EARING IN CUPPING EXPERIMENTS RELATED TO ANISOTROPIC PLASTICITY THEORY . Thesis for the Degree of Ph. D. MICHIGAN STATE UNIVERSITY * ROBERT W. BUND 1969 “Thesis I LIB R A R Y MlCl‘ilgdu State University This is to certify that the thesis entitled Earing In Cupping Experiments Related To Anisotropic Plasticity Theory presented by Robert W. Bund has been accepted towards fulfillment of the requirements for Ph.D. degree in Mechanics Department of Metallurgy, Mechanics and Materials Science / , \ / l \ A j) .1 (I f" O ,1 k.) L C Li ( / v ‘ 5“ \J. 'Li‘t VVJ L“- Major professor \ Date August 13, 1969 0-169 J’- ABSTRACT EARING IN CUPPING EXPERIMENTS RELATED TO ANISOTROPIC PLASTICITY THEORY by Robert W. Bund During the operation of drawing a cylindrical cup from a flat, circular sheet—metal blank, undulations or ears are produced at the free edge. A study of the earing phenomenon was made from an experi- mental and a theoretical point-of-view. The general objective of this investigation was to study the earing phenomenon theoretically using plasticity theory, and then to compare the results of this theoretical analysis with the experimental results of cupping tests. The theo- retical analysis is an extension of the work of Chung and Swift, and of Hill. The General Electric 265 computer was used during the in- vestigation to facilitate the computations. Commercially-produced, aluminum—killed steel sheet was used to produce blanks (4.800 inch diameter by 0.035 inch thick) for the cupping eXperiments. A polar-grid pattern was imprinted on the flat blanks by the electrochemical etching method to eXperimentally de- termine strain at nine successive stages of partial draws. Polyethy- lene film was used as a lubricant during the draw operation to preserve the polar-grid pattern. The double-action draw die.used in the ex- periments was actuated by a single-action, straight-sided mechanical press equipped with a pneumatic die cushion. The theoretical study used Hill's anisotropic yield function to introduce anisotropy into the plane stress analysis. The direct Robert W. Bund method was used to determine the anisotropic parameters by directly measuring the yield stress at selected orientations. The indirect method (strain-ratio method) was used as a check on the direct method. Plastic potential theory was used to derive the stress, strain- increment equations from the anisotrOpic yield equation. A rigid work-hardening material was assumed since the elastic strains were considered negligible compared to the plastic strains. Strain hardening was introduced into the theoretical study by means of the three-parameter Ludwik stress-strain relation. It was assumed that hardening causes the anisotropic yield ellipse to enlarge without changing its shape (isotrOpic hardening) while pre— serving its initial anisotropy. As a result of the investigation, it was found that the theo- retical analysis did predict strain fields of the type associated with the 0° and 90° earing which occurred during the experimental study. However the radial strain field from the theoretical analysis for the 0° and 45° directions indicated strains smaller in magnitude than occurred during the experimental cupping. It is believed that better agreement could be obtained by using the indirect method to determine the anisotropic parameters. Since both theoretical and experimental results of this investigation indicate prOportional straining, a total strain theory could be used to replace the incremental theory used in the investigation. EARING IN CUPPING EXPERIMENTS RELATED TO ANISOTROPIC PLASTICITY THEORY By Robert W. Bund A THESIS Submitted to Michigan State University in partial fulfillment of the requirements for the degree of DOCTOR OF PHILOSOPHY Department of Metallurgy, Mechanics and Materials Science 1969 ACKNOWLEDGEMENTS To the many people who have helped and encouraged me, particularly to Professor L. E. Malvern for his valuable counsel throughout the study, and to the members of my guidance committee, Professors T. Triffet, G. E. Mase and R. H. Wasserman. Fifteen months of advanced graduate studies were made possible by a National Science Foundation Science Faculty Fellowship. ii TABLE OF CONTENTS LIST OF TABLES O O O O O O O O O O O O O O O I O O O 0 LIST OF FIGURES O O I O O C O O O O I O O O O O O O O I. II. III. INTRODUCT I ON 0 O O O O O O O O O 0 O O O O O O 1. Preliminary Remarks . . . . . . . . . . l. l. weer- Of H. W. SWift O O O O O O O O O I O O 1.4 The Contribution of H. W. Swift an Others to IsotrOpic Cup-Drawing Research . . . . 1.5 More Recent Research Pertaining to Measures of Anisotropy O I O O O O O O O O O O O O 1.6 Recent Research Pertaining to the Cup-Drawing Process for AnisotrOpic Metals . . . . 1.7 The Present Investigation . . . . . . . Some Early Studies Pertaining to AnisotrOpy Studies of the Cup-Drawing Process up-to-the EXPERIMENTAL DETERMINATION OF THE TENSILE AND SHEAR YIELD STRENGTHS O I O O O O O O O O O O O O O O I 0 Preliminary Remarks . . . . . . . . . . Theory 0 O O O O O 0 O O O O O C O I O O NNN WNH stress 0 O O O I O O O I O O O O I O C 2.4 Experimental Determination of th Tensile Yield Stress as a Function of Orientation . THE DERIVED ANISOTROPIC YIELD FUNCTION . . . . Preliminary Remarks . . . . . . . . . . Computation of the Shear Parameter N . . 3 1 3 2 3 3 Computation of the Tensile Parameters F, 3.4 An Appraisal of the Computed AnisotrOpic 3 5 3 6 Fourth Quadrant . . . . . . . . . . . iii C, an Parameters Transformation of the Anisotropic Yield Function . A Linear Approximation to the Yield Function in the Experimental Determination of th Shear Yield H. Page vi 10 14 16 18 18 19 .22 23 31 31 32 32 36 43 48 Page IV. EXPERIMENTAL DETERMINATION OF THE STRAIN-HARDENING BEHAVIOR I I I I I I I I I I I I I I I I I I I I I I I I 56 4.1 Preliminary Remarks . . . . . . . . . . . . . . . 56 4.2 The Strain-Hardening Assumption . . . . . . . . . 58 4.3 Tensile Test Procedures . . . . . . . . . . . . . 66 4.4 Ludwik's Three-Parameter Stress-Strain Equation . 69 V. THEORETICAL ANALYSIS OF THE CUP-DRAWING PROCESS . . . . 74 5.1 Preliminary Remarks . . . . . . . . . . . . . . . 74 5.2 The Yield Condition . . . . . . . . . . . . . 78 5.3 Stress Analysis Theory for the Flange . . . . . . 82 5.4 Strain Analysis Theory for the Flange . . . . . . 87 5.5 Stress and Strain Analysis for a Rim Element . . 91 5.6 Stress and Strain Analysis for Interior Elements. 94 5 I 7 Results I I I I I I I I I I I I I I I I I I I I I 101 VI 0 CUP-DRAWING EXPERIMENTS o o o o o o o o o o o o o o o o 114 6.1 Preliminary Remarks . . . . . . . . . . . . . . 114 6.2 Producing a Polar Grid Pattern on Sheet-Metal Blanks I I I I I I I I I I I I I I I I I I I I 115 6.3 Measurement of Grid Spacing . . . . . . . . . . 117 6.4 Experimental Cup Drawing ... . . . . . . . . . . 121 6.5 Procedures Used to Compute Strain from Experimental Data . . . . . . . . . . . . . . . 123 6 I 6 ReSUItS I I I I I I I I I I I I I I I I I I I I I 131 VII. SUMMARY AND CONCLUSIONS . . . . . . . . . . . . . . . . 141 7.1 Preliminary Remarks . . . . . . . . . . . . . . . 141 7.2 Comparison of the Theoretical Strain Field with the Experimentally-Determined Strain Field . . 141 7.3 Conclusions and Recommendations . . . . . . . . . 143 MPEND Ix I I I I I I I I I I I I I I I I I I I I I I I I I I I 14 7 BIBLIOGRAPHY I I I I I I I I I I I I I I I I I I I I I I I I 151 iv Table 203“]. 2.4-1 304-1 305-1 306-1 306-2 306-3 4.3-1 501-1 5.5-1 5.6-1 5.7-1 5.7—2 6.5—1 6.5—2 6.6-1 LIST OF TABLES Single-Shear Test Results . . . . . . . . . . . Summary Results of the Tensile Yield Stress Deteminat ion I I I I I I I I I I I I I I I I I SIGPLT Computer Program Output . . . . . . . . Computer Output for YIELD Program at a - 0° . . YIELD3 Computer Program Output for a - 0° . . . Computer Output from Standard POLFIT Program for a - 0° I I I I I I I I I I I I I I I I I I I I Linearized Anisotropic Yield Equations for Five Orientations . . . . . . . . . . . . . . . . . . Computer Output from the TENSIL Computer Program for Three Coupons at a - 0° . . . . . . . . . . . . Notation for Chapter 5 . . . . . . . . . . . . . Partial Computer Output for the Stress and Strain Analysis of a Rim Element at a = 0° . . . . . . Partial Computer Output for ANI C7 . . . . . . . The Effect of Increment Size on the Computed Rim Thickness for a = 0° . . . . . . . . . . . . . . Computed Strain Ratios for the Rim Element vs. Rim POSition I I I I I I I I I I I I I I I I I I Typical Computer Programs for Radial Data . . . Computer Print-Out for Radial Strains . . . . . Computer Print—Out for Tangential Strain-Draw Number 1 I I I I I I I I I I I I I I I I I I I I Page 26 30 37 45 52 53 54 68 77 97 102 103 108 129 130 134 Figure 101-1 101-2 2.3—1 2.3—2 3.4-1 3.5-1 3.5-2 3.6—1 4.4-1 5.2-1 5.3-1 5.3-2 505-1 5.5-2 5.6—1 5.7—1 5.7—2 507-3 .5.7—4 LIST OF FIGURES Cross Section of Draw Die Showing Partially-Drawn Cup Sketch of a Partially-Drawn Cup with Ears in the 0° and 90° POSit ions I I I I I I I I I I I I I I I I I I Half-Size Layout of the Single-Shear Test Coupon . . . Definition of Yield Stress . . . . . . . . . . . . . . Best—Fit Curve for Tensile Strength vs Orientation . . Definitions for Transformation of Axes . . . . . . . . AnisotrOpic Yield Function for a = 0° . . . . . . . . . Transformation of Axes in or, 0 Stress Space . . . . . 9 Effective Stress-Strain Plot for Three Orientations . . Yield Conditions for the Isotropic Case . . . . . . . . Notation Used in Force Equilibrium for a Flange Element Terminology for a Partially-Drawn Cup . . . . . . . . . Flow Chart for the Stress and Strain Analysis of a Rim Element I I I I I I I I I I I I I I I I I I I I I I I Computer Program for the Stress and Strain Analysis of a Rim Element at a 3 0° I I I I I I I I I I I I I I I Flow Chart for the Stress and Strain Analysis of an Interior Element . . . . . . . . . . . . . . . . . . Computed Strain History of a Rim Element at a = 0° During the Cupping Operation . . . . . . . . . . . . Comparison of Computed Rim Thickness at a = 0° and a = 45° I I I I I I I I I I I I I I I I I I I I I I I Comparison of Computed Rim Radial Strain at a = 0° and a = 45° I I I I I I I I I I I I I I I I I I I I I Computed Thickness Strain for Flange Elements at a = 0° I I I I I I I I I I I I I I I I I I I I I I vi Page 24 25 38 46 47 49 73 79 83 86 95 96 100 104 105 106 109 Figure Page 5.7-5 Computed Thickness Strain for Flange Elements at a = 45° ' o o o e e o o o o o o o o o o o o o o o e 110 5.7-6 Computed Radial Strain for Flange Elements at a 3 0° I I I I I I I I I I I I I I I I I I I I I I 111 5.7—7 Computed Radial Strain for Flange Elements at a = 45° . . . . . . . . . . . . . . . . . . . . . 112 5.7-8 Computed Circumferential Strain for Flange Elements . 113 6.5—1 Flow Chart for Chord Program . . . . . . . . . . . .. 125 6.5-2 Chord Program . . . . . . . . . . . . . . . . . . . . 126 6.5-3 Flow Chart for Radial Program . . . . . . . . . . . . 127 6.5-4 Radial Program . . . . . . . . . . . . . . . . . . . 128 6.6-1 Experimental Radial Strain for Flange Elements at a . 0° I I I I I I I I I I I I I I I I ’ I I I I I 135 6.6-2 Experimental Circumferential Strain for Flange Elements at a = 0° I I I I I I I I I I I I I I I I 136 6.6-3 Experimental Radial Strain for Flange Elements at a a 45° I I I I I I I I I I I I I I I I I I I I I 137 6.6-4 Experimental Circumferential Strain for Flange Elements at a 8 45° . . . . . . . . . . . . . . . . 138 6.6—5 Depth of Draw vs. Rim Position . . . . . . . . . . . 139 6.6—6 Experimental Strain Ratios vs. Draw Number for the Element r0 = 2 I 35 I I I I I I I I I I I I I I I I 140 7.2-1 Comparison of Theoretical and Experimentally- Determined Circumferential Rim Strains . . . . . . 145 7.2-2 Comparison of Theoretical to Experimentally- Determined Radial Rim Strains . . . . . . . . . . . 146 vii I. INTRODUCTION 1.1 Preliminary Remarks The drawing process, by which a flat circular blank is trans- formed into a cup, has been studied by many investigators since the beginning of the twentieth century. Several of these studies will be reviewed in Sections 1.3 to 1.6. Some of these investigations were metallurgically oriented, while others were based on solid mechanics and continuum theory; some were experimental while others were ana- lytical, and many were combined experimental and analytical studies. The cup-drawing process is illustrated in Figure 1.1-1. Earing is the name given to the development of waviness or undulations at the free edge of a cylindrical cup which has been drawn from a flat circular blank; this is illustrated in Figure 1.1-2. Be- cause of the greater trim allowance required, a larger blank is needed to produce a certain size cup from sheet stock which develops ears than from sheet stock which does not ear during the draw operation. The expense of this trimming operation has encouraged research on the ear- ing phenomenon, resulting in hundreds of publications during the past fifty years. One indication of the importance of this problem is that an earing test has recently been proposed to the industry [1, 49]. A good current review of the earing phenomenon and the associated liter— ature was published by Wright [53] in 1965. 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THE DERIVED ANISOTROPIC YIELD FUNCTION 3.1 Preliminary Remarks As discussed in section 2.1, it was decided to use the direct method to determine the tensile parameters F, G, and H, and the shear parameter N. The direct method implies that experimentally-determined initial yield stresses will be used to evaluate the four anisotropic parameters. These four parameters are needed for the plane stress specialization of the anisotropic yield function of Equation (2.1-2), repeated here for convenience. (G + H) 0‘2 - 2H0 o + (H + F)02 + 2er = 1 (3.1-1) x x y 7 xy It must be recognized that this equation is valid only when the x-, y-, and z-directions are the principal anisotrOpic axes as defined by Figure 1.1-2. Chapter two discussed the eXperimental procedures used to determine the initial shear yield stress To (corresponding to Txy), and the initial tensile yield stresses at nine selected values of "a" to the rolling direction. Chapter three further develops this anisotropic study. Section 3.2 discusses how the shear parameter N was calculated, and section 3.3 discusses the "least squares" pro- cedure used to determine the "best" values of the tensile parameters F, G, and H. A discussion of the indirect method (strain-ratio method) of computing the anisotropic parameters is presented in section 3.4 as a check on the direct method used in the investigation. 31 32 In section 3.5, the anisotropic yield equation is transformed for use at selected angles "a" to the rolling direction for elements in the flange of the partially-drawn cup. The straight line approx— imation to the anisotropic yield function in the fourth quadrant is found for a = 0° and a = 45° in section 3.6. 3.2 Computation of the Shear Parameter N The direct method was used to compute the shear parameter N. The average value of To, corresponding to Txy for the orientation of axes shown in Figure 1.1—2, was found to be 16,923 psi, as listed in Table 2.3-1. The anisotropic yield equation for the plane stress case was specialized for pure shear in Equation (2.2-7). With Equation (2.2-7) and the average value of To from Table 2.3-1, the value of the shear parameter N was computed as follows: N =-—l— = 1 = 1.745 x 10'9 (3.2-1) 2T3 2(16,923)2 Inasmuch as the load for initial shear yield, the thickness, and the shear length were each measured to three significant figures, the accuracy of the shear parameter N is also limited to three sig- nificant figures. 3.3 Computation of the Tensile Parameters F, G, and H An examination of the results of the tensile yield strength study, as reported in Table 2.4-1, clearly shows the problem associ- ated with the direct method of computing the tensile parameters: The tensile yield strength changes only a small amount with a change 33 in orientation. For this reason, Hill [27] page 321 in Chapter 12, suggests that a more sensitive measure of anisotrOpy is given by the strain-ratio method, which will be discussed in section 3.4. It is theoretically possible to compute F, G, and H by choosing any three orientations of tensile coupons and their corres- ponding initial yield stresses, as given in Table 2.4-1. As a pre— liminary method, this approach was tried. Three pairs of (a, 00) were inserted into Equation (2.2-6), which is repeated here for convenience. '3; = F sinza + G cosza + H + (2N - F — G — 4H) sinza cosza “ (3.3-1) Each pair resulted in one equation with three unknown parameters. The values of the three parameters were then computed using the three equations. However, the computed values of F, G, and H de- pended upon which three pairs, from Table 2.4-1, were used. Hence, it was decided to modify this approach. F, G, and H were determined in this investigation using the least squares method as described in section 5.6 of Wylie [78] be- ginning on page 175. Equation (3.3-1) was rewritten in the form: 2 '3: = F(sin a)1+ + G(cos a)“ + H(cos Za)2 + N $§lgL2E2—'. (3.3—2) 0 d Then, one term was transposed to get: 2 F(sin on)1+ + G(cos a)“ + H(cos 2002 = A. _ N(s:n 20) 0' . (3.3-3) 2 a 34 The least squares method consisted of setting up a difference equation by subtracting the right member of Equation (3.3—2) from the left member. This difference was called 5a. 1 N(sin 20:)2 — + . 02 2 a (3.3-4) 6a = F(sin a)“ + G(cos 01)l+ + H(cos 201)2 — Each pair (a, on), from Table 2.4-1, gave a difference equation which had to be minimized to get the "best" values of F, G, and H. This was done by first getting an error function "E" which was defined as the sum of the squared differences. E = Z (0“)2 0. 2 E = z [F(sin a)” + G(cos a)“ + H(cos 2(1)2 - £3-+ N(sin 2&1] a 0a (3.3-5) The error function was minimized in the usual way by setting the partial derivatives of the function, with respect to the three variables F, G, and H, each equal to zero. ——-= o ——-= o -—— = 0 (3.3—6) This resulted in three equations to solve for the three unknowns F, G, and H as follows: 2 0 = 2 (sin a)1+ [E(sin a)“ + G(cos a)” + H(COS 20)2 ' l;'+ N(sin 2a) ] 2 a 0a (3.3-7) 2 0 = 2 (cos a)” [F(sin a)” + G(cos a)1+ + H(cos 201)2 — gj'+ N(sin 20) ] a (3.3—8) 35 o. z 6.. 2620.... 6» + .6... w + m... 262 - O G a 2 These are three linear equations for the "best—fit" values of three unknown parameters, of the form 81F + b1G + ClH = d1 l O. N (3.3—10) a3F + b3G + c3H - I Q: m The coefficient evaluations were performed on the General Electric 265 Time-Sharing Computer System, using the FORTRAN lan- guage, to give 1.661F + 0.37350 + 1.176H 2.138 x 10"9 0.3735F + 1.6610 + 1.176H 2.224 x 10-9 (3.3-11) 1.176F + 1.1760 + 2.127s = 2.978 x 10-9 These simultaneous linear equations were then solved for F, G, and H using the standard library BASIC language computer program "SIMEQN" on the General Electric 265 Time-Sharing Computer. The "best" values were F = 6.94 x 10-10 0 = 7.60 x 10"10 (3.3-12) H = 5.96 x 10"10 As was the case with "N," the accuracy of the "best—fit" tensile parameters is limited to three significant figures. As the dis- cussion of Figure 3.4-1 in the following section indicates, the accuracy was actually less than this. ;L_+ N(sin 20:)2 J 36 3.4 An Appraisal of the Computed Anisotropic Parameters There are at least two ways to judge the reasonableness of the anisotropic parameters as computed by the direct method. One way is to plot Equation (3.3—l), using the computed values of F, G, and H, and to compare this curve with the results of Table 2.4-1 plotted on the same graph. A second way is to use the indirect method, as described in Chapter 12 of Hill [27], to compute F, G, and H from a few tests assuming that N = 1.745 x 10—9 as found in section 3.2.. Both of these checks were made and are discussed in this section. Equation (3.3-l) gives 0a = [F sin2 a + G coszci-Fli+(2N - F - G - 4H) sin2 a cos2 01]-1 (3.4-l) With the values of N, F, G, and H from Equations (3.2—l) and (3.3-12) a simple program in the BASIC language was used to compute values of "0" at five-degree intervals of "a." The resulting computer output is presented in Table 3.4-1 and plotted in Figure 3.4-1 along with the nine average values of the experimental data from Table 2.4-1. From Figure 3.4-1, it is evident that the ex— perimental data required a lot of "smoothing out" during the "least squares" procedure. The indirect method of computing the anisotrOpic parameters requires a consideration of the plastic potential theory as proposed by Mises [8, 9], and as given by Hill [27, 55] for the anisotropic case. A rigid, work-hardening material is assumed; hence the plastic strain increment is the total strain increment. Plastic potential III I." l.IIIIKI.|¢¢| In. ll. l1. 1| [i lll' [11' .l III III 37 theory assumes that the stress, strain-increment relation is de- rivable from the yield function f(oi ) by the relationship 3 d6., = d1 3f (3.442) 13 30.. 13 where f(oi ) is defined by Equation (2.1-2) repeated here for con- 1 venience: Table 3.4—1 SIGPLT Computer Program Output SIGPLT A3 O 58 2714683 A3 5- 53 2717788 A' 108 53 2726986 A3 158 53 2741386 A3 208 33 2759688 A3 250 S8 2780189 _ A: 30; 5= 2800888 A3 358 58 2819684 A3 408 5: 2834587 A: as. s= 28442.3 A- so. 5: 2847887 A8 558 $3 284568 A. 608 = 2838381 A8 658 53 2827581 A8 708 53 2815088: A: 755 53 2802987 A: 808 , = 2792982 A= 858 53 2786381 A: 908 = 2784001 TIME: 1 SECS. Tensile Yield Strength 28800 28600 gpll? 28400 Zi%, 3‘\eg;\\k 28200 \q 28000 p ‘E 27800 27600 //§;/( 27200 CD/ 27000 {u 0 10 20 30 40 50 60 70 80 90 Degrees to Roll Direction I DATA FROM TABLE 2.4—1 (Experimental) C) DATA FROM FIGURE 3.4-1 (Least Squares Fit) Figure 3.4-1 Best-Fit Curve for Tensile Strength versus Orientation 39 a ._ 2 _ 2 _ 2 2 2f(oi ) F(oy oz) + G(oz ox) + H(ox oy) + 2LTyz + J l ZMT2 + 2N12 . (3.4-3) zx xy Equations (3.4-2) and (3.4-3), give the following relationships: dex = dA[(G + H) ox - Hoy - Goz] day = dA[(H + F) oy - Foz — Hox] (3.4-4) dsz = dA[(F + G) 02 - Gox - Foy] de = dA[NT ] . xY xy It should be noted that dex + day + dez = 0, which is consistent with the assumption of a rigid, work-hardening material. For a tensile test coupon oriented in the x-direction, which is the direction of rolling, oy = oz = Txy = 0, and Equations (3.4—4) reduce to: dex = dA(G + H)ox, day = -dA(H) ox, ds 2 = -dA(G) ox. (3.4—5) The ratio of width to thickness strain increments for this test coupon at a = 0° then can be written: dsw dc H R0 33:: st = C— (3.4-6) 40 Similarly, a tensile test coupon oriented in the y-direction (a = 90°) gives the following ratio for width to thickness strain increments: H R90 - (1E - d8 = F . (3.4-7) H N For the more general case of a tensile test coupon oriented at the arbitrary angle "a" to the direction of rolling, the width strain increment must be found from the general strain transformation equation. deij = Eik Ejm dekm (3.4-8) Specializing Equation (3.4-8) for the width strain of a test coupon oriented at the angle "a" results in 2 de = de sinza + ds cos a - 2de sin 0 cos a (3.4-9) w x y xy to produce a ratio of width to thickness strain increment as follows: ds de sinza + de cosza - 2de sin 0 cos a w x y xy a I d;;— = ds (3.4-10) R 2 Equations (3.4-4) can be transformed to refer to a tensile H 1' coupon oriented at a to the direction of rolling by using stress transformation equations 2 o = 0 cos a a = 0 sin2 a T = 0 sin 0 cos 0 (3.4-11) x Y xY (where o is the uniaxial stress acting on the test coupon) to get the following stress strain increment relations: 41 dsx = dA[(G + H) 0 cos2 a — H s sin2 a] day = dA[(H + F) 0 sin2 a - H 0 cos2 0] (3.4-12) dsz = dA[—G 0 cos2 a - F 0 sin2 a] de a dA[N a sin n cos 0] xy When Equations (3.4-12) are inserted into Equation (3.4—10), the general strain ratio equation is obtained as follows: d6 = EEK , (3.4-13) t = H + (2N - F - G - 4H) sin2 0 cos2 a F sin2 a + G cos2 a R a which reduces to Equations (3.4-6) and (3.4-7) for the special cases of a = 0° and a = 90°. Tests by several investigators, including Bramley and Mellor [54, 77], Atkinson [2], and Lankford, Snyder and Bauscher [38] indicate that, for low carbon steel, the width to thickness strain ratio increments do not vary as the material strain hardens during the tensile tests. This fact permits the strain ratios to be com- puted at larger values of strains to get more accurate results and permits finite strains to be used in place of strain increments in equation (3.4-13). During experimental determination of the data required for strain-hardening information, discussed in Chapter 4, strain ratio data were obtained for three coupons, one coupon at a = 0°, one at a = 45°, and one at a - 90°. For the assumed volume constancy, the strain ratio R is given by [H Width Strain _ ln w Thickness Strain — 1 1w] ' n I‘0‘”0 R = (3.4-l4) 42 In Equation (3.4-l4), "w" is the current coupon width, and "2" is the current length between gage marks. Atkinson [2,3] recommends that the strain ratio should be measured just prior to necking, at a logarithmic length strain of about 0.20 for low carbon steel. From measurements of the coupons, after each had been strained approximately 20% in the length direction, the following strain ratios were determined: R0 = 1.63 8,5 = 1.22 R90 = 1.90 (3.4-15) Using these values of the experimental strain ratios and the value of N - 1.745 x 10-9 in Equation (3.4-l3), specialized for a - 0°, 45°, and 90° resulted in the following three equations: H R0 = 1.63 8'6 = H + (2N - F - G - 4H)(cos 45°)2(sin 45°)2 R“5 = 1'22 F(sin 45°)2 + G(cos 45°)2 (3°4_16) H R90 = 1.90 ='§ whose solution gave F = 4.68 x 10'10 0 = 5.46 x 10’10 (3.4-17) H = 8.90 x 10’10 These results are based on very limited data. They were calculated after the completion of the direct method calculations, which were used for the analysis of the problem. Since Equations (3.4-17) indicate greater anisotrOpy than the direct method Eq- uations (3.3-12), it may be that the indirect method would be more suitable to use in future research of this type. 43 3.5 Transformation of the Anisotropic Yield Function The shear parameter N was determined in section 3.2, and the tensile parameters F, G, and H were computed in section 3.3. With these values, the plane stress, anisotropic yield function of Equation (3.1-1) for the aluminum—killed steel used in this study is 13.5762 - 11.920 0 + 12.962 + 34.9:2 . 1010 (3.5-1) x xy y Ky Equation (3.5-1) applies only for the coordinate axes as defined in Figure 1.1-2. Stress transformation relationships must be used for other axes. During the cup-drawing process, the stress state for a = 0°, 0 - 45°, or a - 90°, where "a" is the angle to the direction of rolling, is: or 0 0.1 0km = 0 06 0 (3.5-2) 0 0 0 L _J since the radial and the tangential directions are principal dir— ections for a = 0°, a = 45°, and a = 90°, and a plane stress condition is assumed. The stress transformation equation 7 . _ oij likljmokm. (3.5 3) can be expanded as follows with the 0 components given by Equation km (3.5-2). 44 =2+2 Ox zxror £x8°e a 2 2 0y Eyror + £y0°8 (3.5-4) Txy = 2xrzyror + £xe£y8°0 With the definitions shown in Figure 1.1-2 and Figure 3.5-1, Equations (3.5-4) can be rewritten as: 2 2 0x - or cos a + 06 sin a o - a sin2 a + 0 cos2 a (3.5-5) Y r 0 Txy = (06 - or) sin n cos 0 Substituting these transformation equations into the aniso- trOpic yield function of Equation (3.5-l) results in the following equation: a: (13.57 cosu a + 22.98 sin2 a cos2 a + 12.9 sinus) + oroe(-ll.92 cos1+ a — 16.86 sin2 a cosza- 11.92 sin” a) + as (12.90 cosl+ a + 22.98 sin2 n cos2 a + 13.57 sin” a) = 1010. (3.5-6) This equation has the form of a quadratic in or 2 2_ 10= _ blor + (bzoe) or + (b3o 6 10 ) 0 (3.5 7) For a given angle "a," or can be found as a function of 06. For a particular "a," Equation (3.5-7) can be plotted as an ellipse in Or’ 0 stress plane to graphically show the yield function for 6 that orientation. Elements in the flange of a partially-drawn cup are subjected to a non-negative radial stress and a non-positive tangential stress; hence only the fourth quadrant of the or, 06 45 stress plane affects this investigation. Equation (3.5-7) was solved for or using the quadratic formula. The solution was obtained using the "YIELD" computer pro- gram. The computer output is listed in Table 3.5—1 for a = 0°. Figure 3.5-2 presents this data graphically for the fourth quadrant. Table 3.5—1 Computer Output for YIELD Program at a = 0° YIELD ANGLE IN DEGREES T0 RDLL DIRECTION: 0 813 13-57 B2=~11-92 B3= 12-9 13-57 51'2-11-92 51*52+ 12-9 52'2 = 1 TANGENTIAL + RADIAL - RADIAL YIELD 'YIELD YIELD STRESS STRESS STRESS -27842-3 5-39736 E-S -24456-9 -25058-1 5154-16 ~27165-4 ~22273-8 9217-07 -28782-6 '19489-6 12632-1 ~29751-9 ‘16705-4 15585-9 -30260- '13921-2 18177-2 ~30405-7 '11136-9 20464-8 -30247-6 '8352-69 22485-9 -29823. -5568-46 24264-3 -29155-7 -2784-23 25815- -28260-7 '5034058 E-S 2714603 '2714603 2784-23 28260-7 -25815- 5568046 '2915507 ‘2426403 8352-69 29823- -22485-9 11136-9 30247-6 -20464-8 13921-2 30405-7 -18177-2 16705-4 30260- -15585-9 19489-6 29751-9 -12632-1 22273-8 28782-6 -9217-07 2505801 2716504 '5154016 [27842.3 24456-9 -3-77815 E-4 46 90° a Rolling Direction N ll Transverse Direction “<2 11 Thickness Direction N l Radial Direction '1 II CD ll Tangential Direction Figure 3.5-1 Definitions for Transformation of Axes 47 °0 10,000 20,000 30,000 i 5 f1 -10,000 -20 ,000 // -30,000 Figure 3.5-2 Anisotropic Yield Function for a = 0° 48 3.6 A Linear Approximation to the Yield Function in the Fourth Quadrant The method used to find the "best" linear approximation to the yield function in the fourth quadrant for selected values of "a" will be discussed in conjunction with Figure 3.6-1. The first step was to rotate the axes through an angle 9, such that a straight line connecting points E and F in Figure 3.6-1 became horizontal. Then the least squares method was used to fit a straight line to the curve, after which the straight line was rotated back through the same angle 6. The necessity of rotating the axes before attempting a least squares fit became apparent after observing results without first rotating the axes. For a curve, symmetrical with respect to the line 0G (whose slope is -l) in Figure 3.6-1, the slope of the "best fit" line should be unity, but it is not. The usual least squares method, which involves minimizing squared vertical devia- tions at equal horizontal intervals, resulted in weighting that portion of the curve from F to C more heavily than the part from E to G. The rotation of axes method provided the necessary im- provement in results. The transformation equations for a rotation of axes counter- clockwise as shown in Figure 3.6-1 through an angle 0 are 0 0: cos 6 - 0* sin 0 r 6 = * * _ 00 or sin 6 + 06 cos 6 (3.6 l) 49 Yield Equation: A02 + Bo o + Co2 = D r r 6 6 121/E. 0) Yield Equation Graph Figure 3.6-1 Transformation of Axes in Or’ 0 Stress Space 0 50 After Equations (3.6-l) are inserted into the anisotropic yield equation of the form of (3.6-2) 2 2= _ Aor + Boroe + Coe D (3.6 2) The equation can be simplified to get (A sin2 0 - B sin 6 cos 6 + C cos2 0) 032 + {[(cos2 6 - sin2 6) B + 2 sin 6 cos 6(C - A)] 0:} 03 + [(A cos2 6 + B sinEBcos 6 + C sin2 6) 0:2 — D] = 0, (3.6-3) which is a quadratic in 03. In the notation of Equation (3.6-2), the coordinates of point E(\/§f, 0) are found by putting 06 = 0 in Equation (3.6-2). Similarly, by putting or = 0, the coord- inates of point F are found to be (0, -\/%:). By rotating axes through the angle 0, such that F _ Land 6 = arctan = arctan fg' (3.6-4) L- that portion of the yield ellipse (in the fourth quadrant) between {>IU E and F becomes horizontal relative to the rotated axes. The "YIELD 3" computer program, written in BASIC language, both rotates the axes to make points A and B horizontal, and then computes the coordinates of eleven points between A and B in the rotated coordinate system. The YIELD 3 computer program output for a = 0 is shown in Table 3.6-1. A standard library program written in BASIC language called POLFIT was used on the General Electric 265 computer to find the "best" linear equation to fit the eleven points using the least 51 squares technique. For the computer output at a = 0° from the YIELD 3 program, the "best fit" straight line had the equation a; = 4.495 x 10"+ a; - 21,500 (3.6-5) This is found on the computer output, Table 3.6-2 from the POLFIT program. The final step was to transform Equation (3.6-5) back to the original coordinate system. The vector transformation equa- tions used were 0* 0 cos 6 + 0 sin 6 r r 6 (3.6—6) * _ 06 or sin 6 + 06 cos 6 Inserting these vector transformation equations into the "best fit" linear equation with respect to the transformed axes, * = * _ oe Aor + B (3.6 7) results in the "best fit" linear equation with respect to the orig- inal or, o coordinate system. 6 6 [cos 6 - A sin 6 cs 6 - A sin a a 17‘- cos 6 + sin 610 +l: B J (3.6-8) r c 6 This calculation was accomplished using the BASIC language program ROTATE. 52 Table 3.6-1 YIELD 3 Computer Program Output for a = 0° N: 0798055 SINENJ= -716 CUSENJ= -6981 RAD STR CIR STR ’1993501 '1943607 '16046-5 '20729-2 '1215709 ‘2167609 ‘8269-31 -22325-9 '4380-72 '22703-1 “492-133 ‘22823-5 3396-46 -22692-4 7285-05 '22306-6 11173-6 -21653-9 15062-2' '20710-7 18950-8 ‘19436-7 53 mmmm-ml o_-Vmom a-om¢~mn hoomvm_u w-Ommm~ momme-m: mom-_wb o-mov_ml h-o~homt N-mcom_ mmmNVF- vvm-mm~l v-vmv_ml m-mmo~mu o-m>~_— mvosb-m wow-o_wl _-0mv_mn o-oommm: mo.mwm> mmomm-m mm-vm—_o m-hmv_mn v-NOQNNI ov-bmmm mhbm_-o m-mmm_a m-omv_mc m-mmwmmu MNH-NQVI m~owm-m mh-Homut m-_om_Nu _-mo~mml mh-owmvu Vvomw-m vow-Nch -mom_mu a-mmmmmu Hm-mmmml ~wooow- omo-m>~| w-QOWHN: m-ono_ml m-bm_m~c bovmw-mu Nam-hhb o-oomHN: m-mmhomu m-ovoo_l m_m©-mu Vo-_>om m-mom—NI h-omvm_u _-mmom_u ummouhom kkHQ DJGUI> 4<3h0du> JGDHU¢1K Vim oommv-v _ v-movumu o mv-mmm_ u y mam wh¢zmhmm k8 mammm ohm Hzmuommmmao . SKMH .wmzomc QZHQZMDmG ha Imama 2H m4<~?®2>4®m MIh mhuk ZNIH m2¢ uhuk mm SH JdutnszQm wwmuwc hwmraJ wIH >uuom1m ah mmmD m2844< 7¢mu®m1 .mhznam Jsm J¢Z®3®Ihxs Zc uzumj ngdo whdumd>mm Sh m4¢~2®2>4®1 mmrdUOMThmde mhmm £¢109wm mHIh hakmam no u o How Emuwoum Hquom vumvamum Eouw usauso Hmusmeoo Nlo.m mHan 54 The "best fit" linear equation with respect to the original 0 axes for a - 0° was ° 0 r, 06 I 1.027 0r - 30810 (3.6-9) Equation (3.6-9) can be generalized as follows: 0 = N0 - 0* (3.6-10) Equation (3.6-10) represents a linear approximation to the aniso- tropic yield condition where 0r 3_0 3_0 As the material strain 6. hardens, 0} will increase from its initial value 0: to its current value 0}. Table 3.6-3 shows the "best fit" linear initial yield equations for five orientations of the radial axis with respect to the direction of rolling. For the isotropic case, the "best fit" linear yield equation was computed to be 06 = or — 1.094 '50 (3.6-11) instead of the more commonly used equation 0r - 69 = 1.1 30 (3.6-12) Table 3.6-3 Linearized Anisotropic Yield Equations for Five Orientations 0 Initial Linear Yield Equation 0° 06 8 1.02656 0r — 30810. 30° 06 = 1.01369 0r - 31610. 45° 0 = 0 - 31720. 6 r 60° 06 = 0.98624 0r - 31180. 90° 06 = 0.97412 0r — 30010. 55 The theoretical analysis of cup-drawing in Chapter 5 will use these results along with experimentally determined strain— hardening behavior. IV. EXPERIMENTAL DETERMINATION OF THE STRAIN-HARDENING BEHAVIOR 4.1 Preliminary Remarks As an element in the flange moves inward during the cup- drawing Operation, it strain hardens. Strain hardening is indicated by an increase in the magnitude of the yield strength during con- tinued plastic deformation. There is no adequate theory available for anisotropic strain—hardening behavior. Because it was desired to include the effect of strain hardening in the investigation, some measure of strain hardening had to be found. Svensson [82] pointed out that three physical effects re- sult from plastic deformation: strain hardening, the Bauschinger effect, and the development of anisotropy. During the rolling mill Operations the sheet steel receives a process anneal which virtually eliminates the Bauschinger effect from the blanks prepared for the cupping operation. This implies that the initial yield stresses in tension and compression are equal for any coupon cut from the sheet. During the cupping operation the additional hardening might very well introduce a Bauschinger effect, so that subsequent test- ing would exhibit unequal tensile and compressive yield stresses. But since the stress components acting on a given element of the flange change monotonically (that is, no unloading occurs during the cup-drawing Operation), it was decided that the Bauschinger effect during the cupping operation would not be considered. In section 6.12 of his text, Fung [84] discussed several proposed hardening rules. Isotropic hardening assumes that the 56 57 yield surface in stress space enlarges as the material strain hardens while the shape of the original yield surface does not change. Isotropic hardening ignores the Bauschinger effect, where- as "kinematic hardening" as proposed by Prager [79] does not. As Hill [27], page 332, has pointed out, the problem of relating the parameters of an anisotrOpic yield function to the strain history is extremely complicated. Hill suggested a pro— cedure to follow in a metal which already has a pronounced pre— ferred orientation when further deformation to be considered is such that further changes in anisotropy are negligible. In effect this procedure assumes that in the further hardening, the yield surface enlarges without change of shape (as in isotrOpic harden- ing), but that it preserves the initial anisotropy. This procedure suggested by Hill is followed in this investigation, using Hill's definitions of effective stress and strain together with Ludwik's three-parameter stress-strain relation, as discussed by Hill [27] on page 12. This stress-strain relation is consistent with the assumption of a rigid, work—hardening material. The strain-hardening assumption is presented in section 4.2. Section 4.3 discusses the experimental details of the tensile testing, and section 4.4 presents the procedure used to determine the actual measure of strain hardening used in the investigation. Also presented in section 4.4 is some evidence that the procedure suggested by Hill was reasonable for describing the strain- hardening observations. 58 4.2 The Strain-Hardening Assumption IsotrOpic hardening is usually described by one of two methods. In either method, an effective stress 0'15 defined, a scalar measure of the intensity of the combined stress state, which may be interpreted as a characteristic dimension of the yield sur- face in stress space. Then in the postyield isotropic hardening under combined stress loading it is either assumed that 0'13 a function of the total plastic work Wp or alternatively that 0'13 a function of an accumulated effective plastic strain J'EE , wheremc-l:p is the "effective plastic strain increment." When the Mises yield condition is used, and the effective stress and plastic strain increment are defined as the two invariant expressions - -—- 3 = ' = - 1 ' _ 1/3J2 2 Oij Oij (4.2 l) p=\/%-depj deg , (4.2—2) where J' =-l 0' 0' is the second invariant of the stress deviator ijoij 0&1, the two alternative assumptions turn out to be equivalent, since then it can be shown that _ P - _'——P _ Wp - Joij deij — J 0 dc (4.2 3) is a single-valued function of [02'1 The procedure of this section, following Hill [27], pages 332-334, is analogous to the isotropic hardening procedure based on the Mises yield condition. An effective stress 0'15 defined, based 59 on the quadratic yield function of Chapter 3, in a manner anal— ogous to the way the isotropic 0'13 based on the quadratic in- variant Jé of the deviatoric stress. Since the anisotropic quad- ratic yield function is not an invariant, however, the formula given for 0 must always be evaluated with reference to the axes of ortho- trOpic symmetry, which are assumed to be unchanged during the further deformation process. An accumulated effective plastic strain will also be defined in such a way that Wp = J 0 0;. . In Chapter 3, the anisotrOpic parameters (F0, G0, H0, and No) for the initial yield function were determined. The subscript "O" is used here to designate initial values. Under the assumption that the state of anisotrOpy remains constant during the cup-drawing Operation, the yield stresses in the directions of the axes of symmetry will increase in strict proportion to a single parameter expressing the degree of strain hardening. If h = h(E) is a positive, monotonically- increasing parameter expressing the amount of strain hardening, a function of the effective strain E-to be defined below, starting at unity, then the current yield stress "X" in the rolling direction can be found by multiplying the initial yield stress "X0" in the rolling direction by "h." At the same instant, the current yield stress in the transverse direction is Y = h Y0, and the current yield stress in the thickness direction is Z = hZO. Following Hill [27], page 332, a representative stress 0'15 defined, which will also increase in strict proportion with h, that is 0'= h00. Using the known relationships between the anisotropic param- eters F, G, H, and N and the uniaxial yield stresses in the principal 60 anisotrOpic directions, one can find how these parameters change with strain hardening. For example 2F=_]_‘.+_]_'.__]_'.=_.l__+__1____l__ (4.2-4) 2 2 2 2 2 2 Y Z X (hYo) (hzo) (hXO) 2F = —-:- [—12- + ~17: - 42:] = f [200] (4.2-5) h Y0 20 x0 h F0 or F = —3' (4-2-6) h Similarly, the other anisotrOpic parameters decrease in strict proportion G=_, H:-———, N=—,_. (482-7) The anisotrOpic yield function, as prOposed by Hill, is = _ 2 _ 2 _ 2 2 2 2f(0ij) F(0y oz) + G(0z 0x) + H(ox 0y) + 2LTyz + 2M1zx 2 _ 2N1xy. (4.2 8) The yield condition continues to be 2f(0 ) = l (4.2-9) 151 after deformation, with the increased yield stresses accounted for by the decreasing anisotropic parameters. For the isotrOpic case 0.1s the square root of the quad- ratic yield function, multiplied by a numerical factor so that it reduces to the usual uniaxial yield stress in the case of uniaxial loading. For uniaxial loading in the x, y, or 2 directions, the + 61 anisotropic quadratic yield function 2f(01j) reduces to (0 + H)x2 = 2f(0ij) (H + F)Y2 = 2f(01j) (4.2-10) (F + 0)z2 - 2f(Oij) . Evidently it is not possible to multiply the quadratic yield function by a single numerical factor so that it would in each case reduce to the square of the uniaxial yield stress. A compromise representative dimension 0-of the yield surface is defined by replacing X, Y, and Z, reSpectively by 0'in Equations (4.2-10) and averaging the three to obtain £(F+G+H)02=2f(0 3 .) iJ 2f(0i ) —2=2__J_ _ or 0 2 F + G + H (4.2 11) For the plane stress case, the anisotropic yield function is = 2 _ 2 2 = _ 2f(01j) (G + H)0x 2H0x0y + (H + F)0y + ZNTxy 1 (4.2 12) The anisotrOpic parameters F, G, H, and N thus appear linearly in the numerator and denominator of Equation (4.2-ll). Hence, the effective stress, as defined by Equation (4.2-11) can be written as 1 2_ 2 2 — (G0 + Ho)0x 2H00x02 + (H0 + F0)0y + 2NOT 2 3 xy (4.2-13) 0 = - 2 F0 + G0 + H 0 by using Equations (4.2—6), (4.2-7), and (4.2—12). 62 In order that the increment of plastic work per unit volume can be computed as the product of the effective stress and the effective strain increment (dW = Oijdeij - 0'de), Hill [27] defines the effective strain increment for plane stress as _ 2 _ 2 _ 2 F0(Godex Hodez) +.GO(H0dez Fodex) + H0(F0dex Codex) EE'= A 2 (FoGo + 0080 + HOFO) l. 2dy§ 2 + where 2 A 3 (F0 + G0 + H0). (4.2-14a) Consistent with the experimental evidence that the strain incre- ments for aluminum-killed steel increase prOportionately during tension testing in one direction [2, 38], Equation (4.2—l4) can be integrated for the uniaxial tension test to get _ 2 _ 2 _ 2 F0(G061A H022) + G0(Hoez Fosx) + HO(FOEx G082) E=A + 2 (FOGO + GOH0 + HOFO) .l 27$ 2 N 2. (4.2-15) 0 > where A is defined in Equation (4.2—14a). Plastic potential theory furnishes the following relation— ship between the plastic strain increments and the stress states, where "d1" is a function to be determined. de, = dx 3f (4.2-16) 1j aoij 63 For the plane stress case the plastic potential function is given by Equation (4.2—12) and the strain increments can be found using Equation (4.2-l6) as follows: dex . d1 [(G + H)0x - Hoy] d = dA H + F 0 - H0 4.2-l7 Ey [( ) y x] ( ) dc - d1 [—G0 - F0 ] z x y de - d1 NT xy xY It should be noted that de:x + day + dez = 0, which is the plastic incompressibility assumption since the elastic strain increments are neglected. For uniaxial tension in the x-direction (the direction of rolling) 0x = X, 0 = 0 = T y = 0, and Equations (4.2—l7) imply e : s : e = de : d6 : de = (G + H) : (-H) : (—G) y z (4.2-l8) Specializing Equations (4.2—13) and (4.2-15) for uniaxial tension in the x—direction gives ; =/l (G + Hi ()9 (4.2-19) (4.2-20) Ml II a} f" '11 05+ +05 01+ :13 b1 A 0) >4 V 64 Similarly for uniaxial tension in the y—direction (trans- verse tO the direction of rolling), O = Y, O = 0 = T = 0 (4.2—21) y x z xy Ex 6y £2 = ds de de = (-H): (F + H) : (-F) (4.2—22) 3 = g (F iHG++FHL) (Y) (4.2-23) — _ _2_ (F + 0 + H) _ e — 3 F + H (5y) . (4.2 24) If the strain—hardening assumption is correct, then it is possible to use tensile test coupons cut at any orientation to experimentally determine the strain-hardening equation. The effect- ive stress, effective strain equation derived from data taken from coupons parallel to the direction of rolling should be identical with the equation based on coupon data for an arbitrary orientation. As a check on the reasonableness of the assumption, several experi— mental points from each test are shown on the best fit plot in section 4.4. The effective stress, as defined by Equation (4.2—13), can be transformed for the case of the tensile coupon oriented at the angle "a" to the roll direction using the stress transformation equations 2 0x = 00 cos a 0 = 0 sin a T = oasin 0 cos 0 (4.2—25) y 0 XY 65 1 __ 3 F sin1+ a + G cos” a + H(cos 20)2 + (%)(sin 20) °= '2 F+G+H 2 2 0 The effective strain increment equation can be similarly transformed. The strain transformation equations for a tensile test coupon oriented at the angle "a" to the direction of rolling are de cos2 2 ds 0 + de sin2 a x w ds de sin2 a + de cos2 0 (4.2-27) y 2 p w dsxy a dny - sin 0 cos a(dsw - deg) daz = dst. Equations (4.2-27) can be integrated for the uniaxial case to get 2 2 e = 8 cos a + s sin a x 1 w s = a sin2 a + 6 cos2 0 (4.2-28) y 2 w exy = ny = Sln 0 cos 0(6W - 22) Ez=°t With Equations (4.2-28) and (4.2-15), the effective strain can be found for deformation of a tensile coupon oriented at the arbitrary angle "a" to the roll direction. The effective stress corresponding to this deformation can be computed with Equation (4.2-26). Thus the effective stress and strain coordinates can be computed from the results of tensile testing coupons at any orienta- tion "a." 66 4.3 Tensile Test Procedures Eleven tensile test coupons were cut, at selected orienta— tions, from the same sheet steel from which blanks for the cupping tests had been prepared. Three coupons each were oriented at 0°, 45°, and 90° to the direction of rolling; the other two tensile coupons were oriented at 60° to the roll direction. The approxi- mate dimensions of these rectangular tensile coupons were 0.035 inch thick, 0.571 inch wide, and 7 inches long. Two-inch gage marks were machine inscribed on the test coupons, and the coupon edges were carefully machined to provide square edges which were parallel one to the other. The tensile tests were performed on an Instron Tensile Testing Instrument, type TT-C using a cross-head Speed of 0.2 inches per minute. Before the test, eight pairs of dividers were carefully set to the following dimensions, respectively: 2.10, 2.15, 2.20, 2.25, 2.30, 2.35, 2.40, and 2.45 inches. After the coupon was placed in the jaws of the Instron, the machine was actuated, and the deformation recorded by a three-man team. The divider man noted when the gage marks had stretched to the 2.10 inch setting of the first pair of dividers. At that instant, the second man measured the current coupon width, using a one-inch micrometer caliper, to the nearest thousandth of an inch, while the third man marked the graph of the load curve by momentarily lifting the recording pen on the Instron chart. This 67 procedure was repeated using the eight dividers in turn to get eight experimental points of true stress and logarithmic strain for each tensile test coupon. The original volume of metal between the scribed lines on the tensile coupon was computed as V0 = lowoto, where 20 is the original gage length, We is the original coupon width, and to is the original thickness. Assuming volume constancy, the volume of metal "V" at any other length "2" is equal to the original volume V0. This assumption permitted computation of the instantaneous cross-sectional area "A" at each load reading "P," and hence the true stress: V0 = 20W0t0= V = 2W1: = 2A (4-3‘2) - 1 _ _,Q,__ 8 o A - V0 (4.3-3) P _ fl _ and = A V0 . (4.3 4) The logarithmic strain was computed from s, = 2n (lg-3) . (4.3-5) The effective stress was computed by using Equation (4.3—4) followed by Equation (4.2-26). The corresponding effective strain was computed by using Equations (4.2-28) first, and then inserting the values obtained into Equation (4.2-15). The actual calculations were performed on the General Electric 265 Time-Sharing Computer 68 using the computer program TENSIL written in the FORTRAN language. Typical output for the three tensile coupons at a = 0° are given in Table 4.3—1. Table 4.3—1 Computer Output from the TENSIL Computer Program for Three Coupons at a = 0° fiaVSIL EFF‘esinhkfis SITuAIN 38714130 .00963 42867- -O7391 46084- -09780 4102660 012313651 49921- -14948 51895- -16561 534240 -1n5h1 511.7811:- - 9069/: 2‘51‘ 1' :9 1:12.35 111711») buff/($- -(1/:>~;'>;) 42743- .07391 45841- oUVYOU /HX£HI- jUQUo- 51627- salini- 12108 10305 1(>f:15 19004 C if, S 632'; 8 o '5' 2' I'.) " 1" LE? HEARS; ifmelg .595153- oLRNIAB 21,31163- -i)'//.;H‘J , «1.5-12>, - - -‘"‘: 9 >5 "/ lg ”05252- o1.?15x5 :y)3973 -1¢Lsav DI (0‘73. 010416)“) OsaYnu .1 (£43 I)" '2 .L . o 02:111777" 69 4.4 Ludwik's Three—Parameter Stress—Strain Equation Ludwik's three—parameter equation [85] can be used to get a reasonable mathematical model of the effective stress—strain curve during plastic deformation. This equation is discussed on page 14 of Johnson and Mellor [80], page 12 of Hill [27], and page 20 of Mendelson [83] and has the form 6' = A + B? m. (4.4-1) The three parameters A, B, and m must be computed to give the "best" fit for the experimental data. From Equation (4.4-l) it is evident that "A" is the initial effective yield stress. For the experimental data available, a suitable approxi- mation was obtained by using Equation (4.4—1) with A - 0b, which is the initial effective yield stress computed by inserting into Equation (4.2-26) the average yield strength given in Table 2.4-1 for each of the nine orientations. These nine results were then averaged to determine Eb = 27050. psi. The actual calculations were performed onfthe General Electric 265 Time—Sharing Computer using the FORTRAN program "AVESIG." The two remaining parameters B and m were then calculated using the "least squares" technique. Equation (4.4—1) was re— arranged by transposing 0b and then taking the logarithm of each member to get 2n(0 - 00) = in B + m 2n 2.. (4.4-2) Equation (4.4-2) indicates that after the eXperimental true stress and logarithmic strain data are converted to effective stress 70 ”0" and effective strain "E“ for tensile coupons at any orientation 0 then a plot of reduced stress "0'— 05' vs effective strain should plot as a straight line on log log graph paper, if Equation (4.4—l) is applicable. For each of the eleven tensile tests described in section 4.3, eight values of effective stress "0“ and effective strain "E“ were computed as illustrated in Table 4.3—1. For each pair (0; 23 a second pair (0 - 0b, 2) was found; the coordinates of the second pair were called reduced stress and effective strain. When the reduced stress and effective strain coordinates, based on the experimental data discussed in section 4.3, were plotted on log log graph paper, the data from all eleven tensile tests reasonably approximated a straight line with the exception of the coordinate for the smallest strain value of each test coupon. A similar finding is discussed on page 86 of the text by Thomsen, Yang and Kobayashi [81] for the two-parameter Ludwik equation 0I= C: n. It was decided to exclude this small strain coordinate from the calculations for "best" fit. Figure 4.4-1 presents the data from three representative tensile coupons: one at a = 0°, the second at a = 45°, and the third at a = 90°. This graph of reduced effective stress vs effective strain includes the "best fit" line as a solid line. The dashed lines give an indication of the scatter of the data (with the exception of a few data at low strain values). 71 Using the same "least squares" procedure as discussed in section 3.3, a difference equation was first written for each ex- perimental point based on Equation (4.4—2). 61 = (in B + m In 21) — in (01 - 00) (4.4—3) The error equation was next written. E = 28; = £[(9.n B + man '51) — 1:161 - 30)]2 (4.4-4) The error equation can be considered to be a function of two variables E = E [in B, m] (4.4-5) The "best" values of these two variables are found by differen- tiating the function with respect to each of these two variables and setting these derivatives equal to zero. This procedure re— sulted in the following two equations. 6E SIEETB).= 0 = £2[£n B + m zn'zi) — 2n(0; - 36)] (4.4-6) 3% = 0 = £2[(9.n B + m 9.6 21) - 2:161 — 30)] (in E1) (4.4-7) These two equations were then solved for the values of the unknowns B and m. Mathematically, the best values of in B and m were found by this procedure rather than B and m. This problem is discussed by Wylie [78] on pages 186-191 of his text; the procedure is reason- able unless experimental strain values close to unity are used. The calculations to determine the parameters B and m using the "least squares" technique were performed on the General Electric 72 265 Time-Sharing Computer using the program LUDWIK written in the FORTRAN language. The strain-hardening equation suitable for the particular aluminum-killed, low-carbon steel used in this investi- gation was _ _ 0.518 0 = 27050. + 60700. e (4.4-8) 73 maoaumucmfiuo sense you cfimuum O>wuoommm uoam afimuumlmmmuum m>fiuommmm qu.¢ muawfim o.H w. o. c. m. cm. we. 90. co. i .8 u 8 m 38 d a“ .me u e H meme nu no u a m mama nu nv\\hHUHHMHu\\\\\. Y) \ \3 W. 1 \ 1 V \ 0\ f \, 1 \\ \\ OH ma 0N mm 0m 06 om 00 oh ('ISd J0 SPUESHOLLL) SSBJJS BAIJDBJJH pBOUPBH V. THEORETICAL ANALYSIS OF THE CUP-DRAWING PROCESS 5.1 Preliminary Remarks In order to calculate the stress and strain history of an element in the flange of a partially-drawn cup, a mathematical model must be introduced to represent the actual physical model. In sec— tions 1.4 and 1.6 of this thesis, previous work in this regard is mentioned including the theoretical investigations of Chung and Swift [21] and of Hill [27]. The analysis presented in this chapter assumes that the plane stress condition prevails for elements in the flange. A blankholding force of 3980 pounds was required during the experimental draw oper- ation to prevent the formatiOn of wrinkles. This blankholder force correSponded to an average pressure of 355 psi on the flange surface at the beginning of the draw, and an average pressure of 1530 psi on the flange surface when the partially-drawn cup was 1.12 inches deep. Since this stress is small compared to the yield stress for the aluminum-killed steel used for the experimental investigation, the plane stress assumption was used. These average figures are based on a uniform pressure distribution over the flange. Since, at any stage of the draw except the beginning, the rim thickness is greater than the thickness of interior elements, the greater part of the ‘blankholding force acts at the rim, where the condition is in fact not plane stress. (See the results of the investigation of the distribution of blankholding force over the flange, published in 1964 by Woo [63].) 74 75 Because the blankholding force "H" is considered to be con— centrated at the rim, the plane stress assumption is even more reason— able in the interior than the analysis based on a uniform distribution indicates. The friction at the rim then furnishes a radial force, which is introduced into the plane stress analysis as a radial boundary stress 0b. Equilibrium of forces in the radial direction at the rim, where the current radius is "b" and the thickness is "tb" then yields (20b tb) 0b = 2uH (5.1-1) 0 - JE— (5 1-2) b Tbtb ° where u is the coefficient of friction. The coefficient of friction between the blankholder and the cup flange and also between the die face and the flange of the par- tially-drawn cup had to be used in the calculations. It was decided to use a coefficient of friction u = 0.06 based on experimental work by Swift reported in Table 3, page 359 of his 1948 publication [19] for mild steel of comparable thickness with good lubrication. In Figure 35, page 216, of their 1951 publication Chung and Swift [21] compare radial strain results for three coefficients of friction u = 0, u = 0.06, and u = 0.128; they used u = 0.06 in their cup- drawing calculations. Another assumption implicit in this analysis is that the punch force acting on the partially-drawn cup is balanced by a line distribution of concentrated force exerted by the die ring at the die—profile radius OD. See Figure 1.1-1. A more realistic 76 assumption would be that this force exerted by the die ring on the partially-drawn cup is distributed over some area of the flange; however, it was decided to use the more convenient assumption of a concentrated force. The three-parameter Ludwik equation discussed in Chapter 4 was used as the measure of strain hardening for both the isotrOpic and the anisotropic analysis. This is given as Equation (4.4-8) for the aluminum-killed steel investigated and more generally as Equa- tion (4.4-l). It is the purpose of this chapter to develop the approximate theory used and to present some of the results for the stress and strain field calculations for elements of the cup flange at any stage of the draw. In section 5.2, the yield condition is discussed. Section 5.3 introduces the equilibrium equation and the stress anal— ysis theory, and section 5.4 presents the strain analysis theory. The stress and strain analysis theory is specialized for a rim element in section 5.5 along with the associated computer analysis. Section 5.6 introduces the computer analysis for interior points. Results of the strain analysis are presented in graphical form in section 5.6. The notation used in this chapter is given in Figure 1.1-1 and Table 5.1-1. 77 Table 5.1—1 Notation for Chapter 5 Current radius to the rim of the partially—drawn cup Original radius of the rim; Radius of the flat blank from which the cup was drawn Variable radius to an element in the flange Current radius of the element being followed in the flange Original radius of the element being followed as measured on the flat blank Current thickness and original thickness of the element being followed 0 Current thickness of the flange metal at the rim Mean thickness of the metal between the rim and the element under consideration Blankholder force in pounds Coefficient of friction Radial stress and strain components Circumferential or tangential stress and strain components Component of stress in the thickness direction Strain component in the thickness direction Radial stress component at the rim of a partially-drawn cup Effective or equivalent stress and strain Initial effective stress Material constants in the three—parameter Ludwik stress- equation.3 = Eb + BEm Initial effective stress in the linear approximation to Hill's anisotrOpic yield condition 06 = Nbr - 0* Effective stress after strain hardening in the linear approxi- mation to Hill's anisotrOpic yield condition 0* = 0-* (-) C’0 78 5.2 The Yield Condition An element in the flange of a partially-drawn cup is char- acterized in this analysis by the plane stress condition 0 3_0 = r 2 0 3_0 In the or, 0 stress plane (for oz = 0) the yield condition 6' 6 may be represented by Mises' yield ellipse for isotropic metals or by Hill's anisotrOpic yield ellipse for anisotropic metals. For the anisotropic case different ellipses are obtained for different angles a; see section 3.5. Only one quadrant of the Or’ 06 plane represents possible stress states for an element in the flange; therefore, it is possible to use one linear equation to approximate each ellipse. See Figure 5.2-1 for the isotrOpic case. Because of computational ad- vantages, it was decided to use linear approximations to the yield conditions for both the isotropic and the anisotropic cases. The linear approximation of the initial anisOtropic yield condition is discussed inChapter 3. For an element along the dir- ectiOn of rolling the linear approximation to the initial anisotropic yield condition is given by Equation (3.6-9). The linear approxi- mations for certain other radial directions are given in Table 3.6—3. The general form of the linear approximation to the yield condition is 0 = N0 - 0* (5.2-l) where 08 will increase in direct proportion to 0 with the strain hardening, starting at the initial value 03 = 30810 psi for a = 0° and at 0: = 31720 psi for a = 45°: 3* = 3.3 (3;) (5.2—2) °0 79 Tresca ' . Mises Modified Tresca Figure 5.2—1 Yield Conditions for the Isotropic Case 80 On page 284 of his text [27], Hill remarks that the effective strain E for an element in the cup flange is never more than 3% greater than the absolute value of the tangential strain 56' Using this approxi- mation gives r r e ; Is = - [ d5 = _ [ 23-: ln-—2 (5.2-3) 0 e r r Jro This permits the three-parameter strain—hardening Equation (4.4-1) to be written in the alternative form - - -m - r0 m o = 00 + B5 = 00 + B (1n 7) (5.2-4) Inserting Equations (5.2-2) and (5.2—4) into the yield Equation (5.2-1) results in the following alternative forms of the linear approximation, including strain hardening, of the anisotropic yield condition _ _ _ _ (5.2-5) 0e - N0r - (03/00)0 _ 36) to m (5.2-6) 06 I Nor - (5‘ [0'0 '1' B(ln 7)] 0 06 = Nor — ‘3 (1 + E—E In) . (5.2-7) 0 Equation (5.2—7) is of the form to show the factor h = h(€ij) discussed in the early part of section 4.2. The function h = 0/00 = 1.4-::- is the parameter expressing the amount of strain hardening, starting at h = 1. The value of N also depends on a (see Table 3.6-3), but the hardening function constants are assumed independent of a, as discussed in Chapter 4. 81 As illustrated in Figure 5.2—1 for the isotropic case, a modified Tresca yield equation has the form 0 — 0 = L0 . (5.2-8) If L = 1, then Equation (5.2-8) reverts back to the standard Tresca yield condition, which is a hexagon inscribed within the Mises yield ellipse. Many authors find it convenient to let L = 1.1 to get a better approximation to the Mises yield ellipse in the fourth quad- rant; however, Equation (3.6-11) gives L - 1.094 as the "best-fit" value. Strain hardening is included in the yield Equation (5.2-8) since 0 is the effective stress, which increases with strain hard- ening as given by Ludwik's three—parameter Equation (4.4-l). Insert- ing Equation (4.4-l) into Equation (5.2-8) gives the alternative forms 06 = 0r - L0 (5.2-9) — —m 06 = 0r - L(00 + Be ) (5.2-10) = - I: <1 +931“) <5 2-11> 0e 0r 00 __ e . . °0 Replacing the effective strain E.by Hill's approximation, Equation (5.2-3), gives r _. o m 06 — 0r - L[00 + B(ln 17)] , _* (5.2-12) _ 0 a special case of Equation (5.2-6) with N = l and :f-= L. 0 0 82 5.3 Stress Analysis Theory for the Flange The differential equation of force equilibrium in the radial direction for an element in the flange can be found as follows (see Figure 5.3-1). ZFr = 0 (5.3-1) 0 - (0r + dor)(r + dr)(d6)(t + dt) - 0r(rd6)(dt) 1 d6 - 2[0e dr(t + 2 dt)]( 2) (5.3-2) Neglecting higher order terms and rearranging gives d(0rt) O g dr + (0r - 06) E-. (5.3-3) The equilibrium Equation (5.3-3) and the plane stress assumption assume that the element thickness may change as the cup is progressively drawn. Chung and Swift [21] point out that although the flange thickness generally increases during radial drawing, the actual difference in thickness across the flat flange at any instant is small. For a drawing ratio of less than 2, the maximum difference is about 5%. Hence Hill [27] on page 285 of his text suggests that if uniform metal thickness, at any instant, is assumed for the flange, the maximum error in the radial stress 0r will be 5%. Assuming uni- form thickness across the flange at any instant means that dt = 0 in the equilibrium Equation (5.3-3), which simplifies to d0r 0r - 0e dr + r = 0. (5.3—4) 83 d6 NMH 1 t) 01’“ 0 agar) '1 Figure 5.3-1 Notation Used in Force Equilibrium for 3 Flange Element 84 Rewriting equation (5.3—4) to solve for d0r results in dr d0r = r (06 - 0r) (5.3-5) Inserting the yield condition Equation (5.2-6) into equation (5.3—5) and integrating from the rim to the element being followed results in or' __ r'dr ._ B r' r m d __ r' 0r J d0r - -03 J -1? - 03 (27% J (In -39 —£-+ (N - 1) J (-—) dr. r r r 0b b 00 b b By introducing Equation (5.1—2) for Oh, Equation (5.3-6) can be reduced to ER - b - B J r0 m dr - Or 8 + * — + — — — _ .— 0r, "btb 00 1n r' 03 ( ) r,(ln r ) r -+ (l N) J ,(r ) dr. 00 r The fourth term in the right-hand member of equation (5.3—7) requires a knowledge of how the radial stress 01. varies with r. The stress and strain history for an element at the rim as the cup is progressively drawn must be computed first. Next the stress and strain history for an element close to the rim is followed. By this procedure, it is possible to progressively formulate the function 0r = 0r(r). For the isotrOpic case N.= l and the fourth term of Equation (5.3-7) vanishes; also, 0% = L00 for an isotropic material, which alters Equation (5.3-7) somewhat. The third term of Equation (5.3-7) has an integral that re- quires interpretation. The integration variable "r" varies from r', 85 where the radial stress is desired, to the current rim radius b of the partially-drawn cup, and r0 denotes the initial radius of the element now at r. It is evident that r is not a constant, but rather r O = ro(r). 0 Hence before this integral can be numerically integrated, some relation- ship between ro and r must be determined. In this analysis, it was assumed that an element in a pie- shaped region of the blank moves only radially inward, which seems to be a reasonable first-order approximation. Referring to Figure 5.3-2 and assuming that the volume of metal between the element being followed and the current rim at any instant is equal to the volume between the same element and the rim at the beginning of the draw operation, we obtain «(63 - r3) t0 = «(62 - r2)tm (5.3-8) or r3 tun+1052 b2 t‘“ ‘ (539) """'"" "" 0‘ 0—9 -‘ r2 to r2 t0 where tm is the mean thickness of the flange metal between the rim and the element being followed. Hence r t t ._2.=.l .11 .1. 2 _ 2.49 _ 1n r 2 1n L0 + (b0 b0 toE‘ (5.3 10) r and j: 2 2 to r = b - (bo - r0) f-I (5.3-ll) m Equation (5.3-ll) gives the current position of an element being followed in terms of its initial position r0. '86 Figure 5.3-2 Terminology for a Partially-Drawn Cup 87 Equation (5.3-10) can now be inserted into equation (5.3—7) to get __ __ b 0 0,=-JJ-I'-I-+0*ln-b—,+(l-N)[ (-£)dr I r 1rbtb 0 r Jr r ._ b t t m + O*(‘§\)J l 1n JR + i— (b2 - b2 1'1) 95 (5.3-12) 00 r r 0 In the integration of Equation (5.3-12) known values of b0 and to on the flat blank will be used along with the other known values of u, H, 3:, 30’ B, and N; Then it will be assumed that the blank has been partially drawn to a somewhat smaller rim radius b. Some method must be used to estimate the rim thickness tb as well as the average thickness tm of the flange between the element being considered at radius r' and the rim at radius b. After 0r has been calculated for an element at radius r', then 06 can be computed using the yield Equation (5.2-5) which is repeated here for convenience 06 = NOr - LO (5.3-l3) where L = 03/05 (5.3-l4) 5.4 Strain Analysis Theory for the Flange Equation (2.1-l), which is the anisotrOpic yield function in terms of the principal anisotrOpic directions (shown in Figure 1.1-2), can be transformed from x, y, z coordinates into r, 6, z coordinates using the transformation Equation (3.5-3). Since the radial, the circumferential and the thickness directions are principal stress directions for 0 = 0°, 0 = 45°, and a = 90° (which implies 88 T = T = T = 0), the transformed anisotropic yield function can r6 26 zr be written as 2 2f = F(0r sinza + 06 cosza - oz)2 + G(0z - 0r cos a — 0 sinza )2 + 6 H[0r(cosza- sinza) + 06(sin20 - c0320)]2 + 2N(0e - 0r)2 sinza c0520 (5.4—l) With the plastic potential flow rule de - d). Ji- , (5.4-2) ij 60ij the strain increments in the circumferential and the thickness dir- ections can be derived from Equation (5.4-l), when the elastic strain increments are neglected. : = _ 2 2 _ - 2 _ 2 dct - dez dA[ F(0r sin a + 06 cos 0 oz) + G(0z 0r cos a 0esin 0)] dee = dAlF cosza(0r sinza + oecosza - oz) + G sin201(0r cosza + 06 sinza - 2 _ _ 2 2 _ oz) + H(cos 20) (06 or) + 2N(0e 0r) sin 0 cos a] (5.4 4) After letting 02 = 0, consistent with the plane stress assumption, the ratio of the thickness strain increment to the circumferential strain increment can be specialized for the two directions a = 0° and a = 45° to get dct F0e + Gor a (5.4-5) de6 H0r - (F+H)0e for a = 0°, ‘89 and dct -2(F+G)(0r +06) dee (F+0-2N)or + (F+0+2N)6e for a = 45°. (5.4-6) Equations (5.4-5) and (5.4-6) reduce, for the isotropic case (where 3F - 30 - 3H s L - M . N), to de 0 + 0 '6'? = 32:75. (5-4‘” 6 r 6 Inserting the experimentally-determined values of the aniso— tropic parameters F, G, H, and N reported in Chapter 3 as Equation (3.2-1) and Equation (3.3-12) produces the following specializations Of the strain-increment ratios. For a = 0° 6.94 06 + 7.60 0r d6t ‘ 5.96 or - 12.90 06 dee’ (5'4‘8) and for a = 45° -2(14.54)(or + °0) 7 d6t = -20.36 or + 49.44 0 dee' (5'4‘9) 6.1 The tangential stress 0 in Equations (5.4-8) and (5.4-9) 6 can be eliminated by inserting Equation (5.2-5) and using the appro- priate values of N and 0% from Table 3.6—3 or Equation (3.6—ll) along with the value of 36 = 27,050 from Equation (4.4—8) to get 14.730 - 7.905 3 dr de = r -—- (5.4-10) t 14.693 - 7.288 °r r for the direction a = 0°, 90 d6 [58.163r - 34.1 0] 5.1.; (5.441) t 57.97 '3 - 29.086r r for the direction a = 45°, and d; [2 0r - 1;09‘4 0 ] £1}; (5.4_12) 2.188 '3 - 0 r yr for the isotrOpic case. where _. _. r0 m 1.000518 0 = 0 + B (1n -- = 27,050 + 60,700 (1n -—) 0 r 1' (5.4-13) The increment of tangential strain is dr dse = r (5.4-l4) The strain history of an element is studied, as that element moves radially inward. Hence "dr" must be interpreted in Equation (5.4-l4) as the incremental distance travelled by the element currently at the radius "r." This is in contrast to the use of "dr" in the equilibrium equation, Equation (5.3-4), where dr represents an increment of length over which the tangential stress 06 acts. Integrating Equation (5.4-l4) produces r0 86 = -ln :7 (5.4-15) which gives the tangential strain for an element which was originally at radius r0 and finally at radius r'. 91 The radial strain increment for an element can be found from the volume constancy assumption det + der + (166 = 0 (5.4—16) after the other two strain increments have been computed. The definition of thickness strain increment is given by _.2£ _ which can be integrated to get t' ' at = 1n ?0- (5.4-18) E:1: t, 8 toe O (504‘19) Equation (5.4-l9) can be used to find the thickness t' of an element which has experienced a thickness strain a t 5.5 Stress and Strain Analysis_for a Rimgglement The analysis to determine the stress and strain field for the flange of a partially-drawn cup must start with a rim element having the following specifications. r0 = b0 r = b dr = db (5.5—1) 0r = 0b Several equations were needed for the computational work. The thickness strain increment Equations (5.4-10) and (5.4-ll) were 92 specialized for a rim element to 14.73 0 - 7.905 2? det' L _b :1 51-:— (5.5-2) for a = 0, and d6 8 58.16 Ob - 34.:0 1 db (5.54) t 57.97 3' - 29.08 0b_| b for a = 45°. Equations (5.5-2) and (5.5-3) were integrated incrementally by permitting the rim radius to move in a fraction of an inch at a time. For each increment of rim displacement "db," the thickness strain increment was computed. The total thickness strain for the rim element located at a current rim radius "b" was found by summing the incremental thick- ness strains. Any desired degree of accuracy was possible depending on the number of increments used. The effect of varying the increment size is discussed in section 5.7. The increment size finally used for the rim analysis was 0.001 inch. In order to compute an increment of thickness strain using Equations (5.5-2) and (5.5—3), values of the effective stress 0 and the rim radial stress 0b were needed for each current rim position b. The effective stress was computed using the strain-hardening Equation (5.4-l3) specialized for a rim element. -' -' b0 m 0 = 00 + B (1n b—-) (5.5-4) 93 The value of the rim radial stress needed in Equations (5.5-2) and (5.5-3) was evaluated from Equation (5.1-2), repeated here for con- venience. . _H§L. _ 0b Hbt (5.5 5) b The rim thickness tb in Equation (5.5-5) was determined by special- izing Equation (5.4—19) for a rim element. tb g to8 (5.5-6) Initially the rim thickness strain at was put equal to zero, which implies an initial rim thickness of to. The tangential strain increment, defined by Equation (5.4-l4), can be written for a rim element as de = -—-. (5.5-7) The radial strain at the rim of a partially-drawn cup was determined by numerically summing the radial strain increments. The volume constancy, neglecting elastic strains, demands that der = -det - dee (5.5-9) The tangential stress 06 at the rim was computed by specializing the yield equation, Equation (5.3-l3), for a rim element. 06 = Nob — L0 (5.5—10) 94 The flow chart for the stress and strain analysis of a rim element is given in Figure 5.5-1. This flow chart was used to design the computer programs for the rim element in the two directions in- vestigated, a = 0° and a = 45°, for the anisotropic case. The computer programs were written in the BASIC language and run on the General Electric 265 Time-Sharing Computer. The ANI Al computer program was specialized for a rim element oriented along the direction of rolling (at a = 0°). This program is shown as Figure 5.5-2. Partial output for this program is given in Table 5.5-1. 5.6 Stress and Strain Analysis for Interior Elements The analysis for interior elements, that is elements with initial radius r0 < 2.4 inch, parallels that for the rim element. The stress and strain analysis for the rim preceded the analysis for in— terior elements, since some of the rim element results were used in the computations for interior elements. FOur equations that were needed for section 5.3, starting with Equation (5.3—ll) are repeated here. b 0 =_1£L - .12. _— .1 0r. Hbt + 03 1n r' + (l N) J ' r dr + b r ‘b t t m _ L B J szln [253+i- <63 - b2 2.12)] 51f- (5.6—1) r' 0 r2 0 06 = Nor - Lo (5.6-2) ="*_ .6- L 00/00 (5 3) \/2 2 2 t r = b - (b0 - r0) E—- (5.6-4) 95 H = 3980. , , B = 60700. 0 = 0.06 - _ t0 3 0.035 60 — 27050. b0 3 2 4 m = 0.518 0 = uH/(nth) 06 = N0b - L0 Equation (5.5-2) or Aer = Equation (5.5-3) l £6 = —1n(b0/X) A2 = -A2 - AX/X 1' t to l 3 g =te°t 00 + B ln(bO/X) NO ‘ I'+ I + l YES PRINT 8r’ 86’ E:t °b’ °e I + 1 ‘ * YES ( STOP > 0 YES NO X + X + AX 2 +2 + As r r r s +—e + At t t t Figure 5.5-1 Flow Chart for the Stress and Strain Analysis of a Rim Element ANI 100 110 120 122 125 126, 130 140 150 16’) 170 180 190 195 200 210 220 2.30 240 260 270 280 290 300 3.31 302 304 305 310 320 321 330 340 350 363 365 370 375 500 505 510 520 600 96 A1 LET TO=-J35 LET T330 LET Z=O LET L=30310/27053 LET L1=1-027 LET N=‘0031 FUR K1=30'TJ -499*30 STEP N LET T5=TO¥EKPCT3) LET T1='LQG(30/K1) 605J3 503 LET T7=(14-73*55-7-905*L3)/(14-69*L3‘7-238*55) LET T8=N*T7/K1 LET T9=-T3-N/X1 LET $1=L1*55-L4 LET =-0001 FQQ 1:204 T0 10199 STEP '01 IF A35(K1‘I)- u - 0.06 ESTIMATE t m Arith.Ave. ESTIMATE t0 = 0.035 Compute r' using Eq. (5.6-4) 100 B = 60700. 50‘ 27050. m = 0.518 b + b0 4. NO IS « b < 1.2 - = _ ' 0 00 + B ln(rO/r ) 1 b r! 0 = uH/(nb tb) S6=0* 1n(9—J + (l—N)S4 STOP > r + r' b + b + Ab YES 0 =0 +S6+S* r b 1‘0 ee=-ln(;7J __..A6 2 [Equation (5.6-5)] t or (5.6-6) Figure 5.6-1 Flow Chart for the Stress and Strain Analysis of an Interior Element 101 being followed for selected values of the rim radius b. The POLFIT program then converted these output pairs (tm, b) into suitable second-degree best-fit equations of mean thickness as a function of the rim radius. The computer program AREA evaluated 84 = J (S£)dr from the rim radius "b" to the element being followed (using ghe trap— ezoidal rule) at selected values of the rim radius. Then the POLFIT program was again used to find suitable second-degree best-fit equa- \ 0 tion of the integral S4 = J (—E) dr as a function of the rim radius. r These best-fit equations for tm - tm(b) and S4 - 84(b) were then inserted into the main computer program ANI C7 for the second iteration. Iterations continued until there was negligible thickness change between successive iterations; normally this required three iterations. The main computer program ANI C7 along with the auxiliary programs AVTHIK and AREA are included in the appendix. Partial com— puter output for the final iteration of ANI C7 is shown in Table 5.6—1. The increment size used for the analysis of interior elements was 0.005 inch. 5.7 Results The results of the computer analysis for the rim element at a = 0° are summarized in Figure 5.7-1 which presents the strain history for this rim element as it moves inward during the cup-drawing process. Logarithmic strain is plotted against rim position which is made dimensionless by dividing the current rim radius "b" by the original rim radius "b0.' The stress analysis results are not presented, since they can not be compared to any experimental results. 102 Table 5.6-1 Partial Computer Output for ANI C7 ANI C7 CURR RAD= 2.3 CURR RAD= 1.99278 52/R1= 962.883 52/R1= 1945.32 RIM RAD= 2.4 RIM RAD: 2.1 R/BO= .958333 R/BO= .830324 THICK= .035 THICK= 3.74494 E-2 RAD STR= 2214.63 RAD STR= 3876.59 CIR STR=~28545. CIR STR=-S2108.6 CIR STN=-3.44589 E-8 CIR STN=-.14338 THICK STN= D THICK SIN: 6.76433 E-2 RAD STN= 3.44589 E-g RAD SIN: 7.57367 E-2 EFF STN= 3.97898 E-8 EFF SIN: .143456 CURR RAD= 2.19772 CURR RAD: 1.89001 $2/R1= 1340.7 52/R1= 2315.68 RIM RAD= 2.3 RIM RAD= 2. R’BO‘ 0915715 RIBO= 0787506 THICK= 3.57336 E-2 THICK= 3.84049 E-2 RAD STR= 2946.48 RAD STR= 4376.67 CIR STR=-41732.2 CIR STR=-56064.3 CIR STN=-4.S4908 E-2 CIR STN=-.l96325 THICK STN= 2.07434 E-2 THICK STN= .092837 RAD STN= 2.47475 E-2 RAD SIN: .103488 EFF STN= 4.55495 E-2 EFF STN= .196421 CURR RAD= 2.09533 CURR RAD= 1.78702 $2/Rl= 1627.81 S2/Rl= 2759.76 RIM RAD= 2.2 RIM RAD= 1.9 RIBO= .873056 RIBO= .74459 THICK= 3.65611 E-2 THICK= 3.94356 E-2 RAD STR= 3410.82 ’ RAD STR= 4931.74 CIR STR=-47S30.8 ' CIR STR=-S9626.5 CIR STN=-9.31958 E-2 CIR STN=-.252362 THICK $TN= 4.36377 E-2 THICK SIN: .11932 RAD STN= .049558 RAD STN= .133043 EFF STN= 9.32584 E-2 EFF STN= .252437 103 It is interesting to evaluate the effect of increment size on the computer output. As the incremental rim displacement "Ab" gets smaller, one expects an increase in computing time with improved accuracy up to a certain point where computer round-off errors,inter— fere. Table 5.7-1 shows the effect of increment size on the rim thickness. While computer round-off errors do not appear to affect the output, it was decided that an increment size of 0.001 inch was a reasonable compromise between cost and accuracy. It was expected that the theoretical analysis would show a distinct difference in strains between the direction of rolling where a = 0° and the radial direction where a = 45°. This difference can be seen in Figures 5.7-2 and 5.7—3 where the thickness strain and the radial strain histories of these two rim elements are compared. The thickness strain curve for the a = 45° direction is above the curve for the a = 0° direction indicating a greater degree of thickening along the 45° direction. In addition, Figure 5.7-3 indicates that the radial strain along the a = 45° direction is less than along the a = 0° direction. Both of these facts are consistent with the experi— mental evidence of ears in the direction of rolling. Table 5.7—1 The Effect of Increment Size on the Computed Rim Thickness for a = 0° Increment Computed Rim Thickness Required Computer Size at b/bo = 0.583 Time 0.1 .0460524 2 secs 0.01 .0463866 4 secs 0.001 .0464206 27 secs 0.0001 .0464240 4 mins 19 secs Logarithmic Strain .30 .20 .10 -.10 104 [J Radial Strain () Thickness Strain A Tangential Strain H H "177::5 3;“. .3 .9 ‘ Currant Rm Faxiflaq ’ b/bo y... ....- A- _—-- ..-. .. .2-.. ..--.-.. _. V. n...” _ ,_ p. .._., w —. , .5-“ ‘—- ._-~— ... -._. ....—.- _- - Figure 5.7-1 Computed Strain History of a Rim Element at a = 0° During the Cupping Operation Thickness Logarithmic Strain 105 ' - lb“... p --.-;;;—::.'u.:scra1n .. a = 0° 6 0-30“T.'7.‘“2‘“" .. ..'...-.:_._'----:.;;°i.li;;.+o;zgW4: a 9 45° . 10.....-- ! . I , 4 I. ‘ o f . g. - ‘. 0-. “4*“ L. f .' {.A --o I ‘ l . 19 _. b — a" a” .— ‘v. a. “50.1 c a “a -o - ' . ‘ t p , ) . I q A I V . ' 1 - ..-. .._a n. .. L... .. s —- -. .' Q . ' . I. . x A l . A I C ,- ---_1 -_...-......--- ._-L - , ,‘ . -. . .. - J - . . . . ..s ‘ _ . . 4 . . . ...~.-’ -'--v-u."o- .,-.--.— . . ”-14.... ‘ ...—.J - ,. . . ; Figure Current Rim Position b/b0 5.7—2 Comparison of Computed Rim Thickness Strain at a = 0° and a = 45° Radial Logarithmic Strain 0.30 106 [3 Strain at a 0° 0 Strain a = 45° Current Rim Position b/b0 Figure 5.7—3 Comparison of Computed Rim Radial Strain at a = 0° and a = 45° 107 One simplifying assumption used in this investigation and dis- cussed in section 5.3 was that all elements within a particular pie— shaped region of the blank remain within that sector during the cup- drawing Operation; another way of stating this assumption is that any element moves radially inward during the draw. This assumption meant that no differences in tangential (circumferential) strains would appear when tangential strain is plotted as a function of rim position b/bo. All three strain components for a = 0° were plotted on one graph, Figure 5.7-1, to permit certain comparisons to be easily made. For example radial or proportional straining exists for the rim element if the strain ratios for the rim element remain constant during the draw Operation. This theoretical analysis supports the contention of radial loading. It can be seen from Figure 5.7-1 that the thickness and radial strain components for the rim element are predicted to be approximately equal during the draw by this theory and, therefore, each is about one-half of the magnitude of the tangential strain. Strain ratios (er/se and et/ee) from the computer output for the rim analysis are reported in Table 5.7-2; these results also indicate prOportional straining. The results of the analysis for interior elements were com- bined with the rim analysis and presented in Figures 5.7—4 through 5.7-8. Each of the three strain components is presented on a sep- arate graph. To follow the strain history for a particular element during the cup-drawing operation, one must follow a particular solid line; for example the element originally at r0 = 2.3 inches in the flat blank is identified by data points plotted as small circles and 108 intersecting the abscissa "r/bo" axis at the point rO/b0 = 2.3/2.4 = 0.958. As the draw progresses, this element moves inward, resulting in an increase in the appropriate strain magnitude from zero to its current strain at r/bo following the solid line. Since the computer output was in the form of strain for any element at selected values of rim radius, it was possible to connect appropriate data points on these three graphs with dashed lines which represent the strain across the flange at some particular value of the rim radius. From Figure 5.7*4 or Figure 5.7-5 it is seen that the dashed lines are almost horizontal, although the thickness at the rim is slightly greater than the thickness of interior elements at any stage of the draw. These dashed lines support the assumption that, while the thickness of any element increases as the draw progresses, the thickness does not vary appreciably across the flange at any particular stage of the draw and can be considered constant as a first approximation. Table 5.7-2 Computed Strain Ratios for the Rim Element vs. Rim Position b/bo et/ee sr/ee a = 0° a = 45° a = 0° 0 = 45° 0.958 0.518 0.569 0.482 0.431 .875 .521 .572 .479 .428 5.750 .523 .573 .477 .426 .625 .524 .574 .476 .425 .500 .524 .575 .475 .425 Thickness Logarithmic Strain 109 _ r - -- - _ -. " f 1 1 - ‘c"*‘w » 4 .vmunm *--y——-.--»»~. - - ---—o‘~—-- - b n .. .£ I . . ‘ C -.,: . ... ; TO: ."ro s 22.3 11-14-- L1- ‘ie:¥O§<*‘~f‘g *fZé-T ..o ~-o..-——-..- . . . o o - . * V "in? a; 1,9 .ua .0- .4 O 30 , Fl — - -..w 0...... ..: E. - h--”¥f0~ia;f-‘i:j7‘ ' ' . -A I ~ . O -wnrk .a-o—oc“ V. 9- ~- -l.:..-T~A: A --d.?.‘—:-A. - .‘ '.~ — :— ’ - - a.-- 1‘ . , . . . - ~ . ’I . l 40 . . < . v, .. . . , |. . --"—.-v -v. . .. A . a h ‘ o x .' C C i - ‘ 4 o . >o—-‘-‘~ ,.... - a ‘ . J . ' . I ‘. . A ' .—.— » ‘-.afi - . ~- 0......— 1... x - I. cool- «. ’ ‘1 . 10 4 W" f‘-‘ w 7.7 —-«~r.-:U-I.D ‘O- ‘ ..-0-. . a . 3 z I 1.. I 1 9 q ‘ . '12 . 1...; ‘1? n 1;; * A 7} a "J ‘ o. l 4o H I M I 0 'll .6 .7 .8 .9 1.0 Current Element Position r/b Figure 5.7-4 Computed Thickness Strain for Flange Elements at a = 0° Thickness Logarithmic Strain 11“.; m7“ ..- ~; in —'“Y .“‘r *u-"*‘1';" -d- 4.. , . -¢- -Q .4- 1.14:..1.111+.L- It 0'.- 110 --o-¢¢ '1<$-- 0‘ T;— -. _.I'. ,. c y. -3. ..A._ « u I.-. 44 - ‘ s — - ..‘ .' w I - 4 u. 1-.. .. _ a . ; I ...—-~..... . .._. — Q ,: .2.“ - “a. . «---1.J.¢H.. 5.“... ' ‘_..f,... ' . I .I I r‘.... I I. . _, . . ‘ ‘ . : ~ $4. 7' ; . .~ 9. U 1.0 Current Element Position r/b0 Figure 5.7-5 Computed Thickness Strain for Flange Elements at a = 45° Radial Logarithmic Strain 111 Computed Element Position r/bo Figure 5.7-6 Computed Radial Strain for Flange Elements at a = 0° 112 E] r0 = 2.4 0.". r0 = 2.3 ‘0’ row: 2.1 ‘7 r = 1.9 .30 _, 0.. , [5 r0 = 1.7 Radial Logarithmic Strain Current Element Position r/b0 Figure 5.7—7 Computed Radial Strain for Flange Elements at a = 45° Circumferential Logarithmic Strain 113 __' . , U" r0"'='2.4 IO :0 = 2.3 ' "0'" 7:30. B 52.1 v- r6513 - ‘6“,‘1-0 =."1,'7 .. Current Element Position r/bo Figure 5.7—8 Computed Circumferential Strain for Flange Elements VI. CUP-DRAWING EXPERIMENTS 6.1 Preliminary Remarks Many cup—drawing eXperiments have been performed and re- ported in the literature. Some of these eXperiments were intended primarily to analyze and thus better understand the drawing process, while others were performed to determine the accuracy of certain theories. The series of tests reported here were intended to be used for comparison with results of the theoretical investigation. After several preliminary cupping tests, it was decided that blanks of 4.800 inch diameter and 0.035 inch thick would be used. The blanks were cut from commercially-produced, aluminum— killed, low-carbon steel stock which had been carefully sheared from the coil, so that the rolling direction remained known. The blanks were reduced 46 percent in diameter (which is a safe maximum) during the single draw Operation. The die, Figure 1.1-1, was built to use a cylindrical punch 2.480 inches diameter, with a punch-profile radius of %-inch. The die ring had a cylindrical hole 2.587 inches in diameter with a die- profile radius of %g'inch. The ratio Of die-profile radius to sheet metal thickness was 0.188/.035 = 5.4. The die ring and the blank- holder were machined from tool steel, then hardened and ground. The punch was machined from SAE 1020 steel, but was neither hardened nor ground. The draw Operations were performed using a double—action draw die mounted on the bed of a 150 ton, straight-sided, single-action 114 115 Minster press, model number SC2—150-42-40—H. The press Speed used was 60 strokes per minute and the press stroke was 4 inches. The Minster press was equipped with a die cushion (a pneumatic cylinder attached to the press bed) to Operate the blankholder of the die. The blankholder force must be sufficient to prevent the formation Of wrinkles on the flange of the cup during the draw. Preliminary experimental work indicated that an air pressure of 13 psi in the die cushion was the minimum to consistently produce wrinkle—free cups. This corresponded to a blankholding force of 3980 pounds. 6.2 Producing a Polar-Grid Pattern on Sheet-Metal Blanks In order to experimentally measure the deformation and the strain associated with cupping of sheet steel, it is necessary to apply a suitably-chosen network of lines to the surface of the sheet metal blanks. Then, after cupping these blanks, the associated deformation and strain can be computed from suitable measurements. Many methods of applying a network of lines to sheet metal blanks have been tried and compared [86-90]. The electrochemical method was chosen for this work because it conveniently provides for suitable deformation measurements with minimal effect on the draw process. A ten-inch-square fibrous stencil, a felt pad, the sheet metal blank, and a power unit supplying a 15 volt A.C. current were used to etch a polar-grid pattern onto the sheet metal. The stencil has a polar-grid pattern which is electrically—conducting, while the remaining area of the stencil is non-conducting. The stencils, the power unit, the felt pad and the associated chemicals 116 were purchased from the Electromark Corporation of Cleveland, Ohio. Since it is essential that the rolling direction be carefully desig- H II nated on the blanks, 5%- x 54' rectangular-shaped coupons were square— sheared from the aluminum-killed sheet steel stock so that the longer 5% inch side was parallel to the direction of rolling. The polar-grid stencils, which are 10 inch square as pur— chased, were carefully cut to 5% inch width so that the roll dir- ection could be easily distinguished and marked after the etching Operation. It was estimated that the roll direction on the blanks is known within an error of 2“; the possible error is principally a result of the square shear operation and the etching Operation. H II The process of electro-etching the 5%-x 5%- sheet coupons as standardized for this series was as follows: 1. Clean both surfaces carefully using warm water and Oil immersion cleaner. 2. Rinse with warm water. Dry with clean towel. 3. Clean the surface with vythene degreaser using safety- glass cleaning tissues. 4. Lay sheet coupon on a flat piece of plywood so that one electrode of the power unit can be attached to a corner of the coupon. 5. Overlay the coupon with the electrolyte-soaked stencil. Position carefully for alignment. 6. Turn the power unit to the A.C. setting, using the maximum time-setting. 7. Apply the roller—type bench-mark with attached felt pad (soaked with electrolyte, and connected to the second terminal of the power unit). The actual electro-etching takes about 8-10 seconds as the bench- mark is rolled over the stencil and coupon completing the A.C. circuit. 117 8. Remove stencil and electrode from the sheet metal coupon. Rinse with warm water. Dry with clean towels. 9. Apply polarized Oil to both sides of the coupon to avoid oxidation of the coupons. 10. Mark each coupon to show the roll direction. After the rectangular coupons had been electro—etched, circular blanks had to be cut such that the center of the polar grid coincided with the center of the circular blank. Later, during the cupping Operation, the blank had to be centrally positioned on the punch so that a symmetrically-drawn cup was produced. During the preliminary cupping experiments, many difficul- ties arose, one Of which was maintaining coincidence of the blank and the punch centers during the draw operation. A second diffi- culty was in producing a blank edge which was square with the blank surface. Both of these difficulties were resolved by accurately reaming a 0.125 inch diameter hole at the center of the polar grid, and then turning a group of these blanks on the lathe after first mounting them on an eighth—inch diameter spindle. Since the strain in the bottom of the cup was not being investigated, this procedure proved to be a convenient compromise. 6.3 Measurement of Grid Spacing After the 4.800 inch diameter blanks had been prepared (with the polar grid pattern applied), suitable measurements were made to facilitate the required deformation and strain calculations at chosen angles to the direction of rolling. Since the aniso- trOpic computer analysis was carried out at 0° and at 45° to the 118 direction of rolling, the only eXperimental verification needed was along these two directions. Because of the symmetry in the sheet metal, the 0° dir- ection and the 180° direction are both in the roll direction. Since both are equivalent to the roll direction, each blank was studied to choose the particular direction most convenient from a measurement point-Of-view. Again, because of symmetry, any one of four directions (45°, 135°, 225°, and 315°) can be chosen for measurement at 45° to the roll direction; again a choice was made based on ease Of measurement for each blank. The experimental procedure for measuring grid distances on the blanks (and also on the flat portion of the cup flange after drawing) utilized a Jones and Lamson Optical Comparator and Measur— ing Machine, Model FC-l4. This machine incorporates micrometer— measuring equipment to indicate table displacements; the least count of the micrometers is 0.0001 inch. The comparator magnified the light reflected from the grid surface fifty times, which resulted in actual line widths of 0.005 inch appearing on the screen as .250 inch. Every fifth grid line is double width, approximately 0.010 inch wide, and hence is magnified to appear .500 inch wide on the screen. The grid distances were measured from the center line of one grid line to the center line of the neighboring grid line. This meant that the hair-line on the screen had to be lined up to coincide with the center of the magnified grid lines. Experience 119 indicated that measurement errors were caused by (l) the variation of quality of the etched lines, and (2) variation in judging the location of the center of the magnified grid line. After locating a particular grid centerline and taking a micrometer reading (least count of 0.0001 inch), I have returned to the same grid centerline within 30 seconds with a typical error of 0.0003 inch. A measure of the variation of these grid distances was determined by measuring each chordal grid distance four times and then calcu- lating the average and range of these four readings; each radial grid distance was measured five times, after which the average and range were computed. According to Keeler [91], the accuracy of the applied electrochemically-etched grid is equal to or better than a grid obtained by scribing. Keeler further states that 0.1 inch dia- meter grid circles can be produced with a diameter accuracy of 1% without the stress concentration factors associated with a scribed grid pattern. Pearce and Drinkwater [92] consider this question of accuracy. They conclude that an accuracy of 12% is reasonable to expect using a paper stencil. It should be noted that both of these references discussed the accuracy of producing a grid of specified dimensions. If the desired grid Spacing were 0.1 inch, then the actual grid spacing might be as low as 0.098 inch or as high as 0.102 inch assuming 12% accuracy. The radial increment on the polar grid pattern used in the experimental cupping tests reported in this thesis was supposed to be 0.1 inch. Since the 120 sample averages of the radial readings are indicative of the actual radial grid dimensions, a quick run-down of the experimental find— ings indicates only a very few radial grid readings outside the expected i2% accuracy. The experimental data collected in the series of chordal measurements indicated an average range, for the 156 chordal samples of four readings in each sample, of .000641 inch. Using Table I on page 155 of Moroney [93] or Table D on page 614 of Duncan [94], the factor d = 2.059 for a sample size n = 4 can be used to estimate the standard deviation for individuals from the average range. O - R7d - (.00064l)/(2.059) - .000312 inch is the estimated value for the standard deviation of the population of individuals from which the samples of four were taken. Using this computed estimate of the standard deviation for individuals, the Student "t" test can be used to estimate the maximum expected difference between the sample mean and the "true" p0pu1ation mean for any desired confidence limits. This is a significant calculation since the sample means were used for the deformation and the strain computations. 95% confidence limits were used, which implies that only once in twenty times one would expect a larger difference in the means. Figure 81, page 230, of Moroney [93] showed a value of t = 3.3 for three degrees of freedom (one less than the sample size). This information estimated the maximum eXpected difference in the means to be |§ - I] = (two/JR) = (3.3)(.ooo312//Z) = .00052 inch. 121 Applying this same procedure to the 122 samples of radial measurements (sample size was 5), the estimated standard deviation for individuals was 0 ='R/d = .00034. The maximum eXpected differ— ence of the means was then computed to be If - El = (tug/fr?) = (3.3)(.00034//§) = .0005 inch for the samples of radial measurements. The Student "t" test indicated that the sample averages approximated the true grid dimensions within :,0005. Since the sample averages for the radial dimensions varied from .0979 inch up to a maximum of .1014 inch, it was obvious that the experi~ mental measure of the radial grid dimensions on the sheet metal blank was necessary for the sake of improved accuracy, rather than assuming them to be 0.1 inch. 6.4 Exgerimental Cup Drawing In order to verify the computer-aided theoretical analysis of the cup-drawing process, it was decided to take a series of blanks with suitably etched polar grid patterns and partially draw each blank a different amount. Since the computer print—out from the theoretical analysis gave stress and strain results for radial dis— placements of the rim at 0.1 inch increments, it seemed desirable to get corresponding experimental strain data. However, the earing phenomenon resulted in rim elements at 45° to the roll direction moving in faster than elements at 0° and 90°. The cupping tests were planned so that the average of the rim displacements at 0° and 45° to the roll direction would correspond to the values of 122 the computer print-out from the theoretical analysis. A numerical indicator, mounted on the press ram, showed the distance from a zero reference up to the slide face at bottom dead center position of the crank. The least count of the indicator is 0.001 inch and it was possible to reset the slide to a predetermined reading within 31.002 inch without difficulty. A series of partially-drawn cups were produced during the preliminary investigation using the stan- dard 4.800 inch diameter blanks and the standardized draw die, so that the depth Of draw varied from a fully-drawn cup down to a partially-drawn cup where the punch had barely deformed the blank. In each case the indicator reading was noted as well as the average rim diameter of the cup. The diameter of the rim at 0° to the rolling direction was averaged with the diameter of the rim at 45° to the rolling direction to get the average rim diameter. A computer program then fitted a second degree equation to this data with an index of determination of 0.99897. A second computer pro— gram then predicted the ram indicator setting for pre—selected average rim diameters of the partially—drawn cups. This procedure proved to be convenient and useful. Another concern during the draw operation was the type and method of lubrication. The principal requirement for the work re— ported here was that the etched lines remain clearly visible after drawing. Lubrication literature is very extensive in the field of metal working Operations. Lloyd [95] reported in part 2 of a five— part article that one of the earliest examples of dry lubrication was the use of plastic polymer films. Wilson [96] reported the 123 results of a series of deep-drawing tests using several different lubricants. Rao [97] reported on the use of polyethylene for lubrication during sheet-metal drawing. He discussed alternative ways of applying the lubricant to the sheet metal. After considerable preliminary testing, it was found that 0.002-inch-thick polyethylene film provided excellent protection for the etched grid lines. A sandwich was produced by placing a sheet metal blank between two pieces of the polyethylene film and heat sealing the edges of the two polyethylene sheets with a heated wire. This encapsulated coupon then required only a drop of light oil on either side to give excellent protection and lubrication to the coupon. A series of nine cups were drawn using the standardized conditions discussed, and using the ram settings specified by the computer program. 6.5 Procedures Used to Compute Strain from Experimental Data Radial and tangential strain computations, based on experi- mental data, were needed for elements in the flange of partially- drawn cups. Strains at 0° to the roll direction and at 45° to the roll direction were determined for comparison with the results of the theoretical study. The tangential strains measured the change in length of a circumferential arc subtending a 2° central angle. For this small central angle, the chordal distances and the arc distances were equal for a desired accuracy of 0.0001 inch. 124 Radial and chordal distances for each material element in the flange (of the partially-drawn cup) at 0° and at 45° to the direction of rolling had to be experimentally determined. The corresponding distances in the blank (before drawing) then permitted logarithmic radial and tangential strains to be computed for each element. Each radial distance was measured five times and each chordal distance was measured four times to permit statistical evaluation. Computer programs for both radial strain and tangential strain were devised using the FORTRAN language. The data were placed in separate data programs which could be compiled with the associated main program as desired. Computations were performed on the G. E. 265 Time-Sharing Computer System. The two main programs, RADIAL and CHORD, and their associated flow charts are shown in Figures 6.5-l to 6.5—4. The flow charts were constructed following the suggestions of Moursund [98]. The main programs, such as RADIAL, each required at least two data programs. The first data program had to list radial grid dimensions for the blank along a particular radius, and the second must list corresponding grid dimensions after the cupping Operation. Four typical data programs associated with draw number 1, and used with the main program RADIAL, are shown in Table 6.5-1. RADlA program gives radial grid dimensions on the blank for draw number 1 at 0° to the direction of rolling, while RADlB gives the corre- sponding dimensions after drawing. RADlC program lists the radial grid dimensions on the blank for draw number 1 at 45° to the AVECHORD(J) + [CHORDW(J)+CHORDX(J)+CHORDY(J)+CHORDZ(J)]/4 RANGE(J) + [Maximum Value of Chord]-[Minimum Value of Chord] RANGE(J) I f[CHORDW(J),CHORDX(J),CHORDY(J),CHORDZ(J)] AVECHORD2(J) + AVECHORD(J) 1 I PRINT CHORDW(J),CHORDX(J),CHORDY(J),CHORDZ(J) J RINT AVECHORD(J),RANGE(J),STRAIN(J) W IAVECHORD3(J) + AVECHORD(J) l 1 l STRAIN(J) + LOG[AVECHORD3(J)/AVECHORD2(J)] (:7 STOP ::) K + K + 1 FIGURE 6.5-1 FLOW CHART FOR CHORD PROGRAM CH? 10 20 30 40 50 60 62 63 64 70 80 90 g 100 110 120 130 140 150 160 I65 170 180 190 210 220 230 250 26?) 270 275 310 320 325 326 327 328 329 330 340 350 126 40 0:2 DIMENSION CHOROXCIQ): CHOQDYCIQ): CHJRDZCIQ) DIMENSION CHORDW(12): AVECHUROCIQ): RANG€(12) SIGQANGE=O DIMENSION AVECHOQOZCIQ): AVECHOROS‘IQ): STRAINCIQ) 2 OO 9 M=102 3 OO 4 L=IaN STRAIN‘L)=0.0000 4 CONTINUE PRINT" CHORDW CHOROX CHOROY CHOROZ AVECURO RANGE STRAIN" 5 DO 70 K=102 10 DO 20: I=IpN READ:'CHORDW(I) READ: CHOROX(I): CHOROYCI): CHOROZCI) 20 CONTINUE PRINT DO 60: J=laN RANGECJ)= MAXIFCCHORDXLI): CHORDYCJ): CHORDZCJ):CHORDW(J))- +MINIF(CHOROX(J): CHORDYCJ): CHORDZ(J): CHORDWCJ)) SIGRANGE-‘SIGRANGE + RANGECJ) ' AVECHORDCJ)=(CHORDXCJ)+CHOQDY(J)+CHORDZ(J)+CHOROWCJ))/4 IF (K-I) 35:35:45 35 AVECHORDZ(J)=AVECHORD(J) GO TO 30 45 AVECHORDS(J)=AVECHORDCJ) STRAIN(J)=LOG(AVECHOQDH(J)IAVECHORDQ(J)) 3O PRINT 5%: CHOROW(J): CHOROX(J): CHORDY(J): CHUROZ(J) +3 AVECHOQD(J): RANGECJ): STRAINCJ) 50 FORMATC8F7od) 60 CONTINUE PRINT 7% CONTINUE PRINT"SIGRANGE" PRINT: SIGQANGE PRINT PRINT PRINT 9 CONTINUE END SDATA CORD7A: CORO79: CORO7C: COQD7O FIGURE 6.5-2 CHORD PROGRAM 127 <: START A:>———*:\ READ N M + N - 1 h———.i K + 1 \ READ V(I),.W(I), x(T), Y(I), 2(1) I + 1 l . YES 7 I + I + 1 I N0 J + 1 HL—7 l DELV(J) + ABS[V(J + 1) - V(J)] DELW(J) + ABS[W(J + 1) — W(J)] DELX(J) + ABS[X(J + 1) - X(J)] DELY(J) + ABS[Y(J + 1) - Y(J)] A... DELZ(J) + ABS[Z(J + 1) — Z(J)] RANGE(J) + [Largest minus smallest value of Delta (J)] AVERAGE(J) + [DELV(J)+DELW(J)+DELX(J)+DELY(J)+DELZ(J)1/5 AVERAGE2(J) + AVERAGE(J) ‘ ' PRINT DELV(J),DELW(J),DELX(J),DELY(J),DELZ(J) PRINT RANGE(J),AVERAGE(J),STRAIN(J) A AVERAGE3(J) + AVERAGE(J) J + J + l J < M STRAIN(J) + LOG[AVERAGE3(J)/AVERAGE2(J)] NO YES K + K + l < STOP NO FIGURE 6.5—3 FLOW CHART FOR RADIAL PROGRAM RAD 10 12 15 20 25 3O 35 M 41 43 45 46 47 48 49 50 55 6O 65 75 80 85 90 95 100 105 110 115 120 125 140 145 147 155 160 161 163 164 165 166 167 170 175 180 185 187 190 193 195 200 205 128 IAL N=9 DIMENSION STRAINCIZ) DIMENSION VIIQ): WC12) DIMENSION DELVCIQ): DELW(12) DIMENSION X(16): Y(16): Z(16) DIMENSION DELXIIS): DELYCIS): DELZ(15) DIMENSION RANGE(20)- DIMENSION AVERAGE(QO) DIMENSION AVERAGEZCED): AVERAGE3(29) SIGRANGE=O M=N'1 2 DO 9 L=1:9 PRINT"- V W X Y Z RANGE AVE STRAIN" 3 DO 4 I=1:M 4 STRAIN‘I)=O:OOOD 5 D0 70 K=102 19 D0 20 I=I:N READ: VII): N(I) 20 READ: XCI): YCI): Z(I) PRINT DO SO J=1:M DELVCJ1=AOSCVCJ+1)-V(J)) DELWCJ)=ARS(W(J+1)-H(J)) DELX€J1=ARS(X(J+1)-XCJ)) DELY(J)=ARS(Y(J+1)-Y(J)) DELZCJ1=AOS(Z(J+1)-Z(J)) RANGECJ)=MAXIF(DELV(J): DELW(J): DELXCJ): DELY(J): DELZ(J))' + MIN1F(DELV(J): DELW(J): DELX(J): DELY(J): DELZCJ)’ AVERAGE(J)=(DELVCJ)+DELW(J)+DELX(J)+DELYCJ)+DELZ(J))l5 SIGRANGE=SIGRANGE + RANGECJ) IF (K-I) 35:35:45 35 AVERAGE?(J)=AVERAGECJ) GO TO 55 6M FORMATC8F7o4) 45 AVERAGE3CJ)=AVERAGE(J) STRAINCJ)=LOGCAVERAGE3(J)/AVERAGE2(J)) 55 PRINT 60: DELV(J): DELW(J): DELX(J): DELY(J): DELZ(J): +RANGE(J): AVERAGE(J): STRAIN(J) SO CONTINUE ‘ PRINT PRINT 70 CONTINUE PRINT"SIGRANGE" PRINT: SIGRANGE PRINT PRINT PRINT PRINT 9 CONTINUE END TDATA RADIA: R4014. RADIO. :4110 FIGURE 6.5-4 RADIAL PROGRAM 129 TABLE 6.5-1 TYPICAL COMPUTER PROGRAMS RADIA 560 570 580 590 6001 610 , 620 630 640 .1570: .2564: .3558: 045503 0554fl3 065483 .7544: 085343 .9561: RADIB 560 570 580 590 600 610 620 630 640 0G7443 018193 0287G3 .3918: 049483 .6006: .7035: .8049: 091083 RADIC 560 570 580 590 600 610 620 630 640 .1572: 025773 035663 045653 .5557: 065643 .7562: 085593 095253 RADIO 560 570 580 590 600 610 620 630 640 .0000: 016453 .2G77’ 03105: 041323 .5170: 061573 072g23 031963 .1568: 025643 .3557: 045513 055453 .6549: .7538: 085343 095623 057413 .1812: 028733 039233 049553 .6007: 070343 080533 091123 .1572: .2574: .3565: 045623 055563 065653 075583 .8558: 095233 -.0005: .1044: 029743 031@83 041323 051693 061843 .7201: 081973 FORIMDIALIMTA .1557: .2550: 035473 045383 055253 .6537: 075293 .8522: .9543: 097453 .1815: .2870: 039193 049543 .6008: 07g313 089493 091123 .1583: 025833 035723 045663 055623 065733 075673 085633 095363 000523 .1098: 021323 031623 .4183: .5229: 0624Q3 072573 .3254: 01G7®3 020593 030553 043473 050323 069463 079493 .8034: 09QSS3 0Q7483 018083 028663 039173 049513 066063 07Q323 080513 .9196: .0058: 0IQ6M3 .2056: 03QSQ3 04fl423 .5057: .6048: .7045: 080183 009953 011463 021763 032073 .4232: 052713 062853 073G33 .8300: .1067 .2057 .3055 .4046 .5031 .6044 .7035 .8031 .9058 .0751 .1813 .2870 .3919 .4950 .6008 .7032 .8052 .9106 .0054 .1054 .2052 .3052 .4043 .5053 .6047 .7043 .8023 .0080 .1128 .2161 .3192 .4215 .5252 .6269 .7284 .8284 130 TABLE 6.5-2 COMPUTER PRINT-OUT FOR RADIAL STRAIN - DRAW NUMBER 1 RADIAL v w x Y z RANGE AVE STRAIN .0994 .0996 .0993 .0989 .0990 .0097 .0992 0.0000 .0994 .0993 .0997 .0996 .0998 .0005 .0996 0.0000 .m992 .0994 .0991 .9992 .9991 .0003 .0992 9.0090 .0990 .0994 .0987 .0985 .0985 .0309 .0988 0.0300 .1008 .1004 .1012 .1914 .1013 .0010 .1010 0.0090 .0996 .0989 .0992 .0994 .m991 .0007 .0992 z.@000 .9990 .0996 .0993 .0994 .0996 .0006 .9994 @.@0@@ .1027 .1028 .1021 .1921 .1027 .0007 .1025 0.0000 .1066 .1971 .1070 .1060 .1062 .0011 .1066 .0714 .1060 .1061 .1055 .1058 .1057 .0006 .1058 .0610 .1043 .1047 .1049 .1051 .1049 .0034 .1049 .0557 .1030 .1035 .1035 .1034 .1031 .0005 .1033 .0443 .1058 .1052 .1054 .1055 .1058 .0006 .1955 .0438 .1029 .1027 .1023 .1026 .1024. .0006 .1026 .0331 .1914' .1019 .1017 .1019 .1020 .0006 .1018 '.4239 .1959 .1059 .1064 .1055 .1054 .0010 .1058 .0321 v w x Y z RANGE AVE STRAIN .1005 '.1@02 .1090 .1002 .1300 .9905 .1092 0.0000 .0989 .0991 .0989 .0996 .0998 .0909 .0993 0.9900 .0999 .0997 .0994. .0994 .1000 .0006 .0997 0.0000 .0992 .0994 .0996 .0992 .0991 .mmns .0993 0.9090 .1007 .1009 .1011‘ .1015 .1010 .0008 .1019 0.0000 .0998 .0993 .0994 .0991 .0994 .4097 .w994 0.0000 .0997 .1000 .0996 .0998 .0996 .0404 .9997 0.0000 .0966 .0965 .0973 .0972 .0980 .9215 .9971 0.0000 .1045 .1049 .1046 .1051 .1048 .0006 .1048 .0449 .1032 .1039 .1934 .1030 .1933 .0004 .1032 .0387 .1028 .1034 .1030 .1031 .1031 .0006 .1031 .0335 .1027 .1024 .1021 .1925 .1923 .0006 .1024 .0307 .1038 .1037 .1046 .1m39 .1037 .mnm9 .1039 .0283 .1017 .1015 .1m11 .1014 .1017 .0006 .1015 .0297 .1015 .1017 .1917 .1018 .1015 .0003 .1016 .0189 .0994 .0996 .9997 .0997 .1000 .0006 .0997 .0260 131 direction of rolling, while RADlD lists the corresponding grid dimensions after cupping. A typical computer print-out page is shown in Table 6.5-2 for the RADIAL program and the radial data programs for draw num- ber l. The top eight rows are for the eight radial grid dimensions on the blank at 0° to the roll direction. Since each radial grid dimension was measured five times, these are listed in the first five columns. The sixth column lists the range for the five dim- ensions while the seventh column lists the arithmetic average for the five radial grid dimensions. The second group of eight rows represents the corresponding radial grid dimensions at 0° to the roll direction on the partially-drawn cup; the logarithmic radial strain for each element is listed. The two bottom groups of eight rows each are for the radial dimensions at 45° to the direction of rolling. The first of these two refer to the dimensions on the blank, while the last one refers to the corresponding dimensions on the flange of the cup. 6.6 Results The results of this experimental phase of the investigation are summarized in graphical form as Figures 6.6-l to 6.6-4. On each graph, dash lines were used to show the distribution of strain across the flange for a particular partially—drawn cup. Any solid lines follow the strain history of a particular element during the process of drawing a flat circular blank into a cup. Some of the rim element points, shown by small squares, have been identified with a particular partially-drawn cup to facilitate comparisons. 132 The abscissa values for each graph were computed as di— mensionless values of the current position of the element by dividing the current radial position of the element by the rim radius of the blank. Each partially-drawn cup was measured on the Optical comparator to determine the rim diameter in the rolling direction and at 45° to this direction. Then the current radius for each element was determined from the current rim radius and the current radial grid dimensions. For example, the rim diameter for draw number 1 at 0° to the roll direction was measured to be 4.6451 inches, which gave a current rim radius of 2.3225 inches. At this rim radius, Table 6.6—1 lists the circumferential logarithmic strain as -.0525, which was plotted on Figure 6.6-2 against a current position of the element of r/bo = 2.3225/2.4 = 0.97. The outermost element of this partially—drawn cup has a radial logarithmic strain of 0.0321 as listed in Table 6.5-2. This strain was computed from the change in length of a radial line approximately 0.1 inch long extending in from the rim. The current position of this element was computed by subtracting half of the current radial length of this line from the current rim radius, i.e. r = 2.3225 - 0.5(.1058) = 2.2696 inches. Figure 6.6—5 gives the depth of draw vs. the current rim position b/bo based on measurements taken from the nine partially- drawn cups. This graph shows that, at any particular depth of draw, the rim element at a = 45° has been displaced (radially inward) a greater distance than the corresponding rim element 133 at a = 0°. This figure also gives an indication of the earing which occurred during the cupping eXperiments. Figure 6.6-6 is a plot of the strain ratio, er/ee, as a function of the draw number for the element r0 = 2.35 inches, which corresponds to the rim element (see Figure 6.6-5 to relate draw number to either depth of draw or to b/bo). This figure was drawn to determine if proportional straining occurred during the cup- drawing process. Although the experimental evidence is limited, it does give support to the hypothesis of proportional straining during the draw. CHORD CHORDW .0567 .0595 .0624 .0659 .0700 .0738, .0775 .0804 .0841 .0514 .0542 .0584 .0617 .0661 .0699 .0725 .0761 .0789 CHORDN .0563 .0588 .0629 .0665 .0697 .0732 .0773 .0800 .0839 .0536 .0577 .0607 .0645 .0676 .0707 .0736 .0770 .0797 134 TABLE 6.6-l COMPUTER PRINT-OUT FOR TANGENTIAL STRAIN - DRAW NUMBER 1 CHOQDX .0562 .0589 .0628 .0654 .0687 .0726 .0767 .0803 .0837 .0503 .0539 .0587 .0622 .0662 .0691 .0731 .0763 .0800 CHORDX .0562 .0594 .0639 .0669 .0702 .0729 .0766 .0804 .0837 .0535 .0572 .0609 .0639 .0671 .0709 .0740 .0783 .0811 CHORDY .0566 .0601 .0629 .0661 .0704 .0735 .0774 .0811 .0847 .0504 .0540 .0586 .0626 .0657 .0693 .0728 .0762 .0802 CHORDY .0556 .0589 .0628 .0665 .0698 .0737 .0765 .0800 .0838 .0530 .0575 .0604 .0644 .0676 .0708 .0779 .0809 CHORDZ .0557 .0595 .0627 .0656 .0698 .0732 .0773 .0805 .0839 .0509 .0541 .0586 .0624 .0659 .0689 .0733 .0760 .0801 CHORDZ .0567 .0595 .0628 .0663 .0706 .0731 .0767 .0806 .0845 .0533 .0571 .0607 .0642 .0672 .0708 .0734 .0782 .0813 AVECDRD .0563 .0595 .0627 .0657 .0697 .0733 .0772 .0806 .0841 .0507 .0540 .0586 .0622 .0660 .0693 .0729 .0761 .0798 AVECORD .0562 .0591 .0631 .0665 .0701 .0732 .0768 .0802 .0840 .0533 .0574 .0607 .0642 .0674 .0708 .0739 .0778 .0807 RANGE .0010 .0012 .0005 .0007 .0017 .0008 .0010 .0011 .0003 .0003 .0009 .0005 .0010 .0008 .0003 .0013 RANGE .0011 .0007 .0011 .0006 .0009 .0008 .0008 .0006 .0008 .0006 .0006 .0005 .0006 .0005 .0002 .0012 .0013 .0016 STRAIV 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 '01638 -o@961 -.0681 “OWSSI -.0553 ‘0“558 ‘0“573 -.0565 -.0525 STRAIV 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 -.052@ -.0305 “00392 -.0352 -.0393 -.0337 “00322 -.0304 -.0392 Radial Logarithmic Strain 135 “1' V .9 1.0 Current Element Position r/bo Figure 6.6-1 Experimental Radial Strain for Flange Elements at a = 0° -o 30 -.20 -010 Circumferential Logarithmic Strain 1 .. . . .-A, .1. . , ... . _ . . J ... , . ' ; . , . l 1 .- +| - i .. . u I- ‘1 - ~ - . ‘~.— . 1. —. ~O.-C.Y."HI-. .. -g-o o-l... . ...l ..7 *1 . v.51... . r ‘ ‘ ‘ I ‘ .. . . ' I ‘ >1‘ , - . 136 2.4 2.3 2.1 1.9 1.7 #40013 e o .. .....— .’ '-~ ... ‘ . 1 ... 1 I 4 .. . _ _ .4-. 1.- .-,. -_-<" .. F ‘ v ; 4 “‘ ' __.r. . . §.,I - , . .‘ .‘w L I U ‘1 9 LA - l L anaa-wyn—l . ' n . r.',.“-¢ ; .‘ . ... 1"“.".+'.~ . , my . a .'I:. .3 i J ...... ~ .3 A.» ‘f—‘j fl :17.‘1-.. 7* ; . .7 ‘ A ‘ . , . .1. H14 . . ._ - - 4‘ .H ..‘..A..: . .7- -. wan-1.4-. *0.‘ -f. 41...“-.. B- ..a.117...‘11.. ..--.JJ.. .. ..1 L1. ! ‘7 . .. J .. .. .‘ .,i... '1. ._.,,_ 11 .I . ., “4.. I 1 4. if. .' f. ‘ -:1. 1‘ . O .4 ..-_ I L I 1 .. r 1.0 Current Element Position r/b0 Figure 6.6-2 Experimental Circumferential Strain for Flange Elements at a = 0° Radial Logarithmic Strain 137 .30 .20 'v 'f ‘ 1.;L_. 7 ..1.. _‘ . .45039015k§,41@ u-, .10 4*? Draw Na. 2 .6 .7 .8 .9 1.0 Current Element Position r/b0 Figure 6.6-3 Experimental Radial Strain for Flange Elgnents at a = 45° 138 n _- .. -" __._,_, .. '7 ,... r-. u'. m. _ u... fl. a. p. ‘_. . . ‘1 ‘8‘..- I .. fDMW 10.6 ‘ l I l,» -050 -.40 0 3 _ -.20 -.10 nwmuum Uganuwumwoq amauaoummaboufiu 0 Current Element Position r/b Figure 6.6—4 Experimental Circumferential Strain for Flange Elements at a = 45° Depth of Draw - Inches 139 1.50 1.00 .50 .6 .7 .8 7.9 1.0 Current Rim Position b/bO Figure 6.6—5 Depth of Draw vs. Rim Position Strain Ratio er/e6 140 "g .. .~ , >J—L5153. >. ..I .40 e ' mi-m—a-w-T-L‘m -~ .- '- . ‘7 -A f . AI ' . I . .. t. n '. ;.. . , u , ‘ I t . 4‘ . . z. . . ‘ - r .—< A o ‘ I ‘ 1 I I ‘ ‘. , . 20 ‘4 ‘— .. - a... -,.. ..A J 4' Max-.4-.— -3..~-..4 ..-.r_-- ”To. --—- a . . . -- o p' .L. I . . - ’ ' Y ..' . , L . l . . . , .. . . t , . g " n ,. . . A a q I 10 'u , I. .1 . ,. .» O p. ~01- _ ‘-. . .‘-~‘ . _. - ' - . --_ . .1 : o - I. - q o - s 4 . § A g 8 . -t s... o l r. . '1. b i . A A A A i ' A v 1 2 3 4 5 6 7 8 9 Draw Number Figure 6.6—6 Experimental Strain Ratios vs. Draw Number for the Element r0 = 2.35 VII. SUMMARY AND CONCLUSIONS 7.1 Preliminary Remarks Chapter 5 reports on the theoretical strain analysis of the cup-drawing process, while Chapter 6 reports the strain results from the experimental cupping tests. Section 7.2 of this chapter compares . the theoretical results from Chapter 5 to the experimental results from Chapter 6. No comparison of the results of this investigation with results reported by other investigators was made, since it was believed that a comparison of the theoretical to experimental results from this investigation would be more direct and meaningful. The specific conclusions resulting from this study and recommendations relative to future possible studies are.reported in section 7.3. 7.2 Comparison of the Theoretical Strain Field with the Experi- mentally-Determined Strain Field As was stated in the resultsof section 5.7, the computed strains from the theoretical investigation did show a marked difference between the rolling direction where a = 0° and the direction a = 45°, and the relative magnitudes did correlate qualitatively with the ex— perimental evidence of ears at a = 0° and a = 90°. Similarly, the graphical display of the experimentally-determined strain field, Figures 6.5-1 through 6.5-4, indicated strain differences with a change in orientation. The theoretical analysis does not give any indication of the relationship of the computed strains to the depth of the draw, since it does not provide a relationship between depth of draw and rim radius. In order to compare quantitatively the results of Chapters 5 141 142 and 6, the theoretical and the experimental strain histories for the rim elements at a - 0° and a = 45° are plotted as a function of the current rim position b/bo in Figures 7.2-1 and 7.2-2. Figure 7.2-1 is a plot of logarithmic circumferential strain for the rim element ro - 2.4 inches as a function of the current rim position b/bo. The theoretical strain is plotted as one curve identi- fied by small square boxes and a solid line. The least-squares method was used to get the curves for the experimental data. As was pointed out in Chapter 5, the assumption of strictly radially—inward motion of each element implies that no difference in circumferential strain exists for different angles a, if plotted against the current rim position. It can be seen from Figure 7.2—1 that this assumption was only approximately correct. Figure 7.2-2 is a plot of logarithmic radial strain for the "rim" element as a function of the current rim position b/bo. The radial strain at the "rim" was experimentally determined by measuring the length of the radial line between r = 2.3 and r0 = 2.4 inches 0 at successive partial draws; hence the experimental radial strain for the rim was associated with the mean initial radius of the element r0 = 2.35. The curves from experimental data are "best—fit" curves. In this illustration, the theoretical strain histories for the rim elements (r0 = 2.4 inches) at a = 0° and a = 45° are both identified by solid lines, the line for a = 0 is marked with small squares to differentiate it from the line for a = 45° which is identified with small circles. It is clear from looking at Figure 7.2-2 that the theoretical radial strains are smaller in magnitude than the 143 experimental curves. This is probably a result of the experimental difficulties associated with determining Hill's anisotrOpic yield func— tion by the direct method. Possibly some of this discrepancy might have resulted from the arbitrary choice of u = 0.06 as the coefficient of friction between the sheet metal and the die components. Another possible source of error might have resulted from the plane stress assumption near the end of the draw, when the entire blankholding force is carried by a reduced flange area. Additional errors were very likely introduced by the approximations in the analysis, but it is believed that the major error was in the yield function determination by the direct method. 7.3 Conclusions and Recommendations The following conclusions are based on results from the theo- retical and the experimental study: 1. The method used to include planar anisotropy in the theoretical analysis did result in stress and strain fields of the type associated with the 0° and 90° earing which occurred during the experimental study. 2. The radial strain fields for the 0° and 45° directions indicated smaller magnitudes from the theoretical analysis than was evident from the experimental analysis. 3. The strain—ratio method of measuring anisotropy resulted in an indication of greater anisotrOpy for the aluminum- killed steel than the direct method. 4. Rim elements experience proportional straining during the cup-drawing Operation. 5. The method of electro etching grid lines on the blanks used in the cup—drawing experiments was not completely satisfactory. The lines were not consistently distinct and uniform; this resulted in certain inaccuracies in the experimental data. 144 The following recommendations are suggested for use in future cup—drawing investigations of this type: 1. 2. The strain-ratio method should be used to determine the anisotropic yield function. The linearized approximation to the anisotropic yield function should not be used. This approximation was not essential in this study and probably saved less time than anticipated. A total-deformation theory might be used in future analyses, since the assumption of prOportional straining is supported by both theoretical and experimental results of this in- vestigation. Other methods of imprinting grid lines on the sheet metal blanks should be considered including the technique de- veloped by the printed circuit industry. This is mentioned on page 199 of the article by Palmer [90]. Circumferential Logarithmic Strain -.30 -.20 -.10 145 ‘ t .47.“- '.. ‘ ‘ am me... -... -O‘-~ r..- ’— o. .4 i ‘. .- c O \ .—s~ - . L. ‘.-_4~‘.-«-. Av.- 4‘. .. . . .._¢- 3 .. I .. -4- .l 4. ‘ 6.1 v- «.4 o Mini}. “~41" :....‘:‘-;._;i - . *‘ ‘iiiftftt‘; -: ~ W ~ , .1 ~v Hi 4. A w. 4 ,_ . ,1 o; o 1 .4', . ,r —... ->+ «a... .o—a-é-q -.... 3.. §-~—7¢—--> . .1 A- 0 ,§, .7 .- . .3 44 l . . .- “u—ow a Hod...~ vv—a.- . fi>~e . o , . y-“ :—.u W I .M4- ‘-n .“|-—.-—- H—O A< Q a4“ ‘- . 'n.“ V - «Q a . ‘. . ' , ~. .1 . r . . ' 7..-. I . I. ‘4 ‘-. ' ... . .l—A 4.. . p—w , 1 #— OMI- ck» “Md-l- J..— M . 1 4+4; .‘. ._ -.. . o -. 4 ' r . ML 3 i -.,. . +1-1“. r‘.}. .. ,. .r - J... - ,— .. - .. — - .‘_. -5“ gar-4-- - . L. FY 1-4 . qa‘ . J- .. . e5. . :l-A‘ a ‘ , .. '. . i 4. I ‘ . A A AA A Y, o . ‘ 1.0 Current Rim Position b/b0 Figure 7.2-1 Comparison of Theoretical and Experimentally- Determined Circumferential Rim Strains Radial Logarithmic Strain 146 '40 " --—'"'"," --'*.--‘-. Experimental a 0° 4— a..---.......k Experimental (1 45° . * H... 5h 1 Theoretical a 8 0° ’ 45° :: ' '. - ~ 0 , Theoretical a .6 .7 .8 .9 1.0 Current Rim Position Figure 7.2-2 Comparison of Theoretical to EXperimentally- Determined Radial Rim Strains. APPENDIX ANI 100 110 120 125 126 130 140 150 160 162 164 166 168 190 200 210 215 216 220 230 240 250 260 270 280 390 400 410 510 520 530 535 540 550 560 APFHHHX C7 LET RO=203 LET R1=RO LET 803204 -LET L330810/27050 LET L1310027 LET TO=cO35 LET T330 LET N=-.005 FOR X1=BO T0 o499*80 STEP N IF X1>=2o2 THEN 930 IE Kl>2o0 THEN 940 IF x1>1.3 THEN 950 IE X1<=108 THEN 960 LET R3 SQRCXI'Z ' (BO'Q-RO'2)*T0/T6) LET D1=R1-R GGSUB 510 LET L3=27050+60700*(L0G(RO/R))70518 LET L4=L*L3 LET T7=(14073*52‘70905*L3)/(14069*L3'70288*52) LET T8=‘01*T7/R LET R1=R LET E=o0001 FGR I=204 T9 1.199 STEP -o1 IF ABSCXl-I)