forj=1:3 %Overall computation a(i,j)=a(i,j)+(l/6)*(dk1(iJ)+2*dk2(i,j)+2*dk3(i,j)+dk4(i,i))*dt; E=[a(1,1),a(1,2),a(1,3);a(2,1),a(2,2),a(2,3);a(3,1),a(3,2),a(3,3)]; 85 [v,lambdal]=eig(E); if i=2 if j=3 A(n)=a(iJ); time(n)=(n- 1 )*dt; end end if i=2 if j== B(n)=a(i.i); time(n)=(n- 1 )*dt; end end if i==1 if j== l C(n)=a(iJ); time(n)=(n- 1)*dt; end end if i==3 if j=3 D(n)=a(i.i); time(n)=(n- l )* (it; end end %d(n)=det(E); e3(n)=v(3,3); time(n)=(n- 1 )*dt; e2(n)=v(2,2); time(n)=(n-1 )*dt; en(n)=V(2,3); time(n)=(n- 1 )*dt; e1(n)=v(1,1); time(n)=(n- 1 )*dt; 12(n)=lambdal(2,2); time(n)=(n- 1 )*dt; l3(n)=lambdal(3,3); time(n)=(n- 1 )*dt; - ll(n)=lambdal(l,1); time(n)=(n- 1 )*dt; if i== iszz 86 BB(n)=bb(i,j); BBB(n)=bbb(i,j); end end if i=2 if j=2 CC(n)=bb(i.j); CCC(n)=bbb(i,j); end end if i== if j=3 DD(n)=bb(i,j); DDD(n)=bbb(i,j); end end end end for i=1 :3 for j=1 :3 II(n)=BB(n)+CC(n)+DD(n); HI(n)=BBB(n)+CCC(n)+DDD(n); end end a %Computation of finding tau values %Determine S[I a]; for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIatau(i,j,k,l)=ID(i,j)*a(k,l)+ID(i,k)*a(i,l)+ID(i,l)*a(k,j); SIatau(i,j,k,l)=a(i,j)*ID(k,l)+a(i,k)*ID(j,1)+a(i,l)*ID(k,j)+SIatau(i,j,k,l); end end end end %Determine S[a a]; for i=1 :3 for j=1 :3 for k=1 :3 87 for l=l :3 Saatau(i,j,k,l)=a(i,j)*a(k,l)+a(i,k)*a(j,1)+a(i,l)*a(k,j); end end end end %Determine S[I(a*a)]; for i=1 :3 for j=1 :3 aatau(i,j)=0; bbtau(i,j)=0; for k=1 :3 aatau(i,j) = aatau(i,j)+a(i,k)*a(k,j); bbtau(i,j) = bbtau(iJ)+(a(i,k)-ID(i,l()/3)*(a(k,j)-ID(k,j)/3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=l :3 SIaatau(i,j,k,l)=ID(i,j)*aatau(k,l)+ID(i,k)*aatau(j,l)+ID(i,l)*aatau(k,j); SIaatau(i,j,k,l)=aatau(i,j)*ID(k,l)+aatau(i,k)*ID(j,l)+aatau(i,l)*ID(k,j)+SIaatau(i,j,k,l); end end end end %Determine S[(a*a)a]; for i=1 :3 for j=1 :3 aatau(i,j)=0; for k=1 :3 aatau(i,j)=aatau(i,j)+a(i,k)* 8091); end end end for i=l:3 forj=lz3 for k=1:3 for l=l:3 88 Saaatau(i;j,k,l)=aatau(i,j)*a(k,l)+aatau(i,k)*a(j,l)+aatau(i,l)*a(k,j); Saaatau(i,j,k,l)=a(i,j)*aatau(k,l)+a(i,k)*aatau(j,l)+a(i,l)*aatau(k,j)+Saaatau(i,j,k,l); end end end end %Determine SIaaa; for i=1 :3 for j= 1 :3 aaatau(i,j)=0; bbbtau(i,j)=0; for k=1 :3 aaatau(i,j)=aaatau(i,j)+aatau(i,k)*a(k,j); bbbtau(i,j)=bbbtau(i,j)+bbtau(i,k)*(a(k,j )-ID(k,j )/ 3); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 v SIaaatau(i,j,k,l)=ID(i,j)*aaatau(k,l)+ID(i,k)*aaatau(j,1)+ID(i,l)*aaatau(k,j); SIaaatau(i,j,k,l)=aaatau(i,j)*lD(k,l)+aaatau(i,k)*ID(j,l)+aaatau(i,l)*ID(k,j)+SIaaatau(i,j,k, 1); end end end end %Determine S[(a*a)(a*a)]; for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 Saaaatau(i,j,k,l)=aatau(i,j)*aatau(k,1)+aatau(i,k)*aatau(i,l)+aatau(i,l)*aatau(k,j); end end end end 89 %Determine S[I(a*a*a*a)]; for i =1 :3 for j=1 :3 aaaatau(i,i)=0; for k=1 :3 aaaatau(i,j)=aaaatau(i,j)+aaatau(i,k)*a(k,j); end end end for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 SIaaaatau(i,j,k,l)=ID(i,j)*aaaatau(k,l)+ID(i,k)*aaaatau(i,1)+ID(i,l)*aaaatau(k,j); SIaaaatau(i,i,k,l)=aaaatau(i,i)*ID(k,l)+aaaatau(i,k)*ID(j,l)+aaaatau(i,l)*ID(k,i)+SIaaaatau (H.191); end end end end %Determine a:a (Ila) and alpha(2, l); IIatau=aatau(l ,1)+aatau(2,2)+aatau(3,3); IIbtau=bbtau( 1 , 1)+bbtau(2,2)+bbtau(3 ,3 ); alphatau(2, l )=2*IIatau/ 3 5; %Determine alpha(3,1); ALP 1tau=aaatau( l , l )+aaatau(2,2)+aaatau(3,3); alphatau(3 , 1 )= l / 3 5+(4/ 3 5)*(ALP 1 tau/IIatau); HIatau=aaatau( 1 , l )+aaatau(2,2)+aaatau(3 ,3 ); IIIbtau=bbbtau( 1 , l )+bbbtau(2,2)+bbbtau(3 ,3); %Determine alpha(3,4); alphatau(3,4)=-1/(7*IIatau); %Determine alpha(3,5); alphatau(3,5)=l/IIatau; %Determine alpha(3,6); alphatau(3,6)=-4/(7*IIatau); %Determine alpha(4,l); ALP2tau=aaaatau(l , l)+aaaatau(2,2)+aaaatau(3 ,3); alphatau(4, l)=2/ 35 *ALP2tau+(1/3 5)*IIatau*IIatau; 90 %Determine alpha(4,4); alphatau(4,4)=(- 1/7)* IIatau; %MSU contribution; %Determine pppp1,pppp2,pppp3,pppp4; for i=1 :3 for j=1 :3 for k=1 :3 for l=1 :3 pppp5taU(i.i,k,l)=a(i.i)*a(k,l); ppppltau(i,j,k,l)=alpha(1 , l)*SII(i,j,k,l)+alpha( l ,2)*SIatau(i,j,k,l); %pppp2(i,j ,k,l)=alpha(2, 1)* SII(i,j,k,l)+alpha(2,2)* SIa(i,j ,k,l)+alpha(2,3)* Saa(i,j,k,l)+alp ha(2,4)*SIaa(i,j,k,l); pppp2tau(i,j ,k,l)=alphatau(2, 1)* SII(i,j ,k,l)+alpha(2,3)* Saatau(i,j ,k,l)+a1pha(2,4)* SIaatau( i.j,k,1); %Casel :Michigan State University model; ppppOtaU(i.j.k.l)=C1*ppppltaU(i.i,k,l)+C2*pppt>2taU(i.i,k,1); end end end end %Determine zS for i=1 :3 for j=1 :3 Mtau(i,j)=0; for k=1 :3 for l=1 :3 Mtau(i,j)=Mtau(i,j)+pppp0tau(i,i,k,l)*s(l,k); end end end end %Determine : for i=1 :3 for j= l :3 Ntau(i,j)=0; for k=1 :3 91 for l=1 :3 Ntau(i,j)=Ntau(i,j)+pppp0tau(i,j,k,l)*a(l,k); end end end end %Computation of tau for i=1 :3 for j=1 :3 t2111(i.j)=(&|(i,.i)-1/ 3*ID(iJ))-U*(aa(iJ)-N(iJ))+Pe*M(iJ); if i=2 if j=3 W(n)=taU(i.i); time(n)=(n-1 )*dt; end end X(n)=taU(iJ); time(n)=(n-1 )*dt; end end if i==1 if j== Y(n)=taU(iJ); time(n)=(n- 1 )* dt; end end if i==3 if j==3 Z(n)=taU(iJ); time(n)=(n- 1 )*dt; end end end end %Primary normal stress for i=1 :3 for j=1 :3 P(n)=Z(n)-X(n); end 92 end %Secondary normal stress for i=1 :3 for j=1 :3 Q(n)=X(n)-Y(n); end end %Time average f(l)=0; f(n+ l )=f(n)+1 ; R(n)=0; if all(f(n)>limitnl) & all(f(n)