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University This is to certify that the thesis entitled A STUDY OF A CLASS OF FUNCTIONS HOLOMORPHIC IN THE UNIT DISK presented by Philip James Pratt has been accepted towards fulfillment of the requirements for _Ph...D..__degree in Mathematics fig: (I, % Major professor Date—W— 0-7639 Q 75);? 45L ABSTRACT A STUDY OF A CLASS OF FUNCTIONS HOLOMORPHIC IN THE UNIT DISK By Philip James Pratt The non-constant holomorphic function f is in classB * if and only if for each point of a dense subset of the unit circle f is bounded on an are which ends at the point. The classa * is investigated with respect to its closure pro- perties under certain elementary operations. An approximation technique of Bagemihl and Seidel is used to show that any holomorphic function can be written as the sum and product of two functions each having radial limit zero on a dense subset of C. This result is used to show&* is not closed under addition or multiplication. Approximation techniques involving a repeated use of Mergelyan's Approximation Theorem and modifications of a technique of Earth and Schneider are used to show the existence of a function f which is not in £2 * such that ef is in B * and a function g which is in B * such that foz g (t)dt is not in B *. It is also shown that if f is in a *, ef is in B *. If f is in E3 * and f omits the finite value a, then l/(f(z)-a) is in B *. The fact that f is in B * does not Philip James Pratt imply that f' is in a *. There are no sufficient slow or fast (infinite) growth conditions for a function to be in B,*ornotin E *. Finally, the possibility of extending theorems from nor- mal functions to functions in B * is discussed. A STUDY OF A CLASS OF FUNCTIONS HOLOMORPHIC IN THE UNIT DISK By Philip James Pratt A THESIS Submitted to Michigan State University in partial fulfillment of the requirments for the degree of DOCTOR OF PHILOSOPHY Department of Mathematics 1971 ACKNOWLEDGEMENTS I wish to express my appreciation to Professor Peter Lappan for his help and guidance throughout the preparation of this thesis and to Mr. Edwin F. Smith for drawing the figures that I used. 11 I. II. III. TABLE OF CONTENTS LIST OF FIGURES .................................. iv INTRODUCTION ..................................... 1 OPERATIONS IN CLASS E1 * ........................ 8 FURTHER PROPERTIES OF FUNCTIONS IN CLASS B * 28 Rmuwmmy”HHHHHHHHHHUHHHHHH.37 111 LIST OF FIGURES FIGUREl ............................................... Ill FIGURE2 ............................................... 16 FIGURE3 ............................................... 16 iv I. INTRODUCTION Throughout this paper we shall let D denote the unit disk, 52: lzl(1? , and let C denote the unit circle. {2: ’2’ .. 1}. By a boundary path in D is meant a simple continuous curve 2 =- z(t) (O$t we pick gain 3n a 1 so that none Of the poles of h lie on H, this will still be true. We now get fo Just as before and let 80:“ h - fO . Now gO is meromorphic rather than ll holomorphic, but it still has radial limit zero on a dense subset of 0. Thus, h=f0+go , f0 5 R , go 5 Rm and the theorem is proved for the sum. For the product, we pick $091an a 1 in the same way but we define our continuous function 3 a little dif- ferently. We still define s (z) to be zero if 2 5K. For each positive integer n, we now define s (2) on Hn to be a real-valued continuous function that tends monotonically to 00 as ‘2' tends to l and which satisfies 's(r°(n)‘ > (sup( V293? tn‘lr) for 1 - (1 / 2r1 ) £ r 4 1. We again have that s is con- tinuous on H \l'K. By the same argument as in Theorem 1, we Obtain a holomorphic function f such that (3) lim ,f(rdn)-s(roln)lz o r-n (Ll) lim1 If(rfin)-s(rfln)'=0 By the definition of 3, these become (3') 11m lh(rdn)/r(rotn)/ = o r-9l (M $15,“. If (r Ah.) I If we let f1= f and g1 =:h / f, then hi: fl . g1 , where 1‘1 e R by (3')ands,é Rm by( (u'). THEOREM 3: _I__r_ 1? EH * and if. r omits the finite 12 waflg(z)=l/(f(z) -a), theng é a *. £29.93: If g é a*; then g has 00 as a Koebe value so that there is an are I contained in C, a sequence of arcs $3.13 I: 1 in D and a sequence of positive real so numbers EMn 3 n = 1 such that 3n "" X ’fln -9 OO , and ’8 (Z)! Z [an on In , n=1, 2, But then lf(z) ‘3 l 5 1//"(non In,n=l, 2, "',and 1 /M n --) O. This says that a is a Koebe value for f so that f f a *. This contradiction proves the theorem. THEOREM ll: Iet f G a . If f omits a finite value, then f E 3*. Proof: Let c be the omitted finite value so that g (z) = 1 / (f (z) - c) is holomorphic in D. If f has an asymptotic value at a point, then so does g. (If f -b 00 , g -:b 0; if r—oc, g—soa; if r+bandb7£c, oo , g-)l / (b-C)). Thus g £- a. If f 6 B *, f has 00 as a Koebe value. A similar argument to the previous theorem shows that g has zero as a Koebe value. By [19, Theorem A, p. 18: , this shows that g fl 4 . This contradiction proves the theorem. Putting Theorems 3 and A together gives the following corollary. COROLLARY 4.1: _I_§ f e a and .11 r omits the finite value c, _t_1_u_ep e (z) —-= 1 / (r (z)-c) e E *. l3 THEOREM 5: _I_f_ f e 3* 333g (2) =ef(z), mg 6 B *. 2522:: Let u (2) be the real part of f (z) and suppose C, e B* for the function f. Then there is an are P that ends at z) and a constant M such that 'f(z) ‘ < M on [-7 Thusl8(z)l = eu(z) so that lg(z)l < eM on P Thus C: 63 B* for g and B* for f is contained in B* for g. Since B* for f is dense in C, B* for g must also be dense in Candg e B*. THEOREM 6: There exists é. function h not 3211 B * such that if g (z) =- eh(z)’ then g E- H *. Proof: We pick two subsets of C as follows: H-513, 1.3-5-13 11:3 {1, e21T1/3, euTri/33 , H: _ {8 "1/3, -1, 85 171/3]: H; T 5821411'1/93 :0 {(2191) 11' 1/928 K = O 1 2K'ITi 3”":l 3n-31 2K 1 ni/(3n- -1 3’“l unafe /< 2‘30; :21; +> ph-l O on L81: A1 = nUI Hn , 1 a: l, 2, SO that Al and A2 are countable dense disjoint subsets of C. (See Figure 1). For each non-negative integer n, let 8n =- 1 - 1/(n+1) i a“ and let 3,11 be the line segment from the point 3 en / l'l 'lTi/u to the point snfl e and let In be the line 114 Figure 1. 15 segment joining the conjugates of these points. Let r1 1 = on X: , i 2—. l, 2, and let T be the domain bounded by [1, F2’ andfily. let 1:1 > 132 > 153 > L 0 be a sequence picked so that tn < 1/2 min San - and, Sn+1 - an} and Fn-fz=x+iy:(YI stn,(sn-1+3n)/2 firtpm (|f(z)()+3on 0‘me J if j 2 N. 00 let 8 (Z) =3 2 gm (2). If K is any compact subset m =- l of D, K intersects only finitely many Fmp's, so that for all but finitely many m's we have (gm (2), < 1 / 2m + 1 for all z in K. The series thus converges uniformly on each compact subset and g is holomorphic in D. Set 1'1 (Z) x f (z) + g (z) andvna Tit U U a’np , “ pen“2 00 so that 511,, in a 1 is a sequence of closed curves tend- ing to C. cl? On (rim , '8,“ (z)' 2 If (2), + n and 2 Ign(z)/ Ila-:1, 11%!“ co 5-. <.£-:1/2n =1sothat 11:31 Go lh(2)(=’f(z)+8m(2) + Z 8n(z)l n31, n¥m M 2 lem(z)/ - 3H2)!- Z [8,, (z)/ n‘1:n#m 2 lf(z)l +n -If(z)/-l zn-3 chaff“ upnpm, lf(z)-in I <1,Imgm(z)>-l/2 sothatwehave 19 Ma h() = f z ((2)+sm(2)+n=1’n#msn(z)( .09 2 If (2) + 8111(2), i Ian (2)] n=-1,n7€m 2(n-l)-1/2 -1 2 r1"3 ,0 0n Tn, |f(2) -1nl -< l, (a (2)1 2’; £1 1/2n nae = 1, so that ,h (2)! 2 f (2) -s (2) Thus, on )1“ , [h (z)! 2 n - 3 so that h has 00 as a Koebe value and is not in 8 *. pr 6A1 andz éRp,Re (f(z))IZ(t1)I < 12(5),, lim lz(t)l— 131., and let 91 be sufficiently smooth so that if :0: is para- meterized with respect to arc length 8, then 93% is contin- d z uous and arg ~55- (O) as o, Lef, 9 (s) = arg 9.5%. (s) and - 1 9(3) define a continuous function r by r (z (s) ) a: e If L (z) is the arc length along ’7 from o to 2, then 2 () ’0 I‘(W)dW =I: zr(z(s)) d—5§(s)ds IMZ) e -1 0(3) 13 (s) d 5 (Z) 3‘0” 1%, d8 = [01“) lazl = W) so that I (r) (z) is a real valued function that tends mono- tonically to 00 alonng . Further, 'r(z)’ =- 1 for all z in q . We also require that the length of the inter- sectiononand 52:3n S ’2' 5s gbeat least one for each positive integer n. 1¢ n+1 If p = e 6 Al , let 42 p be the rotation of 7 through angle ? . Define r on 07 p in exactly the same manner that we defined r on 07 . (r is well defined since in both cases arg gag (o)= O and thus r (O) a: e'1 ' O_ l and O is the only point of intersection of ”p and 02 ) Let S = U 7? . We observe that any component of p 6 A1 p 21 \J/ Tfn* intersects S at exactly one point. We define r 11:1 to be constant on each component (namely equal to the value of r at the point of intersection). We now have r con- tinuous on S U( &1 tn" ) which is a network that does not disconnect tgezplane so that we can again use the approxi- mation techniques we used in the proof of Theorem 6, this time being careful to keep the integral of our holomorphic function f "reasonably close" to the integral of r on this network. We thus obtain a holomorphic function f such that (1) For each p in A1 . r is bounded on 7] p , (2) II (“MI 7 n and Im(1(r)(z)) < 1 on Tn“ n a 1’2, 0.. We again construct another holomorphic function g as follows. The constructions have been virtually the same as those Barth and Schneider used in the proof of [:9, Example 1, pp. 15-22;? so that, Just as they did in that proof, for each positive integer m we get a holomorphic function gm such that m p (1)’sm(2)l < 1/2+1 ona U FJm) a g N p (2) 11 (8mm)! < 1 / 2’"+1 on m u FJ m) 3:2” (3) II (sm)(2)l > :13me (I (0(2)) +3 pm on (T J '2. N. J 3 22 p p (4) Re (I (sm)(2)) > - 1 / 2 on JyNUIJm U 53 m) 2 2 where N is the integer such that pm 6 HN but pm é HN 1 . 0° - Let 8(2) = : m(z) so that, as before, g is holomor- m = 1 phic in D. Also, if p 6 A1, [3 (z), _<_ mZ'1(1/2n) = 1 so that, if h =- f+g, h is bounded on W p (both1 f and g are) and hence h 6 B *. We now show I (h) has 00 as a Koebe value along Vn's so that I (h) $3 *. On 0pm, ’I(gm)(z)’ 2 'I(f)(z)l +nand n go ‘2'. #'I(Sn)(z)'££1/2n=lsothat T1131: n 11“]. 00 {100(2) l= lurxz) + I(sm)(2) + Z I(gn)(Z)/ n =-= Loon 74m 2 new): - mm 2)! - Z {1(gn)(2)l =1: n #m 2 11 mm! + n - II(r)<:)I - 1 Z n - 3 «pm U flim II (f)(2)l > n . ‘Im (I(f)(z)) I < 1, and Re (I (8m)(z)) ) - 1 / 2 and f I(gn)(z) < n31,n#m 2: l/2n=lsothat n==1 w II l = lurxz) + I(sm)(2) + Z I(gn)(z)l n=1,n7‘m 23 an? [I me) + I (emxz)! - n “Zn ’I‘Ilglgnflz” IV 2((n-1)*%)-1 Zn-3 00 On Tn , )1 (r)(z)l > n, II (s)(2)' 5- £1(1/2n) = 1 . 1'1" so that !I mm! = I I mm + I (gxz)! z I I (f)(z)"' II (s)(2)’ 2 n - 1 Z n-3 Thus on vn , II (h)(z)' Z n - 3 and the theorem is proved. Lappan, in [153, constructed a function that had 0° as a Koebe value, but whose integral was uniformly nor- mal, hence normal. Since normal functions are in a *, we note the following result. THEOREM 8: There exists a function 1' is B * such that f' _i__s_not .12. B *. THEOREM 9: There exists a function f in B * such that n n I (f) and f( ) are in B * for all positive integers n. Proof: If lf(z)| 5.- M in D, then IIU'HZ)! " z ”o f(t)dtléM'lzl éMinD. Thus,forthe integral any bounded function will suffice. We need a lit- tle more care for the case of the derivative, but this is easily rectified by taking a function holomorphic in 52 : 24 ‘2 l < 2 3 . Then each of its derivatives is also holo- morphic in {z : [2 I < 2 3 so that they are all bounded in B which is a compact subset of this domain. THEOREM 10: There exists é. function g not i_n_ B * J such that 8 is not in_ E2 * for any non-negative inte- ger J. Proof: For each positive integer n we define three subsets of D as follows. 10 ‘ Tn“ ire : r== l - 1 /(n+l), - ”/14 5 65777113 sn= fx:(1-1/n)+1/(4'n-(n+i)) < x < (1-1/n)+3/(4°n°(n+1))3 Gm” Sz: [2‘ <(1-1/n)+1/(8'n‘ (n+1) ) 3 We now construct a sequence of functions inductively. Let V1 be the continuous function defined on GIL/Tl which is equal to zero on G1 and 1% on T1 , we approxi- mate V1 to within § by Mergelyan's theorem [:22, Theorem 20.5, p. 386;] to get a holomorphic function g1 (z) with the property that [31(2)] < 1/2 irzeq [81(2)] 71 ifz éT1° If 81 : 82 9 °" : gn-l have been defined let 25 n - l ( Mn== n + l + 1:: max ( sup ((33 le. OSlsn zflb 1) (2H). Let Vn (2) be a continuous function which is zero in a; , sufficiently small and real on Tn’ sufficiently large and real on Sn, and linear on the two parts of the real axis from 5; to Tn that are not in Sn and approximate Vn(z) to within 1 / 2n by Mergelyan's theorem to get a holomorphic function fn(z) with the property that (In(fn)(2)l < 1/2nifz e 6"” n J 02§1n(:2§n(h (fn)(z)l)) > Mh Then, setting gn = In (fn) we see that )8n(z)l < 1/2n if z 66; (J) 02?er (:fin (Ign (2)“) 2 Mn «09 Let 8 (z) = E gn (2). Since ‘gn (z)((1/2n in n‘= l Gn this series converges uniformly on each compact subset so that g is holomorphic. Let J be a non-negative integer and m > J and look at g(J) on Tm. (J) °° (J) 'g (Z)'=(n§l 8n (2” m - 1 (J) (J) 00‘ =ln§1 g” (2) + gm (Z) + n =Zm+lgfld)(2)‘ 26 - ca 2 (3:33)”), ' E lséj)(2)l - Z 1 /2n n “‘1 n ==m+l m-l m (J) “‘1 ?- ‘ *1 " Ellgn W" ‘2: 1855” (2)! -1 n:= 1 :2 m Thus, for all non-negative integers J, 3(3) has 09 as a Koebe value and hence is not in E *. This proves the theorem. THEOREM 11: There exists a function g not in B * such that IJ (g) is not in; Ei * for any non-nggative inte- ger J. Proof: Let Tn , Sn , and On be as before. Again, we shall define a sequence of functions inductively. Let g1 be as in the proof of Theorem 10 and suppose g1, "': gn_1 have been defined. This time we will let ”- Mn=n+l + Ina an (1) J=- 1 0315.5 2:,“ < '1 (she)! )) and, in exactly the same manner, construct a holomorphic function gn such that (85qu < 1/2n irzea'; .31;an ( inf (II;I (gnsz) > Mn zeTn so We set 8 (Z) =‘ 15::. gn (z) and again the series con- n==1 ‘Verges uniformly on each compact subset so that g is holo- rnorphic. 27 Let J be a non-negative integer and m j) J and look at IJ (g) on Tm. 00 lfll=l i IJ (an) (2)! n an‘1 _ [m - 1 J J (x: _' n2§;1 I (8“)(2) + I gm(z) +n Egg+1lj(gn)(z) I - l 09 2113(gn)(z)l - :gl h‘j(gn)(z)l - S l / 2n n ==m+l m - 1 J m - l J .2Knu1.+h:E;i )I (gn)(z)l) -n:E;; [I (gn)(z)l -1 2m Thus IJ (g) has 00 as a Koebe value and is not in B * for any non-negative integer J. III. FURTHER PROPERTIES OF FUNCTIONS IN CLASS B. * We now turn to growth conditions. As usual, we use the following two measures of growth M_ m(rn) 2 A4. (rn+1) _>_ /“~(r). Since any r that is bigger than r1 is in some interval E rn , rn+1) , this shows that m (r) 2. M (r) and the result is proved. 00 THEOREM 114: Let fzngn a 1 E a sequence 93 points EDsuch thatO < lzll < [22] < ’2 l< :--, lim Iznl“1 on 3 n-Oue and let ("n3 n i: 1 be a sequence of complex numbers. Then There exists a function f in 8 * such that lim 'f(zn) - w I ‘— ""'"— "" — ""'"" n-vao '1 =0. Proof: Let fr 3 00 be a sequence of real numbers __._._' n n - 0 such that r0 < )zl\I,n+1 - Dr) n 'Po(z) + 131(2) + + pun)! < l / 2""1 if z 6 Rn+1 fl OI.n+1 33 where hn (z) is defined by hn ( r “J ) “(130(1'11‘3) + P1(rn 0%) + H. + Pn_1(rn°fj)) ‘ (rn+1-r) /(rn+1 - rn) J -= 1,2,-°°, n n + 1 We define a continuous function h n+1 on ( \./ RJ ) __ , J"1 D - D b /r) ( n+2 rn+1 ) y hn+1 (r on) a (po (rn+1°‘J) + p1(rn+1 0%) + + D“ (rn+1ch) ) (rn+2 ' r) / (rn+2'rn+l) J =- 132’ ...’n+1 and then a function gn+1 on Fn+l by 8n+1(z) =- 0 if z E Dru“ =- hn+1(2) - (190(2) + + pn(2) ) n+1 -——- if z “ng R3 m< Drn+2 - DI. ) n+1 = "n+2 - (po(z) + ---+ pn(z)) if z .- zn+2 - - (po(2) + + pn(2))1f z 6 lime/10%“ Again, 3n+1 is continuous and holomorphic at each interior point so that we can approximate it to get a polynomial pn+1 (2) such that 34 lpn+1(z)' < 1/22n+2 ifz 5: BE” 'Wn+2 ' (po(zn+2) + ... + pn+1(zh+2) )' < 1/2n+2 ”Wm ' “’0‘” + °°°+ pn+l(z) )l < 1 / 2M2 n+1 __ if 26(JEJ1RJ)/\( Drn+2 - Dr. ) n+1 ... n+2 (90(2) + + pn+l (z), < 1/2 if zeRn+2nCrn+2 ”This completes the inductive step. We now define f(z) =J:£O DJ (2). IfzéDrn andm 2, n, thenIpm (z). < 1 / 2m+l so the series converges on each compact subset and f is holomorphic. If z 6 R:j and I2 I > rJ, there exists n 2 J such that I'm £ '2. 09 . Thus 11ml 1‘ (r «J ) .. O. This shows f has radial limit zero I"? at each point of a dense subset of C and hence is in B *. (It is actually in F‘ ). Next 00 If (23) - wfl - Ingo pn (2,) - le < J- 1 oo _. {5:0 I», (2,) - m + 5131me 5 1/2J+1 + E: 1/2’”1 = 11/2“1 + 1/2J 1 / 23"1 Thus, 11m (f (23) - W3 ‘ := O and the result is .1400 proved. 36 Remark: This is an example of the technique of re- peatedly using Mergelyan's Theorem. It is essentially the same as that used by Bagemihl and Seidel in [: 2. Theorem 1.:] and is generally attributed to them. BIBLIOGRAPHY 10. BIBLIOGRAPHY F. Bagemihl, P. Erdos, and W. Seidel, Sur quelques grogrietesr frontieres des fonctions holomorfihes nes certains roduits dans le cercle-unite, EFT-551.com Norm. up. )—'75 U9 W. F. Bagemihl and W. 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