SET FUNCTIONS AND LOCAL CONNECTMTY
Thesis fer the Deflree of Ph. D.
MECHEGAN STATE UNWERSWY
EUGENE LEROY VANDENBOSS
1970
IIIIIIIIIIIIIIIIIIIIIIIIIIIIII
31293 10729 5556
LIBRARY
++J£TCIS
Michigan Sum
University
This is to certify that the
thesis entitled
SET FUNCTIONS AND LOCAL CONNECTIVITY
presented by
Eugene Leroy Vandenboss
has been accepted towards fulfillment
of the requirements for
Ph.D. degree in Mathematics
Time pm
I V flier professor
Date July 23: 197a
0-169
V BINDING BY
HIM AS & SUNS' :
300K BlIIIIEIIY IIIB.
LIBRARY BINDERS
srmsropy, alums!
ABSTRACT
SET FUNCTIONS AND IDCAI CONNECTIVITY
BY
Eugene Leroy VandenBoss
This is a study of the closure, Y, with resPect to con-
tinua with connected interior. Chapter one develops the ele-
mentary properties of Y; Chapter two deve10ps the basic re-
lationships between Y and T, where T denotes the closure
with reSpect to continua; Chapter three develops relationships
between Y and monotone maps.
In Chapter one the usual hypothesis is that S is a
compact Hausdorff Space. The main theorems are:
S Elocalll connected Eflflgfo}; ACS
Y(A) = C1(A).
S ‘13 locally connected 1£.§Eé.flflll.i£
1- Y(p)={p} £9121; 968 2:19
2. S i§_Y-additive.
;£_ S ii Y-symmetric, then S ‘13 locally connected at
p, i_ and only l__ Y(p) = {p}.
‘1: C $3 5 subcontinuum g: the continuum S, then
Y(C) _i_8_ a continuum.
In Chapter two S denotes a Hausdorff continuum. The
main theorems are:
f S is weakly irreducible, then S is locally con-
nected at p, if and only if. S is connected Im Kleinen at p;
Eugene Leroy VandenBoss
moreover, i_i: S _i_s_ also yosyndetic, then S is locally con-
nected.
S is weakly irreducible _i_f_ and _qn_ly _i_f_ for any sub-
continuum, W, _E S, S - W by: a finite number 9_f components.
S i_s loc&l_ly connected giggling E S X S .13
Y-additive.
_g ACInt(B) ch8 Eli T(B) =B, £1131 Y(A) cB.
(Here S need not be connected.)
This last result generalizes the theorem which states:
S is locally connected if and only if S is connected Im
Kleinen.
In Chapter three S denotes a compact Hausdorff space,
which need not be connected. The main theorems are:
_Le_t_ f begmonotone mapgg S Q52 Z,_t_l_1e_n
Y(f‘lom c Flora») :2; 92 A c 2-
_IEE f 19.29. open monotone majgi S 9339 Z, M
Y(A) == f(Y(f-1(A)) g2; §1_1 Ac: 2.
Let f _b__e_a_n open monotone mapo 8 gn_tg Z. $113.9
1. _Ij S _igY-additive, then Z ii Y-additive
2. f S _i_sY-synmetric, then 2 g Y-symmetric.
SET FUNCTIONS AND IOCAI CONNECTIVITY
By
Eugene Leroy VandenBoss
A THESIS
Submitted to
Michigan State University
in partial fulfillment of the requirements
for the degree of
DOCTOR OF PHILOSOPHY
Department of Mathematics
1970
Q ~ (55%:
/ - 3112' ’7/
ACKNOWLEDGMENTS
I wish to thank Dr. H.S. Davis for his guidance and
time in the preparation of this work, also for his aid in
helping me form a style of writing. Above this I wish to
thank Dr. Davis for his time spent developing my mathematical
and teaching abilities.
ii
Chapter
1
2
3
TABLE OF CONTENTS
Page
E IEWNTARY m0 PERT IE S OF Y I O O O 0 O O C O O O 0 O I O O O O I 0 O O O O 1
REIATIONSHI m BENEEN Y MD T O O O O O O O O O O O O O O O O O O O 11
Y MDMONOTONEMB 0.000.000.0000...00.00.000.000. 20
BIBLIOGRAHIY 0...... ..... 0.... OOOOOOOOOOOOOOOOOO O... 26
iii
CHAPTER I
EIEMENTARY PROPERTIES OF Y
Definition. Let S be a set and let P(S) denote the
collection of all Subsets of S. Let S be a topological Space
and let ”‘3 P(S). e is the closure with resPect to n if and
only if e: P(S) « P(S) by the following rule: x is not an
element of 9(A) if and only if there exist N and element
of n Such that x is an element of the interior of N and
N and A are disjoint.
The following are directly verifiable.
Formulas. Let S be a topological space, n<: P(S)
and let 9 be the closure with respect to n, Ehgg
i. AC 9(A)
ii. 9(A n B) C 6(A) n 9(8)
111. 9(A) u 9(3) c: 9(A U B)
iv. 9(3) 8 S
v. 9(A) is closed
vi. If Ac: B, then 9(A) c: 9(B).
In [1] the set function T was defined and its basic
properties were discussed. T is the closure with respect to
the collection of continua.
This paper is a study of the closure with reapect to
continua with connected interiors.
Definition. Let S be a topological Space and let W
be a subset of S, then W is called a strong continuum if and
and only if
1. W is a closed compact connected subset of S
2. The interior of W is connected.
The set-function under consideration is defined as follows:
Definition. Let S be a topological Space, then Y
is the closure with reSpect to the collection of strong continua.
Definition. Let S be a topological space and let p
be an element of S, the 77((p) is the set of all strong continua
W in S such that p is an element of the interior of W.
Following are some immediate results for all topological
spaces S.
Theorem 1. I££_ W CZS be a strgngicontinuum.then the
closure of the interior of W is a strong continuum of S.
Theorem 2. Let A be a subset of S, then
Y(A) = {xwemm = w n A 34 ,5} u {x|W(x) = ,5} = {x|we'm(x) =w n A # go}.
A sequence of related set-functions can be defined as
follows.
Definition. Let n be a positive integer and let A
be a subset of a topological Space S, then Y1(A) = Y(A) and
Ynflm = vane».
Formulas for Y.
1. ACY(A)
2. Y(A.n B) CLY(A) n Y(B)
3. Y(A) U Y(B) CY(A U B)
a. Y(S) = s
5. ‘Y(A) is closed
6. If ACB then Y(A) CY(B)
7. Let m s n then Ym(A)<:'Yn(A).
The following example shows that 77((p) can be empty
and that the inequality in formula 1 may be proper for closed
sets.
Example 1. Let S = {(%,O)}n is a positive integer} U
{(0,0)} with the relative plane topology, then. WK(0,0)) = ®
and Y((fi30)) = {(%,0), (0,0)}.
The following example shows that the inequality in
formula 1 may be proper for a closed set when 1m(p) # ¢ for
all p E S.
Example 2. Let S be the Subcontinuum of the plane
defined by the union of the closed line segments between (0,1)
and (fiyO) for n 2 l and the closed line segment between
(0,0) and (0,1); t0pologically this is the cone over example 1.
In S, Y((O,l)) is the closed line segment between (0,0) and
(0,1).
The following example shows that formula 3 need not be
an equality.
Example 3. Let S be the Subcontinuum of the plane
defined by the union of closed line segments between (0,1)
and q%,0) for n 2 l, the closed line segments between {0,-1)
and %,O) for n 2 l and the closed line segment between
(0,1) and (O,-l); this is t0pologically the suspension over
example 1 with vertices (0,1) and (0,-l). In S, Y((O,l)) =
(0,1) and Y((O,-l)) = (O,-l) but Y({(O,l), (O,-l)}) is the
closed line segment between (0,1) and (O,-1).
The following example shows that Y(A) need not be
Y2(A) and similar examples can be found which have the property
that for m and n distinct positive integers Ym(A) need
not be Yn(A).
Example 4. Let S = {(x,% + % sin(fi))\0 < x s l} U
{(x,-% +>k sin(%))}0 < x s 1} U {(O,y)}-% S y s k} with the
topology induced by the plane, then Y((O,%)) = {(o,y)Io s y s s}
and quoe» = {(0.y)I-% s y s a}.
Definition. A Space S is called Y-additive if and
only if for any collection {Ad} of closed subsets whose union
is closed Y(UanD = U{Y(Aa)}.
The Space in example 3 is not Y-additive since
Y({(O,1)}) U Y({(O,-1)}) #‘Y({(O,l), (O,-1)}).
For the remainder of this chapter S will denote a
compact Hausdorff Space.
Theorem 3. Y(¢) = ¢ if and only if S has a finite
number of components.
Proof. Let S have a finite number of components. Then
each component is both open and closed, hence IW(P) ¢ ¢ for all
p E S and thus if p E S then p E Y(¢).
Let Y(¢) = ¢. Then 77((p) 35 (15 for all p 6 S, hence
each component of S is open. Since S is compact and each
component of S is Open, S has only a finite number of com-
ponents.
The following theorems Show the relationships between
the concept of locally connected and the set function Y.
Theorem 4. S is locally connected at appoint p if and
only if for all subsets A p£_ S, if p is an element of Y(A),
£232. p is an element of the closure of A.
Proof. Let S be locally connected at p and suppose
p is not an element of the closure of A. There exists an
open set U such that p 6 U and Cl(U) n A = ¢. Since S
is locally connected at p, there exist an open connected set
V such that p E V C U. Cl(V) n A = ¢ and Cl(V) 6771(p).
Therefore p is not an element of Y(A) and it follows that
if p is an element of Y(A), then p is an element of the
closure of A.
Let p be an element of S such that for all Ac: S,
if p is an element of Y(A), then p is an element of the
closure of A. Let U be an open set containing p, then
S - U is a closed set and p is not an element of S - U.
There exist W 6 771(p) such that W n (S - U) = ¢, hence
p E Int(W) CiW CiU and thus, S is locally connected at p.
The theorem is proven.
Corollary 5. S is locally connected if and only if
£2£_ A<: S, Y(A) = Cl(A).
The next theorem shows the relation between Y-additivity
and the locally connected Spaces.
Theorem 6. S is locally connected if and only if
1. Y(p) = {p} for all p E S 33d
2. S i§_Y-additive.
Proof. let Y(p) = {p} for all p E S and let S
be Y-additive. Let A¢:.S, then Cl(A) CZY(A) CZY(C1(A)) =
Y(U{{P}IP e cum)
Cl(A). Hence Y(A)
U{Y(P)IP E Cl(A)} = UIIPIIP E Cl(A)} =
Cl(A) and thus by corollary 5 S is
locally connected.
Let S be locally connected and let {Au} be a set
of closed sets such that UIAQ} is closed. By corollary 5
Y(Aa) = Ad and Y(U{Aa}) = U[Aa}. Hence U{Y(Aa)} = U{Aa} ._-
YqJ{Aa}) and S is Y-additive. Since 8 is Hausdorff, for
p E S {p} is closed and by corollary 5 Y(p) = {p}. The
theorem is proven.
The following two examples Show that neither Y-additivity
or Y(p) = {p} for all p E S implies the other.
In example 3 S was not Y-additive, but Y(p) = {p}
for all p element of 8 (hence S is not locally connected).
In example 2 S was Y-additive, but Y((O,l)) =
{(O,y)‘0 s y s 1} (hence S is not locally connected).
Definition. S is called Y-symmetric if and only if
for any two closed subsets A and B of S, if Y(A) is
disjoint from B, then Y(B) is disjoint from A.
Theorem 7. LEE S pg_Y-Symmetric, then S i§_Y-additive.
Proof. Let {Au} be a set of closed sets such that
U{Aa} is closed, then U{Y(Aa)} CiY(U{Ad}). Hence all that
needs to be shown is that YOJ{Ad}) C:U{Y(Ad)}. Let S be
Y-Synrnetric. Let p e Y(U{Aa}), then Y(U{Aa}) n {p} 39 ¢,
hence Y(p)r1 GJ{Aa}) # ¢. Hence there exists 5 such that
Y(p) n A # ¢. Therefore {p} 0 Y(AB) f ¢, hence p E Y(AB)
B
and therefore p E U{Y(Ad)}. Therefore Y(U{Ad}) c:U{Y(Aa)}
and the theorem is proven.
In example 2 S is Y-additive but S is not Y-symmetric
Since Y((O,l)) = {(o,y)\o s y s 1} 3 {(0,0)} and Y((0,0)) =
{(0,0)}.
Theorem 8. L3; S pg.Y-symmetric, then S is locally
connected at p, if and only if Y(p) = {p}.
Proof. Let S be Y-symmetric and locally connected
at p. Let q 6 Y(p), then Y(p) n {q} i ¢, hence Y(q) n {p} # ¢,
hence p G Y(q); since 8 is locally connected at p,
p e Cl({q}) = {q} and hence p = q. Therefore {p} = Y(p).
Let S be Y-symmetric and {p} = Y(p). Let U be
an Open set containing p. If p E Y(S- U), then (S - U) n
Y(p) # ¢, but Y(p) = {p} and hence (S - U) n {p} # ¢, a
contradiction. Therefore p d Y(S - U) and hence there exists
W 67((p) such that W n (S - U) = ¢. Thus p 6 Int(W) CW CU
and the theorem is proven.
Following the convention in [4] page 6, 8 is called
a filter-base in a topological space S if and only if
1. ch(S)
2. 3 ¢ ¢
3. A,B E 8 implies that there exist C E 8 Such
that C is a subset of A intersect B.
8 is said to be proper if and only if ¢ 4 3.
g is Said to be closed if and only if A E 3 implies
A is closed.
Theorem 9. If 8 is a prgper closed filter-base in S,
the; YmIAIA 6 3}) = nIYIA e :5}.
-An
'Fr'
Proof. Let x 6 Y(fl{AIA 6 3}), then for all W E 77((x)
W n (n{A}A E {5}) 9‘ ¢. Therefore for all A E :5 and all W E 772(x),
W n A 9‘ ¢, hence x E Y(A) for all A E 8, hence
x e n{Y(A)IA e :3} and Y(n{A\A e 3}) cn{Y(A)|A e :5}.
Let x é Y(n{A}A E 8}), then there exists W E 771(x)
such that w n (n{AIA e {3}) = 95. Hence w c s - n{A\A g g}
and {S - A}A E 3} is an open covering for W. Since W is
compact there exist A1,...,An such that
w:u{s -AiI1 s i sn] =3 -n{AiI1 s i Sn}. Since {3 is a
prOper closed filter base, there exists an element, A, of 3
Such that Acanill s i S n}, hence W n A = 95 and x é Y(A).
Thereforex 4 n {Y(A)}A e g} and n{Y(A)\A e g} c: Y(n{A}A e 5}).
The theorem is proven.
Theorem 10. S i_sY-additive if and only_if for each
£33 A 93‘}. B of closed subsets of S Y(A U B) = Y(A) U Y(B).
Proof. Let S be Y-additive and let A and B be
closed subsets, then Y(A) U Y(B) = Y(A U B).
Let Y(A) U Y(B) = Y(A U B) for any two closed subsets
of 8. Let {AaIa E d} be a set of closed sets such that
U{AaIcy E d} is closed.
Since U{Y (Aa)Io E d} C Y(U{Aa}a 6 4}) all that needs
to be shown is that Y(U{Aa\or E.d}) C U{Y(Aa)}a E a}.
For each or 6 a let 3(Aa) be the collection of closed
subsets B of S such that Ad C Int(B). If A0 = q) then
Y(Aa) = n{Y(B)|s 6 {50.0)}. If Ad 3‘ ,3, then 39.0!) is a closed
prOper filter base of S and Since n{B‘B E 8(Aa)} = A0,
Y(Aa) = n{Y(s)\B e (Satan.
‘l‘i‘tl‘fll‘ll‘ll I'll I III
Suppose x i U{Y(Ad)Io E afl. Then for each a €<7
there exists Ba e {3(Aa) such that x 4 Y(Ba). {Int (Ba)Ior 6 a}
is an open covering of the compact set U{AdIo E a? and hence
there exists B1,...,Bn such that U{Aa\a e a} c u{1nt(si)|
l s i g n}. By hypothesis Y(U{BiIl s i s n}) =
U{Y(Bi)I1 s i s n}, hence x t Y(U{Bi}l s i s n}) :3
Y(U[AaIa e m). Therefore Y(U{Aan e a}) c U{Y(Aa)Io E d}
and the theorem is proven.
The following example shows that Y({p,q}) = Y(p) U Y(q)
for any two elements of Z and that Z is not Y-additive.
Example 5. Let S be the Space in example 3 and let
Z = S X I. Then Y(p) U Y(q) = Y({p,q}) for all p,q E Z,
but Y((0,1) x I) = (0,1) x I and Y((0,-1) x I) = (O,-1) x I
but Y(((O,l) x I) u ((o,-1) x 1)) = {(o,y)|-1 s y s 1} x 1.
Theorem 11. If for all p E S and any finite collection,
{W1}, of elements of 77((p), there exists W E 77((p) such thc'3_t_
W CZHIWi}, £322. 8 i§_Y-additive.
Proof. By Theorem 10 all that is needed to be shown is
that Y(A) U Y(B) = Y(A.U B) for any two closed subsets of S.
By formula 3 all that needs to be shown is that Y(A U B)<:
‘Y(A) U Y(B).
Let A and B be any two closed subsets of S and
let p d Y(A) U Y(B). There exists W1,W2 €1m(p) such that
W1 0 A = n = W2 .1 B. By hypothesis there exists W E 77((p)
such that W CW1 0 W2. Hence W n (A.U B) = ¢ and
p 4 Y(A U B), thus Y(A U B) C1Y(A) U Y(B). Compare with
Chapter 1, paragraph 2 of [5].
10
Theorem 12. Let C be a Subcontinuum of the continuum
S, then Y(C) is a continuum.
Proof. Since Y(C) is closed and hence compact, all that
needs to be proven is that Y(C) is connected.
Suppose Y(C) = A U Bsep and C CIA“ Since 8 is normal,
there exists U and V Open set with disjoint closures such
that ACU and BCV. Since CCACU and B CV, Y(C)
is disjoint from Fr(V), where Fr(V) denotes the boundary of
V. Therefore for all y 6 Fr(V), there exists Wy E 77((y) such
that Wy n C = ¢. Since {Int(Wy)} forms an open covering of
Fr(V), there exists strong continua 'W1,...,Wn such that
wi n c = C, and U{Int(Wi)|1 s i s n} :> Fr(V). If K is a
component of V then Cl(K) n Fr(V) # ¢, hence
V U(U{Int(Wi)}1 s i s n}) has only a finite number of components.
Therefore each component of V U (U{Int(Wi)\l s i s n}) is Open.
Let b E B and Kb be the component of V U (U{Int(Wi)}1 S i S n})
containing b, then Cl(Kb) E WKb) and Cl(Kb) n C = ¢. There-
fore b 4 Y(C), but this contradicts the fact that B C Y(C).
Therefore Y(C) is a continuum.
CHAPTER 2
RELATIONSHIPS BETWEEN Y AND T
This chapter develOpS some relationships between T
and Y.
Definition. Let S be a topological space, then T
is the closure with reSpect to continua.
Theorem 13. Let A be a subset of the topological
gpggg S, £§gp_ T(A) is a subset of Y(A).
Proof. Suppose x 4 Y(A). Then there exists W E 77((p)
such that W n A = ¢. Since W E m(p), x E Int(W) and there-
fore x d T(A). Hence T(A) C Y(A).
The following example shows that T(A) need not be
Y(A).
Example 6. Let S be the Subcontinuum of the plane
defined as follows. S is the closed line segments between
(1,0) and (O,%) for n 2 1 union with the closed line
segments between (l,%) and (2,0) for n 2 1 union with the
closed line segment between (0,0) and (2,0). T((2,0)) =
{(x,o)\1 s x s 2} and Y((2,0)) = {(x,0)\o s x s 2}.
The following is an example of a Space that is Y-additive,
but not T-additive.
Example 7. Let S be the closed line segments between
0
(O,%,O) and (1,0,0), between (l,%30) and (2,0,0), between
11
12
l
(2:;
(2,-%,0) and (1,0,0), between (3,-%,0) and (2,0,0), between
,0) and (3,0,0), between (1,-§,0) and (0,0,0), between
(1%,O,%) and (0,0,0), between (3,0,0) and (12,0,fi) for
n 2 l unioned with the closed line segment (0,0,0) and
(3,0,0). T((0,0,0)) = [(x,0,0)\0 s x s 1} and T((3,0,0)) =
{(x,0,0)\2 s x s 3}, but r({(0,0,0), (3,0,0)}) =
{(x,0,0)\0 s x s 3}.
Let L = {(x,0,0)\0 s x s 3}. If A.C:S is closed
then Y(A) = A if A n L = ¢ and Y(A) = A u L if A n L # ¢.
Thus S is Y-additive.
For the remainder of this chapter S will be a compact
Hausdorff continuum.
Definition. S is called weakly irreducible if and
only if given C1,C2,...,C subcontinua of S,
n
S - UICiIl s i s n} has a finite number of components.
Lemma 14. Let S be weakly irreducible and let C
be a Subcontinuum of S, then Int(C) has only a finite number
of components.
Proof. Let S - C have components K ,...,K , then
1 n
Int(C) = S - U{C1(Ki)}l s i S n} which has only a finite number
of components.
Theorem 15. Let S be weakly irreducible and let A
be a subset of S, then T(A) = Y(A).
Proof. Since T(A) C:Y(A), all that needs to be shown
is that Y(A) C1T(A). Let x é T(A), then there exists a con-
tinuum W such that x 6 Int (W) and W n A = ()5. Since Int (W)
has only a finite number of components each component is open;
13
let K be the component containing x, then Cl(K) E‘m(p)
and Cl(K) n A = ¢, therefore x é Y(A); hence Y(A)<: T(A)
and the theorem is proven.
Corollary 16. '_f S is weakly irreducible, then
1. S is Y-symmetric
2. S is locally connected at p, if and only
if_ S is connected Tm Kleinen at p.
La.)
0
H
I'h
S is also aposynedetic, then S 25
locally connected.
Proof. This follows from the previous theorem and from
Theorem 6 of [2].
The following develops a weaker statement which is
equivalent to weakly irreducible.
Definition. Let S be a continuum and let A be a
subset of S. S is called irreducible about A if and only
if for C a subcontinuum of S such that A ClC, then C = S.
Notation S = [A].
Definition. Let S be a topological space, let A and B
tuztwo disjoint closed subsets of S and let M be a Subcontinuum
of S. M. is called irreducible from A pp. B if and only if
M intersects both A and B non-voidly and no prOper sub-
continuum Of M intersects both A and B.
The following two theorems are from [6].
Theorem A (Theorem 43). Lg£_ A 22g, B be two disjoint
closed subsets 2;. S, then S contains 3 continuum irreducible
from A _t_9_ B.
14
Theorem B (Theorem 47). Let A and B be two disjoint
closed subsets of S and let M be an irreducible continuum
from A pp. B, then M - (A.U B) and M - A are connected.
Theorem 17. Let C1,C2,...,Cn be disjoint subcontinua
pf S, then there exists a component K pf S - U{Ci|l S i S n}
such that Cl(K) n 01 i‘ (a gig C1(I()n (U{ci|2 s i s n}) ié (2).
Proof. Since C and U{Ci}2 S i S n} are closed dis-
1
joint subsets of S, 8 contains a continuum, M, irreducible from
C to U{Ci}2 S i S n}.
1
Let L = M - U{ci\1 s i s n}, then Cl(L) n 01 # (b,
Cl(L){1 QJ{Ci}2 S i S n}) # ¢ and L is connected. Let K
be the component of S - U[CiI1 S i S n} containing L, then
Cl(K) n 01 59 ,5 and 0100 n (\J{Ci\2 s i s n}) 9‘ $-
Corollary 18. Let C1,C2,...,Cn be disjoint subcontinua
igf S, then there exists K1,...,Km, components of
S - U{Ci|1 S i S n}, m S n, such that (U{K1I1 S 1 S m}) U
{U{Ci\1 S i S n}} is a subcontinuum of 8.
Theorem 19. S is weakly irreducible if and only if
given any W a subcontinuum of S, S - W has a finite number
of components.
Proof. Let S be weakly irreducible and let C be a
subcontinuum of S, then S - C has a finite number of components
by definition.
Let S be Such that for any subcontinuum W of S,
S - W has a finite number of components. [at C1,C2,..-,Cn
be subcontinua of S. Then U{Ci|l S i S n} =lJ{Mi}l S i S m}
where the M1 are disjoint components of U{Ci|1 S i S n}.
15
The M1 are disjoint subcontinua of S. Therefore there exist
k1,...,kL components of S - U{Mi|l S i S m} such that
c = (U{ki\l s i s 5}) u (UMi‘1 s i s m) is a continuum. There-
fore S - C has a finite number of components t1,...,t0. There-
fore S - U{Ci}1 S i S n} has less than or equal to L + 0
components. The theorem is proven.
Theorem 20- L35 3 = [{x1,x2,...,xn}], then S is weakly
irreducible.
Proof. Let C be a subcontinuum of S and let ki
be the component of S - C containing x if x1 E C.
i
(U{kiI1 S i S n and xi 6 0}) U C is a subcontinuum and
{x1,x2,...,xn}<: 0J{ki}1 S i S n and x1 i C}) U C; therefore
3 = QJ{ki|l S i S n and xi 4 C}) U C. Hence S - C has less
than or equal to n components. Therefore 3 is weakly
irreducible.
Corollary 21. f S = [{x1,x2,...,xn}], then
1. S is connected Im Kleinen at p if and only
.if S is locally connected at p
2. S is Y—Symmetric.
Proof. This follows from Corollary l6 and Theorem 20.
In Example 2 S = [{ (%,O)}n > O} U {(0,0), (0,1)}],
but S is not weakly irreducible since S - {(0,0)} has an
infinite number of components.
Definition. B is called a compact separator of the
topological Space 3 if and only if
1. B is compact
2. S'B=HUKSEP.
16
Theorem 22. if A is a subset of S, then Y(A) inter-
sects any compact separator of S that separates A from any
point of Y(A).
Proof. Suppose the theorem is false and there exists a
compact set B such that S - B = H U K sep, AC: H, p 6 Y(A) n K
and S - BID Y(A). Since B is closed, both H and K are
open and since Cl(K) n H = ¢, if k is a component of K then
Cl(k)!) B # ¢. Since B CZS - Y(A), there exists a finite number
of strong continua, Wi, Such that Wi n A 3 ¢ and B<:
U{Int(Wi)}. Therefore K U (U{Int(Wi)}) has a finite number
of components and each component is open. Let k be the
component of KU (U[Int(Wi)}) containing p, then Cl(k) €77}(p)
and Cl(k)[1 A = ¢. Therefore p 6 Y(A), contradiction. The
theorem is proven.
Corollary 23. f A.C:S, then evegy component of Y(A)
intersects A.
Proof. See Corollary 1.1 of [7].
Corollary 24. .l£ A is a closed subset of S and
Y(A) is totally disconnected, then Y(A) = A.
Proof. See Corollary 1.2 of [7].
Corollary 25. Let A and B be closed, totally dis-
connected subsets. whgre ACS1 and B c:82, then for any
closed subset K C A x B C S X 82, Y(K) = K = T(K).
1
Proof. See Theorem 2 of [7].
Theorem 26. Let p E S X S, then Y(p) = {p}.
Proof. Let q = (a,b) and p = (c,d) be two distinct
points of S x S, then a # c or b i d. It may be assumed
17
that a # c. There exists U and V open set such that a E U,
c G U. and d é V: Then (a,b) is an element of the open set
(U X S) U (S X V) and (c,d) is not an element of the closed
set (Cl(U) X S) U (S X Cl(V)).
To Show that (U X S) U (S X V) is connected, it need
only be shown that for (e,f) and (h,g) elements of (U X S) U
(S x V) that there are elements of a connected subset of
(U X S) L) (S X V).
Case 1. (e,f) and (h,g) are elements of U X S or
S X V. It may be assumed that there are elements of U X S.
Let t E V then ({e} X S) U ({h} X S) U (S X {t}) is a
connected set Since ({e} X S) n (S X [t}) ' (e,t),
({h} XS)n (S x {t}) = (n,t) and ({e} XS)U ({h} XS) U
(SX[t})C UXSUSXV.
Case 2. (e,f) E U X S and (h,g) E S X V then
([e} X S) U (S X {g}) is a connected Subset of (U X S) U
(S X V). The theorem is proven.
Corollary 27. The followipg are equivalent
1. S is locally connected
2. S X S i§_Y-additive
3. S X S is T-additive.
In the following theorem the hypothesis that S is
connected is not necessary.
Theorem 28. I_f_ ACInt(B)CBCS a_n<_i_ T(B) =B,
£1193 Y(A)CB.
Proof. First we show that each component of S - B
is Open. Let K be a component of S - B and let x E K.
18
Since x i T(B), there exists a continuum. W such that
xélnt(W) and WnB =¢. Hence WCK and x EInt(W),
therefore x e Int(K). Since x could be any element of K,
K is Open.
Now we Show that Y(A) ClB. Let p E S - B and let
K be the component of S - B containing p. Then Cl(K) €1m(p)
and Cl(K)f] A = ¢, therefore p G Y(A) and thus Y(A)<: B.
Corollary 29. S is locally connected if and only if
S is connected Im Kleinen.
Proof. If S is locally connected then S is connected
Im Kleinen.
Let S be connected Im Kleinen, then T(A) = Cl(A)
and S is T-additive [2]. Let U be an Open set containing
A, then T(C1(U)) = Cl(U), hence Y(A)<: Cl(U) by Theorem 28.
Cl(A) C Y(A) Cn[C1(U)‘A C U and U is open} = Cl(A), hence
T = Y. Therefore S is Y-additive and Y(p) = {p} for all
p E S, thus S is locally connected.
Davis has the following theorem in [9].
Let S be a compact Hausdorff Space, then the following
are equivalent
1. T(A)}fi B = ¢ where A and B are closed
2. There exist closed subsets M and N Such that
AC Int(M), B C Int(N) and TM) 0 N = ¢.
Corollary 30. If_ T2(A) = T(A) for all A CZS, £233
T(A) =‘Y(A) for all Ac: 8.
Proof. Let x Z T(A), then there exists an open set U
such that A<: U and x i T(Cl(U)L [9]. Since T(T(Cl(U))) =
19
T(Cl(U)) and Since A C U C Int (T(Cl(U))), Y(A) C T(Cl(U)) by
Theorem 28, therefore x i Y(A). Thus T(A) = Y(A).
CHAPTER 3
Y AND MONOTONE MAPS
This chapter is a study of the relations between Y
and monotone functions.
For the following theorems all Spaces are Hausdorff.
Definition. A function f from S onto Z is called
monotone if and only if f is continuous and f-1(z) is
connected for all z E Z.
Theorem. L55 f be an open monotone map of S 2353
Z and let A be a connected subset of Z, Epgp f-1(A) is
connected.
Proof. See Chapter VI, section 3, problem 1 of [8].
Theorem 31. Let f be a closed monotone map of S
pppg Z and let A be a connected subset of Z, ppgp f- (A)
is connected.
Proof. Suppose the theorem is false and let C be a
connected subset of Z such that f‘1(C) = M.U N sep.
f(M) n f(N) = 0: for if p e f(M) n f(N), then r'1(p) n N a! 0
and f-1(p) n M # ¢, but f-1(p) is connected, hence
f-1(C) # M n N sep. Therefore f(N) n f(M) = q).
C = f(f-1(C)) = f(M U N) = f(M) U f(N) and C is
connected. Therefore Cl(f(N)) n f(M) ¢ ¢ or f(N) n Cl(f(N)) ¢ ¢.
We may assume that Cl(f(N)) n M # ¢. Let p E Cl(f(N)) n f(M),
20
21
then f-1(P)I] M # ¢. f-1(p) is connected, hence f-1(p)<: M.
{p}<: Cl(f(N)) = f(Cl(N)) Since f is a closed map. Therefore
f-1(p)[1 Cl(N) # ¢, hence Cl(N)t] M # ¢. This is a contradic-
tion of separability. Thus f-1(C) is connected.
For the following theorems all Spaces are compact
Hausdorff Spaces.
Theorem 32. L33 f be a monotone map of S 2353 Z
and let W be a Strong subcontinuum of Z, £hgp_ Cl(f-1(Int(W)))
is a strong continuum.
Proof. Since f is a continuous map of a compact
Hausdorff space onto a compact Hausdorff Space f is a closed
map. Therefore by Theorem 29 f-1(Int(W)) is connected. Since
f is continuous, f-1(Int(W)) is open. Thus, Cl(f-1(Int(W)))
is a strong continuum.
The following example shows that even if f is a closed
monotone map, f"1 of a strong continuum need not be a strong
continuum.
Example 3. Let S = 12, Z = {(x,y)‘k S x S l and
OSyS 1} and let A={(x,y)|0gxs!5 and OSyS 1}.
define f: S a Z by f(x,y) = (x,y) if % S x S l and
f(x,y) = (%,y) if 0 S x < %. Let ‘W = {(x,y)}(x - 3/4)2 +
(y - 1/4)2 S 1/4} U {(350)}0 S y S 1}. £‘1(w)= A U w,
Int(A) n W = ¢ and A n Int(W) = ¢.
Theorem 33. l££_ f be a monotone map of S gpgp. Z,
tree Y(f'1) c Elmo).
Proof. Let A be a subset of z and suppose p e f-1(Y(A)),
then f(p) é Y(A). Hence there exist W 677((f(p)) such that
22
W m A = ¢. Therefore f-1(W) n f-1(A) = ¢. By Theorem 30
Cl(f-1(Int(W))) E 77((p), hence p 6 Y(A) and thus Y(f-1(A)) C
also».
Theorem 34. ESE f be a monotone map of S gpgg Z,
phgp f(Y(A)) C:Y(f(A)).
Theorem 35. lg£_ f be an open monotone map of S 9353
2. thee Y(f'1>.
Proof. By Theorem 33 Y(f-1(A))<: f-1(Y(A)), hence all
that needs to be shown is that f-1(Y(A))'C:Y(f-1(A)). Suppose
p é Y(f-1(A)), then there exist W E 771(p) such that
W n f-1(A) = ¢, hence f(W) n A = ¢. Since f is open
f(W) 6mm») and f(p) t Y(A). Thus p e Elmo) and
Flam) cw'lm).
Theorem 36. LEE f be an Open monotone map of S gppg
2, then Y(A) = f(Y(r'1(A)))-
Corollary 37. LEE f be an open monotone map of S
SEER. Z, EEEE
l. l£_ S is Y-additive then Z is Y-additive
2.
H
f S is Y-symmetric, then Z is Y-symmetric.
Proof. Let S be Y-symmetric and let A and B be
closed subsets of Z such that Y(A) n B ¢, then
Y(f'1(A>>.
f-1(Y(A)) n f-1(B) = ¢. Since f-1(Y(A))
Y(f-1(A)) n f-1(B) = ¢. Since S is Y-symmetric Y(f-1(B)) n
f-1(A) = ¢, thus Y(B) n A = ¢ and Z is Y-symmetric.
Let S be Y-additive and let A and B be closed
subsets of 2, then f-1(Y(A) u Y(B)) = Flam) u f-1,(Y(B)) =
Y(f'1(A>) u Y(f-1(B)) = Y(f'le) u 51(3)) = Y(f'ch u 3)) =
23
f-1(Y(A U 3)), thus Y(A) U Y(B) = Y(A U B) and Z is Y-additive.
Corollary 38. Let $1 and S
S1 X 82 is locally connected if and only if S1 and 32 are
2 be continua, then
locally connected.
Proof. Let P1 and P2 be the two projection maps,
then P1 and P2 are open monotone maps.
Let S1 X 82 be locally connected, then S and S
l 2
are Y-additive and hence it suffices to show that Y(a)
II
r-s
n)
a...)
for all a E 51' Let a 6 Sl,then Y(a) = P1(Y(P11(a))
P1(Y({a} X 82)) = P1({a} X 82) = a. Thus S1 and 82 are
locally connected.
Let 31 and 82 be locally connected. Let p 6 S1 X 82
and let A be any subset of S1 X 82 Such that p é Cl(A),
then there exist 01<: S1 and 02 C 82, both open, such that
p E 01 X 02 and (01 X 02) n A = ¢. Since S and S2 are
l
locally connected, there exist W1 6 7R(P1(p)) and W2 6 771(P2(p))
such that WICO1 and W2 C 02, hence p 6 W1 X W2 and
(W1 X W2) n Ai= ¢. Therefore p 4 Y(A). Thus by Theorem 4
S1 X 82 is locally connected.
Theorem 39. Let H gpd' K be closed subsets of S,
then the following are equivalent.
a. H n Y(K) = (b
b. There exists a finite collection C of strong
continua such that H is contained in the union
of the interiors of the elements of C and the
intersection of each element of C with K ii
empty.
24
c. There exist two closed subsets M Egg N _spgp
gig; H is a subset of the interior of M, K is
a subset of the interior of N _a_r_1_<_1_ M intersect
Y(N) is empty.
Proof. a implies b.
Let L be the Set of strong continua of S such that
Int(W) n H¥¢ and W0 K =9). Since HnY(K) =¢,
HC (U{Int(W)‘W E L}). Since H is compact, there exist
w1,...,wn such that Wi E L and HC (U[Int(wi)‘l S i S n}).
Let c ={wi\1 S i S n}.
b implies c.
Since S is normal there exist V such that V is
open H c: v c Cl(V) cu{1nt(W)\w e c} and there exist 11 such
that u is open KC 11 and Cl(U) n (U{w|w e 0}) = ¢. There-
fore C1(V) n Y(C1(U)) = 95. Let Cl(V) = M and Cl(U) = N.
c implies a.
K CN, therefore Y(K) C Y(N), H C M and M I] Y(N) = (I).
thus H n Y(K) = ¢.
The closed monotone image of a T-Sytrmetric compact
Hausdorff Space is a T-synmetric compact Hausdorff Space. This
final example shows that the closed monotone image of a Y-Symmetric
Space need not be Y-symmetric and that f(Y(A)) need not be
Y(f(A)).
Example 9. Let S be the closed line segments between
(-%,0) and (0,1) and the closed line segments between (Tl-’2)
and (0,3) unioned with [(x,% + Sine-HO S x S l} U
{(x,2% + sin(;]{")}0 < x S l} unioned with the closed line segment
25
between (0,0) and (0,3), then S is Y-synmetric and
Y((O,3)) = {(0,y)|2 s y s 3}.
Let 2 be the closed line segments between (-%,0)
and (0,1) unioned with those between (-%31) and (0,2)
for n 2 l unioned with [(x,% +-sin(§))}l < x S l} U
{(x,l% + sin(§))}0 < x S l} unioned with the closed line
segment between (0,0) and (0,2).
Let f((X.Y)) = (x,y) if y S 1. f((x,y)) = (0.1)
if 1 S y S 2 and f((x,y)) = (x,y-l) if 2 S y S 3.
Z is not Y-symmetric since Y((0,0)) = {(O,y)}0 S y S l}
and Y((O,2)) = {(0,y)|0 s y s 2}. f(Y(0,3)) # Y(f(0,3))
since f(Y((0,3))) = i({(0,y)\2 s y S 3}) = {(O,y)}l s y s 2}
and Y = mm» = {(0.y)|o s y s 2}.
BIBLIOGRAPHY
BIBLIOGRAPHY
Davis, H.S., D.P. Stadtlander and P.M. Swingle, "Properties
of the set function Tn," Portugal Math. 21 (1962), 113-133.
Davis, H.S., "A note on connectedness Im Kleinen," Proceed-
ings of the American Mathematical Society, Vol. 19, No. 5,
October 1968, pp. 1237-1241.
Hocking, John G. and Gail S. Young, Topology, Addison-
Wesley.
Kuratowski, K., Topology Volume I, Academic Press.
Bourbasi, N., General Topology, Addison-Wesley.
Moore, R.L., Foundations of Point Set Theory, American
Mathematical Society, Volume XIII.
Fitzgerald, RHW., "The cartesian product of non-degenerate
compact continua is n-point aposyndetic," TOpology Conference,
Arizona State University, 1967, p. 324.
Dugundji, James, Topplogy, Allyn and Bacon.
Davis, H.S., To appear.
26
"IIIIII'IIIIIIIII'IIIIT