d. I" n~8 r. 1 I:- .. \ . .4 Q 1 . .o I...1 .w 2.... u g 3 m. a .V.\% Wu.) .U J. - § \ l4”. iv:- k5.» .3 h u... b aw... ... a h.“ ......w .u “.... “luv. 31;... fl .N ,w o4.8 .» L N z” 4 I . . ~ . u“ : . H u. 2* 31” .n x . ....‘ifi. ‘ a g ‘ ... \1 2 i .V a. n a . U I x . c u ‘ .o wu‘ N . e fa \N V; 1.. .vi g . .q \ rw. 9 .. w u L k .V- a, ' M1.” A ..- n. ‘ \ x t.“ 7-. .1H.W...u : wk le:\| . I ...! . 7'5 ...“. O G.” $ Q. 6. smW . o. ‘ . . . ..x... .. M: . Ac ..fl . . .. «4 ‘K6 '.0 ‘4. ‘. ‘\ ‘U V,“ v .r A. .‘l ... ...‘o. L| I out u n u .o I HI. ‘X 5‘ .. Ne; .. . i u \ u ‘ . ‘ .‘o. o .r - (S )5 M I 7.. V.) .. . ‘ noa \‘ .1 . \I‘N : W . o ..V... L . v.— r . , .8 3-. Lu. 4 c... v. a . . “\d .... . .. ... c .MV .....‘ \. m. In} . - a a: - o . . .1 Qt o . .‘ 1 My .\. ‘ \. m O .1! 015%.” his . . V ...fi ... . . o 4“.“ .9» re Ki“ v-74... ’ v. v1 . I . .4 .2 L“ k v: ‘ . A! I \_ V.- “w“ . ‘Ioo ...? ‘3 \ a a r ‘4‘ .h d. ‘ i J. - a. . ’2 . \ V I; 1 o f‘ \ E? a v. . .- .o .~ L d. b . 1...... . o ‘ 4\ $5.. r..\ .N u . ‘ g .. ... .u. ., . .. u . . v ‘v H... J; r c ...{H 105‘.& \ ‘ut o. I . .1 O A LJ‘ L .n K ‘ . \.‘ 0 NW. .. \. . “\ws, 0 H .\ .Q o u. 9:. no IM‘“ » I a fi 4‘ . 0 xv”. ' fl;2‘___:_______:A_+_Z_E__:_:___E__ 1H 5915-5 IIIIIIIIIIIIIIIIIIIIIIIIIIIII Ml!”1|“Hull”1H”ll”WIIWIIIWIIHVII”ll 31293 00180 3851 MICHIGAN STATE UNWERSETY UBRARV -_ “ , M w l ‘ JA/ C ‘ CAL-/é (“/L ’L/L 4 MICHIGAN STATE LIBRAR UNIVERSITY v TRANSFORMATIONS 0F ELECTRIC NETWORKS BY MATRICES: CASES OF INVARIANT POWER, NON—INVARIANT POWER, AND INVARIANT INPUT-IMPEDANCE By SAKAE mmum A Thesis Submitted to the School of Graduate Studies of Michigan State College of Agriculture and Applied Science in partial fulfillment of the requirements for the degree of MASTER OF SCIENCE Department of Electrical Engineering 1951 Chapter I. Chapter II. Chap ter I II 0 Chapter IV 0 Chapter V. Chapter VI. Chapter VII. Contents Introduction Derivation of Generalized Transformation Equation necessary and Sufficient Conditions for Invariance of Power Two Kinds of Transformation Matrices Invariant Transformations {on-Invariant Transformations Transformations of Invariant Input» Impedance Page 18 19 Chapter I. Introduction (1) (2‘2) Kron published many papers and books about matrix treatments of electric networks. The core of his works is congruent transformations, which are ex- plained in mathematics hooks(4)and the books by Guil— (5) (C) lemin . Congruent transformations keep quairatie forms, such as electric power in the case of electric networks, invariant, when transformation matrix is non- singular. In this thesis the author deals with both invariant and non-invariant transformations, and defines necessary and sufficient conditions for each case and the valid range of applications of each of them. Although almost all examples are by mesh methods, the same discussions hold for node methods. In Chapter VII transformations of invariant input- impedance are discussed. These are actually reduction of electric networks to Foster's equivalent forms. This process by usual methods(5)is very laborious and tedious. By using the matrix treatments, which are axe plained in Chapter VII, this process is made orderly and less tedious. This papaer is written by the author as the thesis for Haster's Degree. Professor J. A. Strelzoff taught the author matrix treatments of electric networks and made it possible for the author to work on these subjects. To Professor J. A. Strelzoff the author presents his sincere thanks. Chapter II. Derivation of the Generalized Transforma- tion Equation The equation of a electric network can be written in the matrix form of [9] = [Z] [1] 2.1 Now we change current [i] into new current [it] by the transformation equation [1] = [A] [1'] 2.2 Substituting 2.2 into 2.1, we get [e] = [z] [A][i'] 2.3 Multiplying 2.3 by a matrix [B], we get [31b] = [s] [z] [A] [1 '1 2 . A In the process of deriving equation 2.4 we change voltage [e] into new voltage Esq 'hy the transformation equation' [e'] = [Elm 2.5 From 2.4 and 2.5 we get i [6'] = [21sz [1'] . 2-6 Let new impedance matrix for new voltage [e'] and new cur- rent [1'] be written [2'] , then [a] = [20 [v] 2.7 From 2.6 and 2.7 we get [2'] = [B] [Z] [A] 2.8 So we can conclude as following, When current [i] and voltage fie] are transformed into new current [1'] and new voltage [e'] by the transfor- mation equations 2.2 and 2.5, the new impedance matrix [Z{] for the new current and the new voltage is given by 2.8. This is the generalized transformation equation, which contained congruent transformation [61.3] [C] as one special case. Chapter III Necessary and Sufficient Conditions for Invariance of Power To reach transformation equations, Kron started from tho assumotion that power is invariant, th:t is, powers at each impedance branch of new system are equal resoectively to those of old system. And he got the follow- ing results. When current [i] is transformed into new current [ii] by the transformation equation [1] = [CM] 3.1 and voltage [e] is transformed by the equation [e'] =8 [C1,[e] 3.2 , than impelance [Z] is transformed by the transformation equation [2'] : [C1[L][C] 3.3 * From his whole book it Seems that Kron thinks thet 3.1, 3.2 and 3.3 are the necessary and sufficient condi- tions for invariance of power. But it is not correct as explained later. When we compare these equations with 2.2, 2.7 and 2.8, we see that [A] = [0] [B] = [‘31: 3-4 ...... From what Kron derived, we can see that the equations 3.4 are the necessary conditions for invariance of power. But it is not yet clear whether these are the sufficient conditions, too. Let us examine it. Power for the old system is given by P: [9}: [1] 3' 5 And power for the new system is niven by P = [eatfl'] 3.6 From 3.1 we get [v] _= [c]~l [1] 3.7 From 3.2 we set . [6']. = ([0].; [9]), = [e]t[C] 3.8 By substituting 3.7 and 3.8 into 3.6 we get in =[e1.n[c1"[11 =[e1.[11= P 3.9 50 power is invariant for this transformation. This tyne of transformation is called congruent transformation. It seems true that 3.4 is the sufficient condition for invariance of power, too. But this is not sufficient. In the process above we used[CI1 in the equation 3.7. So[p] must be non-singular. ’ Then we can conclude that the condition 3.4 and non—singularity of the transformation matrix EC] are the necessary and sufficient conditions for invariance of power. Here there must be some comments about the statement 7) by Pipe that the transformation matrix [C]( Pipe usesfh] ) need not be non-sinaular. But he insists that only the shape of the enerqy eouation (not the numerical value itself) is preserved under the transformation by 3.4. In order that not only the shaoe of the rncrgy equation but also the numerical value of the enervy are nreserved, non-singularity of the transformation matrix [C] hast be ended. Chapter IV Two Kinds of Transformation Matrices C . To set up sancaicai equations of electric networks, Kron started from their nrimitive networks. For Example, Fig. 4.1 a) is the prinitive network for Fig. 4.1 b) and c). m (c) These are ailinesh.u networks, because they have as many meshes as number of impedances. In these networks all emf's in series with each impedances are short-circuited. So each current in each impedance is not changed by changing interconnections as a), b) and c). In this case power is invariant for these trasfoemations. Let's find the trans- formation matrix [C] between Fig. a) and c) by assuming reference currents indicated in the figures. 10 In imoedance a“_ TL: - fg- id-14' " z... 1" = - 1" n z... 1‘: 1"+ 1’2. 1‘“ 4.1 2“ 1*: . i" I "w- 1*- 1" From these equations we get the trnasformation matrix C a’ b’ c’ d' f' [c]: a ”.1 o -1 -1 0‘} 'b O O -l 0 0. 4.2 rLo o 0.10 The matrix 4.2 in non-singular. Equatifin 4.1 and matrix 4.2 give the correspondences between old currents and new currents. And their corres- * pondences are not only geometrical or positional but also numerical. * Geometrical or positional correspondence means that corresponding currents flows in the same impedance of the network. Nemerical correspondence means that values of these corresponding currents are equal namerically. 11 In 80m: cases correspondence is only fcomctricel, tut not i- J. numerical. Luch case: 'rn crylt nri Eczer. All tran:f:rratien matrice: should be qeemctriCLlly corresOOuecnt. int {may nec‘ not b; numerically corresnon- dent/o Let's examine enother simnle example. 1 z... 1 2..., 2..., LA 25... z... wad (a) (h) Fig. 4.2 a) anl b) are the Lane network, rhich has two inde— pendent mcrhes. In a) T‘ {n1 1b are assumed as indenendent, while in b) fiend id are assumed inieoendent. Only difference in the difference of reference currents. Cor905fiondences of these currents are, If} -? o; ‘ f‘ a - g In impedance a,“ i a i -r‘- r’ H In impedance Z», 1" 12 So the transformation matrix is / I c [Cl = a l o 4.3 b -1 -1 This is a nonésingular matrix. And the correspondence by [1] a [c] [1’] 4.4 is not only geometrical but also numerical. We have Just examined two cases, where transformation matrices are non-singular. It may seem too early to conclude that all non-singular transformation matrices are correspon- dent geometrically and numerically. But this is true. We get non-singular transformation matrices, only when transformations are not accompanied by any change of interconnections of impe- dances. For instance. the transformation of Fig. 3.2 does not have any change of interconnections of impedances. It has only change of reference currents. So all currents at all impedamce branches are invariant at this transformation. Accordingly the transformation matrix for this case is corres- pondent geometrically and numerically. Transformation matrices for tansformations between different independent reference variables of the same circuit are generally non-singular and corresponding geometrically and numerically. 13 It seems likely that the transformation of Fig. 4.1 is accompanied by changes of interconnection of impedances. But all impedances remain short-circuited even after the transformation, and the mumber of meshes remains the same. All currents of imnedance branches remain the Same. So that the transformation matrixIC]of 4.2 is non-singular and correspondent geometrically and numerically. Here we can conclude that all transformation matrices for transformations, where the number of meshes remains the same, are non-singular and correspondent geometrically and numerically, so long as all reference variables are indepen- dent. Let's examine the transformation of Fig. 4.3. " l T )< a- 2“, z“, a: z“, 2-“ 2“,, 'z.cc ea, eb ec. e4’ e5 an. (L) as ) F3}. #;3 (a) is trasformed into (b) by opening one impedance branch 25,. Reference currents are assumed as indicated in the figure. 14 Then the correspondence between old and new currents are 1" ---)~ 1” . 4.5 1" -—-> 1/ So the transformation matrix is 1/ [p] = a 1 4.6 c -1 [C115 singular. It is easily understood that power is not invariant in this transformation. 50 it seems likely that cengruent trasnformation [0142] [C] can not be applied in this case, because Kron proved congruent transformations by assuming that power is invariant in transformations. Let's try to apply it to this For Fig. 4.3 (3) ea_- eh: (Z...+ ‘2“)1‘4» z“ r- 4.7 6&- 8": z“ 1‘ + (255+ Z»)? This is written in matrix fern as below. ’ [e142] [1] when. [a]: at — eh [Z] = Z“)- be 2“ 8e. - e 255 255+ ZG 4.8 [11 = 1‘ it I According to the congruent transformation, new matrices for 15 the new network of Fig. 4.3 (b) are given as following. [0M2] =[1 -1] z“ + 2“ z“ = [2“, - 2%] 2..., Z» + Z“ [2'] =[CJt [z] [c] = [2... - a} 1 = [2“, + 2“] l . 4.9 a]: [alt [e] = [l 4] e.. - lie. - e4 80 for the new nctuork the equation of network(e1 =CZ][ij is e - e = (:4M + z“)! 4.10 a. Ce This is valid as easily seen from Fig. 4.3 (b). SOECIt[Z] [C] method can be applied even for the transformations, where power is not invariant. And this foot is already proved [by equation 2.8, because we did not assume invariance of 'power to derive equation 2.8. But some limitations are necessary for applying 2.8 generally,as explained later. Here we would like to call attention to the fact that equation 4.5 does not hold numerically, but it does hold only geometrically. So "-—9" is used instead of "a ".there. Transformation matrix 4.6 indicates only geometrical corres- pondence between old and new currents. So it is not correct to use[i] =[C] [i'] to evaluate one currents group from values of the other currents group, which are already solved. 16 It is ini*res%inr that consrucnt transformaflisn can he cwpliofi even to casrs whore transformatihn Nitrix is corresnonjont only *eametrically but not numerically. Transforrt?ions, which chance number of imncj"nce breach ;, are acccm“znfed by transfernation wztricvs, which are sinvular. In Rhese cases, pose is not invariant and '1 transfornation matrices are ccrresncnient only rennetrical y, ‘L but no‘ numrrically. As showed shove, congruent *rsnsfernr‘i‘n can to t filifif *o this 0:50. Put numlar n? imna‘1rcn branches 53 ul? Fw chznrmV in'c lezs number. (thermise tkis - riefigmi C'IXI ? la” a fixlinfi. l. ?r{WSfC?HLt10n netrix for transformatirns, which are not t-.CCv.:m 1.9-; tied by chat". 63 ff” number at" imnaziar‘ce ‘ , ' ‘ I g . ~‘ U “113;: .95, {ST‘C “On-5;” fl... LLI‘. ;. non-sin'riar transformat'cn matrices are corros- O J nnnnt fecnntrically ann numerically. *rnation matrices fer transformations, which are accem~anie by channe of number of imnejnnce branCPQs ( into Smaller nutter), are sinrular. 5. 17 Singular transformation matrices are correspon- dent only geometrically but not numericallv. In this case newer is not invariant. But still [0M2] [0] method can be used for singu— lar transformation matrices. But we can not evaluate [i] from [1'] , using [1] = [c] [1'] .. 18 Chapter V. Invariant Transformations. is exnlained in Chester III, the necessary and sufficient conditiots I‘or invariance o- Dower are [A] = [c] [B] = [c],: 5.1 And [9] must be non-singular. In this case formulas of transformation between old circuit ecuation [91“[2131 ‘5 . 2 and new circuit equation [e'] = [2'] [1'] 5.3 are given as following. [1] = [c] [1'] 5.1. W [cit] 5.5 [Z'l= [CL [21E] 5.6 Because [C] is non-sin ".Ult't, [1'1= [CM] 5.7 he can evaluate [i] from [iq, using 5.A, beceuce 5.4 is corresoondent numerically. (1) Host of examoles in Kron's book are invariant transfo nations, althoufin some non-invariant trans forma- tions are mixed, without explanations. So it is not neces- sary to present here more such examples. 19 Chapter VI Ron~invariant Transformations When at least one of the nece.sary conditions for invariant transformations is not satisfied, the transfor— mation is non—invariant. Power is not kept invariant at this transformation. to the sufficient condition for non- invariant transformation is ; l. [A] = [c1 an; [B] a [ch are not satisfiei. or 2. Transformation matrix [C] is sinwular. Accordin? to which necessary condition for invariance of power is not satisf'ed, there are several kinds of non- invarinnt transformations. (1) Cases where [A] 2 [C] and [B] = [Clt are not satisfied. As derived in Chapter II, when old and new variables are related hy [i] = [A] [1'] 6.1 [eq 3 [B][bj] 6.2 , the new impedance matrix [Zflis given by [2’] = [B] [z] [A] 6.3 So lens as transformation equations (.1 and (.2 are numeri— cally correspongmnt, [A] an?[3] can be arhitrary. Numerical 2O corespondences of 0.1 and 6.2 mean that matricesfiflland [S] are non-singular, as explained in Chapter IV. Let's show several examples of this case. T Z“ T Z“, Z“. t 2A4. 25" T 2“ Lo- . Lb ie’ 25' ea. eh ea, eh. Cg, cc (1) ( 5) Fag. A. 1 The network of Fir. 6.1 (a) gives the followina matrix equation. [e] = [Z] [1] , where E6] = at - eD L. - .J [1] : 1'~ 6.5 is [Z] = Z... + 2.. z“ 2... 255+ 2“ Now if independent variables [1] are changed into [1d, which are indicated in fig. 6.1 (b), then the transformation ma trix [C] is L.) 21 [c] O 6.6 N 0‘ m I. ...: I H Here we choose [a] = [c] and [B] = [U] 6.7 , where [U] is a unit matrix. Then [2'] = [51(2) [A1 = [Z] [c] = ”2&4- z“ 2.. "'1 0 Am fi*‘+ an .1 -l = " z» '2... 6.8 L‘Z.5 “(255+ zcc.) [e'] = [B183] = [e] 6.9 So finally we get as [8']: [Z'Hi'] _ I ea- - 8‘ 3 La. - Z“ 1“ , 6.10 eb ......c -2... -(z..,+ z“) 1‘ Fro. 6.10 we get 4 e.(z..+ 2..) - e.z.. - ex... 1 z zaazbb + zbb zen. + Z“. zap 6.11 1 4‘2“; - ebzmi» e¢(ZM+ Z») r = z+zbz+zz 5b 5a cl. 0.0. 22 Now let's use the usual C Z G method. Then to]. [Z] [c] = 1 -1 2 -Z.. ‘4— 0 -1 Jab-(2,32%) = The 2.. 2.. 255 255+ Zc [C]t[e] = . 1 -1 at - e, = €.' eb -e,+ s. {.0 finally we get as [an = [z'] [1'] [e '1 1 ea, - ab = Zu‘i' Z.” Z” 1‘ 6.12 -eb+ ec Z“, be+ L 1d From 6.12 we get ' eav( zbb+ zen.) - glazes". 80..be i‘ a 2.12.“? szufi’ sz‘b 6.13 1Q, .90.sz- ebzmm" oc.( za~+ 26b) 3 ZuLZH;+ ZHDZR_+ Zu’fiub Final results of both 6.11 and 6.13 coincide with each other as exnected. To reach the final result 6.11, we used [A]:[C] and [B] = [U] . To reach the final result 6.13, we used(}] = [C] and [B] = [Clt . So in the latter 23 we must handle more operations, such as [CL [2] [C] and [Gide] . In the former method we can omit these operations, so it is much easier to reach the final answer. This is I ” so simple case that difference of amount of work involved in both methods is not so great. Let's show another more complicated case. 4:3 . \‘Jbb (a) 133. 6.2 In fig. 6.2 there are given circuits of Wheatstone's bridge. At first independent currents are riven as indicated in fig. (a), and then circuit equations are given as holow. r “t. ” - 91 a .. z + 2m + z“ -2“ - -2“, F1 3* a 6.14 0 -2“ 2.2+ 2“ + Q. -2” 1" _o_ L..th .2” 2.. + Z... + 2,5 _1"4 To get the balance condition of Wheatstone's bridge, we nust get current in impedance Z” . So let's assume 1P , ifiland 1‘, as new independent currents, as indicated in fig. (b). 24 Then we get tTe transformatijn matrix [C] f0 3' a! [C] = g r-0 1 01 a O O 1 6.15 bL—l o l .1 Assuming [A3 = [C] and [B] = [U] , we get I ’- . ‘1 [z] =[z] [c] = z“, zfi+ z“ + 23‘ -(Z.. + z“) L-(ZH, + z“ + a) .2“, Zn. + Z“ 80 we get new circuit equation as below. 'e,'= '2‘“L Z”+Z¢+Zu 42;,4-52111‘“ o z” -21 2.1+ z“, 13’ 6.17 1.0.. L‘(Z* + Z“ + Z# ) '2“ 2"" + 2‘4. 111 From 6.17 we get I e (a; Zn.” Zuvz,‘) f = ’ 6.18 D D = z 2W2“ + 2.12.... 2,3 2.12... 233+ zwzm zw+ zuz“ 2,, + z“ z“ z” + zwzuz”; 2,“,2fl 2” + zzzu+2k2hzfi+zzz+z22+ ob as up u. 5’. W Mr.”- 2‘2 2 + z‘gzuz + 2. 2,7,2”; zuzfi z” ”19 33 “' From 6.18 we get the well-known balance condition Z Z Z Z 6.19 av ii- 55 (c, Now let's try the usualUCL [Z][C] method. [2'] = [01 [z] [:1 _ . o o -11 ’ z“ 2,, + zm + z“ 42.. + z-) 1 o 0 2+, -2“, zm+ zm Lo 1 lj L-(Zu. + Z“ + Z” ) -Za 25.3" Zn 1. =fi'2‘b+-zu_+ g” Z...L -(ZH,+ 2&1) 1r Zn: 2.3, + zcc + 2-,, --(zcc + z“) 6.20 -(Zu.*' z“) 4ch + Z“) Zai’ Zn. * 3.. + Zak [9'] = [(3]t [a] = —O O --l" To; 3 P0 '1 1 o o o a, 6.21 0 1 1 0 0 h— -L _ —1 L- -L Now we can set up [6'] = [2'] [1'] 0-1: 2H: + 241+ 2,1 Z“ —-(be+ z“) W ifl 8.} Z“ 233-+ 22¢ + Z“ '(zcc + zit) 1" 6.22 L0 J L-(bef z“) -(zu + z“) z“. z» 1 Z... + Mir/l From 6.22 we get the same final results as (.18, which proves validity «[2] [c] mehtod. [z] [c] method does not involve operations 6.20 and 6.21, so it is much easier to get final results. Sometimes circuit equations are set up, but some 26 terlinals of emf‘s are not accessible, so these emf's can not be measured. In such a case we must change enf's, which appear in circuit equations, into other emf's, which are accessible. Let's Present one example of such a case. Pea: 6. .3 For the network of fig. 6.3 circuit equations are given as below. =3 at - e 3 Zn I -Z 1" 1’ " 5" b 6.23 3“, a o,L + a, Zu+ Zcc 2.. i To use 6.23, no load voltages between terminals 1-8 and A-A' must be measured. But it is possible to measure no load voltages between A-A' and B—B'. Then voltages must be transformed into measurable no load voltages between 14' and 843'. No load voltage between A—A' 9M = a“. + co 6.21. " B-B' ow: ob + ea 27 The relations between old and new emf's are e~v = e + e = 0 1 e a. a a. -e,= O 1 cm3 shy e + e b C a. So transformation matrix [B] is [B] a O l 6.26 -l 1 Then if assumed [A] = [U], [2'] = mm = o 1 zu’ —z.,., -1 1 Z-“+ Zcc Zcc = ZML+ %. Zn 6.27 -zct 256 + Zea. So we get new circuit equation form 6.25 and 6.27. A. 3.. + e: ZM + Z“ Z“ i 6.28 e. + e -Z.. Z». + 2.. 1" This equation contains only measurable emf's, so we can evaluate currents by solving 6.28. This is the case where [A] is a unit matrix and [B] is trnasforaation matrix between old and new emf's. Sometimes we find that a given circuit equation is not adequate, because some of the emf's used in the equation is not accessible and cannot be measured, or because we want 28 to use other independent currents than those used in the given circuit equation. In such a case we must transform both emf's and currents used into other independent emf‘s and currents, which are suitable to our purposes. Then old and new variables lust be related in some way. These relations can be expressed by [11 = [11 [M 6.29 [e']= [B3 [6] A 6.30 Generally [A] and [B] are not related by the relation [B]: [LJt as is the case with congruent transfbrnations. Let's show one such example- For the network shown in fig. 6.4 (a) a circuit equa- tion is set up as below. 29 ”a” - e: = ”z“, 4.. o o 1 ’1“ ea - ed. 0 0 Z“ -2“ 1b ' 6.31 ea, z”) Z.” + z” 2“ + Z” Z” Z” i d. _3a. A _za% 23%- 223 24d- + 234‘ L1 But four currents, which are indicated in fig 6.4 (b), are wanted. And four no load voltages, which are used in 6.31, cannot be measured, but four no-load voltages between 1-2, 4-5, 2-3, and 5-6 can be measured. These four currents, which are wanted, and four measurable no-lcad voltage are assumed as new reference variables. Then relations between old and new currents are, i°' I i" 1" = 1‘" 1° a .1“ 4'” 1‘ a -1“ -16 So the transformation matrix [A] for currents is, [A] a F 1 o o 0'] 0 l O 0 6.32 -l O -l O o -l 0 -lJ _ Measurable four no—load voltages are, = 6a,... .. eb - 2-. at 3 ed Fem - e:]= -- 0 eb - e.i -l ec_ 0 fat I. L0 -1 O .l O l l O 0 .fi -1 l l 6-33 - e ‘L 6.3!. So the transformation matrix [B] for voltages is, [a] = 1" o .1 -1 o 0 1 L_o o l 1 0 0 .17 -l 1 l — 6.35 Impedance matrix for new variables is given by [B][Z][KL that is, [z] [A] = o 7 _1 -2... o 2,, -1 zu+ 231 L0 30 005] 100 0.10 .104 [B] [Z] [A] = fl 2.1 -25., 0 ~an 24¢ -l.._ z“; z” z” -2” Lo .z‘.‘L -2” r 2.1 + z“ + 2;} ZH -Z.. __0 31 So the new circuit equation, which is suitable to our purposes, is given from 6.34 and 6.36 as below. 3 " Z“; 2,“ + Z” 2,, 7m .2cc o o -2“ zbb+zd+gf o Zcc O z... -(zcc + 23% ) -283, .2 .(de+ 233. a? 6. 37 We can check easily validity of 6.37 by inspecting fie. 6.4 and 6.37. All exanoles in this article are the case where the condition [£043] and [B]=[C]t are not satisfied. 0 T Z... “23% -(Zdu- Zeal z” 2.. o Zhb+ Zm+ Z” O 244. o -(zu_ + z ) J” ‘2“. - z” -(ZM+ .. 6.36 ] 32 Here it should be emphasized that both [A] and [B] are non-singular and give numerical correspondences between old and new variables. Sometimes [A] or [B] is a unit matrix, which is apparently non-singular. Cases, where [A] or [B] is singular, are treated in the fellowing article. (2) Cases where transformation matrix [C] is singular. In Chapter IV we explained that transformations, which changes number of impedance branches, are generally accompanied by singular transformation matrices. And singular matrices relate old and new variables only geo- metrically but not numerically. In Chapter III we expalained that power is not invariant even when [CLfZ] [O] transform- ationis used, if'[C]is singular. Let's show examples. ._, Ly IF—e F e 9a.. ec ea- l )< '23).» 1 Zoe. L2”. 2.5:, ,2 Zoe ed (a) (b) i 33 The circuit equation for figure 6.5 (a), which is the same as figure 4.3, is e... =3 Z + Z 25', Le" a bb (1.28 Lo at 2H, be+ zcc In figure 6.5 (b) branch of §~is broken, and one new cur- rent if is enough to describe the circuit behaviors. Then the correspondence between old and new currents is lk-d’ it 6.39 1 4 ~31." This is a geometrical corresuondence but not numerical. Be it is numerically wrong when we write [i]: [CJIiflas below. I i 1 i1 6.40 if -1 ‘ So it seems wrong to use the C Z 0 method for this case, because we use numerically wrong equation [1] = [CJ[1q . But it was already shown in Chapter IV that the [CLIZIIE] method is valid even for this case. Let's try here once more. 2] [C] = z“; z z 1 = 2... L "" b” ‘ 6.41 34 [2'] = [chm m = [1 .1] _ z.“ = [hi 2“] 6.1.2 L.zct. [e'] = [OLE-#1 = [l -1] 9J3 [9..." cc] 6.43 92‘ So we get as the new circuit equation, e - 9., = (Zn-0’ Z“) 11’ 6.11;. O. This is evidently correct for the circuit of figure 6.5 (b)- Next let's try the case where [A] = [C] and [B] is a unit matrix. From 6.41 we get the result at once. That is, eUL 3 thvgfij 6.45 ea ~Lm Expanded we zet, e 8 QM‘11’ I 6.46 e = -@m 1‘ This is evidently incorrect for the circuit of figure 6.5 (b). Next let's try the case where [B] = [CLrand [A] is a unit matrix. [Olin] = [1 '1] Zao-+ zen, 2'56 3 [2a - Zea] “ 6.47 z z + 2 H. H, cc 35 From 6.43 and 6.47 we get, _ L (e... - g- [2.0. - or] W That is, at - eb = an 1L - ZULic 6.49 This result is not wrong, but it is not adequate to solve. the circuit of figure 6.5 (b), because it contained two currents for the one-mesh circuit. Let's examine the case where a 3-meshes circuit is transformed into a 2~mczice'circuit as shown in figure 6.6. I X L am. is ca is da 85 “. 2%, 3; z“; 2“ at a; Eh. 2‘ . f m (a) Fig, 6. l, The circuit equation for figure 6.6 (a) is “a: 3 [2“) z» 7‘5». 2% _ Vivi ea 21* 255+ a 2H, 1" 6.53 _o _L 1 2“, 2,, 256+ 2,, 3* 36 In figure 6.6 (b) branch of Z is broten and new currents _ be are assumed as shown in the figure. Then geoxctrical corresponcences between old and new currents are given by ’fi='1 0'1 1" I 1° 0 1 1‘ 6.51 1“ E1 .1 b - Equation (.51 woes not correspond numerically. From 6.51 we get a singular transformation matrix EC] . [c]='1 07 o 1 6.52 _-1 —1_ Then 2] [C]_== '2”; z“, z“, z.,., l" 1 o“ z... 2.5+ z“ 7..., o 1 _z... z,,,, . 255+ 24$ _.1 -1_ 2 F2“, 0 l o z“ 6.53 -Z.u .zu_ [z']=[01t[z] [c] = z“; 2...; 2M 2M zc‘ + 2“ 37 [e'] = cue] = 1 o -1 ”9;: 1., - 6.55 O l -1 8L ea —O-‘ 80 we get as [e'] = [Z'] [1'] ea. z“_+ g, z“ 1“- I I 6056 8c 244. ch + Z“ it This result is evidently correct for the circuit of figure 6.6 (b). Next let us examine the case where CK] = [C] and [B] is a unit matrix. From 6.53 we at once as the new circuit eduatiou, "eja ' z“, 0T1“ e. 0 1a 1" 6.5 L9.. L‘ZEL “zed This result is eviiently incorrect for the circuit of figure 6.6 (b). Let us examine the case where [B] = [Ck and [A] is a unit matrix. 38 [0M2]: 1 o .1 _zu+z» 2.. 2.. ‘1 o 1 .1 2., zm+zbb z“, Us 2., z“, + 24 = z“ o .2413 6.58 O Zu_ —Z&L _ From 6.55 and 6.58 we get as the new circuit equation, eL = Zap O - Did] a. o z“ .2“ r’ 6.59 1" ‘ That is, a z 1" z 10” e” ”’ ,- ”L 6.60 qL=3 Z“ i‘ - Zagr“ This result is not wrong, but is not adequate to solve the circuit of figure 6.6 (b), because it contains more numbers of reference currents than numbers of independent meshes. From two examples above we lay conclude for the case of singular transformation matrix DC] as following. (i) The method of '[e'] 8 [01b] , [i] = [C] [1'] and [z']=[c1.[Z] [c] . is valid. 39 (ii) The method of '[e']=[e'l, [i]=[C] [i'} and EZf] = [Z][C]' is wrong. (iii) The method of '[e'] 2 [C1,[e] , [1'] =[i] and [2f]: [CL[Z] ' is not wrong, but is not adequate for solving the problems, because it contains more currents than numbers of independent meshes. It seems rather stranse to reach the right results of (i) and. (iii), even when we use the numerically wrong relation [1] = [C] [i'] . Let us consider the reason. for it. In the method (iii) we use [o']=[C]t[e], but do not use [i] = [C] [1'] . And it is easily understood from the two examples above that [e'1=[C]¢[e] is numerically correct, while [i]: [C] [i'l is numerically wrong. In figure 6.5 (b) the new mesh emf' e' is e' a eL- eL 6.61 , while [Clerc] =8 [1 ~12] e = [9... — ea] 6.62 a . From 6.61 and 6.62 we see that [e'] = [Ck [e] is numerically correct. finother thing, which should be emphasized, is the fact that all emf's, which appear in matrix equations, are AO mesh—emf's. Hesh-emf's mean that they are emf's which act around closed meshes. Then we choose new emf's for transformed circuits, we must choose mssh—emf's. The transformation [e']=[C]t[e] gives automatically mesh-emf's, as new emf‘s [e’] , because [B] = [Ch is a transformation * matrix between old and new mesh—currents . And even when ‘* Here it should be stated that branch—currents can be considered as mesh-currents, so long as these branch- (8) currents are independent. [11 = [C] [i'] is correspondent only geometrically, Le') =[Clt [e] is correspondent geometrically and numerically. This is‘ the reason why method (iii) gives correct results, while method (ii) gives wrong results. When we applied method (ii) to figure 6.5, we got 6.45, which is wrong. In 6.45 emf's are not mesh-emf's, but branch-emf's or open emf's. So it is impossible for them to give correct circuit equations, which are actually the Second Kirchhoff's law. Pre-multiplication of [231:0] by [Clt is equivalent to transforming of open emf's into mesh-emfs, and it sets up the Second Kirchhoff's Law correctly. So method (1) gives correct results. It is not necessary that [A] = [C] and [B];[Clt are satisfied, to reach correct results. For instance, in method (iii) [Blsfclt and [A] is a unit matrix. fie can use any transfbrmation matrices [A] and [B] , so long as [i] = [A][iT] gives geometrical correspondences between old and new independent currents and [eTl=[B][e] gives geometrical and numerical correspondences between new and old independent mesh-emf's. Let us apply the case where [B] 75 ”[A]{ to figure 6.6. We assume that new currents are the same as shown in figure 6.6 (b), but new emf's are those acting meshes of 2...," Z“ and Z“: d, . Then [9'] =[B] [e] is ev-ecz 1 -1 0 To: em - O l O -_ eg 6.63 l—no-J [Zlfl] = [Z][C] is given by 6.53. Then [z']=[31[21m= 1 -1 o z”, 07' 1 o .1 o zcc 3 zeal. .ZCL 6 0 6'4 ZW+ 24¢ de From 6.63 and 6.64 we get as the new circuit equation, I 3., " e. 3 Zea. .2“; 1L , 6. 65 ea, Zola—‘- zdd. Zr“. 1‘. It is easily seen from figure 6.6 (b) that 6.65 is correct. Here it shall be mentioned that we must be carerl in setting up [e'] = [B][e] as shown in 6.63. That is, when there is no emf in some branches, some simbol (here we use 0) must be substituted to get the right [3), 'Ve Now we can conclude about transformations by singu— lar matrices es felling. (i) The method of n [e'] = [c149] ,[i] = [01(1'] and [2']: [C]J2][Dl “ can be used correctly. (ii) The method of ' [cf] = [Blfe] , [i] = [A][ii] and [2C] 2 [B][Z][A] " can be used correctly, so lonfi as all emf's and currents assumed are indecen- 43 * dent mesh—emf‘s and infependont mesh-currents. (iii) The method of " [1] = [C][1€l and [2f] = [Z][C]” is not correct. (1v) In all cases powers :r: not invariant. * Breech-currents can he considerei as mosh—cur— (8) rents, so long as these branch—currents are indenenflent. Chapter VII Transformations of Invariant Input- Impedance. So far "Invariance of Power" has meant that not only input-power at terminals but aISo all powers consumed or stored in all imoedances are invariant. But at some practically very important aoplications of circuit trans- formations only input-nower at terminals and consequently input-impedance are kept invariant. Transformations between equivalent circuits are the case. So far transformation matrices contain only integers as their elements, mostlyizl or 0. But transformation matrices of invariant input—impe- dance can have non-integer elements as shown later. Here it is not attempted to discuss whole asnects of transformations of invariant input-impedance, but one interesting example is to be explained; that is a new method of reduction of networks to their Foster's Forms by means of matrices. As Guillemin explained very nicely in his book, any dissipationless network can be reduced to four equivalent canonic forms, which have least number of elements. Two of 45 them are Foster's forms and other two are Cauer's forms. Reductions to Cauer's forms are easier than to Foster's forms, because amdular determinant (or its minor) must be solved, to reduce to Foster's forms, but it is not necessary for Cauer's forms. Here let us try other approach to Foster's forms. 69%: fl Ts” T ¢ -“n Fia.‘1 1 Figre 7.1 shows one of Foster's forms. Independent currents are aSSumed as shown in the figure. Then the circuit equation is, "' ' '1 «fl: L.A+S——J o .o W 1" e’ o LzA-‘I'LSXz' - -. - o 11’ 7.1 I 5.. u, Led L o o - - IAN-71E .4. ..L... , where k‘dt’ A-j alt. 46 This equation has a diagonal or normal forms. So the inductance matrix [L] is, [L]="L, o o-H-o 0 L1 0.00.0 7.2 O O L300000 L-—O O OOOOOL’L The susceptance matrix [S] is, [51:75. 0 o-°--o1 o s, o----o 7.3 o o 83 O O O O o o o 0°°°°s I.— "z... 7.2 and 7.3 have diagonal or normal forms. VJ 171_ ' I I ' I I ' 'I Fka.‘7.2, Figure 7.2 shows the other form of Foster's equivalent circuits. Independent junction voltages are assumed.as 47 shown in the figure. Then the circuit equation is, rI": rogue-r} o - ~ - - o T W," I 0 qu+§é . . - 0 V; 7.4 _I: _ o o ' ° ' QA-i'ffi VJJ This circuit equation has diagonal or normal admittance matrix. Then the capacitance matrix [C] is, [c]=’c, o o-°-ol 0 C 0 ° ° ' O " 7.5 0 O C;"° ° 0 o o 0... on The reciprocal inductance matrix fl_] is, [HAVE 0 0- - 'ol 0 r2 0. o .0 7.6 O 0 ,30000 _0 o 0' - Tn, 7.5 and 7.6 have diagonal or normal ferms, too. A8 ?hen a dissinetionless network is aiven, we Can easily write down its matrices of [L] and [S] by means of mesh method, and its matrices of [C] and U") by means of node method. And if we can diagonelize these matrices in such a way as transformed circuit equations have the forms of 7.1 or 7.4, then we can write down its Foster's equivalent circuit as shown above. Let us assume that a given two-terminal network has following [L] and [S] . [L] 2 FL” er' . . . L’J' Luv in ' ° ° Lzu 7.7 LL“. I'M; o o 0 LI": [8) = ’5” sn- - - - s": 82' S21. 0 o 0 82m 7.8 H1 tum—j Then the next step is to find such a transformation matrix [C] as [CLIL] [C] gives a diagonal form. flfltEflID] gives a diagonal form. 49 Now we can see that the problem is simultaneous reduc- tion of two matrices [L] and [S] to their diesenal forms. Guillemin treats very nicely simultaneous diaconali7a- tion of two matrices in his book.(10) But we can not apply to this case directly what is exnlained in his ‘ ck. Let us explain necessary procedures. Using [L] and [S] of 7.7 and 7.8, \XU-l + [s] I = o 7.9 has generally n roots of7\. 7.9 can be exoanded as below. AL” + S" AL,1+ 8,1. 0 0 0 KLmi- 8,,L = O KL1,+ St, AL,,_+ S2,: ' ° ' ALm-O- Sm: 7.10 5 O O I O O O O O O C O O O O O O KLM + SM KL)..." 81:; . . . Aland" Sun And 7.10 is the determinant of n set of homogeneous equations below. (RLH + §)x'+ (Mu-Ir 8,1)11‘0- . . + (ALmi- SJ)“: 0 (KI.fl + g')x,+ (AL,,+ 5,933+ . . + 0ng 5.,ng 0 7 11 (M... + ax.“ N.» sax» - . +01...» sex: 0 50 7.11 has solutions when 7.? and 7.10 are satisfied. So 7.11 has n sets of solutions for n roots ofik., which satisfy 7.9 and 7.10. But these n sets of solutions for 7.11 are not unique, but only proportionalities among each components 1,, x1, 33.... are determined. If cofactors of the determinant 7.10 for the sth root of K's are denoted by gig , then one set of solution is given by s Keg £5: ,_ 4 fl.) + (Huh - - -+ (no? (for k=l,2, n) 7.12 , where the index i is arbitrary but must, of course, be the same for all sets of.l's. Then 55:4; = a!“ (for k = l, 2, n) 7.13 satisfy 7.11, where 95 is a arbitrary constant. 7.11 can be expressed by using matrix as below. (MI-l +[S] )-[x]= 0 7.14 , where [x] =‘i,”h x1 J;E. 51 Substituting 7.13 into 7.14, we get Amfips g]: —[.81[(p5125)] 7.15 There are n equations 0? this form for nlis. And these can be combined into one matrix ecuation by defining a new matrix, which is called a modal matrix. The modal matrix for this case is, («$1, 2,; - - mi El 211. . . . [In 7.16 1;, 2h} . . . ILnJ L ,where the first column elements are given by 7.12 for s = 1. Then n equations of the form of 7.15 can be combined into [L1 [men/d = - [81(26le 7.17 , where [A] is the diagonal matrix with n latent roots of}\ls diagonal elements, and [p] is the diagonal matrix with arbitrary constnat g, g,....ntas diagonal elements. 7.17 is pre—multiplied on both sides by transpose of [£1th . then [DELHI-l [£1 [pH/U: _[flt[z1t[5][£][p] 7,13 In 7.18 [flt[x]t[L][£][p] and [p],[£]t[S][:f/] [p] are symmetri- cal, because [L].and [S] are symmetrical. But the left- 52 hand side of 7.18 is not symmetrical due to post-mul- tiplication by DA], which is a diagonal matrix, if [fikECLIL][Kfl[fi] is not a diagonal matrix. So only one possibility is that both [ply]. [1.105103] and [pltmltlbj [IHp] must be diagonal matrix(li) in order for 7.18 to be correct. That is EPMJCML] [1:] [p] = [In] 7.19 [pltfiltEE-Hflm = [Dz] 7,20 , where [DJ and [D2] are diagonal matrices. From 7.19 and 7.20 we know that [c] = [:6] [p] 7.21 is the matrix which diagonalizes both [L1 and [S] simul- aneously. But [C] is not unique, because it contains the diagonal matrix [Q] , which has arbitrary diagonal elements. So the next problem is to choose from 7.21 the proper matrix [I] , which keeps the input—impedance invariable. This proper diagonalizing matrix be desig- nated by [F]. Then the relation between old current [1] and new current [1'] is given by [11 = [F1 [1'] 7.22 53 It is easily seen from figure 7.1 that the following relation must exist between old and new currents for invariance of inout-imoedcnce. That is i =i"+1”+- . - +1"! 7.23 ,where i is the input-current of the original network, which is counted as the first mesh—current. From 7.22 and 7.23 we can see that [F] must have the form as below. [F]: "1 1.... 1'7 z” sh: . . . 13‘ 7.24 f“ f“. . . . 'fimJ _ For [C] given by 7.21 to be identical to [F] given by 7.24, [p] must be the diagonal matrix as below. [p1="'1/z.,o-----o ‘ O 1/4212. o o o o O ooooooooo 7.25 [F] =[x] [P] = r12., 2,; ' - 2,: [1, 21‘. o 0 an P _ LE,” (12,. o o ’[nu-J ‘&%Zr'éyzz° ° 66%62 EH/III [flu ' 1 1. . . . 1 T MIL-d h r-llg .‘ II o 1/,g,z...o 0.00-01/fimJ From 7.12 we get the following relation. As/«Exs 3 5 t/ x- (fl— 0 . . . 0 54 7.26 7.27 s , where Kiais cofactor of the determinant 7.10 for the 8th root of [F] = I I 2. z n. n- K-u/ Kit KQ/ Kc; . ' xiz/ Kt/ nK's. So [F] can be expressed as below. 1 l {1&1 ii, Ew/ ii, 1 it"! i}, 1' db 7.28 7.26 or 7.28 gives the transformation matrix [F] , which reduces [L] and [B] of a given network to their diagonal forms and keeos the inputcimoedemce invariant. 55 Here it should be explained that the new voltage matrix obtained after the transformation by [F] has the form of the left—hand side of 7.1. The given network is a two-terminal passive network, so its voltage matrix has the form as below. [e]t= [e o o - - - 0] 7.2.9 Then the new voltage [e'] is [e'] -.-. [rue]: F. l O u 7.30 M So we can see that the transformed circuit equation has the form of 7.1,whioh is the circuit equation of one of Foster's equivalent circuits. Now we can say that we have reduced the given network to one of its Foster's equivalent circuits. .28 is the better formula of the transformation matrix than 7.26, because calcu- lation of 7.12 is not necessary for 7.28. Let us derive here some very useful relations. Putting 7.19 and 7.20 into 7.18, we get [DJ [A] = - [Dz] 7.31 56 Three matrices containtd in 7.71 are diaeonal. So we get from 7.31, 1. ..J I -.2 ... . where c,sano assere diagonal elements 0? [JJ_nnf [Li] .I sth latent root of ecnation 7.10. (‘0 ...1 LL u? I J. .31 or 7.32: we can derive [73,] or [£32] from each. It is easily seen from 7.32 that A‘must be neevtive or zero, because dgsand d; must be both positivgt for the equivalent network to be physically realizable. That Atare negative or zero was anticipated from the (12‘) fact that [L] and [S] are both positive definite. We started from equation 7.9, where A.is atta- ched to [L] . If [L] is singular, some of K’s are infinity. But.Ns must be finite. In this case A~must be attached to [5] instead of [L] ; that is “Ll +A[s]} a o 7.73 At least either of [L] or [S] is non-singular, because these are matrices for solvine electric networks. According to whic. of [L] or [S] is non-singular, we choose 7.9 or 7.93. Otherwise the procedures remain * Including zero. 57 the same as shove. All procedures 0? reducing a given network to its Foster's equivalent form shown in figure 7.2 are the same as exuleined so far in this chapter. But in this case the original matrix equation of a riven net- work must be written by the node method, using capaci- tances and reciprocal inductances. And capacitance matrix [C] and reciprocal inductance matrix [Tflare diefionelized simultaneously. That is 7.9 and 7.33 is substituted by me] + [r1‘ = 0 or Ho] +Mr1|= o 7.31. , according to which 0? [C] or Uilis non-singular. n3 tnc Same. 7.24 remains t3? *1. The form oi 7.12 rams same, because in this case 7.22 3 replaced by ,I r I V ==V,+V2+~--+V,, 7.35 h 4‘ So we can use the same 7.;6 or 7..8 ,or this case, using n roots of A.for 7.34. Example. Wt LL21 SLr-l Lb Li Lb=2 sb=2 fiL 55 Ln = 3 o—e -I- LL 3 4 Let us reduce the network of figure 7.3 into the form cf resonant components in parallel. [Z] = L&_+ Ls --L‘, [s] ’s M |>\[L] + [3| = Solving 7.38 we get }\= 0, A2: .. Cofoctors of 7.38 for K" =£ 2, K s 1.32 1 KIZ .2 o“ : _ 3 -2 Lb + LC 0 -2 5 0 LJ L_o o 0']: ' 1 -1 0—1 + s, '5. -1 3 -2 ss_ _0 -2 2 3 + 1 -2 — 1 o -2 - 1 5 + 3 -2 o -3: 4 + 1.068, A3: -0341 these his are 8.) 3 ii, = -3175 Km: 0.232 = 2 ’3 - -Z’O272 is: 0.636 Substituting these values into 7.28, we get [1’]: 1 1 L1 l -1 1 -0.0637 -0020 ‘ This is the transformation matrix. 07' O 7.36 7.38 7.39 7.40 7.41 59 Then [u] = [runs] = ’m 0 0 l 0 26.21 0 7.42 _0 0 3.432] Lni [5 '1 = [Flt] B‘] = "o o o 7 0 .9.3 0 7.43 _P O 1.149d From 7.42 and 7.43 we can write at once the Foster's equivalent form es shown in figure L' = a: s; z . ‘ T _T L. J II Fig.7.“- 7.4. 7.0 s; = 0 26.21 s; = 23.0 3.435 s; = 1.169 Using equations 7.31 or 7.32, 7.43 can be derived from 7.39 and 7.42 as below. [s'] a - "9.0 0 0 _i 0 26.21 0 L0 0 3.435] = "o 0 o " o 28.0 o L o 0 1 .161 This is the same as 7.43. T—o O O O O -O.341 ..JL 7.44 (1) (3) (A) (5) (6) (7) (8) (9) (10) (11) (12) (13) 60 References Kron: Tensor Analysis of Networks Kron: Short Course in Tensor Analysis Slepian: A. I. E. E. , Vol. 56, P. 617 (1937 May) Bocher: Introéuction to Richer filgebra Guillemin: The Hathematics of Circuit Analysis Guillvmin: Communication Networks, Vol. II, Chap. VI Pipe: "Transformation Theory of General Static Polyphaae Networks", Trans. of A. I. E. B. Vol. 59 Kron: Tensor Analysis of Networks, p. 152 Guilleminz Communication Betworks, Vol. II, Chap, VI Guillenin: The Hathematica of Circuit Analysis, 9. 156 ' ' p. 163 ' “ p. 158 ' Communication [ctworks, Vol. II, Chap. V