‘w‘fi-——v—-——v— V SOME ERGODIC PROPERTIES OF ’MULTI-DIMENSIONAL F--EXPANSIONS Thesis for the Degree of Ph. D. MICHIGAN STATE UNIVERSITY MICHAEL SPENCER WATERMAN 1969 LIBRARY ' Michigan State University This is torcertifg that the thesis entitled SOME ERGODIC PROPERTIES MULTI-DIMENSIONAL F-EXPANSIONS \ presented by Michael Spencer Waterman has been accepted towards fulfillment of the requirements for __Eh_._D_._ degree inms & Probab ility I // Major professor I Date @4415 f 0-169 ABSTRACT SOME ERGODIC PROPERTIES OF MULTI-DIMENSIONAL F-EXPINSIONS By Michael Spencer Waterman Let F be a one to one mapping of a convex set A<: Rn onto (0,1)n with nonzero Jacobian. For x 6 (0,1)“, we consider {ak(x)}k21, ak(x) = [F'1(5k'1(x))] where 6(x) = F'1(x) - [F'1(x)] and ['] is the greatest integer function taken coordinate by coordinate. For each set of coordinates k1,...,kv, we define the cYlinder BV = {x : ai(x) = ki, i = l,...,v} and Jv(t)’ the Jacobian of F0:1 +F(k2 +3..+ F(kv + t)...)). Also Bv(x) = {y : ai(y) = ai(x), i = 1,...,v}. The following assumptions are imposed (m denotes n-dimensional Lebesgue measure): sup lJv(t)l V V :65 B C) inf [Jv(tfl S C ° t66va L) o < L s m(5"B") Av+1 . . Q) For each BV there exists B , a collection of cylinders B:+1<: Bv satisfying 6 v+le+1 = (0,1)“, such that Av+l O < q S m v ° m(B) ”'1‘ v“ ~- Michael Spencer Waterman Under these conditions we show there exists a measure p ~ m so that 5 is a measure preserving transformation. If ufix : diam Bv(x) a 0} = 1, then 5 is ergodic. If 6 is ergodic with respect to n, then we have rates on v the measure of B (x) as v a m: 1 1 1m 3 log u) = lim 3 log m=f dx E (log 2) (1+x) has the preperty u(5-1E) =‘i(E). That is, p is an invariant measure for 6. u is known as Gauss' measure. This result was, as we see below, already contained in Kuzmin's Theorem, but Ryll-Nardzewski made an application of the individual ergodic theorem to obtain, for all Lebesgue integrable f, -1 1 , 1 n k 1 f t 11111; )3 f(6 (x)) = 10 21.7143; dt, a.e. [In]. n—m k=0 g o This result yields various measure theoretic results on continued fractions such as xrwu For each natural number p, the frequence of p in 2 . 1 (112) the sequence {an(x)} 15 log 2 log p(p+2) for al most all x. The next advance came in 1957 when A. Renyi [18] established similar results for the f-expansions of Everett [6] and Bissinger [3]. Suppose f maps a subset of the real line onto (0,1) in a (1-1) fashion. We formally define 6(x) = r1(x) where also =[f‘1(x>], r1(x> = f‘1>1. rn = f'1) - [f'1]. Note an(6(x)) = an*1(x). That is 6 is still the shift operator. When f(x) = %3 we obtain the continued fraction coefficients and w a (x) when f(x) = 2- we obtain the q-adic expansion x = 2 nn . n=l q Convergence theorems are stated below. A) The following conditions for decreasing f are due to Bissinger [3]. We assume Al) f(1) = 1 A2) f(t) is non—negative, continuous, and strictly de- creasing for 1 s t s T and f(t) = 0 for t 2 T where 2 < T is an integer or +-m. A3) |f(t2) - f(t1)| s |t2 - 1:1] for 1 _<. t < t and l 2 there is a constant I E (0,1) such that if 1+f(2) 1 is an integer or +00. f(tz) - f(tl) t2":1 Then for all x 6 (0,1), we have B3) <1,0st1 [Domes], ek = Dok'lx) - [D O for all x E (0,1): and the closure of Bv(x) is assumed Jordan measurable for all x 6 (0,1);. The identity x = F(a1(x) +-F(a2(x) +;..+'F(av(x) +-5V(x))...)) can be written x = f 1 o f 2 o...o f v(6V(x)) if f i(t) = F(ai + t). a a a a Since'there is a chain rule for Jacobians ([1], p. 140) just as there is for functions of one variable, and since the integral of a Jacobian is area ([1], p. 271), we make fundamental use of this composition of functions. The entire theory we construct is based on the following observation: 12 1 Lemma 2.1. If B" is generated by k ,...,k", then V Bv = f 1 o f 2 o...o f (5VBV) = n o f i(5"3"). k k kV i=1 k Proof. f 1 o f 2 o...o f v(6VBV) = U {F(k1 +F(k2 +...+ F(kv + 6v(x))..))} = k k k xer = lJ {x} = Bv. xEB\J The assumptions on F made above will be used throughout and when they hold we will write F E 3. Below we make three additional assumptions on F. Every use of these conditions will be clearly indicated. The following condition generalizes condition C) of Renyi [18]: sup ‘Jf (t)| teavsv v C) SC<+oo inf Jf (t)] t€5va v v where fv = H o f i for each v 2 l and all admissible cylinders i=1 k Bv(k1,...,ky). This condition is to assure us that no path of the process is too flat or too Steep. That is, condition C) is a reg- ularity condition on the flow. v v n . It should be remarked that 6 B ; (0,1)F but Strict con- tainment can occur. In the n-dimensional continued fraction (to be discussed below) for example, 6VBv = [x : xj < xn, j s n-l; xn 6 (0,1)] occurs a countable number of times (whenever ky = (k,...,k), k 2 1). If bva = (0,1);, we say Bv is proper; otherwise BV is said to be improper. Difficulties associated with imprOper cylinders lead 13 “3 t0 the next two conditions. v v o L) m(éB (x))2L>O for all xEB ,v=1,2,... . . . v . Condition L) assures us that 6 Bv is never too small. A \)+l For each Bv(x), there exists B a collection of proper cylinders of order v + 1 contained in Bv (x) such that m ev+l o q) Lv 2q>O forall xEB,v=1,2,.... 11103 (X)) Condition q) implies that the sum of the measures of the proper cylinders of any given order is at least q > O. III. CALCULATION OF THE INVARIANT MEASURE For any F 6 3 with conditions C) and L) satisfied, we Show there exists a probability measure u invariant with respect to 6. This is the initial step in establishing an ergodic theory for g. The proofs follow Renyi's [18] technique for the one-dimensional case but must be modified to handle 5V3” # (0:1);- It is this techni- cality that complicates F. Schwieger's [26] calculation of the results of Ryll-Nardzewski's Theorem for the n-dimensional Jacobi Algorithm. Theorem 3.1. Suppose that F 6 5 satisfies condition C) and con- dition L). Then, if g is any Lebesgue integrable function on (0,1)“, we have (by an Ergodic Theorem) 1 v-l j A lim'; 2 g(6 (X)) = 8(X) van j=0 exists for a.a. [m] x E (0,1)n . g E L and g = E(g]l) where l I = {E : 6-1E = E] and E(-) is with respect to u below. Also there exists a probability measure n on (0,1)n such that u << m and 6 is a measure preserving transformation for u. Moreover u(E) S'i'm(E) holds for measurable E<: (0,1)“. V Proof. Let J (t) = J (t), f = n o f ., and 3V = Bv(k1,...,kv). v i=1 k By an area theorem for Jacobians and Lemma 2.1 I. ‘Jv(t)]dt = m(Bv). 5V3V 14 15 Lfit <3 denote an admissible sequence k1,,,,,kv, If 6 runs v over all admissible sequences From this we obtain la 2 inf ‘Jv(t)‘m(6va) s 1 s 2 sup ‘Jv‘m(6va) 6v 5"}3" 6v 6va I ' and 1 I (3.1) L: inf IJ (t)] s 1 s2 sup Id l. i .1 v v V 6 v v v v 6 B v 6 B It Now we set E = X [a,,b,) where O s a, s b, s l. , 1 1 1. 1 i=1 6-V(E) = (F(k1 + F(k2 +...+ Fae" + t)...)) : t e E n (9’3"). 5 V Due to the 1-1 property of F, the above union is disjoint. By a Jacobian argument similar to the one above, we obtain m(b’vE) = z I \J (t)Idt s z sup N Im(6VBv n E) s 6 v v V 5 v v V v 6 B OE v 6 B 0E _<. 2 sup ‘Jva(E) = m(E) z sup lJvI. (3v 6va 6v 6va Using the earlier inequality (3.1), z supIJ I s V C -v m(E) v __ ““6 E) S L z inflJvls me)' 6V This yields 1 v-l _. (3.2) 3 z m(6 JE) s f m(E) j=O It l6 VVQTEE E is the product of rectangles, and hence (3.2) holds all measurable subsets of (0,1)n. By the direct application of a theorem of Dunford and Miller [5], (3.2) implies 1 V']. k A (3.3) lim - E g(6 x) = g(x) v v4» j=0 exists for all g F L1(0,1)n and a.a. x 6 (0,1)“. We may also define (applying (3.3) above) 1 v-l -j ”(E) = 11m; 2 m(6 E) van j=0 which easily has the properties ME) s §m 0 such that v EMELQ_§_2.2 d' v m(B ) uniformly in E 6 Id and proper Bv, v 2 0. Proof. As usual we write Jv(x) = Jf (x), fv = v i 1 k1 v v n B = B (k1,...,k ). We Show the inequality for E = X (ai’b 1, i=1 0 3 a1 S b1 3 1, where m(E) = d. Since 6-vE = E, 1 (x) = 1 (x) = 1 (5vx) = 1 (f’lcx)) for x 6 EV E -v E E v ’ ' ' 6 E Then,using the transformation theorem for Jacobians, f1E(x)dx =]‘1E(f;1(x))dx = 13V . BV = I IE(t)|Jv(t)|dt. oVBV Using this relationship (and 6VBV = (0,1);), m(Bv n E) 2 inf ‘Jv(°)‘ I IE(t)dt = m(E) inf ‘Jv(.)] 2 (0.1);l SUP‘JV(')I 2 m(E) ____E_____ . [ii 1.. 20 But sup ‘Jv(-)| 2 I IJth)Idt = m(Bv), n n (0,1)F (0.1)F so that m(E n Bv) 2 LII-g)- m(Bv) or —SE—-—lm nBv 2é=d'>0. mas") C Next we note that condition q) allows us to replace an im- proper cylinder by the proper cylinders contained in it and lose an arbitrarily small portion of the cylinder. Lemma 4.2 corresponds directly to a result of Schwieger [25] concerning the Jacobi Algorithm. Lemma 4.2. Suppose F E 8 and satisfies condition q). Then for an arbitrary cylinder Bv and e > 0, there exists countably many dis- joint prOper cylinders B“ and an integer v = v0(e) such that v 0 o (i) BVD U B” a u=v+l and V v o u (ii) m(B .. U B)m 0 Such that v Wzdtl>o m(B) uniformly in E 6 Id and BV (v 2 0). 22 Ptoof. We apply Lamas 4.1 and 4.2. 2' denotes a summation over 11. proper cylinders as above. For all e > 0, v Vo ' V'l']. ' O V p, m(Eij:=zm(EnB )+...+zm(EnB )+m(EnB "#13” v v v m(B ) 2'm(Bv+1) +...+ 2'm(B 0) + m(Bv ... \H’I B“) t V 22 m(E n Bv+lj +...+Z'mG n B o) v Z'm(BV+1) +...+2'm(B o) + e If we let 6 —» O, we can obtain m(En sz 29:: d" 2 . m(BV) We now must define a Vitali covering. We follow Saks and Banach([22], p. 105-118). ‘Suppose EC Rn' Then r(E) = inf BE)- , m(J) ’ where the infimum is taken over all cubes J23 E. {En}n21 will be called a regular if there exists a > 0 such that r(En) >'a for n = 1,2,... . We say that {EnInzl tends to a point x if, x 6 En’ n 2 l and diam(En) » O as n ~»m. A family .8 of sets is said to cover A in the sense of Vitali, if for every point x E A, there exists a regular sequence of sets in .b tending to x. The Lebesgue density theorem then states that m(En C B) lim———— =I (x) for a.a. x. En-tx m(En) B We can now prove the following theorem. 23 “\EOrem 4.1. Suppose F 6 :3 satisfies condition C) and condition q). M Also assume [Bv]v20 covers (0,1); in the sense of Vitali. Then -1 6 E = E implies m(E) = 0 or 1. Proof. Suppose m(E) = d > O and 6-1E = E. Then we have a Vitali covering in which the relative density of E in each set Ev E [Bv]v20 is strictly greater than 0. The Lebesgue density theorem asserts m(Ev O E) lim -————————-= I (x) for a.a. x. qux m(Ev) E m(E fl Ev) ll But Corollary 4.1 proves "ETE‘T" 2 d > O for all Ev. Thus v IE(x) = l a.e. and m(E) = 1. Since there exist interesting examples (which include the n- dimensional continued fraction) where {Bv}v20 is not a Vitali cover, we proceed to extend Theorem 4.1. Our method will be to construct an ”approximate" Vitali cover from the EV. We will be considering cases similar to the f-expansions of Everett [6] and Bissinger [3]. The generalization to be considered is diam(Bv(x)) a O which will be alternatively written as Bv(x) a x. The idea is that x E Bv(x) for all v. If y # x satisfies y e B"(x) for all v then dianai"(x)) 2 IIx-yII > 0. Thus the generalization is a natural extension of the one-dimensional con- vergence. Notice that if {Bv]v20 covers (0,1); in the sense of Vitali, we have Bv(x) a x for all x. The following theorem characterizes this convergence. Schwieger [25] uses conditions ii) and iii) in showing ergodicity. We will make use of the theorem in connection with proving a.e. convergence and constructing the approximate Vitali cover below. and 3£811 "here 24 r‘ihjfi-Orem 4.2. Suppose F E 8 and condition q) holds. Then v m(x : B (x) a x) = 1 if and only if for all Bv and all e >'0, there exists countably many disjoint Bu<: Bv and v0 = vo(e) such that v v0 i) B :3 U B” u=v+l ii) diamcs”) < e and v V 0 iii) m(E ,, U B”) < e. u=v+l 'ggggf. Assume m(x : Bv(x) a x) = 1. Therefore for a.a. x there exists v(x) such that diam(BV(x)(x)) < e. For each v we search for the set of Bk such that x E Bv and Bk(x) = Bk(x)(x). Then the x E U Bk is removed from further consideration. The remark above allows us to write m(B" .. U B”) = 0. IJ-ZV'H- The B” in the union are countable and disjoint. Thus L lim m(B" .. U B“) = 0 L—m p=v+l and there exists a (L = v0 such that iii) holds. Conversely suppose i), ii), and iii) hold. Choose 6 > 0. Then repeatedly apply the o O O O O assumption with B minus certain cylinders and 6/2v to obtain 0 v-l u sv(e> = (B .. u Sk(e)) .. U s k=l u where diam(Bu) < 9/2v where m(Sv(e)) < e/Zv. Let 25 (D Q 3(a) = U Sv(e). m(S(e)) S E m(Sv(e)) = e. But x 6 Bo ~ 8(a) v=1 V=1 unplies diam Bv(x) * 0. Therefore m(x : diam B"(x) —. o} 2 1 - m(S(e)) 2 1 - e for all e > O and we conclude m(x : diam s"(x)) -. 0) = 1. If (0,0,...,0) belongs to the closure of 6va(x) for each x then if F(a'(x) + F(a2(x) +...+ F(av(x))...)) exists and is continuous there, it belongs to the closure of Bv(x) and lim F(a'(x) +F(a2(x) +...+ F(a"(x))...)) = x a.e. vdw This is the direct extension of the one-dimensional f—expansion. The following lemma asserts that when Bv(x) a x a.e., the cylinders are essentially equivalent to a Vitali covering. The equivalence of course only holds when we consider properties holding almost everywhere with respect to m(-). The lemma and its proof are due to Schwieger [25]. Lemma 4.3. Suppose F E 8 is such that Bv(x) a x for a.a. x. Then, if Q is an arbitrary cube in B0, for each s > 0 there exists a countable disjoint collection of the B” such that V o m(Q a U 3") < e. u=1 Proof. Let Q have sides of length a. Form a covering of 3(0) according to i), ii), and iii) of Theorem 4.2, with 0 z e' = §—-;:I- . 2na +1 This effectively replaces B0 by countably many cylinders with diameter less than 5'. Choose all B” in this cover that intersect 26 Q. 'Tlie measure of the points in these B” that lie outside Q cannot exceed e'(2nan-1) since the diameter of the B” are all less than 6' and Q has 2n sides of area an-l. Also no more than 6' of Q can fail to be covered according to Theorem 4.2. v o p. n-l Therefore m(Q .. U B ) s e'(2na + l) = e. u=1 Finally we come to the theorem that unifies and summarizes the results of this section. Theorem 4.3. Suppose F E 3 satisfies condition C), condition q) and m[x : Bv(x) —» x] = 1. Then 6-1E = E implies mE = 0 or 1. Proof. Suppose 6-1E = E, m(E) = d > 0, and E G Id' Then by Lemma 4.3 v 1 v0 0 u Zm(EnB)+...+):m(EnB )+m(En (Q... UB) MEOQ)= u=1 2 m(Q) v v0 2m(Bl) +...+2m(B °) +m(Q... u B”) u=1 1 v0 sz(EnB)+...+zm(EnB) v Email) +...+Zm(B o)‘l'e holds for all e > 0. We apply Corollary 4.1 to obtain ESELIllll 2 d" >~0 m(Q) for all cubes in Bo. Since the [Q] form a Vitali cover of B0, we apply the Lebesgue density theorem as in Theorem 4.1 to obtain IE(-) = l a.e. Since the theorem holds for all rectangles, we conclude it true for all measurable E Such that 6-1E = E. 27 It should be again remarked that Theorem 4.3 contains Theorem 9-1. For x E Bv(x) for all v if x 6 Bo, and Bv(x) is the only cylinder of order U such that x E Bv. But if y # x and y E Bv(x) for all u then diam B"(x) .t o, and {13"} would not be Vitali. It is quite natural to ask whether all F E 5 satisfying condition C), condition q), and 6 ergodic have the property that m{x : Bv(x) a x} = 1. This is not the case as the following example shows. Define l F(x,y) = (,7. y + E mod 1) where g is irrational and F : (l,m) x (0,1) a (0,1)2. Now lJF(x,Y)I = l? f 0 for all x G (1,m), and the cylinders are well X behaved rectangles. D 1, it does not seem to be easy to generalize the methods on one-dimension and obtain the same conclusion. As noted above, we will consider F to expand on n-dimensional number x if diam Bv(x) ~ 0 as x a m, and write this convergence as Bv(x) a x. Theorem 4.2 is restated here for convenience. Theorem 4.2. Suppose F E 3 and condition q) holds. Then v mfx : B (x) a x] = 1 if and only if for all Bv and all e > 0, there exists countably many disjoint Bpl CIBv and v = v (e) such that v o o O i) B”: U B” u=v+l 30 31 ii) diam (31") < e and v 0 iii) mas"- U 3“)”. u-firtl We now use this theorem to deduce sufficient conditions on Bv(x) a x a.e. The hypothesis clearly contains a version of con- dition q). Theorem 5.1. Let F E 3. Also suppose there exists L 2 l, I G (0,1), q' > 0 such that for each Bv there exists Bv+i ; Bv, a cylinder of order v +-L, satisfying a) dismay-FL) s x diam (BV) and ev+1 b) 0 0. Repeatedly applying our hypothesis, Av+kL there exists B such that ' k diam fivflq’ s 1k diam Bv S I. < e and a + k m(fi"+k’“1 913% = M o < q" = (q') S mév+(k-1)L) mas") him") 9 where k = min {r : )r < c]. This implies (taking the union over all V + k6 cylinders with diameter less than c) m(BV ~ U BV'l'kL) S m BV - m(fiV'l'kL) S (1 _ qll)m(BV). Ail 32 Proceeding as in Lemma 4.2, we obtain P " .. U 3“”) s <1 - q">"m. u=1 m(B We let vo(e) = min {p 2 (1 ' Q")p < c}. This theorem is applied to X = _1. .1 F(X1,...,xn) (x , M2 x ,ooo,Mn x n n n with M1 2 1, Mi > O, i = 2,...,n in Section XII below. The application is rather involved and needs the Special properties of the F deve10ped in Section X. As a simple illustration of Theorem 5.1, we consider = i .1 F(X,Y) (2 9 2). 2 F 3 (0’2) X (032) " (0:1) 9 D(X,Y) = (2X:ZY) Suppose we have a cylinder Bv(k1,...,kY) (which is a square). Then + .. + Bv 1(k1,k2,...,kv,(1,l)) = BV 1 is the Square in the upper right hand corner of Bv. . + (3" 1) firm") and diam 6" = % dianas") _ l _ . _ 1 . _ Thus ) - 2. and q - q - 4' (With L - 1). Since convergence seems to be difficult to deduce, we consider cases when B"(x) —. B(x)=n B"(x) satisfies m(B(x)) = o. This is v21 33 cleathy Inuch weaker than Bv(x) A x but is somewhat easier to show. The F considered in Section IV above, F(x,y) = fig , y + 5 mod 1), has cylinders which are rectangles of height 1 which converge to vertical lines having measure 0. Observations on this version of convergence are contained in the next proposition. Progosition 5.1. Let F E 3. Then a) sup [ squ [J (t)!} a 0 as v a m implies m( 0 Bv(x)) = 0 EV tE6vB v v=1 for all x. b) If condition C is also satisfied, as sup [ inf ‘Jv(t)l} » 0 as v ~ w implies m( n Bv(x)) = 0 v B tE6va v=l for all x. c) Suppose for a.a.' x, Bv(x) is regular. Then sup [ sup ‘Jv(t)|} a 0 as v a m implies m{x : diam Bv(x) a 0] = l. v v v B 6 B Proof. a) m(B"(x))= [I |Jv ax- a > 0 such that X v Thus there exists a sequence of cubes Jx such that m Bv(x) 2 “x m(J:). Let J: have sides of length a x' Then V) V m 2 a o B (X) ax V ,X By the hypothesis lim m Bv(x) = v-coo n Therefore a 2.0 so that a .4 0. But v,x v,x , v diam B (x) s g av,x where g is fixed and positive. This completes the proof. One basic technique for satisfying conditions in Proposition 5.1 is to utilize the chain rule for Jacobians. of this rule we obtain v (5.2) .Jf (t) = n .( 11 o f kj(t)). v i=—1Jk1j=i+l v where f = U f .. Our method is to work on V i=1 k1 By repeated application F which satisfy t 3 all. 3‘-.. ' 35 lJf in” s 1, t e (0.1); k and such that in any sequence of r consecutive terms of the product in (5.2) we find at least one which is in magnitude less than or equal to I (l 6 (0,1)). The most trivial situation is when ‘J i(t)| s l < 1 for all t 6 (0,1): and for coordinates ki. Then k v v v v m(B ) s sulev(t)] = supl n J i( 11 o f j(t))| s 1 i=1k j=i+l k If, for example, M x x F(X ,...,X)=(_1',M Kla---3M m); M.>0 l n x 2 n n x J n n then i i _ Ml k1+tl kn-l+tn-l f i(t1,...,tn) — ( i , M2 1 ,..., M —I---—fl k k+t k+t “k +t n n n n n n and n U M Jr (9 = H)" 'El—ji—m- k1 x +kn) Now n U Mj (if (m 21L. i Mn k l n n If M > U M , then we have m( n Bv(x)) = 0 for all x. As even 1 j=2 j v21 the non-classical convergence proof of Section XII requires M1 2 1, this result is distinct although the conclusion is weaker. If n M: = H Mj’ then we must examine (5.2) more closely. i=2 Next we illustrate our method by proving the convergence theorem of Bissinger [3]. Let F be a real valued function of a real variable 36 satisfying Al) F(l) = 1 A2) F(t) 2 O, F(t) continuous and strictly decreasing for 1 s t s T and F(T) = O for t 2 T, where 2 < T S +m. (F(hn) = lim F(t)). t—o-I-oo and A3) F is everywhere differentiable and lF'(t)‘ s l for t 2 1, and there is l 6 (0,1) such that IF'(t)| s i if 1 + F(2) s t. (Bissingerls condition has to do with slope instead of derivatives, but as we are to deal with Jacobians, derivatives suit our purposes.) We now prove Bv(x) # x for all x E (0,1)F. As above V V mag") = f n f'i( n o f j(t))dt. 6VBV i=1 R j=1+l k i i V i If k 22, then k + n ofj(t)2k 2l+12l+F(2). j=i+l k V i V Thus |£'i( n o f j(t))| = |F'(k + n o f .(t))| s 1. k j=i+l k j=i+l kJ Similarly if ki+1 2 2, . I If' (n of (t)) Si. 1+ k 1j=i+2 kj Thus suppose k1 = k1+1 = 1. Then V l+F(l+ n ofj(t))21+F(l+l) =1+F(2), j=i+2 k (cm s i. v and again ‘f'i( U o f j k j=i+l k 37 Thus r21 21 -2 2 rum") 3 m(6VBV) 1 s 1 . Since m(Bv) = diam(BV) we have Shown the convergence of the algorithm. Bissinger's technique is essentially the same. The regularity of cylinders allows us to see the relevancy of part c) of Proposition 5.1. Next we perform analogous calculations on M x x _. _l .;L n-l F(xl’ooo,xn) - 9 M2 X ,’° 3 Mn x ) n n n where Mj > O for j = l,...,n. - M1"_,2 M_1_ _y_3 E13,, :1 D(y1:°°':yn) (M: 3'”: M 9 )- y1 ”3 Y1 n y1 y1 Thus k; 2 M1 for all i. We consider an arbitrary sequence of n + 1 consecutive coordinates k1, ki+1,..., ki+n. If any k: 2 M + l, we have l n n in 1Mi U M3 ”13 (t)|= jn+1S -1 n+1 ° 3 (t n+k n) (M +1) k 1 Next suppose kg = M1 for J = i, i+l,..., i+n. Then i J ( M1 M tl+kl M tn-l n-l) ,..., = ’ + ’°°°’ + fkj(xl xn) M1+tn 2 M1 tn n M1 tn iii . . Suppose kn- 1 2 1, j = 1,2,...,n. The n-th coordinate of f i+j(t) j k t 1+kn- 1 is M. -E:--- and thus satisfies n t +'M n l kj M M n-1 n-1 2 n n t +M1 M1+1 ' This implies 38 J (f (t))ls . ‘ f ki--+j -1 ki+j M n+1 For our induction hypothesis, we suppose wt... ll :2 u. I - l,...,l'H‘l k31_1=0 , j=i+1,...,i+n _ i+L,ooo,i-H1 i+l Now consider the assumption that kn::_1 = k 2 1. We must evaluate the .. l 'r I! I 'A i 1 .M l 1 '1 : E .. x . ’I‘. ‘- g . I n-th coordinate of f . o...o f 1+1 (t): k kid-1+1, f . (t) k1+1-hf, (...M $22.1 M i=1...,MEn;1_) ’ n-L M1 + tn ’ n-ul M1+tn ’ ’ an-Pcn f o f . (t) = ki+L k1+£+1 ( k+tn-L-1. tn-L ”" 4, nL+1M (M-I-t )+Mt ’- MMn-L+l n—L+2 2 ’ n-l M1+M1tn +Mn c “_1 MnMn-ltn-Z O O O , 2 ) M1+Mltn “Win t “_1 L U o f .+ (t) = j=0 k1 l+j ( (k + tn-L-1)Mn-LMn-.Q+1”.Mn ) ML+1'HV{’t +ML‘1M t +...+M M ...M l 1 n 1 n t n-l 1n n-L-i-Z t:n-Jf,-l-1+M n Mn-L-l-l n-L ' =0 k=1t= =...= = ' Setting tn_‘{’_1 , , n tn-l tn-l l, we obtain a lower bound for the n-th coordinate 39 n n H M W M gal-L j = j=n-L j L+1 - 9 (M ) ’ +0.. 0.. .0. M1 Mimi 1Mn +Man Mn—L+2+Mn Mn-L+l L 1 +1 L L-1 = I O I C I C + I I C where 91,011) Mi + M1 + 1 Mn + + Man Mn-L+2 Mn Mn-L+1’ L 2 1. The same result holds for fki+jo...o fki+J+L(t)’ 1 s j s n-L, and :1 LI (L f (cm s 1'21 M i+j-1 H ° 1+j+v n ' f v=0 k V M r2“ , r n+1 + ___lu__ (“1 amp ) Thus we may now consider the hypothesis (5.3) with L = L + 1. This brings us to L = n - 1 and the end of our calculations. If n n H M U M i=1 i r=l r l = max { +1 ; , L = l,...,n-l} < l, (M +1)n “ 1 , rEn_ Mr n+1 (M + 1 9.1041) then 1—"—J +1 m(BV(x>) s 1 “ and our result holds. We note that when M = M =...= M = 1, 1 2 n VI. ROHLIN'S FORMULA In this section we obtain rates and bounds on rates for the u-measure and the m-measure of Bv(x) for large v. Our formula will be similar to that which Rohlin [20] used to compute the entropy of one-dimensional f-expansions. Kinney and Pitcher [12] have used Rohlin's formula for rates on one-dimensional f-expansions when the formula did not represent entropy. The calculations of this section follow Rohlin [20] as Schwieger [27] did in his computation of entrOpy for the Jacobi Algorithm. Jv(t) will denote Jf (t), fv = 1510 fki. The next theorem corresponds to Theorem 3.1 2nd only gives an upper bound on the rate for u(Bv(x)). Theorem 6.1. Suppose that F e 8 satisfies condition C) and con- dition L). Assume log ‘JD(-)| is Lebesgue integrable on (0,1)n and that 6 is ergodic (indecomposable) with respect to m. Then, if we take u to be the measure of Theorem 3.1, lim‘ 1 log 1 = + log J (t) du(t) v—m V m(B"(x)) I ‘ D ‘ for a.a. x. Also 23-1- log ——1——— 2 +j‘ log |JD(t)|du(t). v WV MB ()0) Proof. By Theorem 3.1, u(E) s %-m(E). Then v filog—i——-%log—:——=%logL@-Jlsllogg. mas (x)) MB (x)) mas > " 40 or.'l=_.”'a§fi.9 '.:n'J-'.L'-.!.‘.I'IIL\ L a; wv-H . h ‘4 r it, _ . Thus, if lim 1 log v—m lim 1 log v—m Condition L) and l 1 ‘-'log v m Bv(x) We next obtain a to lim 1 log V mas"(x)) 41 v exists, m(B x) l 1 s lim 1 log-—-1;-—- M13 (X)) m(B"(x)) v7; " condition C) imply 1 ‘JV(5vx)| limit for ‘1 log which will then be equal v 1 For x E Bv, fv 0 6v(x) = x so that Jf 06V(X) = 19 V and by the chain rule f 06 Therefore Jf V Noting J - JD 6 (X) V v-l n J6(6i(x)). Jf (5"(x)) V = Jf (5"(x)) v i=0 1 V'1 i v = W J6(6 (x)). (6 (x)) i=0 we have 42 v-l llog 1 :1 V " \Jf (6" 1 such that P(Tn(A) (A)) = 1 (A E d) and for all measurable sets X,C A with measurable image ‘ .Tn (A) (X) nOA) (A)) s Mm Pa PQ)’ then T is an exact endomorphism. Theorem 7.1. Let F E 8 satisfy condition C), condition L), con-7 dition q), and m(x : Bv(x) 4 x) = 1. Then 6 is an exact endo- morphism for ((0,1)“, 6“, u), where p is as defined in Theorem 2. 3522:. If we consider ((0,1)“, 8“, m) and the basis Bv,b = {x 6 (0,1)n : [ZVx] = b} (b is an n-dimensional vector of zeros and ones) we observe that we have a Lebesgue space with con- tinuous measure. Since u N m, the same statement holds for ((0,1)n, 6n, p). 6 is, of course, an endomorphism. We take ¢7 to be the collection of all proper F-cylinders of all orders. To index the set a' we define Bv(x), x 6 (0,1);, to be the v-th proger cylinder containing x. We apply Lemma4.2(letting e -' O) to obtain Bv(x) exists for a.a. x. Thus, since BV(x) ..x a.e. 45 n and Bv(x) 3 B (x), we have Bv(x) -» x a.e. Consider x E X [ai’bi)° v . i=1 For a.a. x there exists Bv(x) such that diam B (x) < min {x - a1, b, - x}. Therefore the union of these i=1,ooo,n n 1 cylinders is equal X [ai’bi) modulo 0. Now, the o-algebra gen- i=1 erated by d is contained in 8n and we have just shown 4 can, modulo 0, make up a generating ring for 1am. Thus the o-algebras coincide and d is thus dense in 3. If Bv(x) = BV(X) (x) 6 a, then 5"(")CB\,(x)) = 5"(")B"(")(x) = (0,1);l 8° that 11(6"(X)Bv) = 1’ and we have only to establish v 11(6 X) sMLLQVL n(B ) for prOper cylinders Bv and measurable X<: Bv such that 6v(X) is measurable. (13") = J (1;) dm(t) s sup J (-) m 611; 1 v 1 1 V 1 and m(X) = idx = I ‘Jv(t)‘dt 2 inf ‘Jv‘ m(69x). 6Vx Therefore m(X) C mix) m m(avcx» s . s s c .. inf |JV(-)‘ sulev(-)‘ m(BV) Also, from Theorem 3.2 9. 9. C m(E) s ”(E) s L m(E). Thus R1 We 3 Lp.(5"X) 5m(5"x) s C2Q%_S€__fl§3_ C m(n) (11103) or (6VX)5i v p‘ qL 11(3) C4 The theorem is proved by setting M = ;_E > 1. According to the classical definition, an endomorphim is mixing if for any two measurable sets A and B lim u(T-vA n B) = n(A)1L(B)o qu This definition has been generalized as follows: Consider vectors Ar = (k0,k1,...,kr) of non-negative integers. We define M(Ar) = inf |k ’k,lc 0si|» 5 B 6 B and l 1 1 (7.1) m(B) log (sup ‘J1(-)l) s m(B) log m(B) s m(B) log L inf ‘J1(.)‘ . 6B 6 B AS in Section VII, __1.__ J (6(X)) ° f1 Taking supremum and infimum over B, JD(X) = J6(x) = 11" “- 7...-—'-..._,_——.-.—-1. ”uJ-l a 1:1: 3" n 1 1 sup ‘Jl(')‘ S ‘JD(X)‘ S inf ‘J1(‘)1 , x E B. 6 B 6 B Thus 1 1 (7.2) m(B) log sup ‘J1(-)[ Sflog ‘JD(x)|dx s m(B) log inf 131('y1 . 6 B 6 B Summing (7.1) and (7.2) over B, l l 1 Z m(B) 10g . s 2 m B 10g -—-S E m(B) log - log L [J1( )l mB inf'J1(°)l sup 6 B 6 B and l l 2 m(B)log sup [J1(-)‘ s I nlog ‘JD(x)‘dx s z m(B) log inf 1J1(')T . 6 B (0,1)F 6 B But 0 s m(B) log inf1}1(')[ - m(B) log sup 1:1(')1 s m(B) log C so 6 B 6 B that the Sums bounding H(§) and I log ‘JD(x)\dx converge and n diverge together. Therefore H(§) < +-m if and only if I log ‘JD(X)|dx < +00. 50 c.0t0118ry 7.1. Suppose F E 3 satisfies condition C), condition L), and condition q). Then 1 l HG)=-zmm)hgmm)<+w if and only if log lJD(')| e L1(m, (0,1)“). fin.xw;ikfafi.fif—n n 3‘ VIII. EXAMPLES In this section we develop applications of our general theory to two main examples. Besides the independence example developed first, we present the Jacobi algorithm. In his paper on one-dimensional f—expansions, Renyi [18] considers the following examples: q-adic, continued fraction, Bolyai, and B-expansions. Thus we cannot expect many concrete examples in our situation. AS has been stated earlier, the motivating example for our work is the Jacobi continued fraction algorithm. But the most natural and easily handled algorithm is F(X1:'° ° axn) = (f1(x1) ,f2(X2) a°°°afn(xn)) 3 n (A1: B1) " (0:1) . vs 11>¢n 1 1 where f1 is either in the class of increasing f's or decreasing f's. That is, f satisfies condition A) or condition B) of the i introductory section. _ -l -1 Now D(y1,...,yn) - (f1 (yl),...,fn (yn)) and 6(t1,...,tn) = (51(t1),...,sn 0 for all i without loss of generality. It is clear that 6123 {k : B(k) is proper}. Next we obtain a Kuzmin relation for p(-). Suppose E<: Ai' ME) = LNG-IE) and 6-1(E) = {x : 6(x) G E} = U {fk(t) : t E E} = U fk(E)' kEai kEKi Due to the 1-1 nature of F the unions above are disjoint. Thus ”(E) g p(x)dx = I p(x)dx = Z I p(x)dx = 6-1E RG61 ka 2. p>1J (x)1dx. keai‘g 1‘ fk This implies p(°) satisfies 3 D I! ., (9.1) p(X) = z: p(fk(x))‘Jf (X)! a X 6 Ai. kesi k The relation (9.1) suggests that we formulate a Kuzmin theorem where the recursion is done in separate components. The following lemma points out that such an approach is feasible: Lemma 9.1. Let Yo(x) be given and Yv(x) be defined by 156.) = z: ‘i’v_1(fk(x))‘Jfk(x)|, x 6 A1, 1 = 1,2,... REGi Then ()01 YV(X) = z Yo(fv(X))‘va(X)\. x 6 Ai. v where f = n o f i and the last summation is over all admissible i=1 R cylinders (k1,...,ky) where ky E 61- Proof. The proof is by induction. Assume _ (v) 11v(x)- z Yo(fv(x))‘va(x)‘ , x 6 A1, 1 = 1,2,..., where the sum is over all admissible (k1,...,ky) with kV E 6i. For v = l the induction hypothesis holds by definition. Now, for XEA.: l 1v+1|: i where the second summation is taken over all admissible (k1,...,kv) with kv E 6 and fk(x) E Aj. 3 Since fk(x) E Aj and (V)j that 6va:3 Aj’ then (k1,...,kY,k) with (k1,...,kv) C (v)j runs are all admissible sequences Such 57 0‘79]? all admissible sequences ending in k. This allows us to write (Using the chain rule) (v+l)i 11mm = z 1110(1.=v+1k‘ (v)i‘anv(x)‘ s N D 2 z -——————— +-M. z -—-—-—- s 3 xj 1 l k=1 5 xj 8 xj s n N D1D3 +~M D2 = D4. We now establish another Lemma to be used in the remainder of the proof: Lemma 9.2. If constants t, T exist such that t p(x) < V") < T p(x). x 6 3°. then 0 t p(x) < Yv+1(x) < T p(x), x E B . Proof. The hypothesis implies t p(fk(x)) < Yv(fk(x)) < T p(fk(x)); k c 81, x 6 Ai Then (V)i (V). (v)i 1 c z p(fkcx))1Jfk(x)| < )3 11v - p(y')| s an (N + g A)Hy - y'H an (N + g A)O(v) where y and y' belong to BV, and H°H is Euclidean distance. Combining the above results (v). 1 “’69) 2 fifv wo(x)dx +% z (epo(fv(x)) - wooymm") > CI (v)i >3? (po(x)dx - %/n (N + g A)c(v) - z m(B") > c‘.’ l 1 -/n >EI cpo(x)dx - E— (N + g A)O'(V) . a: Now define 1 Li = E'I mo(x)dx > 0. C? l 61 We now write > - Q + = - . m(x) Li C (N g A)a(v) Li claw) In the same manner we obtain 9. 2% z go>masv), (v). I cody=zlg-(1:vj‘ go(x)dx - — “(N +c A)0‘(v) o. 1 or,defining 1 1 - d >0, L. =Cft; t;o(X)x a: §v(x) >uL: - C2 C(v). It now follows that L1 0100:) YV(X) > 8 p(x) +Li - C100,) = p(X)(g +m - p(x) C c C(v) L 1 2 p(x)(g +35% - ———q ). and 62 l 1 Li C26(v) - -|- = _.:—.——.+__.___ Yv(x)3 mas > 2 v v Ci Ci 2 G—EE E'm(Bv) >- 'G—;E(q). where the last summation (2') is over prOper cylinders of order v and the last inequality is due to condition q). The importance of this result is to establish lower bound on Li +'L: which is uniform in i and v. It is this bound which allows us to iterate below and obtain the geometric bound. Now L G -gls(c-g)<1-93->+c 6(v). 1 C 3 Now 0 < q s 1, O < L s 1, and without loss of generality C > 1. Thus 0 < a = l - Q§Lu< 1, and C 61 - g1 s (G - 2M + c3 o(v). 63 We now summarize the result just obtained. From the conditions that g p(X) < YO(X) < G p(X). ‘a—XQ‘ < N: j = 19°°°9na J we have shown that for sufficiently large v as g1p < wvcx) < clam ‘9. A g. u E a. 1.. Q. 0 where g < g13< G13< G; G1 - g1 S (G - g)& +303 0(V)- By noting that we have earlier shown a? 8;:1 < D4 , j = 1,...,n, we can repeat the argument to obtain (for a fixed v 2 v0) gzp(x) < Y2v (x) < G2p(x) < C , and where g1 < g2 < G2 1 (:2 - 82 s (G1 - gl)q + C4 0(v) where C4 is a function of D4. The argument for g2 and G2 can be iterated to obtain grp(X) < Yrvm < Grp (X) where Gr - gr s (Gr-1 - gr_1)q +-C4 o(v) s...s A ‘1 A“ s qr(G - g) +C4 C(V)(ar + qr 2 +...+-1) s Ar 04 S <1 (G - g) +fi0(v)- 64 Therefore G - g s C e-xr + C o(v) 5 6 C4 where -x = log a, C5 = G - g, C6 = l:€" and ii: Gr = :2: gr = a follows. If we set r = v, Iv (x) -apl= n 1 2, J 1-1 -1 . . n and D = F 18 defined on (0,1) by M 13 23 3 “ M2 3'13 M3 y1 3 3 Mn 3'1 y1 Theorem 10.1. Let P = {x E (0,1)n : 5:(x) = O for some k 2 1}. P is equal to a countable number of hyperplanes intersected with (0,1)“. Proof. From M M M = fl :2 .11; _1 _1_ 6(x1,x2,ooo,xn) x -[M x],ooo,x -£X ]) 2 1 2 1 l l we obtain k-l M 5 5k = 0 iff ‘-l ._Z__ = m for some integer m. l M k-l . 2 61 and k-l k-l M162 -mM2 61 -0. Now suppose (letting 5: = l for all v) n z: b, 5‘33” = 0. i=0 1 1 Then n-l M 5" M '+ +1 1 + 330+ 331(M1 :1 33333 )+bn(v 33335—0 i=1 1+1 5 5 1 1 or n 2 b! 6 = 0 . 1 68 where b'= b M1 n I = _ \1+1 b1 b0 .E bi ai 1-1 M1 b' =—-—'b, for i=1,...,n-1. i+l M1+1 1 which can be obtained by allowing m to range over the non-negative integers and ak over k-tuples of positive integers. Therefore 6:(x) = 0 is equivalent to x being on one of a countable set of hyperplanes (intersected with (0,1)n). Since k runs over a countable set we have proven the theorem. Corollary 10.1. m(P) = 0. We will thus use our algorithm to expand x 6 (0,1): = (0,1)n n F. The usual one-dimensional continued fraction expansion of x E (0,1) can be set into matrix form: 3 + n OH 1(x) = H ,0 l k=1 1 ak(x) , 0'(X) = I- =_]: =1--. where of course a1(x) [x], 61(X) x, [I], _ _13_3_ = 1__._ 1__. ak+1(X) - [6k(x)]’ 6k+1(x) 6k(x) [6k(x)], 0n+1(x) = Pn_1(x) pn(X) qn_1(X) qn(X) where 69 P_1(X) = 1, P0(X) = 0. pn(X) = an(X)pn_1(X) + pn_2(X), n 2 1, q_1(x) = 0. qo(X) = 1. qn(X) = an(X)qn_1(X) + qn_2(><). n 2 1- P (X) The convergence theorem says that lim an?;7 = x. Another useful n—oco property is n+1 _ n det G (x) = pn_1(X)qn(X) - qn_1(X)pn(X) - (-1) , n 2 0. These coefficient matrices have analogies for the present trans- formation. The connection between the matrices defined below and F is given in Corollary 10.3 below. 1 0 O 0 0 O F n 1 0 0 . 0 O 0 A0 = M2 , O -— 0 0 0 O F 1 Mn 0 0 0 0 0 n-l 0 0 0 M1 k l 0 0 Fla1 1 A = k 0 l . 0 F232 ’ o o . 1 Fak n n and 0 0 . 0 1 k l 0 0 Fla1 k A = , k 2 2, 7O Whet'e n (n M )j/n+1 ._ 1 Fj = 131 , j = 1,2,...,n. n M. i=1 1 Next we define k-l k a (x) = U A"(x> = v: k - (wij) ’ 1=0,...,n . 0,...,n Luis ll k+1 The relation det 0 (x) = (-l)k, k 2 0, of the one-dimensional continued fraction has an analog in our case. n , ‘ k nk H Mi Proposition 10.1. det O (x) = {-1) i=1 , k 2 2 n n F i=1 1 n Proof. fl M1 det A0 = (_1)n 1:2 , n F i=1 1 det A1 = (-1)n M , det A33 = {-1)“, k > 1. Therefore n H M k = i det G = U det A3 - (-l)nk inl , k 2 2 i=1 n F. i=1 1 The following lemma allows us to recover x and corresponds to a result of Perron [l7]. 71 'Leunna 10.1. If x 6 (0,1);, then \— n k :+1 + Z w: . F Xi— ,n i=1 a] J J 9 k+1 “ k k m + 2 w 6 F 0.n 1=1 0.1 1 1 k k where k = 1,2,..., 1 = 1,2,...,n, and wij E O (x). Proof. Let k = 1. Then the assertion is n + l 6' F “’m 131 “’31 j J x = . i 2 n ' ' + w 6 F “’0,“ 3321 0,1 J 1 Now let i = 1. Then n w2 2 w 6' F + l, j=1 lj j j M1 0 = M1, = x n I 1_. I M X 1 wZ + E w' , a + F 6 Fn l l 0,“ _ OJ J j n j-l For i 2 2 n M (.0 + E (D3 53 F I .i I i n j=1 j j J a1-1 Mi + Fi_1 61-1F1-1 n = I I M/x 3330,n+ E (00:16ij 1 l j-l M x l i M. -— -) = i 1 M1 = x Ml/x1 1 Thus the lemma is established for k = l with {F1}:=1 arbitrary. They will be determined in the calculation for the induction step. Suppose the formula holds for k - 1. We reduce the formula for k to that for k - l, establishing the induction step. Now by the form of AR, k 2 2, and Qk+1 = Qk Ak we have 1'1 3.3331 =u> + E a33 3.3. and k _ k-l _ “31,1 1,j-H. , j 0, ..,n 1. Thus k+l “ k w E w. 6 F = i,n 3:1 1,1 j j k n k = + F a + “’1.0 jilu’m 1(1 51) k-l i,0 1:1 1,j j j+1 61- 1,n n 61— k-1 =FnM1{wk +2101 F3 k-l+wk L, 6E-1 1,n j=1 1,j FnMj+l j+l i,0 Fan k-l = Fan {wk + “£1 wk-l Fj k-l +_wk-1 E;__ } 5E-1 1,n j=1 i,j+l FnMj+1 3+1 1,1 Fan We would like the quantity in brackets equal to n z w?31 F. 5k'1. j=1 1,j J j i,n This yields the following system of equations 1 F = 1 Fan F -1 Fj = fii§« , j = 2,...,n j n or 1 F — 1 Fan 1 F = 2 2 M1M2Fn F = 1 n 73 Tfilus With these Fj’ then, :1 k+l k k '01 k n k- k-1 = + “’i.n E “’1.1 51 F1 k-l ”i,n 2. “’m 131 33 3 j-1 1 j-1 In a like fashion n k+l k k n 1 k -1 k-l w + )3 u) .6 F = _ {w + 2 (n F 6 } 0,11 j=1 0).] j J 03:1 0,11 j=1 09.3] .3] j and by appropriate division the induction step is complete. Corollary 10.2. n wk+1 + Z wk+j-n 6k F 1,n =1 i,n j j X = j i n w:+: + Z wg3a-n E F. 9 j=1 : J k = k-1 = = k+J-n Proof. wi,j wi,j+l ... mi,“ . 1 2 k _ Corollary 10.3. F(a (x) + F(a (x) +...+ F(a (x)...)) — k+1 k+1 = (wln (x) wnn (x)) k+l )""’ k+l( ) ' (”0n (x (”cm x 1 Proof. Note that x = F(a (x) + F(a2(x) +...+ F(ak(x) + 6k(x))...)). Now the equation in Lemma 10.1 holds not only for x 6 (0,1); but for any x such that a1(x),...,ak(x) is defined. If we set y = F(al(x) + F(a2(x) +...+ F(ak(x))...)); aj(y) = aj(x) for 74 1 s; j s k and 6j(y) = 0. Applying the identity in Lemma 10.1 we obtain our result. Thus the approximates of x are obtained from Ok(x). Next we prove a theorem analogous to the convergence theorem of continued fractions. The proof is similar to the one which Perron [17] supplied for Jacobi's Algorithm but has minor changes. Theorem 10.2. If x 6 (0,1); then k mi n(x) lim -—*—-—- = x,, i = 1,2,...,n. k 1 ka m (X) 0,n Proof. By Corollary 10.2, we have n k+1 k+j-n k mi,“ + E wi,n éj Fj n+1 k wk+j-n -l i X- = 1 = E I Ting—a 1 (”k+1 + 2 wk+j—n 6k}? j=1 3%: 0,n H cm 1 J ’ wk+1 where xk+1 0,n , “ k+1 “ k+j-n k w + w 6 F 0 n j'l 0,n j j and k+L-n k k w 6 F A = 03“ l 3 9 L = 1:23' -In k+1 + Z wk+j-n k 0,n j=1 0,n J j k n+1 k If we note that 3j 2 0 and 2 3j = l for all k and assume i=1 that k w lim —%‘E k4” u30,n exists (and equals 81’ say), then we conclude xi = $1. k w. TVuas we need only show lim -i*fl exists for i = l,...,n. kam m 0,n Define k .1; n 032‘“: Bi = min{;E*- ,..., _Eifi } 0,n “’o,n and k k+n mi n i n Bl = max{F_ , , “Fa-*3} 0,n 0,n We have “ k+j k+n k+n+l w. + 2 w. F a k+j w. 1,n _ 1,n j j n w, 1,n j-l = Z 1 1,n u)k'l'u'rl k n k+j k+n n=0 J wk-l-j 0,n w + z m F a. 0,n 0,“ _ 0:“ j J j—l where k+n k+j k a F mo n = 1 m _ 1 lj k+n+l (F0 , 8° - 1 for al m). 0,n Thus wkfln+l n i n k k _a__ = k+n+l 2 E 33- Bi 5 w n=0 0,n and therefore k+1 wk+n+l k+1 i n i n k Bi — minf-E$T ,..., giifili ] 2 Bi . w0,n 0,n Similarly, BE+1 S BE, and k + + OSB.SBFISB331sBl.3. 1 1 1 1 Define a = lim 8% and B, = lim BF. Then 1 Raw 1 1 1 k—m 76 OSBESBiSBiSBI' k w. Choose e > 0 such that k > k' implies in > Bi - e- w Then 0n k+n+l k+j k+n win 33 k 3331,n “'1 k k (”in —____. = - + —_—— _ k+n+l 520 "j k+j > f 3‘j (Bi 3) 33n (”k+n wOn w0,n on k+n _ k k i n —(1‘)\n)(Bi'€)+)\n k-l-n’ w 0,n or k+n+1 k+n m -iE—- - a > 1k 31*3 - e ) - k+n+1 1 n ( k+n i e ' on u30,n We now show _1 I n-j ’ n (Fan) 5’37:- 133% V\ u: L- a: k+n “ k~1+j k-l+n k+n-1 k-1+n w = w F, a 2 w a n,n j=0 n,n J j n,n n n - + _ 2 wk+n 1 F M 2...2 wk 3 (F M )n 3. n,n n 1 n,n n l M y M M Also, since -l -i s -l y, s -l , we have Y y J y j 1 l 1. 1 1’; 1' aj s an and L s n Therefore k k+n k+j 11 = w 5 _1 1 k - 1 1313+" F (1)3333" Fn (F M )In j n n n nn n 1 1 1=kk+...+)\ks)\k{max (F) --1— -{1+F—M-+.. .+——}= o n n . Fn Fn M1 (F M )n J n 1 k =‘x B. n o k 1 Thus xnzB >0, so that o wk+n+1 k+n 1_ in - - k—w-m+l 81>]; (k+n Bi) ’3 u’On o wOn By induction we obtain k+n+v k+n w_i.2n__ >1_(win _ )_ (1+1—4. +1—) k+n-h) Bi v k+n 91 e B (B )v-1° w0,n o wOn o o E“ 0f any consecutive sequence of n+1 terms 6&3 , we have at 0n least one less than or equal to Hi and at least one greater than or equal to Bi. Thus we can choose k C> k') such that kin win k+n 2 Bi u)On and then choose v E [1,2,...,n} such that “"15?” k+n-h) S Bi ' 0n 0.) Thus we obtain o 1 _ - 1_ L. > (B )V (Bi Bi) 3(1 + Bo +...+ BV-l), O 0 and, by noting Bi 2 Bi’ we have (letting a a O) B. = 6,. XI. ERGODIC AND INFORMATION THEORY OF THE MODIFIED JACOBI AIGORITHM The main task here is to show that the conditions of our above work are met. When this is accomplished direct application of the theorems yield our results. Our most difficult job will be in evaluating Jf (t) where v v v 1 v fv(t) = 1'1 0 f i(t). Set B = B (k ,...,k"). Then Lemma 10.1 i=1 k states v+l v v V min + E wiL XL FL wio Z wit 0L (f (x)) = L21 = L21 V i wv+1 + Z wv X F wv + Z wv fl 0n L21 0& L L 00 L21 1L L whe e = x + kv F . Define = F = l. B differentiatin r aL ( L L) L do 0 y 8 \J V B(fv)1 _ . wii - yi mo. axj ’Fj 2: v ‘ (D 0’ L20 0L L Thus we wish to compute v _ v v _ det(wij - (fv)i woj) —————-————-— det{w. LEO mOL aL This determinant can be evaluated in identically the same fashion that Schweiger [23] makes a similar evaluation. As the computation is quite long, we simply state the result. 78 — 1; I. f f 79 v V v v v n—l n v d. - + , = -1 d t . et(wij2w0£al{’ wOijLLo/L} QwOLaL) () e O n W M. v _ nk i=1 1 . We apply det Q - (-l) —;———— to obtain H F i=1 1 n (-1)Ink n M. . 1 i=1 L20 0L L 1 l 1 Finally we obtain n H M n . 1 _ 1 i=1 _ ‘Jv(x)‘ - .n F1 v n+1 n _ i=1 ( Z 0L QL) H F L20 i=1 1 n U M. = i=1 1 v+1 “ v n+1 + F (“’On 1,21 “’01, x4, I.) The remarks that wv 2 mV kv d v v On Oj’ n 2 1, an k.n 2 kj are useful in computing bounds: v+1 n v v n v v = + + 0’01: + E ”’04. XL FL "’00 E “m(x aL)FL L—l L- implies F a. wv s wV+1 +- ; wv X F S wV +' 2 mV (1 + av)F S n n On On _ 0% L L On _ On n L L‘1 L-l V V V n v v v 2 = . S wOn an +-LEI w0n( an)FL wOn an (1 +'2 Lil EL) This implies 80 n n n Mi U Mi 1: 1 n+1 i=1 1 n+1 n n+1 aV v ) S ‘JV(X)| S F )n+l ( V v ) O (1 + 2 2 FL) n wOn ( n u)On {F1 This yields n l + +1 SUP IJ (')I 2 [:1 FL n V S = C < +00. inf |J (-)| F v n so that condition C) is verified. It is difficult to verify condition L) for arbitfiary Mi. If M2 = M3 =...= Mn = l with M1 an integer, then v . l l 6 BV‘D {x : xj S xn, xn F (0,1) and x E (0,1)F}, which occurs if and only if k" = (k,k,k,...,k), k 2 1. Thus m(s‘fis") 2 ‘11—! = L > o and condition L) is verified. Using this bound n n W Mi U M i=1 1 v i=1 1 L n n+1 (av v )n+l S m(B ) S (F )n+l (av v )n+l (1 + 2 2 FL) n wOn n n 0n L=1 and for BV-I-1 C Bv n n W Mi W M. i=1 1 v+1 i= 1 L n n+1 ' v+l v+l n+1 5 “‘03 ) S (F )n+1 ( v+l v+l n+1 ' (1 + 2 2 FL) (an u’On ) n n (”0n ) L=1 Now v n w v+l v v v v v 0n = + = ...+ wOn uJ00 Lil mob at FL u)On an (Fn + wv av) 0n n so that .31 :2; u... < . «a. ~_ -. . 9:5..smigx n F a u," swVH V a" (1+ 2 F)- n On On 0 n L=1 L Therefore n+1 L (Fn) l S mg§v+12 S n n v+l n+1 v + (1 +2 2 FL)n+1(l+ 2 FL)“ I“ ) (B) L=1 L=1 n n+1 '(1+2 2 F) s 1 45;" +1 +1 2 +1 (a: >“ L(Fn) (“ ) Thus given any cylinder Bv we choose a proper cylinder A + A Bv 1 inside Bv with aV+1 = (0,0,0,...,M). This gives condition q) with F ' n+1 q = L n n n > 0. (1+ 2: FL)(1+2 2 FIN“) [4:1 {1:1 -’ MI 1 n Now (noting ‘JD(x)‘ = n (;-) ), we make an application H M. i=2 1 of our general theory: M M.x 'M x Theorem 11.1. For F(x1,...,xn) = (;l', -§-l',..., -2;E:l) as above n n n (assume condition L) holds), we have a) There exists a probability measure u on (0,1)n such that p ~ m and 6 is a measure preserving and ergodic transformation for u. Mbreover %S§:(x> =p(x)£% for a.a. x E (0,1)n, where C, q, and L are defined above, b) 5 is an exact endomorphism, 82 awui c) Letting h(5) denote the entropy of 5, n has) = n log M1 - 2 log ML - n f log (x1)p(x)dm(x). =2 ' n L ms) Also h(5) = lim é-log'-l--— = lim fi'log--—%——- a.e. Vam m B (x) vdw u 3 (x) Proof. We need only establish m(Bv(x) a x} = l to conclude our theorem. Now suppose x s B0 such that Bv(x) 4 x. Then there exists y E Bv(x) for all v such that x # y. But ll >4 lim F(a1(x) +-F(a2(x) +;..+ F(ak(x))...)) k-a lim F(a1(y) + F(a2(y) +...+ F(ak(y))...)) k—aoo ll ‘< implies that there is a v such that av(x) # av(y). Therefore yéfsx XII. A NON-CLASSICAL CDNVERGENCE ROOF FOR THE MODIFIED JACOBI AIGORITHM It should be noted that the theorems applied in Theorem 11.1 above did not require that Bv(x) » x for all x F (0,1); but that m(BV(x) a x) = 1. It can then be asked if there is an alternate to the classical Jacobi-Perron technique of establishing this result. We establish this alternate by means of Theorem 5.1 in the section concerning convergence of F-expansions. Lemma 10.1 above is required. We write D(61-1) = (dj,...,di). Then by Lemma 10.1 n n + R (”11211 + 2 03:1 61; F “’10 + Z an:j <11; F. x = i=1 J = i=1 J = i n n k+1 k k k k k U.) + 2 u) 5, F u) + Z 0) d F n wlf-n + 2 (”1.6-1 m d1? F in 1:1 1n J j k-n n k+j-n k (”On + jEI (”On dj J Thus for all u 2 O we can write v n +- +n w, +' Z w? j dv F X, - 1 n w; +- Z w3+j dV+n F. n j=1 n j J +n Now we consider the diameter of Bv : 83 “in n (x - x ) wv-l-n _ in = )3 dv+n v+j i 1 _ 1n = 1 u)v-I-n j=0 J j 011 F d\J-I-n v+n 1 wv-l-n 0n n n On 0n + +n “ v+n v+j 2 03:3 dv F -xi )3 d, F (110 F dv-l-n v-I-n 3:0 n J j j=0 J n + x _ n n will d\H‘n v+n i F v+n v+n Fn n (”On n n Ll)On n 1 v+j v+n n—l v+j win in dj Fj E (”On dj F. = j=o _ x j o J F dv-ln v+n i F d\H-n v+n n n (”0n n n u’On v-I-n v+j v+j = _ n 1 F d (”On x _ u)in +n v+n 1 v+j dv j=0 Fn n u)On u)On v+n v+n _ v+n . v v v+1 . Now dn 2 dj , dn 2 1, kn (”0n s (”0n g1ves us v+n v+j x _ win “51 F l x _ u"in ' + + + - + 1 wv+n j=0 Fn k” jk‘J j 1...kV+“ 1 ~1 wv 3 0n n n n 0n v+j Letting F = max {F /F } and x, - m s diam B(Vfi), .=0 n-l j n 1 u)V'l‘j J ,.I., on we obtain (1):? n-1 1 v+j x - s F 2 —-——-——— diam B ‘ +n + + +1 +n-l ' 1 wv j=0 kv jky 3 ...kV 0n n n n + Since diam B” j g diam BV for j 2 o and kg 2 1. v+n v in Lung. xi v+n S “F v+n-l ' w k 0n n -2!qu -- ,...,...- Hm 85 'B\1t if x = (x1,...,xn) ranges over BV+11 we obtain from the triangle inequality +n di v diam B" s ZnF -———m B kv-l-n-l n We choose a cylinder §v+n whose k:*“'1 = (0,0,...,o, max {M1.2([2nF] + 1)}>- Thus we have (v+n-l)-st coordinate is diam év+n s 1 diam (3”), 1 c (0,1) uniformly in v where §v+n is determined only (at this point) to the coordinates k1,k2,...,kV and kv+n-1. The work above established n n+1 L F2+l 1 \ S n n v+l v+2 v+n (1+2 2 FL)“+1(1+ 2 13’1““ kn kn "'kn {1:1 L=1 mfiv-I-n S v m(B) Specifying kj = (0,0,...,0,M1) for j = v+l,...,v+n-2, v+n, we have / Fn+1 \n n+1 L n 1 F )n+l M2-1(max{M1:2([2nF]+1)}) L q: n n+1 n (1+EFL) (1+2 i=1 L=1 Thus we have established an alternative to the classical approach of Theorem 10.2. Since Lemma 10.1 was not dependent of the Mi being greater than or equal to l we need only have M 2 l and M2 > 0,...,Mn > 0 for the proof of this section to hold. Therefore the result is weaker but holds over a wider range of parameters than the classical one does. XIII. A CLASS OF F-EXPANSIONS AND SOME LIMIT THEORY Since the above sections were completed, some recent work of F. Schweiger [30] has come to our attention. His results, similar to ours, are established for a general class of F-expansions with the property that all cylinders of all orders are proper. This is a natural generalization of Renyi [18] and does not include the Jacobi algorithm. Besides showing convergence, Schweiger constructs a meaSure ergodic and invariant with respect to 6, proves a Kuzmin Theorem, generalizes a theorem of Gauss, obtains a strong mixing condition, calculates the entropy of the shift, and proves other number theoretic results. These results are established in much the same manner as our results, although the difficulties are fewer since all cylinders are proper. In this section we restate the conditions on the class of F- expansions Schweiger considers. Then we generalize Gauss' Theorem and obtain a strong mixing condition. The latter result allows us to obtain some limit theory for F-expansions. For f = E o f i’ define - k i-l H H B(f ). J = sup V lsi,jsn 5x1 Then F satisfies condition S) if 31) F e 3 $2) ”JV“ 3 m(v) 86 87 where T(') is a non-negative, decreasing function on [l,m) such that T(1) s l and lim T(X) = O. This inequality must xqm v hold uniformly for admissible k ,...,k . 83) All cylinders of all orders are prOper. Theorem 13.1 (Schweiger). If F satisfies condition S), then diam.Bv(x) » O as v a m for all x. The theorem is proved by considering the components of fv and applying the mean value theorem for functions of n variables. Then 82) yields the result. This work gives a relationship between the Jacobian and the diameter of the cylinders. It would be useful to apply Bissinger's [3] technique to give conditions that F satisfy condition S). However it is not easy to apply Theorem 13.1 to I x +'k, i 1 2 +k (Xu H) matrix (but are lost when the determinant is taken). the Jacobi algorithm due to the terms which occur in the In Schweiger's proof showing the shift ergodic, it is remarked that the Lebesgue density theorem can be applied. It cannot be applied directly as the following example.shows. Let F(X:Y) = ()3: ’ %)’ then ”Jo“ = :v+l and condition 8) is satisfied. However m(Bv) = Z-vA-v = 2-3v while the smallest cube covering the rectangle Bv has area (Z-v)2. There- fore 2-3v r(x) = lim = 0, 2-2v 88 Enid {Bv(x)} is not regular for any x. Following Schweiger's use of a technique of Billingsley([2], p. 44) ‘we can shorten Section IV. Corollary 4.1 essentially states m(E n Bv) 2 C-1m(E)m(BV) for all cylinders BV. In Section VII we show that the cylinders generate the Borel sets. Thus we have m(E n E) 2 C-1m(E)m(E) and m(E) = O or 1. The Kuzmin Theorem appears in Schweiger's paper with an error bound of the form b T(V). He then uses this result to generalize a result of Gauss that states m(6"’(E>> - ME). We have no difficulty generalizing Schweiger's Theorem to the general F-expansions considered above. Theorem 13.2. Let F E 8 satisfy condition C), condition L), con- dition q), and m{x : Bv(x) a x} = 1. Also assume that the hypothesis of Kuzmin's Theorem 9.1 is satisfied for p and fv' Then |m> - ME)! < b m(EMe'V" + we». for all Borel sets E. Proof. Define Yo(x) = 1. Then Theorem 9.1 states (13.1) m(x) - a p(x)} < b(e'V" + am») But corollary 9.1 shows a = _ Multiplying (13.1) Y (x)dx - 1. B0 0 by IE(x) and integrating, we have If IE(x)‘i’v(x)dx - u(E)| < b m(E)(e"‘/" + cm,» 0 B 89 We complete the proof by f0 IE(x)‘1’v(x)dx = 2: g YV(X)IE(x)dx = B 1 (V)i =§ z {owo)IE(x)1Jv(x>ldx = 1 Mi ._ V _ - E 2 £ A. IE(6 x)dx - \) 1 "V = I I (x)dx = m(6-vE). 3° 5 E The next application of the Kuzmin Theorem gives us a rate on the strong mixing condition. It is this result which allows us to obtain the limit theory. Theorem 13.3. Let F E 3 satisfy condition C), condition L), con- dition q), and mfx : Bv(x) a x} = 1. Also assume the hypothesis of Theorem 9.1 is satisfied for p and fu' Then ‘u(B(k1.o.-.ks) n 6-V'SE) - n(B(k1.-o-.k§))u(E)l s s 9:} (e'W + UC/n))u(B(k1,o--,ks))u(E). for all admissible k1,...,kS and Borel sets E. Proof. Let B(k1,...,ks) = B8 be a preper cylinder. I s(X) 100:) = 45-8- p(X)- uCB ) As usual Yv is defined by Define 90 (v). 1 (13.2) Yv(x) = z Yo(fv(x))|Jv(X)‘- Since Yo(x) = O for x 4 BS, we cannot apply Kuzmin's Theorem to {Yv}v20° However, since 6113 {k : B(k) is proper}, p(f (x)) 1’30.) = —:—— |Js(x)|, x 6 Bo. MB) The hypothesis of Theorem 9.1 then applies to the sequence {Yv}v28’ and -Vn (13.3) mac) - a p(x>| < b(e + 01/11)). Applying Corollary 9.1 to {Yv}v20 gives a = 1. We multiply (13.3) by IE(-) and integrate to obtain \f IE(x)‘i’v(x)dx - “(ml < b(e'V“ + quantum) s 0 B C b -1/h s (e + «fawn-(E)- Proceeding as in Corollary 9.1, I rIE(X)‘1’V(X)dx = )3 f IE(x)‘i’v(x)dx = BO 1 Ai (em)i =2; 2 j; IE>|Jv|dx = 1 (SW). 1 s+v =1; 2 I Yo(x)IE(6 (x))dx =j1ro(x)1 (x)dx = 1 fv+s(Ai) Bo 6-s-v uCBS n 6-8-VE) . S MB) 91 Thus the conclusion of our theorem holds for proper cylinders. Leanna 4.2 states that the measure of any cylinder can be approximated by the measure of countably many disjoint proper cylinders whenever condition q) holds. This completes the proof. To apply the limit theory developed by Ibragimov ([7], [8], [9]) and Reznik [19] we need the following assumption -L/ k M) 2 (e “ +a(/n)) < +... v-l For the cylinder Bv(x) and g 6 L2(O,l)n we write (x) 1 [s] = ——-j‘ E .11 V n(BV(x)) Bv(x) Hen, =11 32cm? Then we have Theorem 13.4. Suppose F E 8 satisfies condition C), condition L), condition q), condition M) and mfx : diam Bv(x) a 0} = 1. Also suppose the hypothesis of Theorem 9.1 is satisfied for p and fv. Assume g E L2(0,1)n and I g du = 0. Then if a 21113 - [glvflub < +.., it follows that usnfi + 2 2 1 gg