THE CLOSURE PROBLEM FDR THE BACKWARD SHIFT OPERATOR IN THE. HARDY p-CLASSESI 5: R “RR, Thesis for the. Degree Of Ph‘ D. MICHIGAN STATE UNWERSITY HAROLD ARTHUR ALLEN 1970 I‘HESIS L I B 24’ 14 R Y M;;1310 .. State University This is to certlfg that the thesis entitled THE CLOSURE PROBLEM FOR THE BACKWARD SHIFT OPERATOR IN THE HARDY p-CLASSES 1 g p < co. presented by Harold Arthur Allen has been accepted towards fulfillment of the requirements for Ph- 13- degree inmflics Major professor? Date 9-25-70 0-169 ABS TRACT THE CLOSURE PROBLEM FOR THE BACKWARD SHIFT OPERATOR IN THE HARDY p-CLASSES 1 s p < m. BY Harold Arthur Allen The Hardy p-class of the disc is the set of all func- tions f(z) holomorphic on the open unit disc for which 2R - sup I |f(rele)|pde < a. OSr 1] U [on]. Let u(z) be a real valued continuous function on D, possessing continuous second order partial derivatives with respect to x and )r where z = x + iy, x and y real numbers. u(z) is said to be harmonic on D if and only if u(z) satisfies Laplace's equation on D, uxx(z) + uyy(z) = O 5 in Cartesian coordinates, or 19 1 ie A ie urr(re )+-r‘ur(re )+r2 ueg(re ) = O in polar coordinates. A complex valued function u(z) continuous on D is said to be harmonic on D if and only if both the real and imaginary parts of u(z) are harmonic on D. For 0 < p s a and for u(rele) harmonic on D, we define the Lp means of u on |z| = r by 2O ie p l/p '5; £) [u(re )I def 1f 0 < p < m m r,u = p( ) . sup [u(rele)| if p = m O$9§2W If f(z) is holomorphic, and hence harmonic, on D‘we adopt the notation Mp(r, f) = mp(r, f). For 0 < p S m, we define the Hardy p-classes: hp(D) = [u(z): u(z) is harmonic on D and sup m (r,u)<:m] O$r 0. Then f1(z) = f2(z) for each 2 E D (or De)' Motivated by this theorem we identify any two boundary functions which are equal for almost all ei9 G T. It is well known that every function in HP, p > O and every function in hq, q z I possess unique non- tangential boundary values for almost all e16 E T [14], 10 and that given the boundary function we can reconstruct the original function. For completeness we shall develop these facts here. For the most part we shall follow the develop- ment of Duren [5], Hoffman [13] and Priwalow [14]. The most natural place to begin this task seems to be with harmonic functions in classes hg, q a l and then to extend these results to the HP classes, even for O < p < 1. We begin with a very important harmonic function, the Poisson kernel, P(r,e). Definition 2.3: 2 4L l-r P(r,9) — 2%\l-2r cose + r2_)' 0 s r < 1, O s A 5 2R. We list some of the more important and well known pro- perties of the Poisson kernel. See, for example, Hille [12] or Hoffman [13]. Q (i) P0139) = Z r n="w Inleine' for O s r < l and O s 9 S 2O with convergence of the series abso- lute on D, and uniform on compact subsets of D: (ii) P(r,e) > O, for O s r < l and any 9 E [0,2w]: 2W (iii) f P(r,e)de = 1, for any r e [0,1]; 0 (iv) For any real number a, O<€ < O, limsup [P(r,e)| = O. r4I'(fl>e Perhaps the most important property of the Poisson ker- nel is furnished by the following theorem.which says, among other things, that the Poisson kernel can be used to produce 11 a harmonic function on the disc, given an integrable function defined on the unit circle. Definition 2.4: If f(ele) is a LebeSgue integrable function of e on [0,2w] we define the Poisson integral of f to be 2w . I f(elt) P(r,q-t)dt. 0 If u(t) is a complex Baire measure on [0,2w], the Poisson integral of u is 2w ] P(r.e-t)du(t). 0 Theorem 2.2: [13, pp. 33-34] Let f be a complex-valued harmonic function on the open unit disc, and write fr(eiq) = f(reig), then (i) If 1 < p é m, then f is the Poisson integral of an Lp function on T if and only if f(reie) 6 n9. (ii) f is the Poisson integral of an integrable func- tion m on T if and only if the functions fr converge to m, as r41", in the L1 norm. 12 (iii) f is the Poisson integral of a continuous func- tion on the unit circle if and only if the func- tions fr converge uniformly. (iv) f is the Poisson integral of a finite complex Baire measure on the unit circle if and only if f e hl. (v) f is the Poisson integral of a finite positive Baire measure if and only if f is non-negative. Theorem 2.3: (Fatou's Theorem) [13, p. 34] Let u be a finite com- plex Baire measure on the unit circle and let f be the harmonic function on D defined by i9 2W f(re ) = f P(r,e-t)du(t). 0 Let 90 be any point where u is differentiable with re- spect to Lebesgue measure. Then lim f(releo) = u’(O ). r41' 0 18 and in fact lim f(re 19 ) = u’(eo) as the point z = re approaches eieo along any path in the open unit disc which is not tangent to the unit circle. There is much contained in these theorems. First of all we wish to point out that Theorem 2.2 (iv) says that any function u(z) E h1 can be represented as the Poisson inte- gral of a finite Baire measure u on the unit circle T. 13 Theorem 2.3 says that u(z) = u(rele) 4 u’(eo) as z = re16 4 e190 non-tangentially for almost all eo€E[O,2O]. When no confusion can result, we will denote the boundary 1 by the function u(ele) where it 6 values of u(rele) E h is to be understood that u(e1 ) is unique up to sets of Lebesgue measure zero on [0,2w]. We also note that since hp c h1 for p a 1, every function u(z) 6 hp, p g 1 has non-tangential boundary values almost everywhere on T. The same is true for H1 as H1 c h1 and thus for Hp, p g 1 since HP c H1 when- ever p (IV 1. Also it is a corollary to the proof of Theorems 2.2 and 2.3 that for 1 < p s a if f(z) e hp with boundary function f(eie), then f(z) is the Poisson integral of f(eie) [13]. This is not true in hl, but it is still true for H1. [26]. We shall need some results for the classes HP, 0 < p < 1 which are not true for the corresponding hp classes, but one of the classical methods of deriving these results is to obtain them from the results true for Hp or hp, 1 < p g a. To this end we state the Nevanlinna Theorem. Theorem 2.4: [5], [15] A function f(z) holomorphic on D is in class N if and only if f(z) is the quotient of two func- tions from H”. (We do not allow the function in the denomi- nator of the quotient to be the zero function.) 14 Since every function in HQ has non-tangential boundary values almost everywhere on T, Theorem 2.4 suggests the same may be true for all of class N. However, the possibility that the numerator and denominator functions from Theorem 2.4 could both have boundary value zero creates a problem. For- tunately the class N is a class of "well behaved" functions as the next theorem shows. First we state a Lemma. Lemma 2.5: (Jensen's Formula) [12, II, p. 189] If m(z) is holo- 2W - morphic on D, then I lnlcp(re19)|de increases monotoni- O cally with r, O s r < l and 1 2R i6 PEI 1“ [Wm H59 = 1n Ico(0)| + Z(co.r). 0 where Z(m,r) = 2 1n ——', with [rn]0° n=O the sequence of modulae of the zeros of m repeated according to multi- plicity. Now we can proceed. Theorem 2.6: [5], [14] If f(z) E N, then f(z) has non-tangential limit f(eie) almost everywhere. Furthermore, ln|f(eie)| is integrable unless f(z) E O and f(z) 6 Hp for any p > 0 implies that f(ele) 6 LP. 15 Proof: Because of the importance of this theorem we include the proof as found in Duren [5]. Let f(z) E N be given. Assume f(z) # 0. By Theorem 2.4 there exist two functions u(z), 6(2) 6 HCO such that f(z) =-QLEL , for each 2 E D. 6(2) Without loss of generality we assume that Ha” a g l and that ”B” m s 1 since if Ha” w > 1 or ”6“ a > 1 we H H H could replace u(z) and 6(2) respectively by a'(Z) = max {lla1]:.H,.HBH and 6"“ max (Hall: ”min, which are well defined since ”6” w+ O and which satisfy H HA (i) “01’” a 1 and 115’” w— H and .. _ g’(z) (11) f(z) — B,(z) . Now by Theorem 2.3 u(z) and 6(2) have non-tangential limits u(ele) and 6(ele) respectively almost everywhere. Noting that -Jxa|a(re19)| O and that ”V -ln|a(eie)| a.e. g -[-1n|an ,- H L We comment that Theorem 2.11 is a stronger result for Hp than Theorem 2.2 (i). For 1 < p < m the conclusions are the same. For 0 < p < 1, Theorem 2.11 tells us that fr(e19) = f(rele) E Hp converges in Lp norm to the bound- ary function f(ele), while for O < p < m an hp func- tion need not have non-tangential boundary values. We now wish to characterize the class of all boundary functions of Hp. Definition 2.6: Let ©p(D) = 6p denote the set of all boundary functions f(eie) of functions f(z) 6 HP, 0 < p g m. We note that by Theorem 2.6 hp c LP, 0 < p E a. Since the HP classes are linear spaces, it is clear that Op is a linear manifold in LP. Also hp must contain all polynomials in elne, n a O, that is, functions of the N . 1k . . form k2 ake 9 since each Hp class contains the polynomials =0 § k az k=0 k 20 Lemma 2.12: [5] If f(z) 6 HP, 0 < p < m, then P 1 1/ lf 0 be given. Choose N so that if m,n, g N, an(z) - fm(2)H < e. Let r 6 (0,1) be fixed and m a N be fixed. 2R . . p 2W . . [ |f(rele) - f (rele)| d9 = lim I If (rele) - f (rele)[pde . m n m 0 k4m (D k HA r]. since fn (z) converges uniformly to f(z) on [2:Izl k Now 27T- ' I p 27” O D P 9 -—7- lim I Ifn (rel ) - fm(re19)| d9 s 11m [ lfk(rele) - fm(re19)|de. k-oco O k 4m 0 But since m a N, 2R - . lim [ lfk(re19) - f (rele)|pde g ep.2w km» '0 m Hence 2W . . p [ [f(rele) - f [(re19)| d9 < ep.2n .O m Now by Fatou's lemma [15], letting r41- we obtain 2w . . I If 0 was arbitrary, . '9 ie 11m ||f(el ) - f (e )H 4 0 III-Om m Lp 22 Hence f(eie) = m(eie) a.e. Thus 6p is closed in LP. It remains to be shown that the polynomials are dense in 6p. Let f(z) 6 HP and e > 0 be given. Choose an R, O < R < 1 so that ”f(Reie) - f(eie)H p < 3&4. We can pick such an R by Theorem 2.11. Let Sn(:) denote the nEh partial sum of the Taylor series of f about the origin. 0n the compact set [2: [z] s R < l], sn(z) converges uni- formly to f(z) so pick N such that n a N implies that sup [f(z) - sn(z)| < 9%-. [ZISR Define p(eie), a polynomial in ei6 by p(eie) = sn(Rele). Now ||p(e19) - f(elg)” p s Mme”) - f(Re19)+ f(Rele) - f(ele)“ p L L < 19 _ i9 i9 _ i6 -_2[Hp(e ) f(Re )HLp + ”f(Re ) f(e )HLpJ <2-e/4+2-€/4 Since a > 0 was arbitrary we have shown that the polynom- ials in e19 are dense in SP. We comment that Theorems 2.11 and 2.13 enable us to define a linear isometry between Hp and 6p, namely, the 23 correspondence between a boundary function in 6p and the holomorphic function in Hp, 0 < p < m. 2. The J Operator In Chapter III we will need to know something about the relationship between functions holomorphic inside the unit disc and functions holomorphic on the complement (with respect to the Riemann Sphere) of the closed unit disc. The method which we will employ was chosen primarily to simplify notation. ‘Qefinition 2.7: Let f(z) be holomorphic on D. We define HA 8 § (Jf)(2) = f(l/Z) for 1 < |z| 1 where we adopt the convention that -; = 0. If f(z) is holomorphic on De' we define (J-lf)(z) = f(g) for 0 g |z| < l, with the convention '% = a. We point out that if f(z) is holomorphic in D with on Taylor series about the origin f(z) = Z anzn, then n=0 - -n a z . on (Jf) (2) = n ll M8 If g(z) is holomorphic on De with Laurent series g(z) = m -n 2 anz , then n 0 (J‘lg> 0 implies that f(ele) 6 LP. Proof: Let f(z) E N(De). Let h(z) 6 N(D) be such that (Jh)(z) = f(z) for any 2 with [2| > 1. Let h(ele) be the boundary function of h(z). Then f(z) has non- tangential boundary values f(ele) = h(ele) a.e. Also by Theorem 2.5, ln|h(ele)| is integrable and hence ln|h(elq)| = ln|f(ele)| is integrable unless h(z) E O, that is, f(z) s 0. Furthermore, f(z) E Hp(De) implies that h(z) E Hp(D). By Theorem 2.5, h(z) 6 HP(D) implies that h(elq) = f(ele) 6 LP. Definition 2.9: Let p be fixed, 0 < p s a. We define the class $p(De) to be the class of all boundary functions of func- tions in class Hp(D ). e 27 Theorem 2.12’: Let p be fixed, 0 < p < m. 69(De) is the Lp clo- sure of polynomials in éie. (Polynomials in e-19 means I O I I O _i linear combinations of non-negative integer powers of 1e 9). Proof: By Theorem 2.5’ we have bpwe) c Lp[0,2‘lT]. Since each polynomial in powers of e“16 is in ©p(De), it remains to be shown that ©p(De) is closed in Lp and that the poly- nomials in e—19 are dense in OP(De). Now from the defini- tion of the J operator and the discussion following that definition, @p(De) contains exactly those functions which are complex conjugates of functions in bp(D). By Theorem 2.12 ©p(D) is closed in Lp[0,2w] and hence hp(De) is also closed in LP. . ie . . in e are polynomials in Since complex conjugates of polynomials e-le, by Theorem 2.12 we can conclude that polynomials in e_19 are dense in ©p(De). 3. Conjugate Harmonic Functions If u(z) is harmonic on D, we say that a function v(z) harmonic on D is a harmonic conjugate of u(z) if and only if u(z) + iv(z) is holomorphic on D. Any given u(z) harmonic on D has many harmonic conjugates all differ- ing by constants. Definition 2.10: If u(z) is harmonic on D we say that v(z) is the normalized harmonic conjugate of u(z) if and only if v(z) is harmonic on D, v(O) = O and u(z) + iv(z) is holomor- phic on D. The problem with which we are concerned is the following: Given u(z) 6 hp can we claim that v(z), the normalized harmonic conjugate of u(z), is in any hp class? The question is answered in part by the following theorems. Theorem 2.14; [26, p. 253] (Theorem of Riesz) If u(z) is real val- ued, u(z) 6 hp, 1 < p < m, then v(z), the normalized harmonic conjugate of u(z) is in hp and there exists a constant AP depending only on p such that Hv(z)||hp s Apuu uhp. The Theorem of M. Riesz is false for p = l, a counter- example being the Poisson kernel [13]. In the case p = 1 we do have the following theorem. 28 29 Theorem 2,15: [5] or [26, p. 254] (Theorem of Kolomogrov) If u(z) is real valued and u(z) E hl, then v(z) the normalized harmonic conjugate of u(z) is in hp for any p 6 (0,1) and there exists a constant Bp depending only on p such that Hvuhp e spuuuh1. Harmonic functions are very closely related to Fourier series. We observe that if f(ele) 6 L1[0,2R], then for each integer n, 2W . '1 19 -in9 271 I0 f(e ) d9 — Cn exists, and Icnl 4 O as |n| 4 m; however, it is suffici- ent for our purposes to know the cn's are well defined and uniformly bounded. Definition 2.11: If f(elq) E L1[O,2R] we define the Fourier series of (D f to be the formal power series 2 cnelne, where n=-m 2R . . _ 1 19 -ine cn =‘5; £3 f(e )e dB, and we write ie ° f(e ) ~ 2 c e n n=-m ine 30 The complex number CD is called the Fourier coeffici- A ent of index n, and will be denoted by CD = f(n). Now the connections between Fourier series and harmonic functions with which we are concerned are the following: Theorems 2.16: If f(eie) E L1[O,2R] has the Fourier series 5 cneine, then u(z) = u(reie) = E cnr|nleine is harmonic EH-QD. n=—m Theorem 2.17: If u(eig) E L1[O,2R] has the Fourier series E cdeing, then, n='° . i9 2” it . . (i) u(re ) = fl) P(r,9-t) u(e )dt 15 harmonic on D; (ii) u(rei“) e hl; (iii) u(reie) = E cnrlnleine, 0 s r s l, 6 E [0,2R]; n=-m a (iv) g(z) =n§0 cnzn is holomorphic on D: (v) 9(2) 6 Hl/Z: and (vi) 9 § C u(eiq) , where C is a constant u RBI/2 u 1L1 independent of u(eie). Proof: (i) and (ii) are restatements of Theorem 2.2 (ii). Q . Since P(r,9) = 2 rlnlelngo we have by substitution 31 . 2w 0 . _ . u(rele) = I 2 rln'e1n(9 t)u(elt)dt. 0 n='°° Fix r, 0 S r < 1. Then, by uniform convergence, w rInIeine . U(e1t)dt = Z O n=-m n=-a 0 2” -int it e u J..27T E rInleinM-t) (e )dt m In] ine = Z r e C n="m n. Thus (iii) holds. Since [on] S ”u(eie)H g(z) is holomorphic on D. Ll, (v) will follow from (vi) To prove (vi) we treat the case where u(ele) is real valued first, and then extend to the complex valued case. Case I: 19) 9) is real . . i Assume u(e is real valued. Since u(e valued cn =‘E_ Let v be the normalized harmonic conju- gate of u(rele). Then 29(re19) = u(rele) + iv(re19 n' ) + co. Now for O < p < 1, Theorem 2.15 implies that sup __]__ 2TT ie p l/p sup J— 2'TT i9 33 .- n 33) 3...... .... We is _ ie = BpHu(re )th — BpHu(e )HLl. Since _.J- 2" 19 c0 — 2w £3 u(e )de, we also have ICOI S ”u(e16)H 1. Thus, if we fix r, 0 g r < 1. L - - “a . 32 2W 2W ' - ' ' l i. P l . P 3; £) |g(re q)| d9 S EEC) [u(rele) + iv(rele) + col de 2w . 2'IT . p g 31- |3<3319>IP39 + —1—- |v 0, then f(z) is uniquely determined by these boundary values. Now if there is a function f(z) meromor- phic on De' which also has non-tangential boundary values ‘f(eig) on the same set E c T with f(eie) = f(eie) then in some sense f(z) and ‘f(z) uniquely determine one anot- her. We formulate this in a more precise manner in the following definition [21]. Definition 2.14: If f(z) is meromorphic in D we say that f(z) is pseudocontinuable across T onto De if and only if the following hold: (1) f(z) has non-tangential boundary values f(eie) for almost all g e [0,2n], (ii) there exists a function f(z) meromorphic on De’ (iii) ‘f(z) has non-tangential boundary values ‘f(eie) for almost all 9 6 [0,2w], and (iv) he”) = f(eie) a.e. We remark that we have defined a pseudocontinuation across T onto De and in this definition we require that the pseudocontinuation be meromorphic on all of De' The 38 39 reason for requiring De to be the domain for a pseudocontin- uation for our purposes will be made clear in Chapter III. In general one could define a pseudocontinuation across a sub- arc of T (with positive one-dimensional Lebesgue measure) onto a subarc of De having the arc as part of its boundary. See Shapiro [21] for a discussion of Pseudocontinuations. We note that if f(z) is holomorphic on D and if f(z) can be continued analytically across T onto De 'with the continuation meromorphic on De' then the analytic continuation is a pseudocontinuation across T. A pseudocontinuation may exist even though the original function is nowhere analytically continuable [3] or [21], To see this we first consider inner functions. Theorem 2.20: [3] If f(z) is an inner function, then f(z) is pseudocontinuable across T. Proof: Let f(z) be an inner function, that is, [f(ele)| = l a.e. The function (Jf)(z) = f(£2) has boundary values f(ele) = f(ele) of modulus l for almost all e16 e T, hence f(ele) =‘lé=——a.e. Thus the function f(z) = -——1—-— Hana) . . (Jf) (Z) has boundary values f(elg) = f(ele) a.e. Finally, f(z) is holomorphic on De except at the zeros of (Jf)(z), that 40 is 'f(z) is meromorphic on De' We also note that if f(z) is a singular inner function (no zeros on D), then the pseudocontinuation f(z) is holomorphic on De. Theorem 2.21: [13, p. 68] If Su(z) is the singular inner function determined by the positive singular measure u, then S is analytically continuable everywhere in the complex plane except at those points which are in the closed support of LL The function Su (or even ISuI) is not continuable from the interior of the disc to any point in the closed support Of u. Now take a measure n which is positive and singular with respect to Lebesgue measure on T and with the closed support of u all of T. The singular inner function Su(z) is pseudocontinuable across T onto De' the pseudo- continuation is holomorphic on De and Su(z) is not analy- tically continuable across any subarc of T onto any sub- domain of De' A question which arose when Shapiro [21] defined pseudocontinuations was: Are there any functions which do not admit a pseudocontinuation? The answer given by Shapiro was: The function M8 2n f(z) = 6:57 . M s 1. is not pseudocontinuable across any subarc of T. n=O 41 6. Continuous Linear Functionals on Hp. We shall have need of an integral representation of the continuous linear functionals on the HP classes. Definition 2.15: For 0 < p E a, a mapping @: Hp 4 C such that ¢(af + g) = a¢(f) + 2(9) for each a E C and f.g E Hp for which there exists a real number M satisfying sup |i> (f)I§M nfn pél H is called a bounded linear functional on HP. For 1 g p 5 m. HP is a Banach space,,and it is well known that a linear functional is bounded if and only if it is continuous. For 0 < p < 1, HP with the metric p(f,g) = Hf—ngp is a Frechet space as we have noted. It is known [6] tgat a linear functional on HP, 0 < p < l, is continuous in the Frechet space topology if and only if it is bounded. For 0 < p < a, we can regard HP as a subspace of Lp [0,2w] by identifying f(z) with the corresponding boundary function f(eie) E @p c Lp. For 1 s p < a this approach is quite fruitful for considering the continuous linear functionals on Hp since DP is a closed subspace 42 of Lp and for l s p the spaces Lp have many continuous linear functionals. In the case 0 < p < 1, however, only the zero functional is continuous on Lp [6] while for Hp we still have enough continuous linear functionals to sepa- rate the points. Theorem 2.22: [22] If ¢ is a continuous linear functional on HP, 1 < p < m, then there exists a function 9(2) 6 HQ, q = 59$. such that 2 o o @(f) = jL-f ”f(ele)g(ele)de, for each f 6 HP, "' o and conversely, each 9 6 H9 so defines a continuous linear functional on HP. We restate this theorem in a form which we will find more useful. Theorem 2.23: If ¢ is a continuous linear functional on HP, 1 < p < m, then there exists a function 6(2) 6 Hq(De), _ .2. q — p-l , such that __L 4)“) — 27T IO 2w . . f(ele)G(e19)de, for each f 6 HP and conversely each G e H9(De) so defines a continuous linear functional on Hp. 43 ££22£= Hg(De) was defined in terms of the J operator on Hq(D). Given p e (Hp)*, take the g(z) E Hg(D) guaranteed to exist by Theorem 2.22. Define G(z) = (Jg)(z). Then G(z) e Hg(De) and G(eie) = g(eie). Similarily for the converse. Theorem 2.24: If ¢ is a continuous linear functional on H1, then there exist two functions G(eie), g(z) such that (i) G(eie) 6 Lco [0,2w]; (ii) 9(2) 6 Hp, for any p < m; -..L 2W 19‘1“? , (111) ¢(f) — 2w I f(e )G(e )de. 0 2V . . (iv) ¢(f) = 1im_-§; I f(rele)g(e19)de: r41 0 and (v) if G(ele) has the Fourier series 2 cnelne, then a n=-m g(z) has the Taylor series chzn about the . n=O origin and g(ele) has the Fourier series Q o 2 Cne lne. n=0 We shall need to know something about the linear func- tionals on Hp for O < p < 1. We first define several classes of functions. J 44 Definition 2.16: [26, p. 42] Let A denote the class of functions holomorphic on D and continuous on the closed unit disc. Let f(ele) be defined for e E [0,2v]. We define the modulus of continuity of f by m(h7f) = sup [f(eit) - f(eis)| It-sl g h tl S 6 [0; 2”]. For f 6 A, we say that f 6 Ad (0 < a s 1) if and only if w(h;f(e19)) = (0(ha ) as h 4 o, and we say that f E A* if and only if ei(t+h)) - 2f(eit) + F(e i(t-h)” = 0(h). |f< uniformly in t as h 4 0. Theorem 2.21: [6] Let A 6 (Hp)*, O < p < 1. Then there is a unique function g E A such that 2W - _- (1) 9(f) = 119-§% ] f(re19)g(e 19)de. f 6 HP. r41 0 ..l. .1 _ ... (n-l) If n+1 < p < n (n—l,2, ), then 9 6 Ad' where _.l _ a — p n. (n-l) Conversely, for any 9 with g E Aa' the limit (1) 45 exists for all f E Hp and defines a functional 9 6 (HP)*. In the case p = -l- 9(n-1) E A*: and conversely, any 9 n+l' with g‘n—l) e A* defines through (1) a bounded linear functional on Hp. Corollary 2.2&: a 2“, then for n n 0 any fixed n (n = O,l,2,°-°), the mapping Pnf = an is a IIMS If f E Hp has Taylor series f(z) = bounded linear functional on Hp. This corollary implies that if we have a sequence of functions [fn] C HP (0 < p < l) with fn 4 O in Hp metric as n 4 m, then the Taylor coefficients converge to zero. We state this in a corollary. ‘Qorollary 2.27: Let p be fixed, 0 < p < 1. Let Mn]co c Hp. If n=l there exists a g 6 Hp such that an-gH p 4 O as n 4 m, H then if fn(z) = 2 an 2k, |z| < l, k=0 ’k and ” k g(z) = 2 bkz , |z| < l, k=0 then lim a = bk' for n = 1,2,3, n4co 'k CHAPTER III The Closure Problem for U* 1. Characterization Theorem. In this chapter we will present a characterization of the non-cyclic vectors for the left shift in the Hp Spaces, 1 g p < m. The main result of Douglas, Shapiro and Shields E3 is a characterization of the non-cyclic vectors in H2 for the left shift in terms of pseudocontinuations across T. The specific techniques used by Douglas, Shapiro and Shields involved identifying H2(D) with 12 (the space of all square summable sequences of complex numbers [an] with 2 2 ”[an}H 2 = E [an[2) and the dual space of L with itself. i There is little difficulty in extending their result to the Hp spaces, 1 < p < a. The extension to H1 is quite difficult due to several factors. First of all the dual space of H1 is not as neatly described as that of H2 or HP, 1 < p < a. Secondly, in the H1 case one has problems with sequences of L1 functions which converge in L“, O < u < l. but perhaps not in L1. This latter convergence causes prob- l lems as we will have a sequence of L functions for which the Fourier coefficients of index n = O, $1,12,--- converge 46 I. W. l 47 to zero but the sequence may only converge in the L1/2 metric. We will want to be able to conclude that the limit function is the zero function but we will need to use much of the structure of the Hp spaces as Fourier coefficients LP do not make much sense in the spaces when 0 < p < 1. We shall first state and prove the characterization theorem for Hp with l < p < a, basically repeating the methods of [3], but changing the notation. We recall that the left shift operator U* is defined by = f(z) - f(O) * (U f) (2) z * if and and that f(z) is said to be non-cyclic for U only if span [U*nf]:=0 is not dense in Hp. It is to be understood that when speaking of the left shift operator one has a fixed space (p) in mind. In the proofs of Theorems 3.3 and 3.4 we will need some relatively straightforward results whose proofs are simply computations. In order to keep the notation somewhat reason- able we state these results in the form of two Lemmas. Lemma 3.1: Let H(z) e Hp(De), l s p s a have boundary values H(ele). Then 9 (n) = O for n = +l,+2,°°-, that is, the positive Fourier coefficients of H(ele) vanish. 48 2322:: Since Hp(De) C H1(De) for l s p it is sufficient to prove the Lemma for H1(De). Let H(z) E H1(De) be given. Denote the boundary val- ues of H(z) by H(ele). Let c > 0 be given. By Theorem 2.12’ there exists a polynomial Q(z) such that T ”H(ele) — Q(e-lg)” 1 < e. Let n be any positive integer. L Now .-i A 2W - . l -1nA |H(n)l = lg; [ e 'H(e19)de| 0 2V . . . 1 -1n 1 -i = [3; f e e[H(e 9) - Q(e eflkel 0 2V . . l 1 — .5 g [me E’) - Q(e 16)Ide O = “H(e”) — Q(e-19)“ 1 < e. L A Since 6 > O was arbitrary, H(n) = 0. Lemma 3.2: Let G(ele) and g(ele) be any two non-zero functions . 2 . . . 19 ".8. ing in L [0,2w] With Fourier series G(e ) ~1 2 (n)e i9 ” 4 ing n=_m a and g(e ) ~ 2 g(n)e respectively. Let G(n) = g(n), n=-w . for n = -l,-2,--:. Let f(z) = f(rele) be a holomorphic function on D. For each value of r, O s r < 1 define hr 1. Define a continuous linear functional ¢ on HP by 2w ¢(k) = :%-f k(ele)H(eie)de, for any k(z) 6 HP. 0 where k(ele) and H(ele) denote the boundary functions of k(z) and H(z) respectively. Now by Theorem 2.6 and Theorem 2.5’ we have k(ele) e Lp[0,2w] since k(z) 6 HP, and H(elq) 6 Lq[0,2w], for %'+ i = l, 51 since H(z) e H°°(De ) c: que). Thus by Theorem 2.23 ¢ is a continuous linear functional on HP. Observe that ¢ is not the zero functional since H(z) # 0. We claim that ¢ annihilates f and all of its left shifts. We proceed by induction. 27T . . 27T . _ 4L. 19 19 _.JL 18 ¢(f) — 2” f f(e )H(e )de — 27 f G(e )de. 0 0 since G(ele) = f(ele)H(ele) a.e. [0,2w]. . 277' . Now since G(z) E H1(De), lim [ZWG(re19)d9 = I G(e19)de, O r41- 0 2" 19 but ( G(re )d9 = G(m) = 0. Thus ¢(f) = 0. Let n be 0 a fixed non-negative integer. Assume that p((U*)kf) = O, for k = O,l,°°°,n. We wish to show that ¢((U*)n+1f) = O. * n n-l k Set K(z) = [(U ) f](z), p(z) = Z akz . Thus, k=0 an(z) = f(z) - p(z) or f(z) = an(z) + p(z). We must show that @(U*K) = 0. NOW 2n_- . . 4> 1. ' 1 By definition of Hq(De), we have G(z) e H9(De), G(ele) = g(ele) and G(ele) E L9[O,2w], where G(ele) is the bound- ary function of G(z). Now define (3.2) H(eie) = f(eie)G(ei9) a.e. By the Holder inequality [15] H(elg) E Ll[0,2w]. We claim that H(ele) E 91(De). This will follow from the hypothesis that f is non-cyclic for U* and a theorem of F. and M. Riesz. We first show that the non-negative Fourier coeffi- cients of H(ele) are all zeros. Now note that 2w . 2w . . 2w . . ] H(ele)d9 =]“ f(ele)G(ele)d9 =f f(e19)g(e19)d9 = 2w ¢(f) = o, O O O or H(O) = 0. We now show by induction that the positive Fourier coefficients of H are all zero. Let n be a non- negative integer and assume that 2 7r_. . I e1k9H(ele)de = O for k = O,l,°°°,n. O 55 zk. Recall that (U*n+lf)(z) = f(z)-p(z) O k zn+1 Also note that 19 19 19 -i(n+1)9 f)(e ) = [f(e ) - p(e )]e a.e. Now by hypothesis, 2’IT . . _. ——-.—- 0 = 4>(U*“+lf) = 517] we”) - p(ele) 1e l""'1"’<_:;(e19.)n mnf - fn 1 L L But by Theorem 2.11, “f(reig) - f(eig)H l 4 O as r41" . . L and thus Hk (e16) — k(elq)H 4 O as r4l‘. r L1 We now use the hypothesis that f is non-cyclic for U* to show that the non-negative Fourier coefficients of hr(e1q) converge to zero as r41- If we denote the Fourier coefficient of index n of i9 hr(e ) by hr(n), then . 1 2” 19 19 O = ¢(f) = 11m '5; I f(re )g(e )d9 r41’ 0 27 . = lim 5%] hr(ele)d9 r41' 0 = 11m fir(0) r41" 60 Next, 2W . . = ¢(U*f) = lim -§= ] (U*f)(re19)g(e19)d9 _ w r41 0 . 1 2” 19 -1 -1 i =lim Z—I [f(re )-f(0)]r e age %d9 — w r41 0 = lim_[-21—r1[:Treigf(reig)g(eie)d9 - r41 _ 2w _. . -§; r 1f(0)[) e leg(elq)d9] . -lA = 11m [r h (+1) - O] r4l’ r A l = hr(+) since by Theorem 2.24 and Lemma 3.2 the Fourier coefficient of index +1 of g(elg) is zero. We proceed by induction. Assume that lim hr (k) = O r41 for k = O,l,"',n-l. Set n-l . p(z) = 2 a 23 n=0 3 Then, by Theorem 2.19: n _ (U* fl(z) = f z n z , for O < |z' < 1. so that 2W '_‘_-_‘ o = ¢(U*“f) = lim 21] (U* nif)(re e)g(eigme r41- ! 1 ‘- : 61 2W . . _ _. . = lim 21i0[f(relg) - p(re19)]r ne lneg(emmg _ w r41 . l -n 2” -in9 19 19 1 -n 2” -in9 =11m-2-Erj'e f(re )g(e )-'§'T'Fr[e r41- 0 O p(re ol)g(e fide] -qin- -l . 2w . . -———r- = lim [r rlhr (n) -'§— 2 a ray el(J n)eg(ele)de] r4l- W j=0 j o =lim_[r"r1 hr(,n)]-O r41 since for j-n < 0, 2w . . -———r- l 1 - i EFJ‘ e (j n)eg(e 9)de 0 is a Fourier coefficient of positive index of g(ele) and thus is zero by Theorem 2.24. We have thus shown that O: limhr (n), for n=O,l,2, r41 We now restate the functions which we have defined and some of what we have shown about them. kr(ei9) f(reie)G(eie) hr(eie) f(rei 9i)g(e 6) For r fixed, 0 < r < l, 62 where convergence of the two series above is in the L sense. Thus, by the Riesz-Fischer Theorem [13] . —1A . A o k (e19) = z k (n)elne+ 2 k (n)e1ne r r r n--m n=0 and . -J_A . m A . h (e19) = 2 h (n)ein9+ Z hr(n)elne, r n=-m r n=0 again r is still fixed and convergence of each series is in the L2 sense, to an L2 function. Now by Lemma 3.2 we have fi(—)—1’§ 1 r n — r( n), for n — + ,+2,+3,'° Thus on A _ o 2 hr(-n)e 1n9 = Qr(-n)e-1ne a.e. n=l n "MB 1 Now we have shown that “kr(eie) - k(eie)H l 4 O as r4l‘, and by Theorem 2.17 for any fixed r, OL< r < l we have 1/2 H 2 Q (n)zn - 2 k(n)zn g k (e ) - k(e ) n=o r n=0 ”HI/2 H r N 1/2 L1 Now by the Riesz-Fischer Theorem [Hoffman, p.14], 2 Ikr(n)|2 < w. Hence by the Riesz-Fischer Theorem [Rud1n, “=0 °° A n 2 1/2 p. 332], we have ngo kr(n)z e H (D) c H (D) for O:sr< 1. then f is either cyclic or a rational function (and hence non-cyclic). Proof: By Theorem 3.6 rational functions are non-cyclic. If f(z) is non-cyclic and holomorphic in |z| < R. with R > 1, then the pseudocontinuation of f, f, is an analytic con- tinuation of f across T. Since f can be continued to be meromorphic on the Riemann Sphere, f is a rational function. 67 Theorem 3.9: [3] Let f and g be non-cyclic and h be cyclic for U*. Then f + g is non-cyclic and f+h is cyclic for U*. Furthermore, fg and €®3 are non-cyclic while fh and $41 are cyclic for U* insofar as any of these are in Hp, 1Sp