Y ;" iNVESTEGATIQEd SF A DYNAMIC SAINT-VENANT REGEON N A SEMI-ENFINSTE STRIP 7 Thesis for the Degree of Ph. D. MICHIGAN STATE UNIVERSITY HARTLEY T. GRANDIN, JR. 1972 “ems This is to certify that the thesis entitled INVESTIGATION OF A DYNAMIC SAINT-VENANT REGION IN A SEMI-INFINITE STRIP presented by Hartley T. Grandin, Jr. has been accepted towards fulfillment of the requirements for Ph.D. degree in Mechanics Major professor ; \ MW ‘ I . 1 0-169 LIBRARY MlChlgan State University ABSTRACT INVESTIGATION OF A DYNAMIC SAINT-VENANT REGION IN A SEMI-INFINITE STRIP By Hartley T. Grandin, Jr. The investigation examines the steady state response of a semi-infinite strip with stress-free edges to time-harmonic self- equilibrated shear and normal stresses on the finite edge. The mathematical analysis is based on the equations of linear elasticity for generalized plane stress and involves a biorthogonal eigenfunction expansion of a four component stress vector. Solutions for three different boundary stress distributions at one frequency are examined in detail and reveal significant non- decaying stress modes. The shapes of these modes are shown graphically. The eigenvalues are tabulated for seven different frequencies between 100 and 100,000 cycles per second. INVESTIGATION OF A DYNAMIC SAINT¥VENANT REGION IN A SEMI-INFINITE STRIP By Hartley T. Grandin, Jr. A THESIS Submitted to Michigan State University in partial fulfillment of the requirements for the degree of DOCTOR OF PHILOSOPHY Department of Metallurgy, Mechanics and Materials Science 1972 ACKNOWLEDGMENTS I wish to express my gratitude to Dr. Robert Wm. Little for his encouragement to enter upon a formal graduate degree program and his guidance throughout my course of study. His interest in this research endeavor and seemingly unlimited capacity to sort order out of chaos have contributed immeasurably to the tangible results embodied in this paper and the intangible personal inspiration of its author. I wish to thank Committee members Dr. Gary L. Cloud, Dr. J. Sutherland Frame, and Dr. George E. Mase for their help and suggestions. Finally I would like to express my indebtedness to Dr. Donald J. Montgomery for his support during my course of study at Michigan State University and to the Division of Engineering Research for the financial support during a portion of this research. ii Chapter I. II. III. TABLE OF CONTENTS ACKNOWLEDGMENTS LIST OF TABLES LIST OF FIGURES LIST OF PRINCIPAL SYMBOLS INTRODUCTION 1.1 Historical Background 1.2 Problem Statement 1.3 Assumptions and General Solution Outline FORMULATION 0F PROBLEM FOR FIRST MIXED BOUNDARY CASE 2 1 Equations of Elasticity 2 2 Boundary Conditions 2.3 Equations for the First Mixed Case 2 4 Solution of the Equations for First Mixed Case 2.5 Definition of the Biorthogonal Operator and the Adjoint Equation 2.6 Solution of the Adjoint Differential Equation 2.7 Summary FORMULATION 0F PROBLEM FOR SECOND MIXED BOUNDARY CASE 3 1 General Remarks 3 2 Boundary Conditions 3.3 The Auxiliary Variable, Q 3 4 Equations for the Second Mixed Case 3 5 Solution of the Equations for Second Mixed Case 3.6 Definition of the Biorthogonal Operator and the Adjoint Equation 3.7 Solution of the Adjoint Differential Equation 3.8 Summary iii Page ii vii viii bur—I 14 17 19 21 21 21 22 23 25 29 33 3S Chapter Page IV. FOUR-VECTOR FORMULATION FOR THE PURE STRESS CASE 37 4.1 The Odd Problem Four4Vector Formulation 37 4.2 The Even Problem Four-Vector Formulation 38 4.3 Four4Vector Form of the Biorthogonality Operator 40 V. SATISFACTION OF BOUNDARY CONDITIONS ON THE SURFACE X = 0 43 5.1 Procedure Outline 43 5.2 The Adjoint Function Arbitrary Constants 44 5.3 Satisfaction of Boundary Conditions for the Odd Problem 45 5.4 Satisfaction of Boundary Conditions for the Even Problem 50 VI. DETERMINATION OF THE EIGENVALUES 54 6.1 General Remarks 54 6.2 Determination of the Real Eigenvalues for the Odd Problem 54 6.3 Determination of the Real Eigenvalues for the Even Problem 57 6.4 Determination of the Complex Eigenvalues for the Odd and Even Problems 58 VII. SPECIFIC BOUNDARY VALUE PROBLEMS 64 7.1 General Remarks 64 7.2 The Boundary Term FS 65 7.3 Results and Conclusions 66 BIBLIOGRAPHY 8O APPENDICES APPENDIX A. TABULATED EIGENVALUES 82 APPENDIX B. ASYMPTOTIC SOLUTION OF THE ODD PROBLEM TRANSCENDENTAL EQUATION 89 iv Table VI-l VI-Z VI-3 VI-4 VII-l VII-2 VII-3 A-l A-2 A-4 LIST OF TABLES Real Eigenvalues and Phase Velocities for the First Four Modes of the Odd Problem Real Eigenvalues and Phase Velocities for the First Four Modes of the Even Problem Comparison of Low Frequency, Odd Problem, Complex Eigenvalues with the Static Problem Eigenvalues Comparison of Low Frequency, Even Problem, Complex Eigenvalues with the Static Problem Eigenvalues Convergence of Eigenfunction Constants for Problem 1 Convergence of Eigenfunction Constants for Problem 2 Approximation of Boundary Function, Problem 1 Roots of Transcendental Equations (6.1-1) and (6.1-2) Frequency = 100 cycles per second Roots of Transcendental Equations (6.1-1) and (601-2) Frequency = 1000 cycles per second Roots of Transcendental Equations (6.1-l) and (601-2) Frequency = 6380 cycles per second Roots of Transcendental Equations (6.1-1) and Frequency = 10000 cycles per second Roots of Transcendental Equations (6.1-1) and (601-2) Frequency = 31600 cycles per second Page 59 6O 62 62 70 71 72 82 83 84 85 86 Table Page A-6 Roots of Transcendental Equations (6.1-1) and (6.1-‘2) Frequency = 63800 cycles per second 87 A-7 Roots of Transcendental Equations (6.1-l) and (601 -2) Frequency = 100000 cycles per second 88 vi Figure VI-l VI-2 VI-3 VII-1 VII-2 VII-3 VII-4 VII-5 VII-6 VII-7 LIST OF FIGURES Phase Velocity Variation for the First Three Modes of the Odd Problem Phase Velocity Variation for the First Three Modes of the Even Problem Eigenvalues in First Quadrant of Complex Plane for Frequencies of 1000 and 31600 cycles per second; a = X + iY Boundary Stresses on Surface x The Non-Decaying Wave Modes at Stress 0 at x = 0, Problem YY Boundary Stresses on Surface x The Non-Decaying Wave Modes at Stress ny at x = 0, Problem Boundary Stress Oxyb Modes at x = 0, Problem 3 vii X X 2 and the Non-Decaying Ox 0, Problem 1 = 0, Problem 1 0, Problem 2 = 0, Problem 2 y Page 61 61 63 73 74 75 76 77 78 79 LIST OF PRINCIPAL SYMBOLS stress components in Cartesian coordinates. auxiliary "stress like" variable. displacement components in Cartesian coordinates. boundary stress and displacement functions on the finite edge x = 0. angular frequency. time. density. Young's modulus. Poisson's ratio. propagation constant in the x direction equal to Zn divided by the wavelength. 2 = 1%2 _ EL (1 _ V2) a E d 2 ='l\/;2 - £QQ_ (1 + v) a E = (1 + n2)/(\)n2 - v - 2) = (vn2 + 2n2 - v)/(1 +~n2) v _ 1 . . . = , eigenvector of the first mixed v2 boundary case. z7 1 = z , adjoint problem eigenvector for the 2J first mixed boundary case. viii = , eigenvector of the second mixed WZJ boundary case. L = , adjoint problem eigenvector for u2 the second mixed boundary case. J eigenfunctions of the four-vector formulation. normalization constants. arbitrary constants of the adjoint functions. w/a , phase velocity. \IE/p , phase velocity of infinitely long waves in a cylinder. 2 1:— (1 - v2). represents complex conjugate transpose. represents complex conjugate. CHAPTER I INTRODUCTION 1.1 Historical Background In 1853, Barre de Saint-Venant presented his solution for torsion in long prismatic bars of various cross sectional shapes (1). In this solution, he was able to satisfy the end conditions producing the twist in the bar only up to a resultant force and couple, the distribution of which, he assumed, could differ from the required distribution in the body of the bar. He postulated that variations in the distribution of statically equivalent end loadings must have little effect on the twisted bar except near the ends. This declaration became the basis for what is now known as the Saint-Venant principle. In a footnote of his memoir, Saint-Venant went on to say that the influence of forces in equilibrium acting on a small portion of a body extends very little beyond the parts upon which they act (2). The importance of this principle in the subsequent develop- ments of the theory of elasticity cannot be over-stated, and the problem of providing mathematical clarification of the principle and justification of its use has been the subject of serious consideration since its enunciation. As a practical matter, analytical stress analysis of equilibrium systems using classical theory constantly resorts to the principle by replacing one force system with a statically equivalent one with the assumption that the resulting errors exist in a region extending very little beyond the surface of application. Indeed, without the use of this principle, many problems would be too complicated to solve. The earliest solution for a system of forces in equilibrium on the edge of a plate is attributed to Thomson and Tait (1867), followed by a more complete solution by Maurice Levy (1877), (3). M.J. Boussinesq (1885), (4), one of the most distinguished pupils of Saint-Venant, was able to define the region of local perturbation resulting from the application of statically equivalent systems of loads normal to the infinite half Space. This work has been a standard reference in textbooks as proof of the Saint-Venant principle. As recently as 1945, von Mises (5) argued that Boussinesq's solution was for a particular loading, and that Saint-Venant's principle in its traditional form does not hold true if equilibrant force systems are introduced tangent to the plane surface. He prOposed to modify the principle with the introduction of the concept of astatic equili- brium which requires forces to remain in equilibrium when rotated through any angle. E. Sternberg (1953), (6) supplied a precise formula- tion and proof of the SainEVenant principle as modified by von Mises. The von Mises-Sternberg papers define the Saint-Venant boundary region for bodies having very general geometries. Recent engineering requirements have necessitated the determination of the magnitude of the stresses in this boundary region for specific geometries. Tech- niques now exist to investigate the stress distribution in the Saint- Venant boundary region for particular time-independent boundary con- ditions on the semi-infinite strip (7), cylinder (8), wedge and cone (9). The investigation of the possible existence of a dynamic Saint-Venant region is limited. B.A. Boley (1954), (10), using a simple model, found that a region similar to the static boundary region exists for slowly applied loads; but as the rate of loading is increased, the region extends to longer portions. L.w. Kennedy and O.E. Jones (1969), (11) examined the effect of altering the radial distribution of statically equivalent pressure step loads on a semi-infinite cylinder having zero lateral displacement on the end. They concluded that any differences in time-average dynamic stresses and strains are negligible at distances greater than five times the cylinder diameter, and differences in peak values are small at dis- tances greater than twenty diameters. The effect of a self-equili- brated load representing the difference between the two statically equivalent applied loads remains undetermined. The Kennedy and Jones investigation, as well as other of the most recent studies in wave propagation, employed transform techniques which permit asymptotic solutions to the equations of motion at large propagation distances only for the mixed end boundary conditions of one stress and one displacement (12). The important Saint-Venant boundary region with pure end stress conditions specified still re- quires investigation. 1.2 Problem Statement A semi-infinite strip with stress free edges is end loaded with time-harmonic self-equilibrated shear and normal stresses. The decay characteristics of the resulting stress distribution and pro- pagation modes are investigated through the analytic solution of the equations of linear elasticity. 1.3 Assumptions and General Solution Outline The homogeneous, isotropic, linearly-elastic, semi-infinite strip occupies the region -1 s y s l and x S m. The solution is based on the linearized equations of elasticity for generalized plane stress and is obtained by use of an extension of a technique of biorthogonal eigenfunction expansion developed by M.W. Johnson and R.W. Little (1965), (7). The boundary conditions for this problem are: a bounded solution as x approaches infinity (1.3-l) stress free infinite boundaries, y = + l oyy(X, :,1) = oxy(x, :_l) = 0 (1.3-2) and one of the following conditions on the finite boundary x = 0: the first mixed boundary condition Oxx = 0*Xb(y) cos mt (1.3-3a) u = u ( ) COS wt y yby the second mixed boundary condition Oxy = okyb(y) cos wt (1.3-3b) ux = qu(y) COS wt the pure stress boundary condition Oxx = oxxb(y) COS wt (1.3-3c) o (y) cos wt oxy xyb the pure displacement boundary condition u = uxb(y) cos wt (1.3-3d) u = uyb(y) cos mt . This problem is formulated to investigate the Saint—Venant boundary region with pure stress end conditions. In the course of the development, formulations are obtained which accept the Specifica- tion of each of the mixed boundary conditions. The mixed boundary cases are not examined separately because these boundary conditions are not of immediate interest to this problem. Their development, however, is a vital step in the formulation of the pure stress problem. The formulation of the pure stress case involves three major steps, each of which is discussed separately in Chapters 11, III, and IV. In Chapter II, a second-order partial differential vector equation is deve10ped in terms of the normal stresses Oxx and Oyy' This development is called the first mixed boundary case because specification of Oxx and Oyy on the boundary x = 0 is equivalent to specification of the normal stress Gxx and the displacement u in the y direction. The stress Oyy by itself is not a boundary stress on the surface x = 0, but in combination with Oxx allows specification of uy. The homogeneous boundary conditions on the infinite edges leads to an eigenvalue problem which is solved for the eigenvalues and eigenfunctions. A biorthogonality operator is found which permits the direct calculation of the eigenfunction constants from the prescribed mixed boundary conditions. As was indicated earlier, the investigation of the Saint-Venant boundary region is to be made for pure stress end conditions, not conditions involving one boundary stress and one boundary displacement. Thus, for this study, the solutions developed in this chapter will not be used to solve a particular mixed boundary value problem, but rather, they constitute an intermediate step in the pure stress boundary formula- tion continued in Chapters III and IV. ’In Chapter III, a second-order partial differential vector equation is developed in terms of the shear stress Oxy and a new function Q. This deveIOpment is called the second mixed case be- cause specification of Oxy and Q on the surface x = 0 is equi- valent to specification of the shear stress Oxy and a displacement ux in the x direction. The solution proceeds in the same manner described for the first mixed case. Again, the solutions obtained for the second mixed case are treated as elements of the final formulation. In Chapter IV, the results of Chapters II and III are com- bined to write a series eXpansion of the vector [0 ,o ,0 ,Q]. XX yy xy The two biorthogonality Operators are combined to produce a biorthogonality operator which can be applied to the four component vector. In Chapter V, boundary functions a and o xxb x are s ecified yb p ’ and Oyy and Q are written as a series expansion on the surface x = 0. The eigenfunction constants are obtained by applying the four-vector biorthogonal Operator. Chapter VII includes a discussion of three examples. CHAPTER II FORMULATION OF PROBLEM FOR FIRST MIXED BOUNDARY CASE 2.1 Equations of Elasticity The governing equations for the first mixed case are derived from the following linearized equations of elasticity using the gen- eralized plane stress assumption. Equations of Motion 2 BOXX + 3331 = p i_3§ (2.1-1) ax ay 3:2 2 23:1.+ 3311.: p 2_3x. (2.1-2) ax ay atz Stress-Displacement Relations Bux l g; - E— (oXX - voyy) (2°1‘3) All __x.= l _ . - By E (oyy egxx) (2.1 4) 3:§.1.i:x = Ziktal (2 1 5) by ' ax E Oxy ' ' 2.2 Boundary Conditions For the first mixed case, the boundary conditions specified on the finite boundary x = 0 are oxx = oxxb(y) cos wt (2.2-l) U =11 y yb (y) cos wt . (2.2-2) As has been indicated earlier in Section 1.3, equation (2.1-4) shows that the condition (2.2-2) is equivalent to the specification of (2.2-1) and ny on the boundary x = 0. = cos mt (2.2-3 The infinite boundaries, y = :pl, are taken to be stress free, O'yy(xs : 1) = OXY(X’ i 1) = 0’ (202-4) and the solution is required to be bounded as x approaches infinity. 2.3 Equations for the First Mixed Case The general equations given in Section 2.1 can be reduced to two equations for Oxx and oyy. Differentiating equation (2.1-5) once with respect to x and once with respect to y yields the following expression 3 3 2 a U A U A o X + ———1—-= Zglfyl» XY . (2.3-1) 2 2 axsy ayax E axay Substituting equations (2.1-3) and (2.1-4) gives 2 2 2 2 2 5 0 B 0 a G A o a o ZXX - v -—§11-+ ——§11 - v ZXK = 2(l+v) —;—51-. (2.3-2) ay ay ax ex 3 5y Differentiating equation (2.1-l) with respect to x, (2.1-2) with reSpect to y and adding gives 2 2 2 a a 2 BU an A o a o 2_Xt=pa_(x+__r)___>_<1___1x . (2.3-3) axay 2 ex ay 2 2 at 5x BY Substituting equation (2.3-3) into (2.3-2) and using equations (2.1-3) and (2.1-4) yields the first equation. 2 2 (1_ 2) 2 a—2(oxx+o)+a—3(oxx+oyy)=gEv EL2(oxx-to) 3x yy By at yy (2.3-4) The second equation is obtained by differentiating equation (2.1-l) with respect to x, (2.1-2) with respect to y, subtracting and substituting equations (2.1-3) and (2.1-4). 2 2 a o a o 2 xx _ yy = Q£1+V) A _ - 2 2 E 2 (OXX ny) (203 5) BX BY at Equations (2.3-4) and (2.3-5) can be written in matrix form 28 28 28 A5—2+a—2=N5—2, (2.3-6) Bx By at where 2 1 r0 1 xx A = ’ S = -l O o 1 yys 2 u 2+v-v -\)(1+\)) = 2 N E -(1+v) l+v This matrix equation is the desired first mixed boundary case formulation. 2.4 Solution of the Equations for First Mixed Case The boundary stresses (2.2-1) and (2.2-3) are time-harmonic of frequency w. Thus, a time—harmonic solution form is assumed 10 using separation of variables 3 = V(y)X(x)eiwt , (2.4-1) where V1(y) V(y) = v2(y) Substituting this assumed form of solution into equation (2.3-6) yields 2X 2V 2 Ava—5+Xa‘7'l'w vi=0. (2.4-2) BX BY This suggests the possible form X(x) = emX which when sub- stituted into equation (2.4-2) yields dZV 2 ——-—2 + (sz - a m = 0 , (2.4-3) dy or 2 g—%-+-HV = 0 , (2.4-4) dy where 2 2 2 '2 2 27 P—,‘§’—-(2+v-v)-2a -1;3’—(v+v)-a H ='. 2 2 ‘2 - 53%— (1+v) + 01 9-9— as.) E E J Equation (2.4-4) is an ordinary second-order matrix differential equation with constant coefficients. EXpanding equation (2.4-4) yields ll 2 d v1 2 + hllvl + h12v2 = 0 (2.4-5) dy 2 d v2 + + = .- 2 h21V1 h22"2 0 (2 4 6) dy These two equations may be written in the form d4 d2 v1 ——""l" 'l' —-+ - = . .- 4 (h11 h22) 2 h11h22 h12h21 O (2 4 7) dy dy v2 The roots of the characteristic equation obtained from (2.4-7) are: _ _l”__2 _“w r = + w/az _ EQ_.(1-VZ) = + am (2.4-8a) 1,2 —- E ._ 2 2 7"? _-._ " r3 = +1 a - —E£— (1+ ) = + an , (2.4-8b) ,4 -' E '- where 1 \/ 2. ”Quasi—m7“ 2 A m = 3' a - E (l-v ) (2.4—9) 1 2 lwé 2-”- _.. n = —’ a --—9£— (1+v) . (2.4-10) a E The solution of equation (2.4-4) has the following form: v1 = C1 Slnh amy +C2 cosh amy + C3 sinh any + C4 cosh any v2 = C5 Slnh amy + C6 cosh amy + C7 Sinh any + C8 cosh any Substituting these expressions for v1 and v2 into either of the equations (2.4-5) or (2.4-6) defines four of the constants. v1 = C1 sinh amy +C2 cosh amy + C3 sinh any + C4 cosh any (2.4-ll) 12 = KC1 sinh amy + KC cosh amy - C sinh any - C cosh any , (2.4-12) 2 3 4 1 + n2 vn2 - v - 2 The remaining constants are determined from the boundary conditions. Satisfaction of the boundary conditions on y = i_l. (a) On the surfaces y = :.l, the normal stress Oyy is zero for all x and time t. This implies, from equation (2.4-1), that v2(:_l) = 0. Thus from equation (2.4-12): ll O KC1 sinh am - C3 sinh an (2.4-13) I O KC2 cosh am - C cosh an - (2.4-l4) 4 Two equations appear as a result of separating the solution into even and odd functions of y. (b) 0n the surfaces y = :_l, the shear stress Oxy is zero for all x and t. The governing equations do not explicitly contain ny’ so that a relationship between Oxx’ Oyy’ and Oxy must be constructed. Differentiating equation (2.1-2) with respect to x and substituting equa- tion (2.1-5) yields 2 2 32a=paz 2am, 3:. 1.15m 5x2 8,2 E xy ay axay Differentiating this equation with respect to x and sub- stituting equation (2.1-3) yields 2 2 2 2 [5—_20(1+\D az]aoxv=_[a__2__g_\;a_z_]§fzx_ E 2 ex E at 5x ax at ay 2 ac - 9 3— i. (2.4-15) E 2 by at 50 If C is constant at y = + 1, then -—§l-— 0 and xy BX equation (2.4-15) becomes 2 2 BO 2 50 a.— _ E2.a__. __11.+.Q.a__.__§£.= 0 at y = + 1 . 2 E 2 By E 2 By — ax at . at Using the assumed solution form from equation (2.4-1) gives (2.4-16) E d + [ 2 + u 2] v2(il) - U)2 dv1(_l) y E dy Substituting equations (2.4-11) and (2.4-12) into equation (2.4-16) and separating into even and odd functions of y yields 2 ’2 K 2 C am(a K.+ E£_ - —2EQ—)cosh am 1 E E 2 2 + C3an(-a + ”w + 39w )cosh an = 0 (2.4-17) E E and 2 .2 K 2 C am(a K + Efl— - —22£—)sinh am 2 E E 2 2 + Caan(-a +19; + vgw )sinh an = o . (2.4-18) The solution of equations (2.4-13) and (2.4-17) yields the transcendental equation for the odd eigenvalues. tanh am _ 4mn _ . (2.4-l9) tanh an (1+n2)2 14 In a similar manner the equation for the even eigenvalues is obtained by solution of equations (2.4-14) and (2.4-l8). tanh an 4mn .__..___ = _—_———— 2. -2 tanh am ( A 0) (1+1?)2 The transcendental equation, (frequency equation), (2.4-l9) is used to define the eigenvalue a when the eigenfunctions v1 and v2 are odd in y, and equation (2.4-20) is used when these eigenfunctions are even. The eigenfunctions divide into even and odd functions of the form: K sinh am Ov1 = C1 (Sinh amy + —-;E;E—;;'31nh any) _ . K sinh am . Ov2 C1 (K Sinh amy -—;E;E—;;-51nh any) (2.4-21) e 1 2 amy cosh an COS any) _ _ K cosh am ev2 — C2 (K cosh amy -—:;;E—EE-cosh any) . The constants C1 and C2 are determined from the boundary con- ditions on the remaining surface x = 0. 2.5 Definition of the Biorthogonal Operator and the Adjoint Equation Consider Vr as the solution vector of the differential t equation (2.4-3) associated with the r h eigenvalue ar' 2 d V 2 "55 = (arA - wZN)Vr (2.5-1) dY Premultiplying equation (2.5-1) by the complex conjugate transpose of some arbitrary vector function of y, ZS, and integrating from 15 y = -l to y = l yields(1) 2 z 1 d V 1 31 + + 2 I Z 21‘ dy = by Z (a A - sz)V dy , Z = _1 s d _1 s r r s z y 82 Integrating the left side by parts gives + avr dz:v1 1 .122: 1 2 __ _ __ = A _ . _ s dy dy _1 dyz [182+ (a u) 2% dy. (2 5 2) . . . . th ConSider the arbitrary vector function ZS as being the 3 solution vector of the following differential equation, termed the adjoint equation(2) 2 d Z + + -—-25 = (azA - wZN )z , (2.5-3) dy s s where the eigenvalue a8 is determined from the same transcendental equation obtained for the equation (2.5-l). It remains to be shown that this condition is satisfied. + Premultiplying equation (2.5-3) by Vr and integrating from y = -l to y = 1 produces 2 l d Z +( A+ J‘v+——dy=f1r(av-2 -wZN+)Zdy r -l dy Taking the complex conjugate transpose of this equation, 1 d22:1 2 y=J‘1::2r2(aA-wN)de, -1 dy + (1) () represents complex conjugate transpose (2) "' ( ) represents complex conjugate l6 and subtracting from equation (2.5-2) yields + l +:v—rufiv =(2- 2)IZ+AVd (25-4) 8 dy dy r _1 01r 0[s [I s r y ' ° Expanding the left side of equation (2.5-4) gives - - l d d E vrl + ; dvr2 _ dzsl v _ 232 v = $1 dy $2 dy dy rl dy r2 _1 ( 2 2)1 Z+AV d 2 5 5 0’r - 0[s [l s r y ° ( ° - ) The boundary conditions on the surface y = i_l in Section 2.2 for the original differential equation give: (a) vr2(;t 1) = 0 (b) From equation (2.4-l6) dvr1(:l) 2 E dvr2(tl) dvr2(il) _.____—_=_ +V d a 2 y r pm dy dy where it is noted that the eigenvalue ar appears in the second boundary condition. Substituting these values into equation (2.5-5) yields dv dv dv d2 1 [5 -a2 —§—'-—£g + v r2 + g -——E; -._4§l v = 2 81 r pm dy dy 32 dy dy r1 _1 2 2 1 + (”r - “5)i ZSAVrdy . (2.5-6) -1 Imposing the following boundary conditions on the adjoint problem: d2 (+1) 31" _ (8) §;—"“‘ - 0 (b) 2 (+1)-2L5 (1)-2 (+1) 2 -' as 2 51 V 31 — ’ l7 and substituting these into equation (2.5-6) yields 1 dv l 2 2 - E r2 _ 2 2 + (as - ar)zsl 2 dy — (Ur as)j ZsA'Vrdy ’ pm -1 -l or 1 dv 2 2 + - E r2 - z A + '———-——-— = . 2. - (“r as)[j1 S vrdy 231 2 dy ] 0 < 5 7) - pm -1 Thus, biorthogonality is defined by equation (2.5-7) for a2 # a:. r 2.6 Solution of the Adjoint Differential Equation The adjoint differential equation (2.5-3) can be written as 2 §—%-+ n+2 = 0 dy : (2.6-l) where the matrix H is defined with equation (2.4-4). The solution of equation (2.6-l) is obtained by the same procedure used in the solution of equation (2.4-4). EXpanding equation (2.6-l) gives 2 d 21 _ _ + + = - 2 h1121 h2122 O (2'6 2) dy dzz2 _ _ dyz + hlzzl + hzzz2 = o . (2.6-3) These equations can be written in the following form d4 _ d2 21 — + . —— + - - - - - = . . _" 4 (hll + h22) 2 hllh22 h12h21 z 0 (2 6 ) dy dy 2 The roots of the characteristic equation obtained from equation (2.6-4) are: V/ 2 2 2 r12=i a -9-‘”—(1-v) =-_e_a (2.6-5a) l8 2 = ‘2 2 0‘) = — - r3,4 :\/a - i—E (1+v) i an , (2.6 5b) where - l 2 Q 2 2 m = :' a - w (1‘V ) (2°6‘6) a E - 1 2 29 2 n = a a - Eu) (1+\)) . (2°6-7) The complex conjugate of the adjoint functions representing the solution of the adjoint equation are: 1 Blsinh amy + B cosh amy + B sinh any + B cosh any NI II 2 3 4 B sinh amy + B cosh amy + B sinh any + B cosh any . 5 6 7 8 Substitution of these functions into either equation (2.6-2) or (2.6-3) defines four of the constants. sinh any - KB cosh any (2.6-8) N II B sinh amy + Bzcosh amy - KB 1 1 3 4 22 Blsinh amy +'B2cosh amy + B3sinh any + Bacosh any (2.6-9) Satisfaction of the Adjoint Problem Boundarngonditions. In defining orthogonality in Section 2.5, the following two boundary conditions were imposed on the adjoint problem: délen “0 37— : O 2 —E—2- 210:1) - v£1(:1) . pw (b) 5,011) = a Substitution of equations (2.6-8) and (2.6-9) into (a) and (b) and separating into even and odd functions of y yields the following two transcendental equations which are identical to those defining 19 the eigenvalue a for the original governing equation (2.4-4). For the adjoint functions odd in y, tanh am _ 4mn 2 tanh an (1+n2) For the adjoint functions even in y, tanh an = 4mn tanh am (1+n2)2 Similar to the eigenfunctions, the adjoint functions divide into even and odd functions of the form: - m cosh am 0 1 B1 (Sinh amy - n cosh an Sinh any) N ll - , m cosh am = + _ _.____.. ° 022 B1 (Sinh amy Kn cosh an Sinh any) (2.6-10) - __ fl sinh am e21 B2 (cosh amy - n EEEE—Eg'cosh any) 5 = B (cosh amy + EL- filflh_gfl cosh any) e 2 2 Kn siM1an 2.7 Summary The y-dependence of the solution is carried by the eigen- functions (2.4-21) of which there are an infinite number correspond- ing to the roots, a, of the transcendental equations. The correct solution of the governing differential equations requires the summation of the distinct solutions. Separating the solution into even and odd functions of y, this sum may be expressed as 20 co '- 1< ' h sinh amy + __§%EE_QE sinh any = C1 K sinh e O r C r K sinh amy - —_;IHH€32 sinh any yy __ j (r) r=l (I) _ Fcosh amy + E_EEEE_QE cosh any COS an 1(Q’X+UJC) + C e e r _ 2r K cosh m K cosh amy -----41- cosh any cosh an j . L - (r) r=1 (2.7-1) The constants C1r and C2r are obtained formally by the specifica- tion of Oxx and oyy on the surface x = 0 and the application of the biorthogonality operator (2.5-7). This solution and the solution deve10ped in Chapter III will be combined in Chapter IV in a formulation which allows specification of pure stress boundary conditions, a and o , on the surface x xx xy 0. CHAPTER III FORMULATION OF PROBLEM FOR SECOND MIXED BOUNDARY CASE 3.1 General Remarks In this chapter, the equations given in Section 2.1 are used to derive governing equations for specifications of Oxy and the displacement ux on the finite surface x = 0. To permit formulation of the problem in this manner, a new variable Q is introduced, and the governing equations involving only the stress oxy and the "stress-like" variable Q are obtained. It will be shown in Section 3.3 that the specification of oxy and Q on the surface x = 0 is equivalent to specification of ny and uX up to a rigid body displacement. As in Chapter II, the solutions of the second mixed case developed in this chapter will not be used to solve a particular mixed value problem, but will be combined with those obtained in Chapter II for specification of the stresses ka and Oxy on the surface x = 0. 3.2 Boundary Conditions For the second mixed case, the boundary conditions specified on the finite boundary x = 0 are qu = okyb(y) COS wt (3.2-l) 21 22 ux = uxb(y) cos wt (3.2-2) It will be shown in Section 3.3 that condition (3.2-2) is equiv- alent to specification of (3.2-1) and Q on the surface x = 0. D II Qb(y) cos wt (3.2-3) The infinite boundaries, y = i_l, are stress free, :+1 o y(X _ ) x + l = 0 , 3.2-4 y o y( , _ ) ( ) X and the solution is required to be bounded as x approaches infinity. 3.3 The Auxiliary Variable, Q To construct equations which do not involve o x and Oyy’ x the variable Q is introduced and is defined 2 . so a u a9.= XX - vp._.J£ (3.3-1) ax ay 3:2 with the requirement that it be bounded as dimension x approaches infinity. Differentiating equation (2.1-3) with respect to y and substituting equation (2.1-2) yields 2 2 a ux _ 1. 80xx 8 ”1 BOXX - - v p 2 - . (3.3-2) BXBY E 8y at ax Substituting equation (3.3-l) into equation (3.3-2) gives ax By E ax AX Integrating with respect to x gives 23 _ l ST-E (Q +voxy) + f(y) , and substituting equation (2.1-5) yields Slum, E l ax - E (Q + vsxy) — f . (3.3-3) xy If uy is bounded as x approaches infinity, f(y) may be taken to be zero. Equation (3.3-3) may be written au ——§-— 1 (Q + vo ) Xy ay — E (3.3-z.) Specification of Q and oxy on the surface x = 0 is equivalent to specification of Oxy and uX up to a rigid body displacement. 3.4 Equations for the Second Mixed Case Differentiating equation (3.3-3) with respect to y and substituting equation (2.1-4) into the result gives BC 60 an 59+—¥1-v x"-<2+\»>—-l" =0- By BX BX 8y Differentiating again with respect to y and using equations (2.1-1) and (2 .1 -2) gives 2 2 2 2 u a.9._ 9—331._ 2 §_EEX.+ p 5.. (iii V EQE) = 0 2 2 2 5X ay ay ax sy at Substituting equations (2.1-5) 2 2 2 2 u 2 2 711 3.9.- 2.331._ 2 2_3:1.+ a__.2_i - a__.211:22. + a__.l_x = 0 \J O' \) 2 2 2 P 2 P 2 E 9 2 BY ax ay 5t 5X at Xy at 9x and (3.3-l) yields 2 2 2 2 a.9.-2&1-22__°_xy_+pa_a_ui_va 2(1+v) 2 2 2 25x 9 2 E xy ay ax ay t at 2 2 ECXX_E_02.=O axay ax Using equations (2.1-l) and (2.1-5) yields the first equation for d . Oxy an Q 2 2 2 O' 2 2 2 0 §_§§Y.+ 3 §_;EY.+ BJ% _ aJ% =.E§LZX_L p i_§§1. (3.4-1) E Bx BY BX BY Bt The second equation for Oxy and Q is obtained by adding the derivative of equation (3.3-l) with respect to x to the deriv- ative of equation (2.1-l) with respect to y and substituting equa- tions (2.1-5) and (3.3-4) into the resulting equation. 2 2 B o 2 1+ ~ B_92.+_§>LY.=ELE__ELB__2(Q _vOX) (3.4-2) ax by at y Equations (3.4-l) and (3.4-2) may be written in matrix form 2 2 2 D 9—%-+ a_%.= M a—%-, (3.4-3) BX BY Bt tflmre O l1 0 xy D = , T = -1 2 Q --V 1- -(2+\)) 3 . This matrix equation is the desired second mixed boundary case formulation. 25 3.5 Solution of the Equations for Second Mixed Case The boundary conditions (3.2-1) and (3.2-3) are time—har- monic of frequency w. A time—harmonic solution form is assumed 1'.ch iwt T = W(y)e e , (3.5-1) where w1(y). W(y) = w2(y) Substituting this assumed form of solution into equation (3.4-3) gives 2 (13+ (032M " 021))“, = O 9 (3.5-2) dy or 2 __dV2’+Gw=o , (3.5-3) dy where P 2 2 T 2 -%—E saw-a G = 2 2 2 2 2 _w_2E (2+3\)+\))+Q/ w—JE (3+3v)-201 Expanding equation (3.5-3) yields 2 d w1 -——§—-+ gllw1 + glzw2 = O (3.5-4) dy dzw2 ;;§—-+ g21w1 + gzzw2 = O . (3.5-5) These two equations may be written 26 d4 d2 w1 + - = - 4 + (311 + g22) 2 g115322 g12’321 0 ' (3'5 6) The roots of the characteristic equation obtained from equation (3.5-6) are identical to the roots of the first mixed problem of Chapter II: J2 032 2 11,2": 6* "LE(1"’) =ia‘“ 2 22m2 ‘34:: 0‘ ' E 0+") =i0’“ The solution of equation (3.5-3) has the following form: ll w1 Clsinh amy + Czcosh amy + C3sinh any + C cosh any 4 w2 Cssinh amy + C6cosh amy + C sinh any + C cosh any 7 8 Substituting these expressions for w1 and w2 into either of the equations (3.5-4) or (3.5-5) defines four of the constants yielding: w1 = Clsinh amy + Czcosh amy + C3sinh any + C4cosh any (3.5-7) w2 = Clsinh amy + Czcosh amy + RC3sinh any + RCacosh any , (3.5-8) where The remaining constants are determined by specification of the boundary conditions on the surfaces y = i_1 and x = 0. Satisfaction of the boundary conditions on y = :.l. (a) On the surfaces y = i;l, the shear stress Oxy is zero for all x and t. This implies, from equation (3.5-1), 27 that w1(:l) = 0. Thus, from equation (3.5-7): (3.5-9) ll 0 C sinh am‘+ C3sinh an 1 (3.5-10) I O Czcosh am + C4cosh an - (b) On the surfaces y = i.l, the normal stress gyy is zero for all x and t. Because the equations do not explicitly contain 0 , a relation between 0' , Q, and 0 must YY YY XY be constructed. Differentiating equation (3.3-3) with respect to y and substituting into equation (2.1-4) gives a9. 5" a"x + 41— —’9$ - (2+v)—l = 0 . (3.5-11) BY Bx vBX BY Differentiating equation (2.1-l) with respect to x and substitut- ing from equation (2.1-3) yields 2 2 a o B o 2 2x“ + -——§1-= 9-5—5 (0 - v0 ) . (3.5-12) ax axay E at xx yy Multiplying the derivative of equation (3.5-12) with respect to x by Poisson's ratio, v, and substituting equation (3.5-11) gives 2 ad 2 2 a..- _ 2a..__u a.._ a__a9. ax at2 5x .5x at “y + [-257+§ (2+v) EL—z ——’$l=o . (3.5-13) Bx BC BY 50' If 0 is constant on the surfaces y = i_l, then g;11 = 0 and equation (3.5-13) becomes Using the assumed solution form from equation (3.5-1) gives 28 2 2932. [m dw (:1) + [2a2 - §'(2+v)w2] E;l-—- = 0 . (3.5-14) 2 dy (W (‘11) Substituting equations (3.5-7) and (3.5-8) into equation (3.5-14) and separating into even and odd functions of y yields 2 2 C3am.[(-a2 + 99-")R + 2a2 - (2+v) QQ- cosh an E E 2 2 + Clam[:a - (1+v) QfiL. cosh am = 0 (3.5-15) and 2 2 2 '2 C40n [‘-a +-QEL‘)R + 2a - (2+v)'2£— ] sinh an E E 2 -2 + Czam [a - (l+\)) Li:— J sinh am = O . (3.5-16) Solution of equations (3.5-9) and (3.5-15) yields tanh an 4mn —-———— = —-——-— . 05" tanh am 2 2 (3 17) (1+n) Solution of equations (3.5-10) and (3.5-16) yields tanh am 4mn '—--- = --—-—-. (3.5-18) 2 tanh an (1+n2) The transcendental equation (3.5-17) is used to define the eigen- value a when the eigenfunctions w1 and w2 are odd in y. Note that this equation is identical to equation (2.4-20) which defines the eigenvalue a for the first mixed problem when the eigenfunctions v1 and v2 are even in y. The transcendental equation (3.5-18) defines a when the eigenfunctions w1 and w2 are even in y. Likewise, this equation defines the eigenvalue for odd functions of v1 and v2. This relation is equivalent to the fact that if Oxx and Oyy are even functions of a given variable, 0*y is odd in that variable. 29 It is desirable at this point to define as the even problem the one which has Oxx and ny in terms of functions even in the y-variable and Oxy in terms of functions odd in the y-variable. The odd problem is defined as the one with oxx and Oyy odd in the y —variable and Oxy even in the y-—variable. The presub- scripts I'o" and "e" used to designate odd and even will now be used to identify quantities related to the odd and even problems respectively. Thus, for example, for the odd problem the presub- script "0" is applied to the eigenfunctions of the first mixed case which are odd in the y..variable, and to the eigenfunctions of the second mixed case which are even in the y..variable. The eigenfunctions of the second mixed case divide into sets for the even and odd problems of the form: _ . sinh am . ew1 — C1 (Sinh amy EEKE‘EE'Slnh any) w =C (sinh _R_§_£1£_gm_sinh ) e 2 1 amy sinh an any (305-19) _ cosh am Ow1 — C2 (cosh amy BEEF—EH cosh any) R cosh am cosh an S I o 2 — C2 (cosh amy cosh any) The constants C1 and C2 are determined from the boundary con- ditions on the surface x = O. 3.6 Definition of the Biorthogonal Operator and the Adjgint Equation Consider wr as the solution vector of the differential (2 equation (3.5-2) associated with the r h eigenvalue ar. 3O r = 0 (3.6-l) Premultiplying equation (3.6-l) by the complex conjugate trans- pose of some arbitrary vector function of y, Us’ and integrating from y = -l to y = 1 yields 1 dzwrd 1 Usl + f U fly (a: D - w 2M)w dy . U = S S -l dy2 - u 82 Integrating the left side by parts gives 1 l d2U+ l + 2 2 + j‘ —— ZS--wrdy J" Us(ozrD - w M)Wrdy - (3-6‘2) -1 -1 dy2 -1 +dwr an: UsF-er . . . th . ConSider the vector function US as being the 5 solution vector of the following differential equation, termed the adjoint equation dZU 2+ 2+ 28 = (& D ‘ w M )U 3 (3°6‘3) dy s s where, as will be shown later, the eigenvalue a is determined L from the same transcendental equation obtained for the equation (3.6-l). . . . + . . Premultiplying equation (3.6-3) by wr and integrating from y = -l to y = 1 gives 1 d U 1 + s _ +_2+ 2+ j w 2 dy —-£lwr(asn - w M )Ude Taking the complex conjugate transpose of this equation, 1 dzd: 1 + 2 2 28 - jIUS(aSD - w M)wrdy , -1 dy and subtracting it from equation (3.6-2) yields 31 1 + 2 2 + ——E- S = (a -a)funw dy. (3.6-4) r S '18 r dw dU ) r s dy dy _1 Expanding the left side of equation (3.6-4) yields - - l d a wr1 + a dwrZ _ dusl w _ dusZ w ) = 51 dy $2 dy dy r1 dy r2 _1 l 2 2 + (qr - as)§lUSDwrdy . (3.6-5) The boundary conditions on the surface y = :_1 may be written in the form: (a) ”ti“- 1) = o 2 dw (+1) 2 DLlL __r£:_ 2 _ 9. 2 __ = (b) [-ar '1" E de + [201' E (2+v)u) O , where it is noted that eigenvalue ar appears in the second boundary condition. Substituting these values into equation (3.6-5) gives dw 2a2 - 2-(2+v)w2 dw dd 1 [ - r1 J r' E rl 52 w = u ' 2 "“‘ "“-‘ sl dy 32 - 2 + w dy dy r2 _1 0‘,r E 2 21 + (a - oz )jU D w dy. (3.6-6) r s _1 s r The following boundary conditions are imposed on the adjoint func- tions: ( ) —-—-dusz(i1) = o a dy _ 201S - gnaw,2 _ (b) u (+1) = u (+1) 81 -' 2 32 — Substituting these boundary conditions into equation (3.6-6) gives 32 2 Q 2 2 Q 2 1 20/3 - E (2+vhn _ dwr1 - 2ar - E (2+v)w a dwrl — 2 $2 dy $2 dy _ '02 + QQ_ -a2 + E'wz -l s E r E l 2 2 + (qr - as)f UsDwrdy ’ -1 or 2 2 2 1 + 29$- dw 1 (a -a)jUDwdy- E 6 —-El =0. r s s r 2 2 52 dy -l 2 gm 2 gm -1 (‘Q8 + E )(-ar + E ) (3.6-7) Biorthogonality is defined by (3.6-7), but it is not in a usable form because the eigenvalue ar appears in the Operator. Multiply- 2 ing equation (3.6-7) by (-a: + 2%L2 l l 2 2mg— dw 2 2 + 2 g E - (a - a ) I U (-a + w )Dw dy - '—-—-————— u r1 = O , r s _1 s r E r 2 2 52 dy -a +.E£_ _1 s E and recalling from equation (3.6-l) dzwr 2 aerr = 2 + U.) er , dy the term under the integral sign can be written in the following form 2 2 dw 2+ 2 + + + U(-a2+9—‘”)Dw=9——‘”UDw -U-—-r-wUMw s r E r E s r s dyz s r After these substitutions, the biorthogonality can be defined as 2 l d w J‘ (U+Dw --§—-U+——5-E-U+Mw dy _1 r 2 s 2 p s l dw - v u r1 = 0, a2 f 02 . 2 2 $2 dy 1 r s .22. _ a ' E S (3.6-9) 33 3.7 Solution of the Adjoint Differential Equation The adjoint differential equation (3.6-3) can be written as + d U + c U = o (3.7-1) where the matrix C is defined with equation (3.5-3). The solution of equation (3.7-l) is obtained by the same procedure used in the solution of equation (3.5-3). Expanding equation (3.7-1) gives 2 d ”1 _ _ ——--2 + gllu1 + g21u2 = O (3-7‘2) dy 2 d u2 _ _ ;;§-'+ g12”1 + g22”2 = O ' (3'7’3) These equations can be written in the following form d4 - - d2 — - - - u1 ( 4 + (g11 + gzz) 2 + g11322 ' 812821 = 0 ' dy dy u2 The roots of the characteristic equation are identical to those obtained for the adjoint equation of the first mixed problem: 2 2 2 -—— _ + - _ BE. _ _ 1,2 ._ Vw2352(:1> Substitution of equations (3.7-4) and (3.7-5) into (a) and (b) and separating into even and odd functions yields the following two transcendental equations which are identical to those defining the eigenvalue a for the original governing equation (3.5-3). For the even problem, the adjoint functions are odd in the y..variable, and the corresponding eigenvalues are the roots of tanh an 3 4mn tanh am (1+n2)2 For the odd problem, the adjoint functions are even in the y- variable, and the eigenvalues are the roots of tanh am = 4mn 2 2 tanh 0m (1411 ) 35 The adjoint functions divide into sets corresponding to the even and odd problem in a similar manner as the eigenfunctions. They are of the form: - . m cosh afl . = .. + — eu1 B1 ( R Sinh amy n cosh an Slnh any) 5 = B (s inh am - fl SEE—L” sinh ) e 2 l y n cosh an any (3.7-6) - m sinh am = .. + -— __ Ou1 B2 ( R cosh amy n sinh an cosh any) m sinh am cosh any) . C. I I o 2 - B2 (COSh amy - n sinh an 3.8 Summary The y-dependence of the solution is carried by the eigen- functions (3.5-l9) of which there are an infinite number correspond- ing to the roots, a, of the transcendental equations (3.5-17) and (3.5-18). The solution of the differential equation requires the summation of the distinct solutions. Separating the solution into even and odd functions of y, this sum may be expressed as co '— h oxy cosh amy - EEEE—gg'cosh any ' t = C el(oarx+w ) Q 1r cosh amy - B—EEEflLiflfl cosh any COSh an (r) r=l m r“sinh amy - Eiflh—gm sinh any sinh an i( a x+wt) + C2r R sinh am e e r Slnh amy - sinh an Slnh any (r) _' (3.8-l) 36 The arbitrary constants C11. and C2r are obtained formally by the specification of Oxy and Q on the finite edge x = O and the application of the biorthogonality operator (3.6-9). This solution will now be combined with the first mixed case to form a general solution for any acceptable boundary conditions. As indicated earlier, the stress boundary problem is the one of most importance. CHAPTER IV FOUR-VECTOR FORMULATION FOR THE PURE STRESS CASE 4.1 The Odd Problem Four-Vector Formulation In Chapters II and III, eigenfunction expansions were developed for Oxx and Oyy’ and for Oxy and Q, respectively. These solutions are given by equations (2.7-1) and (3.8-1), and the functions in the odd problem have the following form: m . i( a x + wt) _ , K Slnh am . o r okx - rE£C1r(Slnh amy + —-;EEE—;E Slnh any)(r)e m K sinh QE i(oarx + wt) Oyy = rElclr(l< Sinh amy - sinh an Sinh any)(r)e . (401-1) 00 cosh am 1(oat-x + wt) Oxy - rEIC2r(COSh amy - m cosh any) (r)e 00 l( a X + LDC) _ R cosh am 0 r Q rEICZr(cosh amy -":;;;:7;H cosh any)(r)e In this chapter, the four solutions are combined to form a four-vector [o ,o ,0' ,Q]. Substituting the rth term of the XX yy xy solutions (4.1-1) into the coupled differential equation (3.5-11) 60 50 go a9+7u - v.33}: _ (2 + v) __JLX = 0 (3.5-11) By a a by repeated yields the following relation between the constants C11. and C21. 37 38 = ( 1 2m ) C 2r \m2 - v-Z (r) lr The desired odd eigenfunction expansion of the four-vector becomes o Foul xx 0‘ on2 i( arx + mt) Y)’ = C n e O , (4-1'2) a o r o 3 XY Q oné L .J o b A r=1 (r) where K sinh am . = ' +---—--——- h onl Slnh amy sinh an Sin any _ , K sinh am . GHQ — K Slnh amy - sinh an Slnh any _ 1 2m cosh_gm on3 ——§—-— (cosh amy ESEE-an cosh any) vn -v-2 _ i 2m R cosh am onh ‘——§—-- (cosh amy -—;3;E7;; cosh any) vn -v-2 _ 1 + n2 _ vn2 + 2n2 - v R ‘ “—2—— ’ R - 2 vn -v-2 1 + n a are the roots of %EEE_QE = __3E%_§. . 0’ <1+n > 4.2 The Even Problem Four-Vector Formulation The even problem formulation involves the following variable forms: no 1(ax+wt) _ K cosh am e r Oxx - r£1C3r(cosh amy -—:;;E-;;-cosh any)(r)e m i( a X + wt) Kcosh am e r = -—>_-——-————— h 0yy 2 C3r(K COSh amy cosh an COS any)(r)e r l (4.2-1) 39 co . l( 0/ X + wt) 0‘ = 2C (sinh amy -w—sinh any) e e r xy r=1 4r sinh an (r) w R sinh am i(earx + mt) Q = rEIC4r(S lnh amy - m Slnh any)(r)e Substituting the rth term of the solutions into equation (3.5-11) yields C _ i 2m C _ ( 3r 4r vnz-v-Z )(r) The desired even problem eigenfunction expansion becomes (I) .. - l okx {enl a enz i( a x + wt) yy = c en3 e e r , (4.2-2) e r n ny e 4 Q j (r) e - r=1 where = cosh +-1L£§EEL£EE cosh n enl amy cosh an a y _ K cosh am eflz — K cosh amy -—ES;E—;;'cosh any _ i 2m , sinh am . en3 ~ :;§:;:; (Slnh amy sinh—an Sinh any) _ i 2m , R sinh am . €114 “ an-v-Z (3 1nh amy - -—_—'—S inh om Sinh any) K and R are defined with equation (4.1-2), and a are the roots of tanh an = 4mn 2 tanh am (1+n2) 40 The general solution is the sum of the expansions (4.1-2) and (4.2—2). However, every function can be replaced with the sum of an even and odd function, and the series expansions will be used separately for convenience. 4.3 Four4Vector Form of the Biorthogonality Operator The biorthogonality for the first mixed case is given by (2.5-7). 1 dv + — I 2 AV dy + 4&5 z S r 2 2 —0,ar#as -1 The eigenfunctions nri of the four-vector form equal the eigen- functions vri of the two-vector form divided by a constant, so that the biorthogonality is not violated. 1 1 2 1 an ‘ - E - 2 2 2 I [231’282] “r1 dy +‘__§ zsl d;£_ = 0’ Ur # as -1 -1 0 “r2 pw -1 - (4.3-1) The biorthogonality for the second mixed case is given by (3.6-9). 2 l d w J" (”:Dwr ‘ "E? U: 3;): ' E ”:er>dy -1 pm v _ dwr1 l — 2 2 _-—TE—-——— u 2 E_-— - 0, 0 # a w 2 s y 1 s r £__ - a _ E s The functions “ti equal the two-vector form eigenfunctions wri multiplied by a constant, and the biorthogonality is not violated. 41 l 2 I[JJ]DW3_E[u-]d Tlr3 _ 31’ 52 2 81’ 52 d 2 r4 pw y nr4 (E - - an v - dan 1 - EDEUSI’USZ] M dy - 2 2 ”32 E;——' - O, nr4 2%L'- a -l 2 2 as = or (4.3-2) Combining the biorthogonality relations (4.3-1) and (4.3-2) yields 1 F 2 1 o o" .an-T I1 [zsl’ZSZ’usl’u32] '1 0 0 O nr2 0 0 O 1 “r3 L O O -l 2 nrh r 1 r “New - 2 [zsl’ZSZ’usl’GSZJ 2 “r2 pm 0 o 1 o dy an _o 0 o 1 “r4 ’- _ ' q) 0 0 0 0 “r1 - - - - o o o o ‘ [231’232’usl’u32] 2 “r2 ) dy 0 0 -(v:v ) (1+v) “r3 0 0 -(v +3v+2) (3+3v) “r4 / 1 - - + E 5 d,an _ v - (”113 = 0 2 if 2 (4 3.3) pwz sl dy wz 2 U32 dy ’ 0s 0[r ° ° E - Q’s ‘1 The adjoint functions 231, defined by equations (2.6-10), and usi, (3.7-6), are determined up to an arbitrary constant for each set. The determination of these constants is explained in Section 5.2. The four-vector form of the biorthogonality operator Q can be written as 42 '0 0 0 0 + + E + + - [Zs’Us] [O F] - (;)[Zs’Us] [O M_ J 0" J 0 + + + + + [28413] [0 PJ 6(y-1) - [28418] [0 P] 5(y+1) , (4.3-4) where matrices A, D, F, J, M, and P are defined as 2 .. 2 1 O 1 E 51—2- O A = _1 0 , D = _1 2 , F = ——2- dy 2 am _d__. O dyzg 0 §_ -v 1 O O J = £— y M - ”V P - V ,2 0 0 ’ E “(2+V) 3 , 2 2 £1... 0 94’ L: - as dy CHAPTER V SATISFACTION OF BOUNDARY CONDITIONS ON THE SURFACE X = O 5.1 Procedure Outline The eigenfunction constants are determined in terms of the time harmonic stresses Oxx and Oxy on the surface x = 0. On this boundary, the general eigenfunction expansion has the form r 1 °° , .. oxxb r ‘ O m R xx 1 C. . Oyy 1’21 3ng “2 = cos wt = Cr cos wt , o’xy Oxyb 1‘3 co ' Q "x=0 Z C.n.4 r—l __n4u (r) j=1 J J or F. .. co Oxxb - m n1 C. . E 1ng J “2 = Cr (5.1-1) Oxyb “3 2 C.“. r=1 fl, j=1334 N-(r) . Multiplying both sides of equation (5.1-1) by the biorthogonality operator as, (4.3-4), and integrating from y = -l to y — 1 yields the following equations 43 44 co F + 2 B .C =NC , S =1,2,...,oo . (5.1-2) N8 is a normalization factor, FS involves the boundary stresses 0 and O , and the summed term arises from the series expansion xxb xyb of o and Q. The system of equations is solved for the 3 con- YY stants by truncating the series. 5.2 The Adjoint Function Arbitrary Constants The arbitrary constants of each set of adjoint function vectors are chosen such that the adjoint function vectors and the eigenfunction vectors of each mixed case are a biorthonormal set. The necessity of this requirement becomes evident in the actual de- velopment of equation (5.1-2). Consider the solution of either of the mixed boundary cases. For the first mixed case, the eXpansion (2.7-1) can be used, and the biorthogonality operator of (2.5-7) applied in the manner des- cribed in Section 5.1, or the four-vector expansion can be used by substituting the series expansion for Oxy and Q. In the latter procedure, an inner biorthogonality condition yields the same relation developed using the two-vector expansion. The series term of equation (5.1-2) does not appear in this mixed boundary case, thereby yielding an explicit solution for the eigenfunction con- stants. Also, each term of the resulting equation for the eigen- function constants is multiplied by a single adjoint function arbitrary constant which can be taken equal to unity. These same characteristics are true of the second mixed case. In the four- vector formulation for the pure stress end condition, the equations 45 (5.1-2) involve a sum of terms, some of which are multiplied by the adjoint function arbitrary constant of the first mixed case and others multiplied by the constant of the second mixed case. This condition requires the evaluation of each constant or at least a determination of the ratio of the constants. The second alternative is dismissed because equations coupling the two adjoint problems are not evident. The normalization constant N8 of equation (5.1-2) for the four-vector form is the sum of the normalization constants for the first and second mixed cases N = k(1),,(1) + k(2>N(2> s s s s s ’ 2 where kél) and k; ) are the adjoint function arbitrary constants of the first and second mixed cases respectively. In constructing a biorthonormal set for each case, these constants are chosen as k<1) = 1,Nm k(2) = 1/N<2> S S S S , with the result that NS = 2. 5.3 Satisfaction of Boundary Conditions for the Odd Problem The eigenfunction expansion for the odd problem is given by (4.1-2). Substituting the stress boundary conditions at x = O, premultiplying both sides by the odd problem biorthogonality operator, OQS, and integrating from y = -l to y - l 46 Oxxb _ Cjnjz n1] 1 j—l 1 02 dy = CS I Oi T‘2 dy -1 S °xyb -1 S n3 °° m 2 C “j, _ _ j_ _1 J' o (8) yields F + SB 3 _ (k(1>N(1>+ k<2)N<2))C , 3 i=1 31 5 k3 s s where 1 _ 2 - 2 _ Fs ’ [1 {(2281 z 2)Gxxb + [FV+V )usl + (V +3V+1)“32 1 d E - d2 d _ v 5 kab - 2 L131 Oxyb y 2 2 32 dy 9w dy 22.. a _1 E s 1 E - d2 Bsx =1. { slniZ [vu 1 + (1+3v)u 2 _—2- u32 7] “14 dy 1 Pw dy 1 +2.; dT‘12 2 pm 51 dy _1 1 an 1 k(1)N (1) ‘ ‘ _J;_ - $2 =I1 [(2% z$2)nsl 31n321dy + 2 zsl dy w -1 k(2)N (2)_ 2 - 2 - E .. d2 I [NW )“31 + (V +3v+1)u32 ‘ 2 ”s1 2] “s3 -1 pm dy - - E - d2 - [vusl + (1+3v)u82 + ‘7 U82 ——2] “54 dy pm d 1 _ v - d“s3 m2 - a2 32 dy _1 (5.3-l) (5.3-2) (5.3-3) (5.3-4) (5.3-5) (5.3-6) 47 The odd problem adjoint functions zi are given by equations (2.6-10), the functions ui by (3.7-6), and the eigenfunctions “1 by (4.1-2). The evaluation of the coefficients Bsi requires care. The arguments of the hyperbolic functions are related to the eigen- value a through the following expressions arm =\/oz2 -'Q—-(1-v2) , om =2_\/Q_P_ 20”) The eigenvalues occur in pairs, one of the pair being the negative of the complex conjugate of the other, and some of the eigenvalues are real. Bsi must be determined independently for each of the following relations between the roots 01: 2 2 (l) 01 1‘ 018 (2) 01 = as (3) ai = -as and: (a) O[imi = O[sms’ C1lini = asns’ mi = dms’ ni = -ns (b) aimi = asms, aini = -aSnS, m1 = -ms, ni = nS (C) aimi = -asms, aini = -aSnS, m1 = ms, ni = nS BSi for Case (1) Substitution of the eigenfunctions and adjoint functions into (5.3-4) and performing the required operations yields = (1) . 2 _ 1 1 Bsi 2kg COS“ “smssmh aimi “smSKi 2 2 2 2 2 2 2 2 2 2 2 2 0’ 1'1 "O’Jl. 0’ “1 'Q’.n 0/ n ’O’.m S 1 1 S S 1 1 S S l 1 tanh a SmS aimiKi E ( 2n2 - 2 2 _ 1 tanh a. m. 2 2 2 2 2 C1Is s 0[in i 1 i as ns'a. 1ni pm 1 S 2 2 -a;m. s 1 1 2 2 2 2 *§§'(a n - a,m.) - 1] s s 1 1 pm tanh a n a.m,Kr m [ s s tanh a.m, 1 1 a n m use m use 1 tanh a 2 -a0ni tanh asms a,n,K, E 2 2 2 2 2 (asms - aini) - 1 pm 53H m KJH to .n. 11am (0 I'" tanh a n a.n.K m s s i _§_ _§__ 2 2 2 2 _ +‘ 2 2 n [ 2 (asns aini) 1 tanh a.n. 1 1 a n -aini 8 pm CDNH CDNH . E 2 2 2 1+3v-vR + ———'a.m. (2) Zaim'K' S w2 1 1 + i 2k cosh a m sinh a,m. 1 1 p s s s 1 1 2 2 2 2 2 1 +'n. a n - a.n. 1 s s 1 1 - E 2 2 E 2 2 u _ _ 2 a.(1+n?)R.K, 1+3v vRS + 2 aini l+2v +- 2 aini 4m _ 1 1 1 1 pm _ gm 3 2 2 2 2 2 2 2 2 2 2 2 O’sms ' aini O’sms. " “1‘“1 (I‘ms) E 2 2 E 2 2 .— —— + — 2a m m.K. H3" VRs + 2 aimi 1+2“ 2 “1‘“1 tanh a m _ s s 1 1 gm _ 11w __$___§ 1+1n2 2 2 2 2 2H2 2 tanh aim, i asms aimi aS s aim 1 H-PO E 9w 2 2 2 2 2 l +'n m - .n. i as s 0{1 1 2a m m,K,R, s s 1 1 1 + pwz tanh aSmS - 2 2 2 2 tanh a.m, ' (5.3-7) a n - a.n. 1 1 s s 1 1 1+2v + “—E— a2n2 1 1 BSi for Case (2) ' 1 1 B = k(1)K -1 _IE Slnh am COSh am + am.sinh am cosh am + ss 3 n Sinh an cosh an 2 2 2 2 a m a n 2E n tanh am m tanh an +_ 2-—”-_— 2 m tanh an n tanh am 49 + 2 n_tanh am _ m tanh an 2 2 2 2 m tanh an n tanh am O’m'O’ 1 2mk(2)K sinh osh ' __2__ (1+3v-vR) [1 + 0‘“ C 0"“ 1+n ‘3‘“ ZamR sinh am cosh am 1 n_tanh an ' 22 22 -mtanham am -an + (1+2v) QLR sinh am cosh am 1 +.81nh an cosh an n s1nh an cosh an an + 2am sinh am coshm 1 __m_tanh@” 2 2 2 a m? _ a n n tanh an +201m Sinhamcosham 1 _mtanhcxm am 22 22 ntanhan am E am +— 2 'an 2 2 ' [1 +_31nh am cosh am 1 pm 1 + n sinh an cosh an +_ E2 a2n2 [95 sinh am cosh am an sinh an cosh an ) pm 2amR sinh am cosh am 1 _ E.£§ED_QE;] (5 3-8) O[ZmZ _ aZnZ m tanh am BSi for Cases (3a) and (3b) Eliminating the i subscript from the functions in (5.3-4) through the substitution of the relations given in (3a) gives the same expression for BSi as with the substitution of the relations given in (3b). The resulting expression is almost identical to (5.3-8) except for one sign change. Consider (5.3-8) written as B = k(1)K I - —— . (5.3-8) SS 8 BSi for the cases (3a) and (3b) are 50 B . _—_ kinx + —-—-—-———— . (5.3—9) BSi for Case (3c) Substituting the relations listed in (3c) again yields a relation similar to (5.3-8) except for a sign change on the first term (1) i 2mk(2)K 1331 = -k K - ————5—-§-— . (5.3-10) S l + n Substituting the adjoint functions into (5.3-S) and (5.3-6), and factoring out the arbitrary constants kél) and kiz), the following is obtained for the normalization constants Nil) and N(2): s 2 . N(1) = (1+v)gn -l) m S1nh am cosh am _ 1 s 2 n sinh an cosh an vn - v - 2 fig-D 'tl h 4 2 + 251“ 20”“ C03 0““ [(2-2v)n + (l+5v)n - (1+v)] (5.3-11) 2amm (1+n ) N(2) _ i 2m(l+gxl+2v+n2) m_ sinh am cosh am _ _ 2 . s (vn -v-2)(1+n2) n Sinh an cosh an 2 . + (n -1):mh gm COSh 0““ [ (2-2\J)n4 + (l+5v)n2 - (l+v)] .(5.3-12) 2amn (l+n ) 2 2 In the derivation, biorthogonality was defined for ai * aS but examination of the operator reveals biorthogonality holds for a I ai # aS 130 5.4 Satisfaction of Boundary Conditions for the Even Problem The even problem is handled in exactly the same way using the eigenfunction expansion (4.2-2) and the even problem biorthogonality Sl operator. Substituting the even problem eigenfunctions and adjoint functions into (5.3-3) for Fs’ (5.3-4) for Bsi’ (5.3-5) and (5.3-6) for the normalization constants yields the following: (1) . 2 1 1 = 2 K. _....____ - - Bsi ks 31““ O’s,"‘sC°‘”’h “imi 0’s“"53 1 2 2 2 2 2 2 2 2 2 2 2 2 a n -aun. a m -a n a -a. S S S S S l 1 + tanh aimi “1m1K1 E ( 2 2 _ 2 2 1 tanh a m 2 2 2 2 2 asns “1“1) ' S S OIsns-Q’1ni pm _ tanh aimi aimiKi T;_ _E__( _ 2 2 _ 1 tanh a n 2 2 2 2 n 2 a “ 91mi) s s a n -a.m. 3 pm 5 s 1 1 - tanh aini ainiKi E ( m _ 2 2) - 1 tanh asms 2 2 2 2 2 a O[ini oIsms O[in1 pm tanh a.n, a,n,K, m + 11111 i—(an-2n2)-l tanh asns 2n2_ 2 2 2 “i 1 as s CYin1 S pm 20’ m2K 1+3\)-\)RS + —'2- (rim, 2 o o + i 2k( )sinh a m cosh q,m, 1 1 1 pm 3 s s 1 1 1+“2 2 2 . CY n " CY n. 1 1 1 2 2 +2 ——— 2 1 v't 2 afni 4m 2 2 2 2 a n - a.m, (1+n ) 1 1 s E 2 2 E 2 2 2 1+3 - +-——— 1+2 + ——— 2 C311(1+ni)RiKi V VRs pUL)2 aini V N2 “1% 4mS ' 2 2 2 2 2 ' 2 2 2 2 2 2 - - + OIsms aini Cvsms aimi (1 n5) E 2 2 E 2 2 + _. —— __ 2asmsmiKi 1 3v vRs + pr aimi 1+2v + 9&2 aimi tanh aimi - 2 2 2 2 2 - 2 - 1+ni asm - a.m. a n2 - agm? tanh O(sms s 1 1 s s 1 1 E 2 2 E 2 2 + _ __ __ 2a m m,R.K 1 3V vRs + 2 mini 1+2V + 2 aini tanh cum, + s s 1 1 i ppm _ 49w 1 1+112 2 2 2 2 2 2 2 2 tanh a m 1 asms ' O’i“1 asns " aini S S 52 Bsi for Case (2) 1 + am sinh am cosh cym[—;—‘§+ “-2—2" am an 1 o B = k( )K 1 + m sinh am cosh am 33 s n Slnh an cosh an + 22 _________ 2 n tanh an m tanh am a m -a2n2 m tanh am n tanh an i 2mk(2)K si h sh +————§-—- (1+3v-vR)[l- “ 0‘7"“ 0”" 2 am l+n + 2am R sinh am cosh am 1 _ n_tanh am 2 2 2 2 m tanh an (I’m an E.R sinh am cosh am 1 sinh gn cosh an n sinh an cosh an an + (l+2v)[ 2am sinh am cosh am 1 2 2 .E 2 2 n a m - a n tanh an tanh am + _§__ 2 2 1 _ sinh am cosh am _ Zam sinh am cosh am 20’m Om] 22 22 pm a m - a n m tanh an 1_—_._._____... n tanh am E + 20 pm 2n2 m,R sinh am cosh gm (1’11 sinh an cosh an n sinh an cosh an :3 2am R sinh am cosh am 2 2n2 + 2 am '0’ tanh an 3 1 - — Lam—0"“ J . (5.4-2) Bsi for Cases (3a), (3b), (3c) For the three cases of condition 3, the expression for B81 differs from (5.4-2) by only one sign change. Consider (5.4-2) written as 53 (1) 1 2m k(2)K B S = k K + Z s 3 1+“ Bsi for the case (3) are (1) i 2mk(2)K B . =k K - ————S§— . (5.4-3) 31 3 1+“ The normalization constants for the even problem are: N(l) = gliv)§n2-l) 1 _ m_sinh am cosh am 3 2 n sinh an cosh an vn -v-2 2 ' 4 2 + Q“ "”31““ “‘2“ C03“ m“ [ (2-2v)n + (l+5v)n - (1%)] (5.4-5) (1+n )2qmn N(2) __ i 2m(l+\)) Q+2v+n2) 1 _ Q sinh arm cosh am — 2 2 ° 3 (vn -v-2)(1+n ) n Sinh an cosh an 2 + in -l)sinh am cosh am 2 2 [(2-2v)nA + (1+SV)n2 - (1+v)] .(5.4-6) 2amm (1+n ) CHAPTER VI DETERMINATION OF THE EIGENVALUES 6.1 General Remarks The eigenvalues a are the roots of the transcendental equations tanh am 4mn -— = —— 6.1-1) 2 2 ( tanh an (1+n ) tanh an 4mn -—-——-- = ---- . (6.1-2) tanh am (1+n2)2 Equation (6.1-l) is used for the odd problem, and equation (6.1-2) is used for the even problem. Similar equations occur in the in- vestigation of wave prOpagation in an infinite plate. This prob- lem has received much attention, and the solutions of these equa- tions have been made, but, as far as this writer has been able to determine, not for the complex values of a associated with the decaying wave modes close to the finite edge of the plate. This study is concerned with the investigation of all bounded modes for each frequency of propagation. Equations (6.1-1) and (6.1-2) de- fine the eigenvalues on the real axis and the upper half of the complex plane. 6.2 Determination of the Real Eigenvalues for the Odd Problem The transcendental equations are solved with the frequency w as a parameter and the Poisson ratio v taken to be equal to 54 55 1/3. Recalling that 2 2 2 2 2 a m = a - Q§_'(1'V ) 2 2 2 2 2 (1117-01 ~“5‘UL(1+V) , it is convenient to substitute constants "a" and "b" such that 2 2 2 2 2 2 For v = 1/3, the constant b equals 3a. Equation (6.1-l) can now be written as tanh'2 a =4q2Q2—aJa2-3a a - f——————- 2 2 tanh 2 3a (20 - 3a) a - (6.2-l) Consider the solution of equation (6.2-1) when a is very large compared to "a" and the hyperbolic terms approach unity. a6 - 5.25q4a + 6.75q2a2 - 2.53a3 = o (6.2-2) Only one root of equation (6.2-2) yields a real argument for the hyperbolic functions. This root is a = 1.884 V a . (6.2-3) Consider the solution of equation (6.2-l) when a and "a" are very small and the hyperbolic functions can be replaced by their arguments. 40,4 - 1202a + 9a = 40,4 - 1203.1 (6.2-4) For this equation to be satisfied, "a" (or w) must equal zero. 56 The phase velocity, c, of a given mode equals w/a, and the wave length A is defined in terms of a by a = Zn/A. When a is very large (small wave length), the limiting phase velocity is C w/a = w/l.884‘/a , c = 0.563 E/p When a approaches zero the phase velocity approaches zero. Intermediate values of a have been obtained numerically with the computer for seven values of frequency. For each frequency, the root yielding the lowest phase velocity is identified as the first mode root, and the mode with the next highest phase velocity is mode two, and so on. Table VI-l lists the odd problem real eigenvalues of the first four modes for the frequencies examined and the correSponding \/ E- , the velocity of prOpagation of plane longitudinal waves along a rod. Tabulation phase velocity ratio c/cO where c0 of all the eigenvalues for these frequencies is found in the appendix. Figure VI-l is presented to graphically illustrate the phase velocity-wave length dependence. Phase velocity variation with changes in wave length is termed dispersion stemming from the fact that this characteristic causes distortion of the shape of a prOpagating pulse. The first mode curve is in close agreement with the dispersion curve for flexural waves in cylindrical bars, and the trend of the higher mode curves indicated by the few data points plotted is in agreement with published phase velocity curves for flat plates and cylindrical bars. The intent here is not to present, a complete solution of the transcendental equations, but to attach 57 some physical significance to the real eigenvalues and make some comparisons of the values used to solve the problem with published results (13)-(15). 6.3 Determination of the Real.Eigenvalues for the Even Problem Following the same procedure as in article 6.2, equation (6.1-2) can be written as {‘5 tanh “(12 - 3a - hazvgz - a {(12 - 3a 2 2 tanh '02 - a (2d - 3a) Considering the solution of (6.3-1) when a is very large relative (6.3-1) to "a" yields the result (6.2-3). Considering the solution when a 2.; and "a" are very small yields -8a2+9a=0, Thus, when a is large the phase velocity approaches 0.563 co. or 0 II Q l8 When a approaches zero, the phase velocity approaches co. Intermediate values of a were obtained numerically, and Table VI-2 lists the even problem real eigenvalues of the first four modes and the corresponding phase velocities for the frequencies examined. Figure VI-2 illustrates the dispersive nature of the first three modes. The flmplied shape and values of the curves are close to those found in the literature for flat plates and cylindrical bars. For the first mode, the velocity ratio c/cO approaches 1.062 for the flat plate and approaches one for the cylindrical bar as a approaches zero. 58 6.4 Determination of the Complex Eigenvalues for the Odd and Even Problem Writing equation (6.2-1) in the following form (20,2 - 3a)2tanhV 012 - a - Aazfaz - aJaZ - 3a tanh V012 - 3a = 0, (6.4-l) and (6.2-2) as (20/2 - 3a)2tanhVa2 - 3a - 4(12 {0:2 - a V02 - 3a tanh (:2 - a = 0, (604-2) and letting a = x + iy, solutions were made numerically by use of a digital computer. An asymptotic solution of (6.4-1) for a very large compared to "a" aided the search for the roots by isolating the roots in the complex plane and giving very good approximations of the roots at low frequencies. It is of interest to note the comparison of the complex roots of (6.4-1) and (6.4-2) with the roots obtained by Johnson and Little in their solution of the static problem. This comparison is given in Tables VI-3 and VI-4. The first quadrant complex roots for two frequencies, 1000 and 31600 cycles per second, are plotted in Figure VI-3. The roots for all frequencies examined are tabulated in the appendix. The calculations were made for a material density of 15.1 slugs per cubic foot and a Young's modulus of 30(106) pounds per square inch. All dimensions are in units of feet. 59 Table VI-l -- Real Eigenvalues and Phase Velocities for the First Four Modes of the Odd Problem Eigen- Velocity Wavelength Frequency w Constant value Ratio Strip Width cps "a" Cox c/cO 100 0.00123 0.259 0.144 12.130 1000 0.123 0.969 0.384 3.242 6380 5.0 4.30 0.552 0.731 2.42 0.980 1.300 10000 12.3 6.63 0.561 0.474 5.38 0.691 0.584 3.29 1.131 0.955 1.44 2.583 2.182 31600 123.0 20.89 0.563 0.150 19.12 0.615 0.164 18.38 0.640 0.171 16.90 0.696 0.186 63800 500.0 42.12 0.563 0.074 38.69 0.613 0.081 38.39 0.618 0.082 37.78 0.628 0.083 100000 1230.0 66.07 0.563 0.048 60.18 0.618 0.052 59.63 0.624 0.053 58.89 0.632 0.053 Table VI-2 -- Real Eigenvalues and Phase Velocities for the First Four Modes of the Even Problem Eigen- Velocity Wavelength Frequency w Constant value Ratio Strip Width cps "a" ea c/cO 100 0.00123 0.0372 1.000 84.451 1000 0.123 0.373 0.997 8.422 6380 5.0 4.056 0.584 0.774 2.238 1.060 1.404 1.131 2.097 2.778 10000 12.3 6.580 0.565 0.477 3.926 0.947 0.800 3.316 1.120 0.947 31600 123 20.89 0.563 0.150 18.84 0.624 0.167 17.74 0.663 0.177 15.85 0.742 0.198 63800 500 42.12 0.563 0.074 38.58 0.615 0.081 38.12 0.622 0.082 37.36 0.635 0.084 100000 1230 66.07 0.563 0.048 60.65 0.619 0.052 60.38 0.616 0.052 59.93 0.621 0.052 61 1» 1.5 . c/c 0 C924 h\ 1.0 ~ b X \ \ ®‘H \\ \ \ \ \ \ “ ‘YL \ ‘ ~ ~.1 \"‘ _____________ ‘1i5kc;:; r5 0" E O°5 _ Mode 3 2 L o 5 10 15 20 a L Figure VI-l -- Phase Velocity Variation of the Odd Problem for the First Three Modes 1.5 i 3/ c/co S; c2 Q YEP \ 1.0‘cou In HuHH> eHan ucwumcou 71 -H «00.0 + «00.0: ~H 000.0 + Nq0.0 -H mNH.0 mHH.0 -.-I 000.N Nm0.01 w-l m00.0 + mHo.on mecca mo pHcm HH .C N ‘H m00.0 + m00.0: ~r-Il 0H0.0 + mm0.0 w-i me.0 wHH.0 'H 00H.N Nm0.0u H N00.0 + mH0.0: mecca mo comm oH pxx o u c a %_m moo nxx t O ”-4 000.0 + m00.0u ~H 0H0.0 + 0q0.0 H NmH.0 u 0HH.0 0H 00H.N u «no.0: '1-4 N00.0 + mH0.0| muoom Ho uHmm m "mcoHuocsm kumcosom ~H m00.0 + «00.0: H 000.0 + m¢0.0 ‘H 00H.0 0NH.0 ~H www.H ~m0.0| H «00.0 + NH0.0n muoom Ho uHmm m N EoHpoum HoH museumcou coHuucsucome Ho mucmwpo>coo nu NuHH> oHan k) u L) ucwumooo 72 Table VII-3 -- Approximation of Boundary Function, Problem 1 Boundary Function: 0 = -3y + 10y3 - 7y5 = 0 Series Solution with 15 pairs of Eigenvalues Prescribed Stresses Cxxb 0.00000 -0.29007 -0.52224 -0.64701 -0.63l68 -0.46875 -0.18432 0.15351 0.42624 0.45657 0.00000 nyb 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 Series Solution 0 XX 0.00000 -0.29013 -0.52222 -0.64696 -0.63174 -0.46878 -0.18422 0.15348 0.42612 0.45662 -0.00051 0' xy 0.00000 0.00002 0.00006 -0.00005 -0.00004 0.00009 -0.00001 -0.00011 0.00008 0.00010 0.00000 73 H aoHnoum .0 n x oomuusm co mommouum muwpcsom nu HuHH> mustm 1 0.H: r Moo- b 0.0 0.0 «.0 ~.0 N.0n «.0: 0.0: 0.0: 0 I phxb lll xx . m.0 me u moH + mm- u n b . 0.H 0 74 muoz xx XX b 75 %% H aoHnoum .0 u x us 6 mmouum nu muHH> oustm 70:7. _/ _/ . . _ _ mowoz wchmomaucoz 0:9 uuuuu _ . ”r moOl mmmuum oomuHsmom _ 0 .1 .0 .0 men mH 0H : mu 0H: mHu L? _ 1. a. ._ _. a . 0 . H m o _ e\_ _ . . We 2. I :3 0 m 76 N EoHnoum .0 n x eummusm so mommmuuw assessom :1 quHH> musmHm . 0.H: . n.01 . m.0 77 N .8395 .0 n x as nope: 963 wchmoon—uaoz can. I. nuHH> ousmHm %% N EoHnoum .0 n x on .o amouum nu ouHH> oustm 78 A b: mmpoz mlowumnuooz I.l.n mmouum ucmuHsmmm H.0 N.0u m.0u 79 m EoHnoum .0 u x no memo: xxb monmoeauooz one new xx xx 6 .mopoz mmeuum wcmeoonucoz n:.u O-u Duanb nhx xx ch u u b .mmmuum xumwcsom n% x b mmouum unsucsom uu mnHH> oustm BIBLIOGRAPHY 1? 10. BIBLIOGRAPHY Todhunter, I. and Pearson, K., A History of the Theory of Elasticity and of the Strength of Materials, Vol. 2, pt. 1, Cambridge Univ. Press, London, 1893, Chapter 10. Hr? Todhunter, I. and Pearson, R., A History of the Theory of Elasticity and of the Strength of Materials, Vol. 2, pt. 1, Cambridge Univ. Press, London, 1893, Chapter 10, pp. 11-12. Todhunter, I. and Pearson, K., A History of the Theory of Elasticity and of the Strength of Materials, Vol. 2, p; pt. 2, Cambridge Univ. Press, London, 1893, Chapter 13, p. 273. Todhunter, I. and Pearson, R., A History of the Theory of Elasticity and of the Strength of Materials, Vol. 2, pt. 2, Cambridge Univ. Press, London, 1893, Chapter 13, p. 271. von Mises, R., "0n Saint4Venant's Principle," Bull Am. Math. Soc., vol. 51, 1945, pp. 555-562. Sternberg, E., "On SaintJVenant's Principle," Quart. Appl. Math., vol. 11, 1954, pp. 393-402. Johnson, M.W., Jr. and Little, R.W., "The Semi-Infinite Elastic Strip,"(1uart. Appl. Math., vol. 22, 1965, pp. 335-344. Klemm, J.L. and Little, R.W., "The Semi-Infinite Elastic Cylinder under Self4Equilibrated End Loading," SIAM J. Appl. Math., vol. 19, 1970, pp. 712-729. Thompson, T.R. and Little, R.W., "End Effects in a Truncated Semi-Infinite Wedge and Cone," Quart. J. Mech. Appl. Math., vol. 23, no. 2, 1970, pp. 185-196. Boley, B.A., "The Application of Saint4Venant's Principle in Dynamical Problems," J. Appl. Mech., vol. 22, no. 2, 1955, pp. 204-206. 80 ll. 12. l3. 14. 15. 81 Kennedy, L.W. and Jones, 0.E., "Longitudinal Wave Propagation in a Circular Bar Loaded Suddenly by a Radially Dis- tributed End Stress," J. Appl. Mech., vol. 36, no. 3, 1969, pp. 470-478. Folk, R., Fox, 0., Shook, C.A. and Curtis, C.W., "Elastic Strain Produced by Sudden Application of Pressure to One End of a Cylindrical Bar. 1. Theory," J. Acoust. Soc. Am., vol. 30, 1958, pp. 552-558. Kolsky, H., Stress Waves in Solids, Dover, 1963, Chapter 3. Redwood, M., Mechanical Waveguides, Pergamon Press, 1960, Chapter 5. Jones, O.E. and Ellis, A.T., "Longitudinal Strain Pulse Propagation in Wide Rectangular Bars, Part 1 - Theoretical Consideration," J. Appl. Mech., vol. 30, no. 1, 1963, pp. 51-60. [5: APPEND ICE S APPENDIX A TABULATED EIGENVALUES 82 TABLE A’I --ROOTS OF TRANSCENDENTAL PU N OOQNO‘U‘ FREQUENCY EQUATION 000 PR oaN 1.384371 1.676120 1.858393 1.991577 2.096630 2.183401 2.257323 2.321716 2.378759 2.429960 (601-1) OBLEM .259341 +10.000000 3.748499 6.949802 10.119137 13.277181 16.429796 19.579346 22.726982 25.873337 29.018789 32.163579 = 100 CYCLES POISSON RATIO = 1/3 H- EQUATIONS (6.1-1) PER SECOND EQUATION (6.1-2) EVEN PROBLEM eaN .0371997 +-10.000000 1.125419 2.105550 1.551595 5.356036 1.775555 8.536538 1.929412 11.699072 2.046858 14.853977 2.141895 18.004865 2.221726 21.153355 2.290555 24.300292 2.351050 27.446158 2.405014 30.591255 83 TABLE A-2 --ROOTS OF TRANSCENDENTAL EQUATIONS (6.1-1) AND (601-2) 0 w A) O o: '4 0 U1 10 11 12 13 14 15 16 17 1s 19 FREQUENCY EQUATION (601-1) ODD PROBLEM oaN .969392+-i 0.000000 1.387431 1.677591 1.859280 1.992178 2.097068 2.183736 2.257588 2.321933 2.378940 2.430112 2.476535 2.519015 2.558169 2.594481 2.628334 2.660042 2.689860 2.717999 3.714782 6.932145 10.107082 13.268010 16.422389 19.573132 22.721629 25.868635 29.014596 32.159796 35.304422 38.448604 41.592435 44.735984 47.879302 51.022428 54.165395 57.308225 = 1000 CYCLES PER SECOND POISSON RATIO = 1/3 EQUATION (6.1-2) EVEN PROBLEM a e .3730024-i 0.000000 1.130700 1.553632 1.776676 1.930134 2.047367 2.142276 2.222023 2.290794 2.351247 2.405180 2.453862 2.498226 2.538975 2.576654 2.611694 2.644439 2.675173 2.704127 2.040549 5.332933 8.522219 11.688658 14.845783 17.998107 21.147604 24.295285 27.441726 30.587278 33.732171 36.876562 40.020558 43.164241 46.307669 49.450887 52.593930 55.736826 If 84 TABLE A-3 --ROOTS OF TRANSCENDENTAL EQUATIONS (6.1-1) 10 11 12 13 14 15 16 17 18 AND FREQUENCY = 6380 CYCLES PER SECOND (6.1-2) POISSON RATIO EQUATION (6.1-1) ODD PROBLEM oaN 2.421033 1.355817 1.702163 1.877602 2.005841 2.107627 2.192156 2.264475 2.327682 2.383821 2.434316 2.480197 2.522237 2.561030 2.597039 2.630638 2.662129 : 4.295876+ 1 0.000000 0.000000 1.992252 6.179568 9.609329 12.893890 16.122062 19.322040 22.505794 25.679321 28.845969 32.007763 35.165999 38.321548 41.475016 44.626840 47.777341 50.926763 1/3 EQUATION 1601-2, EVEN PROBLEM eO‘N 4.0559994-i 0.000000 2.237781 1.130842 1.577832 1.798075 1.945888 2.059326 2.151671 2.229616 2.297072 2.356535 2.409702 2.457780 2.501657 2.542008 2.579357 2.614120 2.646631 0.000000 0.000000 4.304994 7.924157 11.261712 14.512666 17.724623 20.915484 24.093585 27.263356 30.427379 33.587264 36.744066 39.898511 43.051111 46.202239 49.352174 'ulkx F. '. LE 85 TABLE A-4 --ROOTS OF TRANSCENDENTAL EQUATIONS (6.1-11 N 0‘ L“ k U h) m 10 11 12 13 14 15 16 17 18 19 AND (601-2) FREQUENCY = 10000 CYCLES PER SECOND POISSON RATIO = 1/3 EQUATION (601‘1) ODD PROBLEM oaN 5.378575 3.286863 1.436153 1.517139 1.826559 1.983445 2.095982 2.185563 2.260571 2.325330 2.382416 2.433512 2.479787 2.522091 2.561062 2.597194 2.630877 2.662425 i 6.630079 + 1 0.000000 0.000000 0.000000 0.000000 4.818572 8.800626 12.306705 15.658226 18.937701 22.177246 25.392200 28.590880 31.778207 34.957288 38.130183 41.298318 44.462708 47.624099 50.783048 EQUATION 1601‘2) EVEN PROBLEM eaN 3.926267 3.315675 .805028 1.710236 1.913085 2.043406 2.142976 2.224562 2.294043 2.354712 2.408631 2.457193 2.501392 2.541960 2.579457 2.614321 2.646901 2.677480 1 6.579686 + 1 0.000000 0.000000 0.000000 1.973710 6.917090 10.582463 13.994701 17.304375 20.561275 23.787170 26.993212 30.185738 33.368631 36.544408 39.714775 42.880930 46.043740 49.203849 52.361744 an. ‘41 ~43'..j W 86 TABLE A-S --ROOTS OF TRANSCENDENTAL EQUATIONS (6.1-1) \OGNO‘U'I 10 11 12 13 14 15 16 17 1e 19 20 AND FREQUENCY = (601’?) POISSON RATIO EQUATION (6.1-1) ODD PROBLEM oaN 19.116382 18.381749 16.903148 14.554569 11.561352 10.709123 9.690573 8.071672 5.638132 1.109372 0.000000 .821718 1.574184 1.705364 1.665112 1.493388 1.058952 0.000000 1.174472 at 20.893342 + i 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 6.327763 11.332493 14.202922 18.660664 22.653411 26.420677 30.065269 33.689863 35.977305 38.321627 31600 CYCLES PER 1/3 SECOND EQUATION (6.1-2) EVEN PROBLEM (I e N 18.839587 17.740090 15.850131 11.088598 10.700487 9.681430 7.950855 4.312302 1.216463 .382669 0.000000 1.365751 1.669688 1.701246 1.597806 1.333585 0.000000 .363617 1.461126 i 20.893334 +i.0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 9.825665 12.971777 16.518870 20.694499 24.557542 28.253380 31.868434 35.246044 36.386089 40.076479 TABLE A-6 --ROOTS OF TRANSCENDENTAL EQUATIONS 87 AND (601-2) (601-1) FREQUENCY = 63800 CYCLES PER SECOND POISSON RATIO = 1/3 EQUATION (6.1-1) ODD PROBLEM oaN :t42.125041+-1 0.000000 38.691841 0.000000 38.387766 0.000000 37.777907 0.000000 36.855312 0.000000 35.603678 0.000000 33.993858 0.000000 31.980117 0.000000 29.496923 0.000000 26.477242 0.000000 23.205347 0.000000 22.171072 0.000000 21.657992 0.000000 20.824644 0.000000 19.670625 0.000000 18.256867 0.000000 16.281783 0.000000 14.064993 0.000000 11.648308 0.000000 4.201674 0.000000 0.000000 11.271708 1.311928 17.237081 .292534 23.194187 0.000000 25.992610 EQUATION (6.1-2) EVEN PROBLEM eaN i 42.125041-11 0.000000 38.577849 0.000000 38.121319 0.000000 37.356459 0.000000 36.272106 0.000000 34.845962 0.000000 33.041099 0.000000 30.802011 0.000000 24.795354 0.000000 22.382882 0.000000 22.202007 0.000000 21.644669 0.000000 20.797816 0.000000 19.682077 0.000000 18.195303 0.000000 16.543159 0.000000 14.153948 0.000000 10.156298 0.000000 7.960167 0.000000 .802532 13.652395 1.161230 20.331783 0.000000 24.405508 .904466 27.419767 1.521996 32.102359 88 TABLE A-7 --ROOTS OF TRANSCENDENTAL EQUATIONS (6.1-1) OGNO‘UTPUNW AND 1601-2) FREQUENCY = 100000 CYCLES PER SECOND POISSON RATIO = 1/3 EQUATION (6.1-1) ODD PROBLEM 60.177115 59.629017 58.893544 57.965518 56.837344 55.498506 53.934958 52.128313 50.054807 47.684164 44.979451 41.904074 38.478920 35.378636 34.900756 34.463530 33.836205 33.033031 32.012504 30.800500 29.420589 27.730862 24.000258 20.984984 17.915348 15.191106 6.107614 0.000000 1.230817 i 66.070545+ 1 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 13.641388 21.138086 EQUATION (6.1-2) EVEN PROBLEM 60.654611 60.381975 59.926245 59.284975 58.454013 57.427032 56.195045 54.745858 53.063368 51.126645 48.908797 40.226163 36.751606 34.853644 34.455069 33.829152 32.991782 31.995858 30.813558 29.399656 27.860995 23.511384 21.533973 18.332334 12.807290 10.498085 .825374 .553100 0.000000 1 66.070545 + 1 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 16.772158 24.873496 28.918273 APPENDIX B ASYMPTOTIC SOLUTION OF THE ODD PROBLEM TRANSCENDENTAL EQUATION The transcendental equation for the odd problem is tanh am 4mn tanh an = (1+n2)2 (3'1) where 2 0,2612 = 82 - 9%— (1 - 02) (8.2) 2 a2n2 = oz - Z§Q_.(1 + v) (B.3) The eigenvalue 0 is found for a given frequency w and Poisson ratio equal to 1/3. Thus, (B.2) and (B.3) can be written in terms of the constant "a" 2 2 a Jug—(1H1) 22 2 am =QI-a qznz = 02 - 3a . Substituting these two expressions into equation (B.1) yields tanh £2 - a = 4072 {0’2 - a «(i172 - 3a (B a) 2 2 tanh o2 - 3a (2a - 3a) The asymptotic solution yields values of a in the complex plane for a very large relative to the constant "a". Substituting 0 = x + iy gives 89 90 Vaz-a= fxz-yZ-a+2ixy =x+€1+i(y+32), (8.5) where 91, 52 << 1. Squaring both sides of (8.5), cancelling like terms, and neglecting the higher order terms of 61 yields .3 Xel - ye2 = - 2 yel '1’ X62 = O . Solving these two equations for 31 and 32 gives c1 = - fix—2 (8.6) 2y a 62 - 2y . (8.7) The right hand side of equation (B.4) becomes 2 . . 4612 1/82 - a V82 - 3a = 40’ [0’ + ‘31 + 162]“ + 3(31 + 1‘32)] (282-4602 (2,2..3.)2 Substituting 6c = 31 + iez, the right side is 2 4o (a + ec)(a + see) 484 +16chc + 1282.: (2a2 - 3a)2 404 - 12a2a + 9&2 As 0 becomes very large relative to "a", this ratio approaches 1. The left side of (B.4) can be written as tanthz - a _ tanh” + 61 + i(y + 6’2” _ tanh(p + 16) r-—--- tanh[x +13; + i(y + 3e )] - tanh(r + is) tanh a2 - 3a 1 2 tanh p +'i tan_gr . l + i tanh r tan 8 1 +'i tanh p tan q tanh r + i tan 3 , (B-8) where 91 p=M1-3fi . r—Ml-Efi 2y 2y ' 3a q=y(1+—32) , 3=y(1+—2) . 2y 2y As X and Y become very large, tanh p a tanh x a l tanh r a tanh x a l and (8.8) may be written as tanh x[1 - tan q tan s] + i[tan q + tanhzx tan s] (8.9) tanh x[1 - tan q tan s] + i[tan s + tanhzx tan q] The ratio (8.9) must approach unity for large a. This requires that tan q equal tan 3 tan q = tan 8 a 3a tan (y + 2y) tan(y 2y) Using the identity for the tangent of the sum, and replacing the tangent of the small argument with the argument itself yields a 3a tan y +~2y = tan y + 2 a 3a 1 - 2y tan y 1 -2y tan y As y increases without limit, tan y should remain of the order of magnitude 1. Thus, tan q and tan s approach unity. Assume for y: = (424-511 '1’ 6 , 6 << 1 . (8.10) a tan y +1;- tan q = tan(y + E;- = ,y = l (8.11) 1 -'- tan y Y 92 For y defined by (8.10), _ 4n+l _ 1+6 tan y — tan[( 4 )n + 5] — {:3 Substituting into (8.11) yields 1:61 a..- 2.12:9. 1-0+2Y 1 2y (1-6) ’ or 6 = - %;' which is negligible for large values of y. Like- wise, requiring tan 5 to approach unity and solving for 6 gives 3a 6 = - E;' which is negligible for large values of y. Thus, for large values of y, the imaginary part of a is approximated by _ 4n+1 y (“Z—‘9n . Having isolated the imaginary part of a, the real part, x, is determined from equation (8.4) numerically with the compUter. LIB 1111'“ 99 MIITIIITIWINIWILIIEW1111011151111| 3 1293 0306171