4 i tH Hi DESIGN OF A FALSE CONCRETE he w i | ARCH RAILROAD BRIDGE 7 | AT EAST BOULEVARD, CLEVELAND, OHIO. - any it THESIS FOR DEGREE OF ©. E. 7 —o0— j JOHN GRIFFITH CAVANAGH Hy —O— kK Ee ie | [Ou 7 oa SUPPLEMENTARY MATE AL. IN BACK OF BOOK MAY 5 - 1913 DESIGN OF A FALSE CONCRETE ARCH RAILROAD BRIDGE AT EAST BOULEVARD, CLEVELAND, OHIO Thesis for degree of C. E. John Griffith Cavanagh 1913 THESIS 94624 DESIGN OF A FALSE CONCRETE ARCH RAILROAD BRIDGE AT EAST BOULEVARD, CLEVELAND, OHIO The conditions which govern the design of structures used in the elimination of a series of grade crossings in cities are of various natures. The primary object in the design of any bridge is to provide a structure that will safely carry the traffic. The secondary object may depend upon local conditions, legal or municipal requirerents, cost or results desired to be attained. The City of Cleveland, desiring an entrance to a park, opened a street known as East Boulevard. In order to cross the tracks of The New York, Chicago and St- Louis ("Nickel Plate”) Railroad, a bridge to carry the railroad traffic was built spanning the street. The street was de- pressed to allow the proper vertical clearance and the slopes graded to harmonize with the surrounding landscape. In 1909 the City of Cleveland and the Village of East Cleveland passed ordinances granting The Cleveland Short Line Railway permission to construct a two track rail- road across several streets, A desirable location for the Cleveland Short Line Railway for about three miles through Cleveland and East Cleveland was found to be adjacent and parallel to the tracks of the “Nickel Plate” Railroad. No grade crossings were allowed in the con- struction of the Oleveland Short Line Railway, which made it necessary, in order to use the above mentioned location, to eliminate the grade crossings of the Nickel Plate Railroad through the zone where the tracks are adjacent. When the grades of the respective railroads were established the elevation of the Cleveland Short Line Railway at East Boulevard was about three feet more than the elevation of the Nickel Plate Railroad at this point. The City of Cleveland established the new street grade, which was only slightly changed from the old grade, and requested that a concrete arch bridge of an artistic design be built to carry the railroad traffic of the two railroads. The difference in elevation of the railroad tracks and a horizontal plane at a given distance above the street surface fixed by the City ordinance for the under clearance of the bridge was great enough to permit the construction of a concrete arch under the Cleveland Short Line tracks but not under the Nickel Plate tracks. After the design of the Oleveland Short Line arch was completed a design was made of a steel and con- 2 orete structure having the appearance of a concrete arch. This structure was placed adjacent to the concrete arch, to carry the Nickel Plate traffic, and consisted of a through plate girder bridge, with concrete floor slab and wing abutments and concrete fascia and soffit arches to conceal the steel. The bridge was designed for Cooper's Class E-60 loading and according to The N. Y. Cc. & St. L. Railroad Company's specifications. Width of street 54'feet Angle between bridge and street, 90 degrees Span center to center of supports, 58.3 feet Distance center to center of tracks 16 feet Track alignment 3° 5' curve Design of Outside Girder. Dead load to be carried by outside girder. Estimated weight of steel in girder 37600 lbs. " " ‘1 t " floor beans 27000 lbs. " " " concrete and drainage gutter 130410 lbs. " fn " ballast 55680 lbs. 250090 lbs. (Notes Ballast is computed to top of tie and the weight of the track is neglected.) — Dead load end shear = 250690 4 2 = 125345 Live load end shear (from tables for Cooper's Clase E-60 loading for 58.3' span) 143610 (400 ) (when L = loaded Impact = live load (300+tL ) length of bridge 120230 in feet) Centrifugal force end shear (Eq. 6 Plate A) 16850 Centrifugal force impact 12140 Total end shear = 418165 The web is taken with a depth of 84 inches End shear 418165 divided by 13500 (shearing resistance of one square inch of web) '= 30.9 square inches = net section of web necessery to resist the end shear. The number of rivets necessary to resist 418165 lbs. in bearing on 1/2" web plate = 40. Use two rows of 7/8" rivets and assume web with thickness of 1/2". Then net section of web * 84 x 1/2 - 20 x 1/2 (rivet holes 1" in diameter) = 32 square inches. Bead load bending moment = 1/8 w 1° where 1 is length and w is load in pounds per foot. . . . 1826900 Live load bending moment (from tables for Cooper's Class E-60 loading) 1852000 (_300__) Impact =(300+L ) live load bending moment 1550640 Centrifugal force bending moment (See Eq.7 Plate A ) 208100 Centrifugal force impact 17