SET FUNCTIONS AND LOCAL CONNECTMTY Thesis fer the Deflree of Ph. D. MECHEGAN STATE UNWERSWY EUGENE LEROY VANDENBOSS 1970 IIIIIIIIIIIIIIIIIIIIIIIIIIIIII 31293 10729 5556 LIBRARY ++J£TCIS Michigan Sum University This is to certify that the thesis entitled SET FUNCTIONS AND LOCAL CONNECTIVITY presented by Eugene Leroy Vandenboss has been accepted towards fulfillment of the requirements for Ph.D. degree in Mathematics Time pm I V flier professor Date July 23: 197a 0-169 V BINDING BY HIM AS & SUNS' : 300K BlIIIIEIIY IIIB. LIBRARY BINDERS srmsropy, alums! ABSTRACT SET FUNCTIONS AND IDCAI CONNECTIVITY BY Eugene Leroy VandenBoss This is a study of the closure, Y, with resPect to con- tinua with connected interior. Chapter one develops the ele- mentary properties of Y; Chapter two deve10ps the basic re- lationships between Y and T, where T denotes the closure with reSpect to continua; Chapter three develops relationships between Y and monotone maps. In Chapter one the usual hypothesis is that S is a compact Hausdorff Space. The main theorems are: S Elocalll connected Eflflgfo}; ACS Y(A) = C1(A). S ‘13 locally connected 1£.§Eé.flflll.i£ 1- Y(p)={p} £9121; 968 2:19 2. S i§_Y-additive. ;£_ S ii Y-symmetric, then S ‘13 locally connected at p, i_ and only l__ Y(p) = {p}. ‘1: C $3 5 subcontinuum g: the continuum S, then Y(C) _i_8_ a continuum. In Chapter two S denotes a Hausdorff continuum. The main theorems are: f S is weakly irreducible, then S is locally con- nected at p, if and only if. S is connected Im Kleinen at p; Eugene Leroy VandenBoss moreover, i_i: S _i_s_ also yosyndetic, then S is locally con- nected. S is weakly irreducible _i_f_ and _qn_ly _i_f_ for any sub- continuum, W, _E S, S - W by: a finite number 9_f components. S i_s loc&l_ly connected giggling E S X S .13 Y-additive. _g ACInt(B) ch8 Eli T(B) =B, £1131 Y(A) cB. (Here S need not be connected.) This last result generalizes the theorem which states: S is locally connected if and only if S is connected Im Kleinen. In Chapter three S denotes a compact Hausdorff space, which need not be connected. The main theorems are: _Le_t_ f begmonotone mapgg S Q52 Z,_t_l_1e_n Y(f‘lom c Flora») :2; 92 A c 2- _IEE f 19.29. open monotone majgi S 9339 Z, M Y(A) == f(Y(f-1(A)) g2; §1_1 Ac: 2. Let f _b__e_a_n open monotone mapo 8 gn_tg Z. $113.9 1. _Ij S _igY-additive, then Z ii Y-additive 2. f S _i_sY-synmetric, then 2 g Y-symmetric. SET FUNCTIONS AND IOCAI CONNECTIVITY By Eugene Leroy VandenBoss A THESIS Submitted to Michigan State University in partial fulfillment of the requirements for the degree of DOCTOR OF PHILOSOPHY Department of Mathematics 1970 Q ~ (55%: / - 3112' ’7/ ACKNOWLEDGMENTS I wish to thank Dr. H.S. Davis for his guidance and time in the preparation of this work, also for his aid in helping me form a style of writing. Above this I wish to thank Dr. Davis for his time spent developing my mathematical and teaching abilities. ii Chapter 1 2 3 TABLE OF CONTENTS Page E IEWNTARY m0 PERT IE S OF Y I O O O 0 O O C O O O 0 O I O O O O I 0 O O O O 1 REIATIONSHI m BENEEN Y MD T O O O O O O O O O O O O O O O O O O O 11 Y MDMONOTONEMB 0.000.000.0000...00.00.000.000. 20 BIBLIOGRAHIY 0...... ..... 0.... OOOOOOOOOOOOOOOOOO O... 26 iii CHAPTER I EIEMENTARY PROPERTIES OF Y Definition. Let S be a set and let P(S) denote the collection of all Subsets of S. Let S be a topological Space and let ”‘3 P(S). e is the closure with resPect to n if and only if e: P(S) « P(S) by the following rule: x is not an element of 9(A) if and only if there exist N and element of n Such that x is an element of the interior of N and N and A are disjoint. The following are directly verifiable. Formulas. Let S be a topological space, n<: P(S) and let 9 be the closure with respect to n, Ehgg i. AC 9(A) ii. 9(A n B) C 6(A) n 9(8) 111. 9(A) u 9(3) c: 9(A U B) iv. 9(3) 8 S v. 9(A) is closed vi. If Ac: B, then 9(A) c: 9(B). In [1] the set function T was defined and its basic properties were discussed. T is the closure with respect to the collection of continua. This paper is a study of the closure with reapect to continua with connected interiors. Definition. Let S be a topological Space and let W be a subset of S, then W is called a strong continuum if and and only if 1. W is a closed compact connected subset of S 2. The interior of W is connected. The set-function under consideration is defined as follows: Definition. Let S be a topological Space, then Y is the closure with reSpect to the collection of strong continua. Definition. Let S be a topological space and let p be an element of S, the 77((p) is the set of all strong continua W in S such that p is an element of the interior of W. Following are some immediate results for all topological spaces S. Theorem 1. I££_ W CZS be a strgngicontinuum.then the closure of the interior of W is a strong continuum of S. Theorem 2. Let A be a subset of S, then Y(A) = {xwemm = w n A 34 ,5} u {x|W(x) = ,5} = {x|we'm(x) =w n A # go}. A sequence of related set-functions can be defined as follows. Definition. Let n be a positive integer and let A be a subset of a topological Space S, then Y1(A) = Y(A) and Ynflm = vane». Formulas for Y. 1. ACY(A) 2. Y(A.n B) CLY(A) n Y(B) 3. Y(A) U Y(B) CY(A U B) a. Y(S) = s 5. ‘Y(A) is closed 6. If ACB then Y(A) CY(B) 7. Let m s n then Ym(A)<:'Yn(A). The following example shows that 77((p) can be empty and that the inequality in formula 1 may be proper for closed sets. Example 1. Let S = {(%,O)}n is a positive integer} U {(0,0)} with the relative plane topology, then. WK(0,0)) = ® and Y((fi30)) = {(%,0), (0,0)}. The following example shows that the inequality in formula 1 may be proper for a closed set when 1m(p) # ¢ for all p E S. Example 2. Let S be the Subcontinuum of the plane defined by the union of the closed line segments between (0,1) and (fiyO) for n 2 l and the closed line segment between (0,0) and (0,1); t0pologically this is the cone over example 1. In S, Y((O,l)) is the closed line segment between (0,0) and (0,1). The following example shows that formula 3 need not be an equality. Example 3. Let S be the Subcontinuum of the plane defined by the union of closed line segments between (0,1) and q%,0) for n 2 l, the closed line segments between {0,-1) and %,O) for n 2 l and the closed line segment between (0,1) and (O,-l); this is t0pologically the suspension over example 1 with vertices (0,1) and (0,-l). In S, Y((O,l)) = (0,1) and Y((O,-l)) = (O,-l) but Y({(O,l), (O,-l)}) is the closed line segment between (0,1) and (O,-1). The following example shows that Y(A) need not be Y2(A) and similar examples can be found which have the property that for m and n distinct positive integers Ym(A) need not be Yn(A). Example 4. Let S = {(x,% + % sin(fi))\0 < x s l} U {(x,-% +>k sin(%))}0 < x s 1} U {(O,y)}-% S y s k} with the topology induced by the plane, then Y((O,%)) = {(o,y)Io s y s s} and quoe» = {(0.y)I-% s y s a}. Definition. A Space S is called Y-additive if and only if for any collection {Ad} of closed subsets whose union is closed Y(UanD = U{Y(Aa)}. The Space in example 3 is not Y-additive since Y({(O,1)}) U Y({(O,-1)}) #‘Y({(O,l), (O,-1)}). For the remainder of this chapter S will denote a compact Hausdorff Space. Theorem 3. Y(¢) = ¢ if and only if S has a finite number of components. Proof. Let S have a finite number of components. Then each component is both open and closed, hence IW(P) ¢ ¢ for all p E S and thus if p E S then p E Y(¢). Let Y(¢) = ¢. Then 77((p) 35 (15 for all p 6 S, hence each component of S is open. Since S is compact and each component of S is Open, S has only a finite number of com- ponents. The following theorems Show the relationships between the concept of locally connected and the set function Y. Theorem 4. S is locally connected at appoint p if and only if for all subsets A p£_ S, if p is an element of Y(A), £232. p is an element of the closure of A. Proof. Let S be locally connected at p and suppose p is not an element of the closure of A. There exists an open set U such that p 6 U and Cl(U) n A = ¢. Since S is locally connected at p, there exist an open connected set V such that p E V C U. Cl(V) n A = ¢ and Cl(V) 6771(p). Therefore p is not an element of Y(A) and it follows that if p is an element of Y(A), then p is an element of the closure of A. Let p be an element of S such that for all Ac: S, if p is an element of Y(A), then p is an element of the closure of A. Let U be an open set containing p, then S - U is a closed set and p is not an element of S - U. There exist W 6 771(p) such that W n (S - U) = ¢, hence p E Int(W) CiW CiU and thus, S is locally connected at p. The theorem is proven. Corollary 5. S is locally connected if and only if £2£_ A<: S, Y(A) = Cl(A). The next theorem shows the relation between Y-additivity and the locally connected Spaces. Theorem 6. S is locally connected if and only if 1. Y(p) = {p} for all p E S 33d 2. S i§_Y-additive. Proof. let Y(p) = {p} for all p E S and let S be Y-additive. Let A¢:.S, then Cl(A) CZY(A) CZY(C1(A)) = Y(U{{P}IP e cum) Cl(A). Hence Y(A) U{Y(P)IP E Cl(A)} = UIIPIIP E Cl(A)} = Cl(A) and thus by corollary 5 S is locally connected. Let S be locally connected and let {Au} be a set of closed sets such that UIAQ} is closed. By corollary 5 Y(Aa) = Ad and Y(U{Aa}) = U[Aa}. Hence U{Y(Aa)} = U{Aa} ._- YqJ{Aa}) and S is Y-additive. Since 8 is Hausdorff, for p E S {p} is closed and by corollary 5 Y(p) = {p}. The theorem is proven. The following two examples Show that neither Y-additivity or Y(p) = {p} for all p E S implies the other. In example 3 S was not Y-additive, but Y(p) = {p} for all p element of 8 (hence S is not locally connected). In example 2 S was Y-additive, but Y((O,l)) = {(O,y)‘0 s y s 1} (hence S is not locally connected). Definition. S is called Y-symmetric if and only if for any two closed subsets A and B of S, if Y(A) is disjoint from B, then Y(B) is disjoint from A. Theorem 7. LEE S pg_Y-Symmetric, then S i§_Y-additive. Proof. Let {Au} be a set of closed sets such that U{Aa} is closed, then U{Y(Aa)} CiY(U{Ad}). Hence all that needs to be shown is that YOJ{Ad}) C:U{Y(Ad)}. Let S be Y-Synrnetric. Let p e Y(U{Aa}), then Y(U{Aa}) n {p} 39 ¢, hence Y(p)r1 GJ{Aa}) # ¢. Hence there exists 5 such that Y(p) n A # ¢. Therefore {p} 0 Y(AB) f ¢, hence p E Y(AB) B and therefore p E U{Y(Ad)}. Therefore Y(U{Ad}) c:U{Y(Aa)} and the theorem is proven. In example 2 S is Y-additive but S is not Y-symmetric Since Y((O,l)) = {(o,y)\o s y s 1} 3 {(0,0)} and Y((0,0)) = {(0,0)}. Theorem 8. L3; S pg.Y-symmetric, then S is locally connected at p, if and only if Y(p) = {p}. Proof. Let S be Y-symmetric and locally connected at p. Let q 6 Y(p), then Y(p) n {q} i ¢, hence Y(q) n {p} # ¢, hence p G Y(q); since 8 is locally connected at p, p e Cl({q}) = {q} and hence p = q. Therefore {p} = Y(p). Let S be Y-symmetric and {p} = Y(p). Let U be an Open set containing p. If p E Y(S- U), then (S - U) n Y(p) # ¢, but Y(p) = {p} and hence (S - U) n {p} # ¢, a contradiction. Therefore p d Y(S - U) and hence there exists W 67((p) such that W n (S - U) = ¢. Thus p 6 Int(W) CW CU and the theorem is proven. Following the convention in [4] page 6, 8 is called a filter-base in a topological space S if and only if 1. ch(S) 2. 3 ¢ ¢ 3. A,B E 8 implies that there exist C E 8 Such that C is a subset of A intersect B. 8 is said to be proper if and only if ¢ 4 3. g is Said to be closed if and only if A E 3 implies A is closed. Theorem 9. If 8 is a prgper closed filter-base in S, the; YmIAIA 6 3}) = nIYIA e :5}. -An 'Fr' Proof. Let x 6 Y(fl{AIA 6 3}), then for all W E 77((x) W n (n{A}A E {5}) 9‘ ¢. Therefore for all A E :5 and all W E 772(x), W n A 9‘ ¢, hence x E Y(A) for all A E 8, hence x e n{Y(A)IA e :3} and Y(n{A\A e 3}) cn{Y(A)|A e :5}. Let x é Y(n{A}A E 8}), then there exists W E 771(x) such that w n (n{AIA e {3}) = 95. Hence w c s - n{A\A g g} and {S - A}A E 3} is an open covering for W. Since W is compact there exist A1,...,An such that w:u{s -AiI1 s i sn] =3 -n{AiI1 s i Sn}. Since {3 is a prOper closed filter base, there exists an element, A, of 3 Such that Acanill s i S n}, hence W n A = 95 and x é Y(A). Thereforex 4 n {Y(A)}A e g} and n{Y(A)\A e g} c: Y(n{A}A e 5}). The theorem is proven. Theorem 10. S i_sY-additive if and only_if for each £33 A 93‘}. B of closed subsets of S Y(A U B) = Y(A) U Y(B). Proof. Let S be Y-additive and let A and B be closed subsets, then Y(A) U Y(B) = Y(A U B). Let Y(A) U Y(B) = Y(A U B) for any two closed subsets of 8. Let {AaIa E d} be a set of closed sets such that U{AaIcy E d} is closed. Since U{Y (Aa)Io E d} C Y(U{Aa}a 6 4}) all that needs to be shown is that Y(U{Aa\or E.d}) C U{Y(Aa)}a E a}. For each or 6 a let 3(Aa) be the collection of closed subsets B of S such that Ad C Int(B). If A0 = q) then Y(Aa) = n{Y(B)|s 6 {50.0)}. If Ad 3‘ ,3, then 39.0!) is a closed prOper filter base of S and Since n{B‘B E 8(Aa)} = A0, Y(Aa) = n{Y(s)\B e (Satan. ‘l‘i‘tl‘fll‘ll‘ll I'll I III Suppose x i U{Y(Ad)Io E afl. Then for each a €<7 there exists Ba e {3(Aa) such that x 4 Y(Ba). {Int (Ba)Ior 6 a} is an open covering of the compact set U{AdIo E a? and hence there exists B1,...,Bn such that U{Aa\a e a} c u{1nt(si)| l s i g n}. By hypothesis Y(U{BiIl s i s n}) = U{Y(Bi)I1 s i s n}, hence x t Y(U{Bi}l s i s n}) :3 Y(U[AaIa e m). Therefore Y(U{Aan e a}) c U{Y(Aa)Io E d} and the theorem is proven. The following example shows that Y({p,q}) = Y(p) U Y(q) for any two elements of Z and that Z is not Y-additive. Example 5. Let S be the Space in example 3 and let Z = S X I. Then Y(p) U Y(q) = Y({p,q}) for all p,q E Z, but Y((0,1) x I) = (0,1) x I and Y((0,-1) x I) = (O,-1) x I but Y(((O,l) x I) u ((o,-1) x 1)) = {(o,y)|-1 s y s 1} x 1. Theorem 11. If for all p E S and any finite collection, {W1}, of elements of 77((p), there exists W E 77((p) such thc'3_t_ W CZHIWi}, £322. 8 i§_Y-additive. Proof. By Theorem 10 all that is needed to be shown is that Y(A) U Y(B) = Y(A.U B) for any two closed subsets of S. By formula 3 all that needs to be shown is that Y(A U B)<: ‘Y(A) U Y(B). Let A and B be any two closed subsets of S and let p d Y(A) U Y(B). There exists W1,W2 €1m(p) such that W1 0 A = n = W2 .1 B. By hypothesis there exists W E 77((p) such that W CW1 0 W2. Hence W n (A.U B) = ¢ and p 4 Y(A U B), thus Y(A U B) C1Y(A) U Y(B). Compare with Chapter 1, paragraph 2 of [5]. 10 Theorem 12. Let C be a Subcontinuum of the continuum S, then Y(C) is a continuum. Proof. Since Y(C) is closed and hence compact, all that needs to be proven is that Y(C) is connected. Suppose Y(C) = A U Bsep and C CIA“ Since 8 is normal, there exists U and V Open set with disjoint closures such that ACU and BCV. Since CCACU and B CV, Y(C) is disjoint from Fr(V), where Fr(V) denotes the boundary of V. Therefore for all y 6 Fr(V), there exists Wy E 77((y) such that Wy n C = ¢. Since {Int(Wy)} forms an open covering of Fr(V), there exists strong continua 'W1,...,Wn such that wi n c = C, and U{Int(Wi)|1 s i s n} :> Fr(V). If K is a component of V then Cl(K) n Fr(V) # ¢, hence V U(U{Int(Wi)}1 s i s n}) has only a finite number of components. Therefore each component of V U (U{Int(Wi)\l s i s n}) is Open. Let b E B and Kb be the component of V U (U{Int(Wi)}1 S i S n}) containing b, then Cl(Kb) E WKb) and Cl(Kb) n C = ¢. There- fore b 4 Y(C), but this contradicts the fact that B C Y(C). Therefore Y(C) is a continuum. CHAPTER 2 RELATIONSHIPS BETWEEN Y AND T This chapter develOpS some relationships between T and Y. Definition. Let S be a topological space, then T is the closure with reSpect to continua. Theorem 13. Let A be a subset of the topological gpggg S, £§gp_ T(A) is a subset of Y(A). Proof. Suppose x 4 Y(A). Then there exists W E 77((p) such that W n A = ¢. Since W E m(p), x E Int(W) and there- fore x d T(A). Hence T(A) C Y(A). The following example shows that T(A) need not be Y(A). Example 6. Let S be the Subcontinuum of the plane defined as follows. S is the closed line segments between (1,0) and (O,%) for n 2 1 union with the closed line segments between (l,%) and (2,0) for n 2 1 union with the closed line segment between (0,0) and (2,0). T((2,0)) = {(x,o)\1 s x s 2} and Y((2,0)) = {(x,0)\o s x s 2}. The following is an example of a Space that is Y-additive, but not T-additive. Example 7. Let S be the closed line segments between 0 (O,%,O) and (1,0,0), between (l,%30) and (2,0,0), between 11 12 l (2:; (2,-%,0) and (1,0,0), between (3,-%,0) and (2,0,0), between ,0) and (3,0,0), between (1,-§,0) and (0,0,0), between (1%,O,%) and (0,0,0), between (3,0,0) and (12,0,fi) for n 2 l unioned with the closed line segment (0,0,0) and (3,0,0). T((0,0,0)) = [(x,0,0)\0 s x s 1} and T((3,0,0)) = {(x,0,0)\2 s x s 3}, but r({(0,0,0), (3,0,0)}) = {(x,0,0)\0 s x s 3}. Let L = {(x,0,0)\0 s x s 3}. If A.C:S is closed then Y(A) = A if A n L = ¢ and Y(A) = A u L if A n L # ¢. Thus S is Y-additive. For the remainder of this chapter S will be a compact Hausdorff continuum. Definition. S is called weakly irreducible if and only if given C1,C2,...,C subcontinua of S, n S - UICiIl s i s n} has a finite number of components. Lemma 14. Let S be weakly irreducible and let C be a Subcontinuum of S, then Int(C) has only a finite number of components. Proof. Let S - C have components K ,...,K , then 1 n Int(C) = S - U{C1(Ki)}l s i S n} which has only a finite number of components. Theorem 15. Let S be weakly irreducible and let A be a subset of S, then T(A) = Y(A). Proof. Since T(A) C:Y(A), all that needs to be shown is that Y(A) C1T(A). Let x é T(A), then there exists a con- tinuum W such that x 6 Int (W) and W n A = ()5. Since Int (W) has only a finite number of components each component is open; 13 let K be the component containing x, then Cl(K) E‘m(p) and Cl(K) n A = ¢, therefore x é Y(A); hence Y(A)<: T(A) and the theorem is proven. Corollary 16. '_f S is weakly irreducible, then 1. S is Y-symmetric 2. S is locally connected at p, if and only if_ S is connected Tm Kleinen at p. La.) 0 H I'h S is also aposynedetic, then S 25 locally connected. Proof. This follows from the previous theorem and from Theorem 6 of [2]. The following develops a weaker statement which is equivalent to weakly irreducible. Definition. Let S be a continuum and let A be a subset of S. S is called irreducible about A if and only if for C a subcontinuum of S such that A ClC, then C = S. Notation S = [A]. Definition. Let S be a topological space, let A and B tuztwo disjoint closed subsets of S and let M be a Subcontinuum of S. M. is called irreducible from A pp. B if and only if M intersects both A and B non-voidly and no prOper sub- continuum Of M intersects both A and B. The following two theorems are from [6]. Theorem A (Theorem 43). Lg£_ A 22g, B be two disjoint closed subsets 2;. S, then S contains 3 continuum irreducible from A _t_9_ B. 14 Theorem B (Theorem 47). Let A and B be two disjoint closed subsets of S and let M be an irreducible continuum from A pp. B, then M - (A.U B) and M - A are connected. Theorem 17. Let C1,C2,...,Cn be disjoint subcontinua pf S, then there exists a component K pf S - U{Ci|l S i S n} such that Cl(K) n 01 i‘ (a gig C1(I()n (U{ci|2 s i s n}) ié (2). Proof. Since C and U{Ci}2 S i S n} are closed dis- 1 joint subsets of S, 8 contains a continuum, M, irreducible from C to U{Ci}2 S i S n}. 1 Let L = M - U{ci\1 s i s n}, then Cl(L) n 01 # (b, Cl(L){1 QJ{Ci}2 S i S n}) # ¢ and L is connected. Let K be the component of S - U[CiI1 S i S n} containing L, then Cl(K) n 01 59 ,5 and 0100 n (\J{Ci\2 s i s n}) 9‘ $- Corollary 18. Let C1,C2,...,Cn be disjoint subcontinua igf S, then there exists K1,...,Km, components of S - U{Ci|1 S i S n}, m S n, such that (U{K1I1 S 1 S m}) U {U{Ci\1 S i S n}} is a subcontinuum of 8. Theorem 19. S is weakly irreducible if and only if given any W a subcontinuum of S, S - W has a finite number of components. Proof. Let S be weakly irreducible and let C be a subcontinuum of S, then S - C has a finite number of components by definition. Let S be Such that for any subcontinuum W of S, S - W has a finite number of components. [at C1,C2,..-,Cn be subcontinua of S. Then U{Ci|l S i S n} =lJ{Mi}l S i S m} where the M1 are disjoint components of U{Ci|1 S i S n}. 15 The M1 are disjoint subcontinua of S. Therefore there exist k1,...,kL components of S - U{Mi|l S i S m} such that c = (U{ki\l s i s 5}) u (UMi‘1 s i s m) is a continuum. There- fore S - C has a finite number of components t1,...,t0. There- fore S - U{Ci}1 S i S n} has less than or equal to L + 0 components. The theorem is proven. Theorem 20- L35 3 = [{x1,x2,...,xn}], then S is weakly irreducible. Proof. Let C be a subcontinuum of S and let ki be the component of S - C containing x if x1 E C. i (U{kiI1 S i S n and xi 6 0}) U C is a subcontinuum and {x1,x2,...,xn}<: 0J{ki}1 S i S n and x1 i C}) U C; therefore 3 = QJ{ki|l S i S n and xi 4 C}) U C. Hence S - C has less than or equal to n components. Therefore 3 is weakly irreducible. Corollary 21. f S = [{x1,x2,...,xn}], then 1. S is connected Im Kleinen at p if and only .if S is locally connected at p 2. S is Y—Symmetric. Proof. This follows from Corollary l6 and Theorem 20. In Example 2 S = [{ (%,O)}n > O} U {(0,0), (0,1)}], but S is not weakly irreducible since S - {(0,0)} has an infinite number of components. Definition. B is called a compact separator of the topological Space 3 if and only if 1. B is compact 2. S'B=HUKSEP. 16 Theorem 22. if A is a subset of S, then Y(A) inter- sects any compact separator of S that separates A from any point of Y(A). Proof. Suppose the theorem is false and there exists a compact set B such that S - B = H U K sep, AC: H, p 6 Y(A) n K and S - BID Y(A). Since B is closed, both H and K are open and since Cl(K) n H = ¢, if k is a component of K then Cl(k)!) B # ¢. Since B CZS - Y(A), there exists a finite number of strong continua, Wi, Such that Wi n A 3 ¢ and B<: U{Int(Wi)}. Therefore K U (U{Int(Wi)}) has a finite number of components and each component is open. Let k be the component of KU (U[Int(Wi)}) containing p, then Cl(k) €77}(p) and Cl(k)[1 A = ¢. Therefore p 6 Y(A), contradiction. The theorem is proven. Corollary 23. f A.C:S, then evegy component of Y(A) intersects A. Proof. See Corollary 1.1 of [7]. Corollary 24. .l£ A is a closed subset of S and Y(A) is totally disconnected, then Y(A) = A. Proof. See Corollary 1.2 of [7]. Corollary 25. Let A and B be closed, totally dis- connected subsets. whgre ACS1 and B c:82, then for any closed subset K C A x B C S X 82, Y(K) = K = T(K). 1 Proof. See Theorem 2 of [7]. Theorem 26. Let p E S X S, then Y(p) = {p}. Proof. Let q = (a,b) and p = (c,d) be two distinct points of S x S, then a # c or b i d. It may be assumed 17 that a # c. There exists U and V open set such that a E U, c G U. and d é V: Then (a,b) is an element of the open set (U X S) U (S X V) and (c,d) is not an element of the closed set (Cl(U) X S) U (S X Cl(V)). To Show that (U X S) U (S X V) is connected, it need only be shown that for (e,f) and (h,g) elements of (U X S) U (S x V) that there are elements of a connected subset of (U X S) L) (S X V). Case 1. (e,f) and (h,g) are elements of U X S or S X V. It may be assumed that there are elements of U X S. Let t E V then ({e} X S) U ({h} X S) U (S X {t}) is a connected set Since ({e} X S) n (S X [t}) ' (e,t), ({h} XS)n (S x {t}) = (n,t) and ({e} XS)U ({h} XS) U (SX[t})C UXSUSXV. Case 2. (e,f) E U X S and (h,g) E S X V then ([e} X S) U (S X {g}) is a connected Subset of (U X S) U (S X V). The theorem is proven. Corollary 27. The followipg are equivalent 1. S is locally connected 2. S X S i§_Y-additive 3. S X S is T-additive. In the following theorem the hypothesis that S is connected is not necessary. Theorem 28. I_f_ ACInt(B)CBCS a_n<_i_ T(B) =B, £1193 Y(A)CB. Proof. First we show that each component of S - B is Open. Let K be a component of S - B and let x E K. 18 Since x i T(B), there exists a continuum. W such that xélnt(W) and WnB =¢. Hence WCK and x EInt(W), therefore x e Int(K). Since x could be any element of K, K is Open. Now we Show that Y(A) ClB. Let p E S - B and let K be the component of S - B containing p. Then Cl(K) €1m(p) and Cl(K)f] A = ¢, therefore p G Y(A) and thus Y(A)<: B. Corollary 29. S is locally connected if and only if S is connected Im Kleinen. Proof. If S is locally connected then S is connected Im Kleinen. Let S be connected Im Kleinen, then T(A) = Cl(A) and S is T-additive [2]. Let U be an Open set containing A, then T(C1(U)) = Cl(U), hence Y(A)<: Cl(U) by Theorem 28. Cl(A) C Y(A) Cn[C1(U)‘A C U and U is open} = Cl(A), hence T = Y. Therefore S is Y-additive and Y(p) = {p} for all p E S, thus S is locally connected. Davis has the following theorem in [9]. Let S be a compact Hausdorff Space, then the following are equivalent 1. T(A)}fi B = ¢ where A and B are closed 2. There exist closed subsets M and N Such that AC Int(M), B C Int(N) and TM) 0 N = ¢. Corollary 30. If_ T2(A) = T(A) for all A CZS, £233 T(A) =‘Y(A) for all Ac: 8. Proof. Let x Z T(A), then there exists an open set U such that A<: U and x i T(Cl(U)L [9]. Since T(T(Cl(U))) = 19 T(Cl(U)) and Since A C U C Int (T(Cl(U))), Y(A) C T(Cl(U)) by Theorem 28, therefore x i Y(A). Thus T(A) = Y(A). CHAPTER 3 Y AND MONOTONE MAPS This chapter is a study of the relations between Y and monotone functions. For the following theorems all Spaces are Hausdorff. Definition. A function f from S onto Z is called monotone if and only if f is continuous and f-1(z) is connected for all z E Z. Theorem. L55 f be an open monotone map of S 2353 Z and let A be a connected subset of Z, Epgp f-1(A) is connected. Proof. See Chapter VI, section 3, problem 1 of [8]. Theorem 31. Let f be a closed monotone map of S pppg Z and let A be a connected subset of Z, ppgp f- (A) is connected. Proof. Suppose the theorem is false and let C be a connected subset of Z such that f‘1(C) = M.U N sep. f(M) n f(N) = 0: for if p e f(M) n f(N), then r'1(p) n N a! 0 and f-1(p) n M # ¢, but f-1(p) is connected, hence f-1(C) # M n N sep. Therefore f(N) n f(M) = q). C = f(f-1(C)) = f(M U N) = f(M) U f(N) and C is connected. Therefore Cl(f(N)) n f(M) ¢ ¢ or f(N) n Cl(f(N)) ¢ ¢. We may assume that Cl(f(N)) n M # ¢. Let p E Cl(f(N)) n f(M), 20 21 then f-1(P)I] M # ¢. f-1(p) is connected, hence f-1(p)<: M. {p}<: Cl(f(N)) = f(Cl(N)) Since f is a closed map. Therefore f-1(p)[1 Cl(N) # ¢, hence Cl(N)t] M # ¢. This is a contradic- tion of separability. Thus f-1(C) is connected. For the following theorems all Spaces are compact Hausdorff Spaces. Theorem 32. L33 f be a monotone map of S 2353 Z and let W be a Strong subcontinuum of Z, £hgp_ Cl(f-1(Int(W))) is a strong continuum. Proof. Since f is a continuous map of a compact Hausdorff space onto a compact Hausdorff Space f is a closed map. Therefore by Theorem 29 f-1(Int(W)) is connected. Since f is continuous, f-1(Int(W)) is open. Thus, Cl(f-1(Int(W))) is a strong continuum. The following example shows that even if f is a closed monotone map, f"1 of a strong continuum need not be a strong continuum. Example 3. Let S = 12, Z = {(x,y)‘k S x S l and OSyS 1} and let A={(x,y)|0gxs!5 and OSyS 1}. define f: S a Z by f(x,y) = (x,y) if % S x S l and f(x,y) = (%,y) if 0 S x < %. Let ‘W = {(x,y)}(x - 3/4)2 + (y - 1/4)2 S 1/4} U {(350)}0 S y S 1}. £‘1(w)= A U w, Int(A) n W = ¢ and A n Int(W) = ¢. Theorem 33. l££_ f be a monotone map of S gpgp. Z, tree Y(f'1) c Elmo). Proof. Let A be a subset of z and suppose p e f-1(Y(A)), then f(p) é Y(A). Hence there exist W 677((f(p)) such that 22 W m A = ¢. Therefore f-1(W) n f-1(A) = ¢. By Theorem 30 Cl(f-1(Int(W))) E 77((p), hence p 6 Y(A) and thus Y(f-1(A)) C also». Theorem 34. ESE f be a monotone map of S gpgg Z, phgp f(Y(A)) C:Y(f(A)). Theorem 35. lg£_ f be an open monotone map of S 9353 2. thee Y(f'1>. Proof. By Theorem 33 Y(f-1(A))<: f-1(Y(A)), hence all that needs to be shown is that f-1(Y(A))'C:Y(f-1(A)). Suppose p é Y(f-1(A)), then there exist W E 771(p) such that W n f-1(A) = ¢, hence f(W) n A = ¢. Since f is open f(W) 6mm») and f(p) t Y(A). Thus p e Elmo) and Flam) cw'lm). Theorem 36. LEE f be an Open monotone map of S gppg 2, then Y(A) = f(Y(r'1(A)))- Corollary 37. LEE f be an open monotone map of S SEER. Z, EEEE l. l£_ S is Y-additive then Z is Y-additive 2. H f S is Y-symmetric, then Z is Y-symmetric. Proof. Let S be Y-symmetric and let A and B be closed subsets of Z such that Y(A) n B ¢, then Y(f'1(A>>. f-1(Y(A)) n f-1(B) = ¢. Since f-1(Y(A)) Y(f-1(A)) n f-1(B) = ¢. Since S is Y-symmetric Y(f-1(B)) n f-1(A) = ¢, thus Y(B) n A = ¢ and Z is Y-symmetric. Let S be Y-additive and let A and B be closed subsets of 2, then f-1(Y(A) u Y(B)) = Flam) u f-1,(Y(B)) = Y(f'1(A>) u Y(f-1(B)) = Y(f'le) u 51(3)) = Y(f'ch u 3)) = 23 f-1(Y(A U 3)), thus Y(A) U Y(B) = Y(A U B) and Z is Y-additive. Corollary 38. Let $1 and S S1 X 82 is locally connected if and only if S1 and 32 are 2 be continua, then locally connected. Proof. Let P1 and P2 be the two projection maps, then P1 and P2 are open monotone maps. Let S1 X 82 be locally connected, then S and S l 2 are Y-additive and hence it suffices to show that Y(a) II r-s n) a...) for all a E 51' Let a 6 Sl,then Y(a) = P1(Y(P11(a)) P1(Y({a} X 82)) = P1({a} X 82) = a. Thus S1 and 82 are locally connected. Let 31 and 82 be locally connected. Let p 6 S1 X 82 and let A be any subset of S1 X 82 Such that p é Cl(A), then there exist 01<: S1 and 02 C 82, both open, such that p E 01 X 02 and (01 X 02) n A = ¢. Since S and S2 are l locally connected, there exist W1 6 7R(P1(p)) and W2 6 771(P2(p)) such that WICO1 and W2 C 02, hence p 6 W1 X W2 and (W1 X W2) n Ai= ¢. Therefore p 4 Y(A). Thus by Theorem 4 S1 X 82 is locally connected. Theorem 39. Let H gpd' K be closed subsets of S, then the following are equivalent. a. H n Y(K) = (b b. There exists a finite collection C of strong continua such that H is contained in the union of the interiors of the elements of C and the intersection of each element of C with K ii empty. 24 c. There exist two closed subsets M Egg N _spgp gig; H is a subset of the interior of M, K is a subset of the interior of N _a_r_1_<_1_ M intersect Y(N) is empty. Proof. a implies b. Let L be the Set of strong continua of S such that Int(W) n H¥¢ and W0 K =9). Since HnY(K) =¢, HC (U{Int(W)‘W E L}). Since H is compact, there exist w1,...,wn such that Wi E L and HC (U[Int(wi)‘l S i S n}). Let c ={wi\1 S i S n}. b implies c. Since S is normal there exist V such that V is open H c: v c Cl(V) cu{1nt(W)\w e c} and there exist 11 such that u is open KC 11 and Cl(U) n (U{w|w e 0}) = ¢. There- fore C1(V) n Y(C1(U)) = 95. Let Cl(V) = M and Cl(U) = N. c implies a. K CN, therefore Y(K) C Y(N), H C M and M I] Y(N) = (I). thus H n Y(K) = ¢. The closed monotone image of a T-Sytrmetric compact Hausdorff Space is a T-synmetric compact Hausdorff Space. This final example shows that the closed monotone image of a Y-Symmetric Space need not be Y-symmetric and that f(Y(A)) need not be Y(f(A)). Example 9. Let S be the closed line segments between (-%,0) and (0,1) and the closed line segments between (Tl-’2) and (0,3) unioned with [(x,% + Sine-HO S x S l} U {(x,2% + sin(;]{")}0 < x S l} unioned with the closed line segment 25 between (0,0) and (0,3), then S is Y-synmetric and Y((O,3)) = {(0,y)|2 s y s 3}. Let 2 be the closed line segments between (-%,0) and (0,1) unioned with those between (-%31) and (0,2) for n 2 l unioned with [(x,% +-sin(§))}l < x S l} U {(x,l% + sin(§))}0 < x S l} unioned with the closed line segment between (0,0) and (0,2). Let f((X.Y)) = (x,y) if y S 1. f((x,y)) = (0.1) if 1 S y S 2 and f((x,y)) = (x,y-l) if 2 S y S 3. Z is not Y-symmetric since Y((0,0)) = {(O,y)}0 S y S l} and Y((O,2)) = {(0,y)|0 s y s 2}. f(Y(0,3)) # Y(f(0,3)) since f(Y((0,3))) = i({(0,y)\2 s y S 3}) = {(O,y)}l s y s 2} and Y = mm» = {(0.y)|o s y s 2}. BIBLIOGRAPHY BIBLIOGRAPHY Davis, H.S., D.P. Stadtlander and P.M. Swingle, "Properties of the set function Tn," Portugal Math. 21 (1962), 113-133. Davis, H.S., "A note on connectedness Im Kleinen," Proceed- ings of the American Mathematical Society, Vol. 19, No. 5, October 1968, pp. 1237-1241. Hocking, John G. and Gail S. Young, Topology, Addison- Wesley. Kuratowski, K., Topology Volume I, Academic Press. Bourbasi, N., General Topology, Addison-Wesley. Moore, R.L., Foundations of Point Set Theory, American Mathematical Society, Volume XIII. Fitzgerald, RHW., "The cartesian product of non-degenerate compact continua is n-point aposyndetic," TOpology Conference, Arizona State University, 1967, p. 324. Dugundji, James, Topplogy, Allyn and Bacon. Davis, H.S., To appear. 26 "IIIIII'IIIIIIIII'IIIIT